In my web application i want to upload file to drop-box. I am getting file name from browser.Is it possible to upload file to drop-box with only file name.
I'm using jsf 2 to upload file, first I upload the file in a system directory, then trying to store the path to database with other information, my stuck is that when submitting I upload the file successfully, find it in the right place, find the other information such as description, file name ... in database but don't find the path. this is my managed bean :
How to upload file to google drive using java. my java code is.
HttpTransport httpTransport = new NetHttpTransport(); JsonFactory jsonFactory = new JacksonFactory(); GoogleAuthorizationCodeFlow flow = new GoogleAuthorizationCodeFlow.Builder( httpTransport, jsonFactory, CLIENT_ID, CLIENT_SECRET, Arrays.asList(DriveScopes.DRIVE)) .setAccessType("online") .setApprovalPrompt("auto").build();
[Code] ....
So in that file object(java.io.File fileContent = new java.io.File("document.txt");) asking complete file path. But in file upload we can get only file name not path.
I wrote a code to download a zip file in jsp, but it is not working as expected, when i execute this following program i am able to download file with "download_all.jsp" name, but now original download file (/tmp/Download_All/1244687508907.Zip). The download_all.jsp is my jsp name which is having the following code. Here is the code snippet:
try { String filename = "/tmp/Download_All/1244687508907.Zip"; if(request.getParameter("filepath")!=null){ filename=request.getParameter("filepath"); } // set the http content type to "APPLICATION/OCTET-STREAM response.setContentType("APPLICATION/OCTET-STREAM");
I have a requirement where a large file (100 -200MB) is uploaded from the client to a content management system. I am using a servlet with Apache Commons File Upload API. Apache FileUpload has 2 ways of handling files,
1) Non-Streaming 2) Streaming
Currently I use the Non-Streaming approach where the servlet stores the file in a temp location and upload the same into the content management system - This is taking lot of time so I am trying to implement Streaming API.
Content Management API supports streaming in 2 methods,
a) SetContent - Takes the file's ByteArrayOutputStream as input -> This gives OutOfMemoryException because the file being large b) AppendContent - Takes the file's ByteArrayOutputStream as input -> This method can be called multiple times to upload the large file but I dont know how to do this. The Apache File Upload gives InputStream of the file and I need to split that into chuncks and append into the content management system.
How to convert InputStream to 4KB ByteArrayOutputStream so that I can use the AppendContent method in content management API?
I need to read folder structure from the excle file and need to read all the files which are available inside folder structure.folder structure like below
c:Migrate C:MigrateMigrateFiles ... ... ..etc.
I am ble to read files which is avalibale in all the folders with single thread,i want to read those files with multiple threads,each thread shoud reads the files from different folder. here how to read.
I developed an application that is accessing some property files. The condition was that the user should be able to modify the content or parameters of those property file.How can I distribute the application using Java web start that also includes those property file in the client side?
I would like to understand how does multipart/form-data works during file upload scenario's, Does it chunks the data from client to server while transferring the files ?
I thought there'd be loads of people looking to do the same. I have just got a Github account and uploaded all my source code for a project and would like to upload the associated JAR file with it. I am not too fussed about the JAR file being on github, providing a link to somewhere else it can be downloaded is fine too.
I am using JSP as a front-end view purpose,From this page I have to push the data to one of the Action Request System form (AR System 6.3). I am using ARS JAVA API.As per requirement I have to upload one file from user on JSP and have to push it to this back-end form.I tried JavaZooms javazoom. upload class but its giving me a error and I couldn''t fine this class file anywhere. So this code didn''t work finally.
I have the file in my project sitemap.xml, which i am trying to write via XMLStreamWriter. My code gets successfully executed as i can see the logs. But my sitemap.xml file keeps blank. Why nothing is getting write in my sitemap.xml file. Below is my servlet code.
I am stuck with my application. I have jsp, servlet application with jasper report server. When I run the application through eclipse, everything works perfectly. But When I try to run it in Tomcat (without eclipse) it gives me the "Unable to resolve the class file " error. I tried all the solutions I got through the google, but still I am unable to come over it.
Batch file (. BAT) problems with some folders on. I created an application in Java and put the JRE folder within the application, because some users do not have Java installed on your machine and the way I did, my application runs. JAR with the JRE that is contained in my application but I created a BAT file that contains the following command:
start "" jre8 bin javaw-jar app.jar
So I run my program in java through the file. BAT calling JRE that is inside the folder and then this JRE runs the mine. JAR and works great anywhere in windows, worked well on a USB key with this command is within. BAT (start "" jre8 bin javaw-jar app.jar).
BAT in certain folders, eg Program Files and Program Files (x86), I need this code to be able to find any directory, regardless of whether the directory has spaces in the name, symbols, numbers or anything else, because maybe people will put the application folder to another location or rename the folder, and if this happens the program will stop working? And especially do not give problems to run inside the Program Files and Program Files (x86) because the application runs everywhere except in these two folders.
After install when i run sqldeveloper command then it prompt me for jdk path
1. Which I don't know how to find 2. When I try to give /usr/bin/java1.7.0_09/ and enter then it give me below error
/usr/bin/java1.7.0_09 Error: /usr/bin/java1.7.0_09/bin/java not found Type the full pathname of a J2SE installation (or Ctrl-C to quit), the path will be stored in ~/.sqldeveloper/jdk
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head>
[Code] ....
In servlet the below code
DataInputStream din = new DataInputStream(request.getInputStream()); byte[] data = new byte[0]; byte[] buffer = new byte[50]; int bytesRead; while ((bytesRead = din.read(buffer)) > 0 ) {
I am working on a chess game. I need to construct a game room where all the player are present and room chat is up. Also some tables where games are being played. Now my question is how to create this game room?
To me this room must need to be like static or global (if I am not mistaken) that is up when server starts and players can join this room and should be down when server is done. How can I implement such room that would stay up for infinite time.
I am trying to connect a remote machine but I can't. There is a shared folder in the remote machine, when I write the path to file browser in local machine, it does not find the path specified. Both machines have successful network condition and ping each other. Also, the shared folder is opened to everyone, there should not be a permission problem, right?
I need to upload a file in R, I can do it with a CSV file or excel ect. The file I received is already in R format .Rdata.It is a file called surveydata.rdata.The two data frames are surveydata.4.num.frame and surveydata.4.lab.frame.The surveydata.4.num.frame is what I need.I can click on it in Rstudio to see the data but I can't load it to run an analysis.How can I upload this?
which works fine. The only issue is that I had to place this in the login page. Is there a way I can only set the path to the base url upon server start up?
