Servlets :: Unable To Get Path Of File When Upload Files In Server After Browsing Folders
Jun 30, 2014
I have a code that uploads files in server after browsing folders and files then get the paths of files but I have a problem in getting the paths
List items = upload.parseRequest(request);
Iterator iterator = items.iterator();
while (iterator.hasNext()) {
FileItem item = (FileItem) iterator.next();
if (!item.isFormField())
{ fileName = item.getName();
root = getServletContext().getRealPath("/");
path = new File(root + "/uploads");
[Code]...
list1 must has paths that I want but I do not get the paths of upload files
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Dec 1, 2014
In my web application i want to upload file to drop-box. I am getting file name from browser.Is it possible to upload file to drop-box with only file name.
Below the drop-box upload code with java.
File inputFile = new File("New Text Document.txt");
System.out.println("inputFile.getAbsoluteFile(): " + inputFile);
FileInputStream inputStream = new FileInputStream(inputFile);
try {
DbxEntry.File uploadedFile = client.uploadFile("/magnum-opus.txt",
DbxWriteMode.add(), inputFile.length(), inputStream);
System.out.println("Uploaded: " + uploadedFile.toString());
} finally {
inputStream.close();
}
In the above code the place New Text Document.txt we have to provide total path of file.
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May 20, 2014
I'm using jsf 2 to upload file, first I upload the file in a system directory, then trying to store the path to database with other information, my stuck is that when submitting I upload the file successfully, find it in the right place, find the other information such as description, file name ... in database but don't find the path. this is my managed bean :
package mbeans;
import java.io.File;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.net.URL;
import java.util.List;
[code]...
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Dec 4, 2014
How to upload file to google drive using java. my java code is.
HttpTransport httpTransport = new NetHttpTransport();
JsonFactory jsonFactory = new JacksonFactory();
GoogleAuthorizationCodeFlow flow = new GoogleAuthorizationCodeFlow.Builder(
httpTransport, jsonFactory, CLIENT_ID, CLIENT_SECRET, Arrays.asList(DriveScopes.DRIVE))
.setAccessType("online")
.setApprovalPrompt("auto").build();
[Code] ....
So in that file object(java.io.File fileContent = new java.io.File("document.txt");) asking complete file path. But in file upload we can get only file name not path.
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Mar 25, 2014
I wrote a code to download a zip file in jsp, but it is not working as expected, when i execute this following program i am able to download file with "download_all.jsp" name, but now original download file (/tmp/Download_All/1244687508907.Zip). The download_all.jsp is my jsp name which is having the following code. Here is the code snippet:
try {
String filename = "/tmp/Download_All/1244687508907.Zip";
if(request.getParameter("filepath")!=null){
filename=request.getParameter("filepath");
}
// set the http content type to "APPLICATION/OCTET-STREAM
response.setContentType("APPLICATION/OCTET-STREAM");
[code]....
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Sep 3, 2009
I have a requirement where a large file (100 -200MB) is uploaded from the client to a content management system. I am using a servlet with Apache Commons File Upload API. Apache FileUpload has 2 ways of handling files,
1) Non-Streaming
2) Streaming
Currently I use the Non-Streaming approach where the servlet stores the file in a temp location and upload the same into the content management system - This is taking lot of time so I am trying to implement Streaming API.
Content Management API supports streaming in 2 methods,
a) SetContent - Takes the file's ByteArrayOutputStream as input -> This gives OutOfMemoryException because the file being large
b) AppendContent - Takes the file's ByteArrayOutputStream as input -> This method can be called multiple times to upload the large file but I dont know how to do this. The Apache File Upload gives InputStream of the file and I need to split that into chuncks and append into the content management system.
How to convert InputStream to 4KB ByteArrayOutputStream so that I can use the AppendContent method in content management API?
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Apr 14, 2015
I need to read folder structure from the excle file and need to read all the files which are available inside folder structure.folder structure like below
c:Migrate
C:MigrateMigrateFiles
...
...
..etc.
I am ble to read files which is avalibale in all the folders with single thread,i want to read those files with multiple threads,each thread shoud reads the files from different folder. here how to read.
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May 30, 2014
I developed an application that is accessing some property files. The condition was that the user should be able to modify the content or parameters of those property file.How can I distribute the application using Java web start that also includes those property file in the client side?
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Apr 9, 2015
I would like to understand how does multipart/form-data works during file upload scenario's, Does it chunks the data from client to server while transferring the files ?
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Jan 22, 2015
I thought there'd be loads of people looking to do the same. I have just got a Github account and uploaded all my source code for a project and would like to upload the associated JAR file with it. I am not too fussed about the JAR file being on github, providing a link to somewhere else it can be downloaded is fine too.
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Nov 16, 2006
I am using JSP as a front-end view purpose,From this page I have to push the data to one of the Action Request System form (AR System 6.3). I am using ARS JAVA API.As per requirement I have to upload one file from user on JSP and have to push it to this back-end form.I tried JavaZooms javazoom. upload class but its giving me a error and I couldn''t fine this class file anywhere. So this code didn''t work finally.
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Mar 24, 2014
code for upload and downloading files with validation (eg. File size not exceeding 100MB) in java
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Mar 14, 2015
I have the file in my project sitemap.xml, which i am trying to write via XMLStreamWriter. My code gets successfully executed as i can see the logs. But my sitemap.xml file keeps blank. Why nothing is getting write in my sitemap.xml file. Below is my servlet code.
@Override
protected void doGet(SlingHttpServletRequest request, SlingHttpServletResponse response)
throws ServletException, IOException {
logger.info("request.getResponseContentType() ::: " + request.getResponseContentType());
logger.info("root path is :: " + rootPath);
if (request.getResponseContentType() == null) {
[Code] ....
I can see "END Document" and "Location is " under my log file.
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Sep 9, 2014
I am stuck with my application. I have jsp, servlet application with jasper report server. When I run the application through eclipse, everything works perfectly. But When I try to run it in Tomcat (without eclipse) it gives me the "Unable to resolve the class file " error. I tried all the solutions I got through the google, but still I am unable to come over it.
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Jul 17, 2014
Batch file (. BAT) problems with some folders on. I created an application in Java and put the JRE folder within the application, because some users do not have Java installed on your machine and the way I did, my application runs. JAR with the JRE that is contained in my application but I created a BAT file that contains the following command:
start "" jre8 bin javaw-jar app.jar
So I run my program in java through the file. BAT calling JRE that is inside the folder and then this JRE runs the mine. JAR and works great anywhere in windows, worked well on a USB key with this command is within. BAT (start "" jre8 bin javaw-jar app.jar).
BAT in certain folders, eg Program Files and Program Files (x86), I need this code to be able to find any directory, regardless of whether the directory has spaces in the name, symbols, numbers or anything else, because maybe people will put the application folder to another location or rename the folder, and if this happens the program will stop working? And especially do not give problems to run inside the Program Files and Program Files (x86) because the application runs everywhere except in these two folders.
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Sep 19, 2013
I am new to linux and using centos ver 6.4 64bit . i want to install sqldeveloper so i run below rpms
sqldeveloper-3.2.20.09.87-1.noarch.rpm
jdk-7u40-linux-x64.rpm
After install when i run sqldeveloper command then it prompt me for jdk path
1. Which I don't know how to find
2. When I try to give /usr/bin/java1.7.0_09/ and enter then it give me below error
/usr/bin/java1.7.0_09
Error: /usr/bin/java1.7.0_09/bin/java not found
Type the full pathname of a J2SE installation (or Ctrl-C to quit), the path will be stored in ~/.sqldeveloper/jdk
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Jan 25, 2014
Iam trying to upload jpeg image.
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
[Code] ....
In servlet the below code
DataInputStream din = new DataInputStream(request.getInputStream());
byte[] data = new byte[0];
byte[] buffer = new byte[50];
int bytesRead;
while ((bytesRead = din.read(buffer)) > 0 ) {
byte[] nData = new byte[data.length + bytesRead];
System.arraycopy(data, 0, nData, 0, data.length);
System.arraycopy(buffer, 0, nData, data.length, bytesRead);
data = newData;
}
What i see is servletinput stream does't have any values.It does't even enter while loop.
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Apr 1, 2014
I am working on a chess game. I need to construct a game room where all the player are present and room chat is up. Also some tables where games are being played. Now my question is how to create this game room?
To me this room must need to be like static or global (if I am not mistaken) that is up when server starts and players can join this room and should be down when server is done. How can I implement such room that would stay up for infinite time.
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May 17, 2013
I ma trying to implement Java "watchService". I am unable to register network mounted drive path. Is there any solution for this.
Path ftpFolder = Paths.get("H:/Ftp/Incoming/");
where H is mounted Drive.
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Jan 30, 2014
I am trying to connect a remote machine but I can't. There is a shared folder in the remote machine, when I write the path to file browser in local machine, it does not find the path specified. Both machines have successful network condition and ping each other. Also, the shared folder is opened to everyone, there should not be a permission problem, right?
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Nov 14, 2014
I upload a file and save it like the following
byte[] uploadedFileBuf = new byte[(int) uploadedFile.length()];
saveFileSystem(excelUpload + getLocalFileName(acad_year, stuid), uploadedFileBuf);
private boolean saveFileSystem(String filename, byte[] data){
try{
FileOutputStream fos = new FileOutputStream(filename);
fos.write(data);
fos.close();
[Code]...
I can not read it use
HSSFWorkbook WorkBook = new HSSFWorkbook(new FileInputStream(filename));
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Apr 23, 2015
I'm having another issue. I have 2 java source files(see below). They are place in the same directory. How do I compile them using classpath?
I have already tried 1st attempt :
javac -cp com.companyname.interview.DuplicateReplace.java DuplicateReplaceTest.java [did not work!]
2nd attempt: javac -cp DuplicateReplace.java DuplicateReplaceTest.java [again, did not work!]
package com.companyname.interview;
public class DuplicateReplace { /* code */}
[Code] ....
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Oct 14, 2014
[highlight = java]
public static int getNumberOfPlaylists(Path p)
This method should return the number of files in this path containing a valid M3U header.
How do I get this done?
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Jan 21, 2015
I need to upload a file in R, I can do it with a CSV file or excel ect. The file I received is already in R format .Rdata.It is a file called surveydata.rdata.The two data frames are surveydata.4.num.frame and surveydata.4.lab.frame.The surveydata.4.num.frame is what I need.I can click on it in Rstudio to see the data but I can't load it to run an analysis.How can I upload this?
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Feb 5, 2014
I have a data.json in my J2EE web app.I need to load it either from local path when unit testing or from url when the server starts up.
so I've set it to get the local path by default and what I'm trying to do is that it is is running on a server, I'd like to change the path to a url.
Here is my code:
public String getUrlBase(HttpServletRequest request) {
URL requestUrl;
try {
requestUrl = new URL(request.getRequestURL().toString());
String portString = requestUrl.getPort() == -1 ? "" : ":" + requestUrl.getPort();
return requestUrl.getProtocol() + "://" + requestUrl.getHost() + portString + request.getContextPath() + "/";
} catch (MalformedURLException e) {
e.printStackTrace();
}
return null;
}
which works fine. The only issue is that I had to place this in the login page. Is there a way I can only set the path to the base url upon server start up?
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Mar 23, 2015
I have normal adress which works, like
localhost/contextPath/foo
In URL rewrite filter I forward that call like
((HttpServletRequest) req).getRequestDispatcher(".....foo1.jsp").forward(req, res);
And it gets there. On that page (foo1.jsp) I have link to original href
<a href="localhost/contextPath/foo">click.</a>
When I click that, in url rewrite filter I get:
String url = ((HttpServletRequest)req).getRequestURL().toString();// http://contextPath/foo/contextPath/foo
String uri = ((HttpServletRequest)req).getRequestURI().toString();// /contextPath/foo/contextPath/foo
which is bad address. How to handle that and why it happens ?
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