filePath = file.getAbsolutePath();
file = new File(filePath);
streamResult = new StreamResult(file);
But it also didn't work. There I got message seems like: "Can't find resource /User/user1/Desktop/program1/resources/file.xml" - but that's really absolute path to a file.
I also made unit test which completed with "green light", but in jar its wrong with message "Can't find resource /User/user1/Desktop/program1/resources/file.xm" ....
In my web application i want to upload file to drop-box. I am getting file name from browser.Is it possible to upload file to drop-box with only file name.
I am facing a problem while executing a task. My task is to make such a code which will search for my source code file (abc.java) in all directories and then displays the code in textarea inside frame and along with that i also have to display the path of the file in text field. I have coded something but i am really not getting anywhere near my task.
First of all, i am using ubuntu and jdk8. My problem: displaying the current path of a file in my system Approach: I have a file called dummy.txt in a given directory which have enough permissions and i did the following:
I expected to see displayed the current path of the file without the name of the file but it is showing a different path. I just want to display the current path of the file without the name.
I already done my program with images on it but when i convert it to exe , the images is not appearing.
Usually my images are located at documents netbeansprojectprojectimage.jpg
When i run the code on netbeans the images are appearing but when i convert it to exe or jar file run on a computer without netbeans.. images is not appearing ...
As you can see I have specified a file path, as it is needed to draw the image.
The image "sun" is in a certain folder inside the directory of my jar file.
But If I were to send the whole package to my teacher to review. The file path would still remain the same, local to my computer making the image, unloadable.?
I'm using jsf 2 to upload file, first I upload the file in a system directory, then trying to store the path to database with other information, my stuck is that when submitting I upload the file successfully, find it in the right place, find the other information such as description, file name ... in database but don't find the path. this is my managed bean :
I am copying the xml files from one folder to other folder, in the source folder, i have some files which have some content like "backing File="$IDP_ ROOT/metadata/iPAU-SP-metadata.xml" but while writing to the destination folder.i am replacing the "$IDP_ROOT" with my current working directory. The entire copying of files is for deploying into tomcat server. The copying is done only when server starts for the first time.Problem: If i change the folder name from my root path in my machine after i run the server,the entire process will be stopped because the destination folder files already contains the content which is with existed files names or folder names.
So i want to change it to relative path instead absolute path. What is the best way to do it? Please look at code below:
[ // Getting the current working directory String currentdir = new File(".").getAbsoluteFile().getParent() + File.separator;
I need to write the exact directory path like C:LisaestUpdate to a properties file.
I am trying it by
FileInputStream in = new FileInputStream(test.properties); Properties props = new Properties(); props.load(in); in.close(); FileOutputStream out = new FileOutputStream(newprop.properties); props.setProperty("myDirectory","C:Lisa estUpdate" ); props.store(out, null); out.close();
but the properties file is updated as C:Lisa estUpdate
Extra comes before :.
How can I remove that.
Even I tried it with an command but got same output.
I'm a Java beginner and I've been trying to scan a file using the Java Scanner. I've tried searching online for this error and I only find people's questions who have entered an incorrect relative path. I'm entering in an absolute path and I'm using Eclipse Standard Edition on a 2013 MacBook Pro with Mavericks 10.9.2.
Anyway, the error message I'm receiving on Eclipse is: Exception in thread "main" java.lang.Error: Unresolved compilation problem: Unhandled exception type FileNotFoundException
at App.main(App.java:12) public class App { public static void main(String[] args){ String fileName = "/Users/Student/Documents/index.html";
[code]...
Why it cannot find this file. I've checked the absolute file path of index.html on my Mac and I've copied and pasted it into my code.
currently I am doing my java web application project ,and it has following steps 1) Upload the txt files 2) java servlet gets the txt file's url , read the data and do the calculation 3) pass the results
I almost finished the second step , and working on the first step .Since there are so many input files at a given time , i have to use drag and drop method to get the file's location.how to pass file's path to servlet.( servlet code can read the data from the given txt file path )software used - tomcat and netbeans 8.0
I'm using a PrimeFaces UploadedFile xhtml page to select a csv file to read and write using a managed bean (SuperCSVParser.java). The file is read and written to an entity class which then persists the data to a database. The application works fine if I specify a file path on the physical server and select a csv file on that file path. But for the production version I want the user to select ANY file name from ANY directory on their local system.
I know about the FacesContext methods and I've looked at some methods from the java.io File class. Most of these methods are about getting the path from the server, where I want to 'pass' the path String from the client machine to allow the uploaded file to go through. When I try with the below code I get:
java.io.FileNotFoundException: data.csv (The system cannot find the file specified)
I'd like to know what I'm doing as I prefer not to explicitly declare a path in the final app. I'm almost sure that's possible.
JFrame parentFrame = new JFrame(); JFileChooser fileChooser = new JFileChooser(); fileChooser.setDialogTitle(txtPushCode.getText()); int userSelection = fileChooser.showSaveDialog(parentFrame); if (userSelection == JFileChooser.APPROVE_OPTION) {
[Code] ....
But as you can see, it downloads only to "C:android empcoloricon.png". I want to download it to path where I chose in FileChooser with the name and extension I choose. In short, how can I use dynamic file path names in where ever I want in my applications?
I have the Java Development Kit downloaded in my C file and my book tells me to compile the program I need to open command windowand change the directory where the program is stored. I tried the command cd to change directory and received this message "The system cannot find the path specified."
I checked the Environment Variables on Windows 7 and the Path says: C:Program Files (x86)Javajre1.8.0_31in
This is after many tries and i still can't change directory and i keep getting the same message.
I have BlueJ installed on my computer and it does the job of compiling the java source code written in it. If I want to write and compile source code outside of BlueJ do I still need to download the Java SDK and set the PATH variable, even though I am apparently able to do it in BlueJ?
which works fine. The only issue is that I had to place this in the login page. Is there a way I can only set the path to the base url upon server start up?
I have the Java Development Kit downloaded in my C file and my book tells me to compile the program I need to open command windowand change the directory where the program is stored. I tried the command cd to change directory and received this message "The system cannot find the path specified." I checked the Environment Variables on Windows 7 and the Path says: C:Program Files (x86)Javajre1.8.0_31in
This is after many tries and i still can't change directory and i keep getting the same message.The book I am using to learn Java is "Java How to Program: Tenth Edition" from Paul and Harvey Deitel.
I've just got a new computer and i tried to set the class path the way i did with windows xp but it's not working. This is what i have done. I added a Path variable to user variables and added C: Program Files (x86)Javajdk1.6.0_20/bin as the variable value. But when i got to command prompt and type javac HelloWorld.java it just tells me javac is not recognised as an internal or external command.
Also another problem is after trying this and it not working i tried to add a path to the system variables. I added a new path variable but i think once i did that it deleted the one that was already there. Is that going to mess up my computer? What the default path variable for windows 7 is?i've got the right destination as i typed cd to change directory and when i typed C: Program Files (x86)Javajdk1.6.0_20/bin it changed to that. And i noticed if i typed in the destination wrong its just made an error.
I'm working on a project right now in JavaFX, and got stuck. I am drawing a path consisting of CubicCurveTo's and I wonder if there's any way to get the X and Y coordinates from certain parts of that path.
Imagine following a curve (path) with a pencil slowly, and every second you take note the X and Y coordinate. I mean I'm not interested in the control points or start and end points, but the points "in between", preferably at a certain interval.
I've searched for many things online, but have trouble knowing exactly which words to search for. "Paths" often bring up file paths, traversing, coordinates etc. all fail to give me any good results.
I tried to be as specific I could, and I don't think my current code is of any interest in this matter.
(The point of it all is that the path should simulate the path a person walks, and I will store the coordinates in a database for every second).
I want to use the bit of code below to re-write the page to tell the user of a successful registration and then redirect them to another page. My problem is that I can't figure out how to get the path right for the login page. As can see, my first choice was to have the use click to the login page and when I use href it works fine.
I tried to use the entire file page starting at C and that didn't work. I also tried
${pageContext.request.contextPath}/Login
which is what I had to do for the action in the form for the login servlet page.
My question is what is the URL I need to use. By the way, if I jut put in google's URL, or any other for that matter, it works fine.