Simple Selection Descending Sorting After Values Assigned

Oct 7, 2014

I am working on descending after I assign values. And everything is sorted, but one value. I don't know why always I get one value is not sorted.

public class SeunghunJunHw6 {
public static void main(String[] args){
double[] randomArray = new double[9];
//assign random double values between 0 to 100 but exclude 100
for(int i = 0; i<randomArray.length;i++){
randomArray[i] = Math.random()*100;

[Code] ....

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Array Sorting - Ascending And Descending Order

Apr 10, 2014

I am sorting an array in ascending and descending order. I am using the nethods in Arrays as below

Arrays.sort(myArray)

I want to print both input and output array in sysout.

Object[] ipArray = [45,8,32,41,11,7];
Object[] opArray;
Object mArray = ipArray;

Arrays.sort(mArray); This is changing the ipArray too ?

How can I get my input array unmodified ?

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Sorting Arrays In Descending Order With Collections Class

Jun 28, 2014

I am trying to create a java program to sort an array in ascending and descending order. Here is the program I created :

import java.util.Arrays;
import java.util.Collections;
public class ArraySort
{
public static void main(String [] args) {
int [] num = {5,9,1,65,7,8,9};
Arrays.sort(num);

[Code]...

BUT I GET THE FOLLOWING EROOR ON COMPILATION

ArraySort.java:12: error: no suitable method found for reverseOrder(int[])
Arrays.sort(num,Collections.reverseOrder(num));
^
method Collections.<T#1>reverseOrder(Comparator<T#1>) is not applicable

[Code] .....

What's wrong with my program?

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JSP :: EL Expressions - Find A Place Where Values For Status Is Being Set / Assigned To

Feb 4, 2014

I have a web application project built in Spring MVC 2.5. There are some EL expressions which are used in JSP as below:

${status.value}
${status.expression}
${status.errorMessages}

But, I coudln't find any place in Java/JSP where the value for status is being set. What could be the possible place where the values for status is being set.

As the code is client specific, so, I couldn't paste the specific code over here but I have searched in whole workspace i couldn't find a single place where values for status is being set/assigned to.

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Sorting Ascending / Descending Methods Not Working On Double Linked List

Sep 12, 2014

I wrote displayAscending() and displayDescending() methods to this double linked list and it is not working at all. Logically it seems fine to me. I positioned the head in the beginning in the ascending method; created a variable named data1 as an auxiliar variable so it can store the values that are going to be moved; and moved the values. Same thing for the descending method but instead of the head I put the tail and move left the list, instead of right.

import java.util.*;
class node {
int data;
node left;
node right; 
node(int d, node l, node r) {
data = d;

[Code]...

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Selection Sort Method - Sorting Array And Return Result Of Each Step

Nov 20, 2014

This time I am having difficulties with selection sort method, but not with the method itself (I think). So I need to sort an array and return the result of each step.

This is the main code:

public class Functionality {
public static int[][] selctionsort(int[] a) {
for (int i=0; i<a.length; i++) {
int least = i;
for (int j=i+1; j<a.length; j++)

[Code] ....

And this is the Test folder:

import static org.junit.Assert.assertArrayEquals;
 public class PublicTests {
public static void main(String[] args) {
int[] a = new int[] { 35, 7, 63, 42, 24, 21 };
int[][] b = new int[][] { new int[] { 7, 35, 63, 42, 24, 21 },

[Code] ....

Now I am not sure what should I write in return since the 2nd (test) project has int[][] and in my main project I am working with int [].

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Java Type Promotion Query - Int Cannot Be Assigned To Byte

Oct 14, 2014

I've a small question relating to type promotion I can't find an answer for on the web. Basically in your code if you have :

byte b = 0;
b = b + 1;

The compiler will complain about the result being an int which cannot be assigned to a byte. That I understand, as b on the right hand side of the expression is promoted to an int and the result of the addition is an int. However the following does compile :

byte b = 0;
b++;

Does the post increment not carry out the post increment as "give me the value of b and then add 1 to b" where I would have expected 'add 1 to b' to do the same integer promotion as the previous example ? The compiler will also allow the following

byte b = 0;
b += 1;

Again , why is no type promotion happening here ?

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Converting Descending To Ascending

May 6, 2014

I have not a clue how to convert this to ascending from its current descending....

class Node
{
private int iData; // data item (key)
//-------------------------------------------------------------
public Node(int key) // constructor
{ iData = key; }
//-------------------------------------------------------------
public int getKey()
{ return iData; }

[Code] .....

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How To Find Longest Descending Sequence Without Arrays

Oct 24, 2014

I am trying to find the longest descending sequence without arrays. So 65124976231 would output 9762.

import java.util.*;
public class HelloWorld {
public static void main(String[] args){
String num = "";
int longestLen = 0;
int currLen = 0;
String max = "";

[Code]...

I keep getting: The longest descending sequence is: 6512 In an infinite loop.

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Reverse Double Linked List In Java - Descending Order

Sep 12, 2014

I have the following double linked list and I'm supposed to order it descending (reverse) using the printInReverse() method; since the list orders itself ascending when the numbers are added, how could I order it descending in this method? Here's the code without implementing descending/reversing methods:

package test;
import java.util.Scanner;
public class MyList {
private Scanner userInput;
private Integer selectedOption;
private MyListElement firstElement = null;
private boolean exitRequested = false;

[Code] ....

I tried to declare a previousElement variable but I didn't figure out how I'd do that.

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Input 10 Integer Elements In Array And Sort Them In Descending Order

Jun 13, 2014

How to input 10 integer elements in an array & sort them in desc. order using the bubble sort technique.

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User Input Student Information - Print Out Name With Grade In Descending Order

Nov 23, 2014

I had to make a program that allowed the user to enter the number of students and the students names and grades and then print out the name with the grade in descending order. right now I only have it where it prints the names out in descending order. how do I get it the print out with the grade?

Here is my code

import java.util.*; 
public class Grades {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter the number of students: ");
int numofstudents = input.nextInt();

[Code] .....

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Recursive Selection Sort

Oct 21, 2014

How would I modify this version of a selection sort into a recursive method?

public static void selectionSortRecursive(Comparable [] list, int n)
{
int min;
Comparable temp;

[code]....

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Using Multiple Selection Choices?

May 28, 2014

This program allows the user to select one of each different type of skateboard/accessories items. Then it allows the user to select as many misc items as he or she chooses. The program works fine for the single choices, but I cannot solve the latter part. I have a get method in the misc class that is trying to pull out any selection or selections that were made by the user, but it simply does nothing...

Here's my program, I have four panel classes for each skateboard type, and then I have one class that takes care of adding each panel to the content pane, and calculating the total cost of the item.

Decks Panel Class:

import java.awt.event.*;
import javax.swing.*;
// The DecksPanel class allows the user to selects a specific type of skateboard
public class DecksPanel extends JPanel

[Code]....

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Selection Sort Method?

Mar 5, 2014

I'm trying to make a selection sort method that will sort a list of Strings alphabetically.

I have a test list of Strings like so:

Joe, Steve, Oscar, Drew, Evan, Brian, Ryan, Adam, Zachary, Jane, Doe, Susan, Fred, Billy-Bob, Cindy, Mildred, Joseph, Hammer, Hank, Dennis, Barbara

However, whenever I run the method, the element that should go last, Zachary, in this case, ends up getting moved to the front for some reason. I'm not sure why.

I tried changing what the first element was initialized to, to the variable i as that would logically work as well, but it ends up missing the first element in the list.

Java Code:

public static void selectionStringAscendingSort (String[] words){
int i, j, first;
String temp;
for ( i = 1; i < words.length; i++ ) {
first = 0; //initialize to subscript of first element
for(j = i; j < words.length; j ++){ //locate smallest element between positions 1 and i.
if( words[ j ].compareTo(words[ first ]) <0 )
first = j;
}
temp = words[ first ]; //swap smallest found with element in position i.
words[ first ] = words[ i ];
words[ i ] = temp;
System.out.println(Arrays.toString(words));
}
System.out.println(Arrays.toString(words));
} mh_sh_highlight_all('java');

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Selection Does Not Contain A Main Type

Mar 23, 2014

I'm trying to run a simple code which is to just print out "Hello World", but whenever I run it, a message appears that reads: "Select a way to run Project_1(Which is the Java Project)"

The selections for it are: Java Applet and Java Application.Whenever I click Java Applet it reads: Selection does not contain an applet.When I click Java Application: Selection does not contain a main type.Here is the code which I believe is correct:

package packag_1;
public class Num_1 {
public static void main(String args){
System.out.println("Hello World");
}
}

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Design Pattern Selection

Mar 27, 2015

I need selecting which design pattern to use in my case.

I am creating a list of objects "items" to be presented in a list for the user to choose from, all objects have a title and a check box. Some objects have additional textbox for user input, some objects have additional image for illustration, and some objects have additional textbox and image as well.

I read and saw online videos but not sure if my selection "Factory Design Pattern" is the best match.

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Applets :: 2 Jlists / Second One Depends On Selection In First One?

Jun 2, 2014

So I have an applet and in the first ScrollPane you have a number of options of businesses

The Centre

IMAX

etc ..

and when you click one , the other scrollpane shows office

so when i choose "The Centre" for example , in the right scrollpane it shows : "Head Str." "Downtown" etc

i can fill in the first scrollpane with:

void myInit() {
DefaultListModel model = (DefaultListModel)businessList.getModel();
model.removeAllElements();
try {
ArrayList<Business> bussinesses = contr.getBusiness();

[code]....

but this gives me a NullPointerException on

ArrayList<Office> offices= business.getOffices(name);

which i don't understand, since business isn't null .. it's the selected value.

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Graphically Displaying Selection Sort

May 20, 2014

I am trying to write a program that graphically displays a selection sort. It needs to sort bars of various heights, and the bars heights are generated from an array of random integers. The program needs to show the bars swapping as they are being sorted, I am having trouble getting the bars to draw, it needs to look like a bar graph. Here is my code thus far (not counting my boiler plate):

import java.util.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.Timer;
import java.awt.*;
import java.util.Random;
public class SelectionSortPanel extends JPanel

[Code] ....

Also right now it is giving an error from the compareTo method?

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How To Do Selection Sort Of ArrayList By Customer Last Name

Nov 8, 2014

I have an arrayList with these values:

Mike Smith with a customer id of 100 has an account number of 1000 and a balance of $5,000.00
Hank Jones with a customer id of 101 has an account number of 1001 and a balance of $45,000.00
Sam Overstreet with a customer id of 102 has an account number of 1002 and a balance of $45,000.00
Hank Jones with a customer id of 101 has an account number of 1003 and a balance of $48,000.00
and so on .....

I am trying to do a selection sort by the account holders last name. I understand how to do if the Arraylist holds integers, but my arraylist holds multiple fields. I am not allowed to use collections as this is a homework assignment.

here is the Account Class

public class Account implements Comparable<Account> {
private int acctNum;
private double balance;
private Customer cust; // note we are putting a Customer object in the Account clas
private static int nextAcct = 1000;// used to keep track of the next available account number

[Code] ....

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Graphic Array Selection Sort?

May 21, 2014

This is a lab for one of my CS classes, and the assignment is to create a randomly filled array (values 10-100) and use these values as the height of an array of rectangles (essentially a bar graph)that will be drawn on a page. After that's done, the code should use the selection sort method to sort the bars least to greatest, being repainted as it's sorted.

I'm receiving no errors, the original draws just fine, and the code sorts the first position and then...it just hangs. Like it's in an infinite loop but I have all of the modifiers in place (I think. I've been staring at this code for three days straight and I don't think I really see it anymore). I've tried talking to my professor and I get that her private life is really busy right now, but she just keeps blowing me off and I don't know what to do. Anyway, done with back story and whining so here's the code.

Rectangle class:
import java.awt.*;
import javax.swing.*;
import java.awt.event.*;
public class Rectangle

[code]....

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Text Adventure - Cannot Use Menu Selection

Apr 30, 2015

I cannot use menu selection 4 5 6 7 8 9 10 ... Why NO_EXIT has been declared and used in defining the contents of the map array, rather than just directly using the value 99999 in the map array definition

I don't understand map[][], objectName[] and objectLocation[]

package Assignment;
import java.util.Scanner;
public class GameWorld
{
// the map array holds details on which paths lead to which other rooms. NO_EXIT indicates no valid exit.
// each element holds the details of all paths leading out from a single-room in the order n ,e, s, w, ne, se, sw, nw
private final int NO_EXIT = 99999; // indicates that there is no exit in that direction
private int map[][] ={{NO_EXIT,NO_EXIT,NO_EXIT,1},{2,0,NO_EXIT,NO_EXIT},{NO_EXIT,3,1,NO_EXIT},{NO_EXIT,NO_EXIT,NO_EXIT,2}};

[Code] .....

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Used Selection Sort Method On Array

Nov 11, 2014

I have a question about selection sort. If I had an array of numbers, 1 2 3 4 100 0, and used the selection sort method (below) on the array,would the 0 slowly work it's way down to the end?

Nest loop = full rotation of nest loop

Nest loop 1: 1 2 3 4 100 0
Nest loop 2: 1 2 3 4 100 0
Nest loop 3: 1 2 3 4 100 0
Nest loop 4: 1 2 3 4 100 0
Nest loop 5: 1 2 3 4 0 100
Nest loop 6: 1 2 3 0 4 100
etc.

METHOD:

static void selectionSort(int[] arr){
int n = arr.length;
for(int i = 0;i<n;i++){
int min = i;
for(int j = i+1;j<n;j++){
if(arr[j]<arr[min]){
min = j;
}
}
int temp = arr[i];
arr[i] = arr[min];
arr[min] = temp;
}
}

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How To Make Green Selection Box To Move Around

Feb 16, 2014

I'm making a simple game where there's a 10x10 grid and you can move around a selection box and you can move around. I've been trying to make the green selection box to move around but it won't move! I only have right movement in the code but it won't work so far. Here are the classes that have to do greatly with each other.

import java.awt.Canvas;
import java.awt.Color;
import java.awt.Graphics;
import java.awt.event.KeyEvent;
import java.awt.image.BufferStrategy;
import java.util.Random;
 
public class Game extends Canvas implements Runnable{
private static final long serialVersionUID = 1L;
 
[Code] ....

I also tried an approach where you click with the move and it snaps to a tile grid but that didn't work either.

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JavaFX 2.0 :: Turn Off ListView Selection

Jul 21, 2014

I have a ListView with ListCells that are complicated things containing other nodes. I want to turn of ListView selection behavior (so not allow selections) without turning of events to the ListCell nodes in the ListView.

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JavaFX 2.0 :: How To Inhibit Changing Selection

May 25, 2014

I have a Master/Detail application with a TreeView as Master Selection. I need to inhibit leaving a page if the contents are "invalid". How can I do that?

I tried to force the page again in a ChangeListener, but that doesn't work well, not even using Platform.runlater().

What's the "Best Practice" in this case?

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