Setting Password And Username - Username Works But Getting Errors For Password?

Apr 4, 2015

username works perfectly, but when I enter password I get this error.

Java Code:

OKbtn.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent evt) {
if(Usernametxt.getText().equals("Admin") &&
(Passwordfld.getPassword().equals("Admin2"))){
System.out.println("permition granted");
}else{
System.out.println("permition Rejected");

[code]....

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JSP :: Validate Username And Password

Apr 21, 2014

I want to validate username and password in JavaScript. I want to validate username and password with database values. If login failed i want to display alert message...ok. But problem is that i have index.jsp page. After clicking login button control goes to homepage.

jsp..okk.. in index.jsp I have taken dropdown to show designation. I select design then control goes to respective homepage... in homepage. I am checking username and password with database values. If login successful it goes to respective pages but if login failed it has to show me alert message. How can i do that ?

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I'm thinking that it is just a case of creating another sql query but i have tried and i cannot see the solution,i can open the employee page by default but that is not what i am trying to achieve. I am using an sqlite database which holds the username and password.

Here is my code
 
private void btn_LoginActionPerformed(java.awt.event.ActionEvent evt) {
// code to login to the back office system
String sql =" select username,password from Employee where username =? AND password =?";//sql query
try{
pst =conn.prepareStatement(sql);

[Code] ......

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Sep 3, 2014

I have a problem with my code i try to identify users by password and username but I cannot recognize only the last row in my table in database what can i do ....

private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {
try {
state=conn.createStatement();
res=state.executeQuery("select*from conex");
String pass=new String(this.pass.getPassword());
String name=this.name.getText();

[Code] .....

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Dec 23, 2014

I having problem on validating email and password whether does it belongs to a registered members or not. I'm using NetBeans and created a database, table name as members. I have done setting up connection pool and fill in data to my members table.This is my members table data.

#|id|email|password|name
1|1|what@what.com|what|Number 1
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This is my index.jsp

<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Library Application</title>

[code]....

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Dec 3, 2014

My homework is asking me to write a program that prompts the user to enter a password and displays "valid password" if the rule is followed or "invalid password"

Sample
enter a string for password: wewewx
valid password

It's being graded on
Design of my GUI
Dialog box
User friendliness
Creativity

My current issues with the current code I have written is simply the password doesn't work unless it starts with 2 digits, the other order it displays as wrong. and I have no idea how to add a GUI.

import java.util.*;
import java.lang.String;
import java.lang.Character;

[code]....

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I have a JSF page for changing login credentials and i preferred to use Java validations instead of JSF validations on the inputText. The password validation works fine but the username validation does not produce any output. This is my JSF form

HTML Code:

<h:form>
<p><strong>Please type your new username: </strong>
<h:inputText size="15" value="#{register.newUsername}"/></p>
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[code]....

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I need the username produced by this program to be in all lower case. The code is below.

/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
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*/

package dcollinshw03;
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[Code] .....

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Sep 1, 2014

I have created a JSP page, on click of a particular button, the control moves to the servlet "TestServlet".

This is the code under TestServlet:

import java.io.IOException;
import java.io.PrintWriter;
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import java.sql.Connection;
import java.sql.SQLException;
import java.sql.Statement;

[Code]...

Now, I have got a comment saying I should get the database connection from connection pool. And one more issue is that I have used the function System.getProperty("user.name") to get the username which i have logged in. But this code will be run on Unix which will not support this function. Any function where I can get the windows username. There is a function getUserPrincipal(), but this function returns a NULL. How to resolve this.

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Oct 12, 2014

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[code]....

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I have not created a class because I really have no clue what to write in this case. My main method is:

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// Create a Scanner object to read input.
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String input;// To hold the input

[Code] .....

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It had no syntax error but if there would be any other error or if i would receive a wrong result

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int size= 0;
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String enter=input.next();
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[Code] .....

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Oct 26, 2014

When I enter the wrong password, it says I have successfully logged in.

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[Code] ....

Also I have to limit password attempts to 3. How would I go about that?

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Sep 1, 2014

i have this source code...

import java.util.Scanner;
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* This program confirms a password typed into a *
* console window *
*/
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[code]....

Now I need to create a second version of this program that uses JOptionPane to get the inputs from the user and show the output!

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I am trying to get through JSF /PF tag for h:inputSecret but its not taking or displaying value. Please see the code snippet below

demo.xhtml

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
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[code]....

I am using JSF 2.2.

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Try again:
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package class1;
import java.util.Scanner;
public class class1 {
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// TODO Auto-generated method stub

[code]....

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import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class Password implements ActionListener {
private String Username = "hudhud";
private String Password = "fitness";

[Code] ......

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[Code] .....

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String enterpwd = "";
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I am asked to use JOption, I completed as follows:

enterpwd = JOptionPane.showInputDialog(""............JOptionPane.QUESTION_MESSAGE);

then I use IF statements

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I am getting an error "java.lang.NumberFormatException: For input string: """

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