I want to send JSON object from html file and receive it in servlet and then convert it into custom class of LastMove using
new Gson().fromJson(input, LastMove.class);
how to do it?
@RequestMapping(value = { "/mapping" }, method = RequestMethod.GET)
@ResponseBody
public Map<A, List<B>> getAsByB(HttpServletRequest httpRequest) {
return map;
}
when i try to get it by url i get an error. how can i send a response of a map as a json ?
I'm new to json and the web. My purpose is to use json data from a server and parse it and show meaningful data to the user. I am aware of json parsing, so no sweat there. However, I would like to know how json data is sent to the front end after which it can be parsed.
Usually in my json parsing examples, I have a variable like var data = ]OR I do a getJSON on a data.json file which I have stored in the project folder. However, I want this data to come real time from a servlet. How to go about this?
So, basically my question is, how do I send real time json data from a servlet backend, say some records which I have extracted from the database using jdbc?
I'm trying to create Web Services with Eclipse (Java Runtime 7 (also tried 8) Tomcat 7 (also tried 8).Web Service with parameter "byte[]" and return value "byte[]" works fine.Web Service with parameter "myOwnClass" and return value "myOwnClass" works also fine.But if I have a "byte[]" element in "myOwnClass" and I run my Client test program I get the following error:
AxisFault
faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Server.userException
faultSubcode:
faultString: java.lang.NumberFormatException: For input string: "MTExMTExMTExMQ=="
Why? I don't have any numeric element (such as int ...) in my class members!?
I'm writing a custom class loader to load some .jar file
public class IQJarClassLoader extends ClassLoader {
private String jarFile = "json-simple-1.1.1.jar";
private Hashtable classes = new Hashtable();
public IQJarClassLoader() {
super(IQJarClassLoader.class.getClassLoader());
[Code] .....
I receive this exception :
Exception in thread "main" java.lang.ClassCastException: org.json.simple.parser.JSONParser cannot be cast to org.json.simple.parser.JSONParser
Everytime, because i don't cast. Casting an object to a class with the same name loaded by different classloaders is no different than trying to cast.
My input class
package core;
import java.util.ArrayList;
import org.lwjgl.input.Keyboard;
public class Input{
public static final int num_key = 78;
private static ArrayList<Integer> currrentkeys = new ArrayList<Integer>();
private static ArrayList<Integer> downkeys= new ArrayList<Integer>();
private static ArrayList<Integer> upkeys = new ArrayList<Integer>();
[Code] ....
Where should I keep a collection of instances of my custom class? In the class itself in a static variable?
class Item {
int quantity;
static ArrayList<Item> list = new ArrayList<Item>();
Item(int q) {
quantity = q;
list.add(this);
}
// Some methods and whatnot.
}
Is it fine like this or should I implement the collection elsewhere? What say you?
Regarding the lifecycle of servlet , in headfirst servlet i can find :
You normally will NOT override the service() method, so the one from HttpServlet will run. The service() method figures out which HTTP method (GET, POST, etc.) is in the request, and invokes the matching doGet() or doPost() method. The doGet() and doPost() inside HttpServlet don’t do anything, so you have to override one or both. This thread dies (or is put back in a Container-managed pool) when service() completes.
How can I call the doGet method of the subclass from the superclass. i am not getting this .
I have this arraylist off a custom object that looks like this witch also contains a list off custom objects
package holders;
import java.util.ArrayList;
public class ManufacturingJobHolder {
private String name;
[code]....
here i have my bean class
package com.emp;
public class salarybean {
private String name;
private Double days;
private Double id;
public String getName() {
return name;
[code]...
now i want to retrieve all these values in another servlet where i want to do some calculation but not able to retrieve it is showing null and indicating for this value in my eclispe IDE " Iterator<salarybean> itr=list.iterator(); "
public class Time extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, java.io.IOException
[code]....
I have data base connection which i have configured via a listener class i configured properly in DD but still i am not able to deploy the project and server log show that startL.java listener class was not found why is this so as config is proper with the name
here is my server log
[2014-08-01T20:53:59.112+0530] [glassfish 4.0] [SEVERE] [] [javax.enterprise.system.core] [tid: _ThreadID=34 _ThreadName=admin-listener(3)] [timeMillis: 1406906639112] [levelValue: 1000] [[
Exception while loading the app : java.lang.IllegalStateException: ContainerBase.addChild: start: org.apache.catalina.LifecycleException: java.lang.IllegalArgumentException: java.lang.ClassNotFoundException: contpack.startL.java]]
**if i remove the Listener tag then app runs fine**
My dynamic web project has a java class that captures a session variable with the following code.
HttpSession LoginSession = request.getSession();
String VAR = LoginSession.getAttribute("myVar").toString(); //This is the row 127
If i test the app in local (Mac + Java 1.8 + Tomcat 8) all works. In my remote cloud server (Ubuntu 14.10 + Java 1.8 + Tomcat 8) all works, except this class, that has this code. I copy the complete error here. Note that the row 127 of the error message is the second row of the previous code; and, if i comment this row with // and assign a fix variable all works. So, the problem is that 127^ row.
14-Dec-2014 08:15:23.923 SEVERE [http-nio-8080-exec-14] org.apache.catalina.core.StandardWrapperValve.invoke Servlet.service() for servlet [srvNavigation.SrvPT] in context with path [/myapp] threw exception
java.lang.NullPointerException
at srvNavigation.SrvPT.doGet(SrvPT.java:127)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:618)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:725)
[Code] ....
How can i solve the problem?
I need to check in my java class the status of the javascript (whether it's enabled or disabled) and based on that few validations will be performed at server side.
If have to use noscript, then any small example for xhtml. My project works on Spring web flow.
how it is decided which class will implement a session listener interface? Which class will implement HttpSessionListener? Which one will implement HttpSessionActivationListener, HttpSessionBindingListener or HttpSessionAttributeListener?
View Replies View Relatedi have file index.jsp , that approach to reguar java class and call function . in that function i want to get attribute from session like this :
List<Coupon> couponsList = (List<Coupon>)request.getSession().getAttribute("listOfCouponsThatNotExpired");
because this regular java class i get error message ,how to solve this ?
I just want to know how to pass an Attribute along with its value from servlets to a plain Java class. Im using java beans but it's showing null...So as an alternative im using session to access variables in java class..
View Replies View RelatedI am stuck with my application. I have jsp, servlet application with jasper report server. When I run the application through eclipse, everything works perfectly. But When I try to run it in Tomcat (without eclipse) it gives me the "Unable to resolve the class file " error. I tried all the solutions I got through the google, but still I am unable to come over it.
View Replies View Relatedagain i am facing problem i am able to run Listener class also the ContextListener is initialised but it is giving me error on Tomcat 6.0 command prompt
Here is my Listener Class Sample.java i am able to compile the code but it is giving java.lang.nullpointer exception at runtime on Tomcat.exe Is there is problem in my code
package servlet;
import java.io.*;
import java.io.FileInputStream;
import javax.mail.*;
import javax.mail.internet.*;
import javax.activation.*;
import javax.mail.internet.MimeMessage.*;
import javax.mail.internet.InternetAddress.*;
import java.util.*;
[Code]...
I have JSON which as response from third party server,i call the URL and i want to print in browser as json but it is not display browser also display well in console i post my code here
URL url = new URL ("http://api.rottentomatoes.com/api/public/v1.0/movies/770672122.json?apikey=qpdtfwugwbxt32awk8jvwcdq");
URLConnection uconn = url.openConnection();
BufferedReader in = new BufferedReader(new InputStreamReader(uconn.getInputStream()));
String line=null;
while ((line = in.readLine()) != null) {
System.out.println(line); }
output in browser
============
The XML page cannot be displayed / Cannot view XML input using style sheet. correct the error and then click the Refresh button, or try again later.
XML document must have a top level element. Error processing resource '[URL] ......'. and also The XML page cannot be displayed Cannot view XML input using style sheet. Please correct the error and then click the Refresh button, or try again later.
A semi colon character was expected. Error processing resource '[URL] ....'. Line 10, Posi...
"canonicalUrl": "/v1/products?format=json&apiKey=9uvqqsjvwxc4c4ferw922k7k",
like error showing
output in console:
{"total":19,"movies":[{"id":"771312513","title":"Captain America: The Winter Soldier","year":2014,"mpaa_rating":"PG-13","runtime":136,"critics_consensus":"Suspenseful and politically astute, Captain America: The Winter Soldier is a superior entry in the Avengers canon and is sure to thrill Marvel diehards.","release_dates":{"theater":"2014-04-04"},"ratings":{"critics_rating":"Certified Fresh","critics_score":94,"audience_score":99},"synopsis":"Steve Rogers continues his journey as the super-powered American soldier who's grasping to find his place in a modern world after being frozen in ice....
I am trying to learn how to parse a Json with java. So I have this code
import java.net.*;
import java.io.*;
public class test2 {
public static void main(String[] args) throws Exception {
[Code] .....
and it has this output
{
"response": {
"version":"0.1",
"termsofService":"http://www.wunderground.com/weather/api/d/terms.html",
"features": {
"conditions": 1
[code]...
How do I turn this information into java objects?
So I would like to get information out of a web-API. But my question is how I do this. I guess I need to read the URL first. And parse it after but what is the best way?
For example : [URL] .....
I would like some clarification on a project I am working on. I need to build a java application to query a xml and json file. I have started by parsing both documents and I am unsure if I am doing the next steps correct. I was thinking about dropping the txt file with both outcomes into a db and doing it that way, is this the right way or is there a better and more efficient way of doing things ?
View Replies View RelatedI have a JSON string
Java Code: {
"AvailableDeliveries": {
"500": {
[Code]....
Number of JSON object can vary. I tried to generate POJO from jsonschema2pojo but it generate fix number of object inside AvailableDeliveries class. How I can define a POJO with collection of object and map corresponding field for above JSON string. I can't change the structure of JSON response as I am consuming the string.
Please find below my JSON object ,how can we split
[
{"alpha2Code":"AF",
"alpha3Code":"AFG",
"altSpellings":"AF,Afganistan",
"area":652230.0,
"callingcode":"93",
"capital":"Kabul",
"currency":"AFN",
"gini":27.8,
[code]....
I need it should be split & Write Java code by JSONArray and JSONObject
Create Json from a List's data
View Replies View RelatedI want to read and write json to/from a file. I read the following document:
JsonReader (Java(TM) EE 7 Specification APIs)
I try to define a JsonReader object in Eclipse:
JsonReader jr
But there appears to be no import for it. Where I am supposed to get the Json library?