I need to write server side program(Servlet) which must be access by several requests at same time.how to handle this using java? Do i need to use queue or multiple instance of same class. Any example server method which returns the results based on ID
public String getResut(int id){
1)get db connection
2)get the result from db
3) retun the result
}
I need to implement Oauth2 with facebook to get authencation. I tried to write a servlet with the method Service, and i got the code thah i have to use in a second request.
Now i need to send a request at this URL :
1) [URL] .....
and wait for a responce with an URL that have the access_token to use with facebook
2) [URL] ....
Is it Possible in a single Servlet after i receive the "code" to send a second request to the URL in 1 and get the response with URL in 2 to retrieve the access_token?? if yes....how??
How is this possible? Here is the servlet page.
/**
* Servlet implementation class InvoicingDeptServlet
*/
@WebServlet("/InvoicingDeptServlet")
public class InvoicingDeptServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
//Make arraylist global object
ArrayList<InvoiceData> invoiceList = new ArrayList<InvoiceData>();
[Code] ....
I want to know what is the best way for server side validation in servlets with JSP.
View Replies View RelatedHow the server know the device type from which request came from. I have requirement to implement the logic based on the type of the device. Eg: Mobile, TAB, PC or Laptop. Is there any existing API in Jquery to know the details about the client?
View Replies View RelatedI would like to know the details about how a server handles a multipart request. I know that a webserver comprises of a HTTP adapter(which is responsible for receiving http requests and sending http responses) and a container(which is responsible for handling dynamic requests).
So, when a client sends a request, the HTTP adapter receives it. Then transfers the request to the container if the http adapter cannot handle it(jsps, servlets for example).
Suppose, a client sends a multipart request which has an avi file of size upto 100mb. For example, lets assume that the client takes 5 minutes to upload the file.
Lets also assume that my application is only interested in flv files. Is there any way to stop/terminate the multipart request before the file is transferred to the server? So that the client's time will not be wasted?
I think that the HTTP adapter will transfer the request to the container only after receiving the entire request, i.e. the servlet will be called only after the file is transferred to the server from client. Is it right?
If its right then there is no easy way to terminate the multipart request unless the entire file is transferred to the server. Is this right?
How does web server differentiates between request for static web page and request for dynamic web page? i think if web server receives request for static page directly renders that to server or else if request is for dynamic web page passes that to web app which processes the request and renders that to client. bUT how does web server differentiates between both the request.
View Replies View RelatedI have some data in the database and values can be added on demand. so when ever the value added to the database i need to promt that message to all users which are accessing my website, so how can i acheive this....
View Replies View RelatedI am very much new to jsp and servlet. I want to set global error page for every exception occured at server side. I am trying with following code , but something is going wrong and I am not able to c error page.
package com.web;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
[Code] ....
I would like to know how we can deploy one Web application on multiple server to share the work between them? My first thought is that we just deploy the same war file on different servers that connect to the same database. However, what will happen when a user enter something like [URL]? How can multiple servers share the same domain name and how the requests from different users are redirected to these different server?
View Replies View RelatedHaving with LSL and JSF working together? The only thing I have gotten to work with LSL is PHP, and I know I could get JSP working with it with a little research. However, I rather not mix them on my server.
The only requirement for LSL to work with it is there needs be a custom page that can handle get and post request directly. I have not done this with JSF yet so I'm wondering how that would look.
I am calling a SOAP based webservice using JAX-WS and a client jar. I want to get a request and response somehow and save it for audit purposes. How I can do this?
When I google it, only Handlers come up, but, as far as I understand, it is not applicable on client side.
I want to ask that, when a server listen to A port and it accepts a request from a client then the server accepts the request using accept method,but how does the server get the info about the client like wat is the port no and ip address of the client,I read a answer regarding this that Server never gets the port no of client only the ip address and it connects to client using a connection stream but as far I know from networking, a device must have the ip address and port no of the device it wants to connect to.
View Replies View Relatedin my web.xml the.STATE_SAVING_METHOD setting is server
<context-param>
<param-name>javax.faces.STATE_SAVING_METHOD</param-name>
<param-value>server</param-value>
</context-param>
for measurement of application security isn't not allow to change this parameter to client , so the problem when I access for application and I open a new page via linker for print for example and I would access for my initial page to make change or modify my initial page it s no possible to make any modification because I have a empty bean , but if the state saving is a client I haven't a problem because a tree map is stored in client browser, so my version of JSF is 1.1.1 ,
I want to create a new instance of a Java model class for each new request coming to a servlet.
How to do that without doing that in doGet() or doPost().
I have a Registration Form in which I am registering user to perform some sort like Entering messages I want to perform some Server Side validation.
Like suppose a user has Enter an Id then as soon as he start entering the Id then I want that this Id should be checked in database that if this Id exists in database or not.
and similar types of validation I want to apply on other fields to.
How can I acheive this?
I have the following questions:
1. Does a GET HTTP request contain a request body? If yes what is contained in it? Are the request headers also part of the request body?
2. Is it possible to send a byte array as part of the GET request in its body?
3. Is there a size limitation on the data that can be sent via a GET request?
In order to create an xhtml view:
1. All jsf tags like datatable, form, etc.. will generate UIComponents in server side, right?
2. All non JSF tags will not generate UIComponents in server side, right?
3. If you want something in a view that will be the same across users and requests, I mean, It will not change like a label tag, it doesn't make any sense to create it with a JSF tag in order to save memory in server side, right?
I am working on a chess game. I need to construct a game room where all the player are present and room chat is up. Also some tables where games are being played. Now my question is how to create this game room?
To me this room must need to be like static or global (if I am not mistaken) that is up when server starts and players can join this room and should be down when server is done. How can I implement such room that would stay up for infinite time.
I have written the following code to handle multiple Client Request. Lets Assume that it takes server 300 nano seconds(ns) to process one connection request. It recieves two connection requests at time t1 and t1+200ns. Since server is busy handling request 1 at time t1+200ns. what will happen to request 2.if yes what is the max size of that buffer?Maximum number of request that a server process per unit time depends on the java code.Is there also a limit to how many request a server can recieve per unit time?
public class EchoServer
{
public static void main(String args[])
{
ServerSocket serverSocket = null;
BufferedReader readSocket = null;
PrintStream writeSocket = null;
serverSocket = new ServerSocket(9998);
[code]...
I am trying to display two JComboBoxes side by side. I can successfully display them as part of a BorderLayout if they are in the North and East, but when I try to display them side by side in the same area, eg North, only one of the combo boxes gets displayed.
package selectingshapes;
import java.awt.Graphics;
import java.awt.Color;
import javax.swing.JPanel;
import java.awt.Graphics2D;
import java.awt.FlowLayout;
import java.awt.event.ItemEvent;
[Code] .....
I have been trying to implement custom request method in HTTP header while posting my data to the server URL. My application specific URL accepts -X parameter and -d for the data and it is mandatory for that url. Basically I am trying to dump JSON data into my influx DB using CURL command which is working fine from the shell. But the issue is, if I am implementing the same in java with proper approach, it is not supported or working. My CURL command is :
curl -X POST -d '<my_json_data>' '<my_url>'
How can I implement the same in java using HttpUrlConnection or other available approach?
I'm using SchedulerExecutorServices to Schedule a task. My Question is how can i schedule more than one task side by side:
Here is what I'm doing:
public class Scheduler {
public Scheduler(Runnable thread, int startAfter, int iterateAfter, TimeUnit timeUnit, int length) {
ScheduledExecutorService scheduler = Executors
.newSingleThreadScheduledExecutor();
final ScheduledFuture<?> timeHandle = scheduler.scheduleAtFixedRate(
[Code] ....
When we forward the request to a jsp , I noticed that the url bar address does not change .
I made a form form.html , and set action to a servlet then in servlet class I set an attribute and forward the request to jsp ,which prints the value of that attribute.But the url in address does not actually points to that jsp to which i forwarded the request.
I have to forward my request to another webApplication using post request parameters. In this case Webaplication-1 need send request using post request params to Webapplication-2 & once Webaaplication-2 receives request it has to process & display output.
For this have tried below 2 options which Servlet API provides.
1. RequestDispatcher : this will used to forward request to another resource within the application.
2. sendRedirect() : this method support doGet() of Servlet.
3. Using HttpClient, which is provided by Apache able to do but it will not displaying Output,It sending back response to Webapplication-1 .
Is there any option which will handover request from one webapplication to another webapplication.
I want to create a new instance of a Java model class for each new request coming to a servlet.
How to do that without doing that in doGet() or doPost().