Sort Array List Print?
Nov 23, 2014
I am having an issue trying to print different types of arrays using one method. Eclipse tells me to convert my print method for each array type:
change method 'printList <e>' to 'printList(ArrayList<integer>)'
change method 'printList <e>' to 'printList(ArrayList<Double>)'
change method 'printList <e>' to 'printList(ArrayList<Character>)'
change method 'printList <e>' to 'printList(ArrayList<String>)'
I would like to accomplish printing all four different arrays using one print method. How to accomplish it or provide examples or links to examples?
import java.util.ArrayList;
public class SortArrayList {
public static class Sort {
[Code].....
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Jun 29, 2014
Directions: public static void initialize(ArrayList names, ArrayList sores)
You should write a function that sorts both array lists, based on the values in the scores array list. This is one of the more conceptually challenging parts of the assignment. You want to sort the scores array list, and simultaneously alter the names array list so that the names continue to line up with their respective scores by index. In the example data above, when the score 9900 moves to the first element of the scores array list, the name "Kim" should also be moved to the top of the names array list. The function should have the following signature:
I'm having trouble figuring out how to sort the lists.
import java.util.ArrayList;
import java.util.Scanner;
public class Assignment5
{
/**
*/
public static void main(String[]args) {
intializeArrays();
[Code] ....
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Oct 22, 2014
Use the sort method of the arrays class to sort the values in the array, and print the median value(the 50th value) on the console followed by a blank line. Then, test this enhancement. Print the 9th value of the array on the console and every 9th value after that. Then, test this enhancement.
import java.util.Arrays;
public class ArrayTestApp
{
public static void main(String[] args) {
double [] arrayTest = new double[99];
//adding random number to each element in the array
for(int i=0; i<arrayTest.length; i++)
arrayTest[i] = 100.0*Math.random();
[Code] ....
OUTPUT
run:
The average is: 49.842845462514944
The median is: 49.68753724038633
The 9th value is: 2.599530043466969
The 9th value is: 11.486193141397095
The 9th value is: 20.14206270200648
[Code] ....
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Feb 14, 2014
I have some class called sorted to sort the linked list through the nodes of the list. and other class to test this ability, i made object of the sort class called "list1" and insert the values to the linked list.
If i make other object called "list2" and want to merge those two lists by using method merge in sort class. And wrote code of
list1.merge(list2);
How can the merge method in sort class know the values of list1 that called it as this object is created in other class.
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Mar 26, 2014
Add accounts on a list, each account contain: name, accountCode, pinCode, balance.
How to show list sort by balance?
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Oct 30, 2014
I searched a lot but can't seem to understand the sorting of a SLLNode... I noticed a method called Bubble Sort, I understand how it works, but can't think of a way to implement it to my code..
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May 5, 2015
I am learning to use heaps and as an exercise I am trying to write a program using a heap class I have created to sort words. I have read in words from a file and added them to the heap successfully. I am having some trouble figuring out how I can print out a sorted list of the words. From my understanding of how a min-heap works, if I remove from the min/root node they will always be removed in sorted order. So far I have tried out to do a simple for loop but, only half of the heap is being removed. Not sure if my logic is incorrect of there is an error somewhere in my removeMin() function specifically in the while loop.
public static void main(String[] args) {
Heap heap = new Heap();
heap = read( heap );
for( int i = 0; i < heap.getSize(); i++){
heap.removeMin();
[Code] ....
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Dec 11, 2014
I've playing around with linked lists and methods for sorting. So far I've tested the iterative sort, insertion sort, quick sort and they all worked perfectly. Now, I am trying to implement merge sort that would take a linked list of jobs and sort them according to their priority. I found a few solutions on the web, of which I am trying to implemented this one: LeetCode.
My system is a simple one, I do have a linked list of print jobs, each of which has the priority. The following code should sort my print queue and return the link node of the first sorted element. Here's the code.
//defining a job that has priority
public class Job {
private int priority;
[Code]....
The problem I've been trying to solve is that I am getting the stack overflow at line
ListNode<T> h1 = mergeSort(left);
meaning that I am getting into a loop somewhere down through the process of breaking the linked list into half, half or halfs and so on.
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May 22, 2014
import java.util.Collections;
import java.util.Comparator;
import java.util.LinkedList;
import java.lang.Comparable;
import java.util.*;
import java.lang.*;
public class MyLinkedListSort {
[Code] .....
Output is :
name is nulland salary is0
name is nulland salary is0
name is nulland salary is0
name is nulland salary is0
Expected output :
Name is Crish Salary: 2000
Name is Tom Salary: 2400
Name is Ram Salary: 3000
Name is John Salary: 6000
Where i going wrong
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Oct 6, 2014
I'm having trouble with sorting Strings- 3 strings inputted by user, and I would like to output them in alphabetical order. I've used the str.compareToIgnoreCase method, and then I've tried to loop them through a series of if/ else statements. Everything I've been able to find online (including the forums here) has suggested to use the Comparator class, or to put the strings into an array, and sort list- I really would like to stick with just the String class, and its methods .
The program itself works and compiles, but I am getting logic errors that I have been unable to solve. I'm using IntelliJ Idea, and I've ran it through the built in debugger, about 100+ times (not exaggerating, lol) just to see what it's doing in particular scenarios. For instance, I can get c, a, b, to print out as a,b,c correctly, but a,b,c, will print out as b,a,c.
For me this is kind of like a Sudoku puzzle, or a Rubik's cube! Each time I fix one scenario, it breaks another one, so I don't know if there's a(logic) solution to fix all possible scenarios (abc, acb, bac etc... to all print abc) or if possibly I just need more if statements. I've only pasted in the area where I'm having problems (the if statements). I'm a big fan of the "Next Line" syntax.
(Note: please assume the non relevant content- import Scanner class, main method, etc... I didn't want to paste the entire program.)
System.out.println("Enter the first statement: ");
//input.nextLine();
string1 = input.nextLine();
System.out.println("Enter the second statement: ");
string2 = input.nextLine();
System.out.println("Enter the third statement: ");
string3 = input.nextLine();
[Code] ....
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Aug 22, 2014
the program does not print the list when i select choice 3 it only prints the original 2 elements, same happens if i use if else statements instead of switch statement. Quote public class linklistdemo{
public static void main(String args[]){
while(true) {
System.out.println("press one enter element");
[Code]....
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Apr 11, 2014
I have been working on this Java Gui program and i cant get it to print to the textbox correctly.i originally had it displayed in a dialog window but it would print one integer a time in a seperate window.
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.util.*;
import java.lang.*;
import java.io.*;
[code]....
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Oct 21, 2014
I'm having some trouble with my project. I have filled the getters using an array and what I now need to do is get the user to type in a day and print the corresponding getters to the lines the day is on in my text file.
{
File file = new File("DailyJobs.txt");
Job newJob = new Job();
try (Scanner scanner = new Scanner(file);)/>
{
while(scanner.hasNextLine()) {
String line = scanner.nextLine();
[Code] ....
This is what I've attempted in terms of entering the day. It recognises the number of lines that has the inputted day but prints out only the very last job ID in the text file.
90301,14304,ITGURU,11/11/2014,Tuesday,735.75,1204,1205
90302,14314,ROK5TR,12/11/2014,Wednesday,335.75,1205
90303,14318,HRTBRK,13/11/2014,Thursday,125.5,1200
90304,14310,EVOH8R,14/11/2014,Friday,1207.95,1211
90305,14300,G4MER,11/11/2014,Tuesday,500,1204,1202
[Code] ....
This is the text file, the first number on each line is the Job ID and always prints the last line regardless of the day I enter.
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Jan 1, 2015
AddItemToFront(Item p) : This method will create a new Node with the Item object as its data value and then add the newly created node to the front of the linked list.
DisplayItems(): This method will traverse the linked list from first node to last node and print data value ( i.e., id, name, type and price of the Item object) of each node.
RemoveItemAtPosition(int n): This method will remove the node at position n in the linked list. Assume that the first node of the linked list has a position number of 1 and the second node has a position number of 2 and so on.
This is my Code
AddItemToFront
public void AddItemtoFront(Item p)
{
Node newNode = new Node(p);
newNode.setLink(head);
head = newNode;
[Code] ....
I don't know what am I suppose to do inside the remove method
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Jan 22, 2015
how can I got about sorting an array that contains more than one value in a single element. Such as my array below has 4 values under one element. I know how to sort elements with single values however, slightly confused on this.
import java.util.Scanner;
import java.util.Arrays;
class Mobile
{
[Code]......
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Jul 8, 2014
I wrote this piece of code, and it is supposed to use bubblesort to sort the array. Yet somehow it re-aranges it, but doesn't exactly sort it. For example, when I enter [3, 5, 6, 9, 8, 4, 7, 5, 6, 2], it prints Done [2, 5, 9, 5, 7, 8, 4, 6, 3, 6]
Java Code:
import java.lang.*;
import java.util.*;
import java.util.Arrays;
public class bubble {
public static int[] array(){
int [] anArray = new int [10];
[Code]...
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Dec 15, 2014
How I would sort two heaps into one array. I know that in a heap the "parent" is guaranteed to be larger than the "children".
So could I simultaneously traverse both trees in order, and while doing so, store the values of each node, one after another? This way the array would be partially sorted and then I could just use an insertion sort.
Is this logic reasonable or am I looking at it the wrong way?
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Mar 9, 2015
How can i convert this linked list code to a read from input.txt
The first line in the input file will give the elements to initialize the linked list with. Consecutive lines will provide operation instructions.
Your code should read one line at a time. After reading each line, it should perform the corresponding operation and print the linked-list on the console.
If an operation is not possible, it should print "N/A".
Sample input file. Please note, the comments (// ...) are given for explanation, the input file will not have them:
4, 5, 6, 3// First line. This will provide the initial values for the linked list : 4->5->6->3
1, 9// Add a 9 at the front of the linked-list. After this operation the linked-list should be: 9->4->5->6->3
2, 1// Add a 1 at the end of the linked-list. After this operation the linked-list should be: 9->4->5->6->3->1
3, // Delete the first node in the linked-list. After this operation the linked-list should be: 4->5->6->3->1
4, // Delete the last node in the linked-list. After this operation the linked-list should be: 4->5->6->3
5, 11// Delete the node with the value 11 in it. Since this is not possible, it should print "N/A"
5, 6// Delete the node with the value 6 in it. After this operation the linked-list should be: 4->5->3
Sample output to the console:
4->5->6->3
9->4->5->6->3
9->4->5->6->3->1
4->5->6->3->1
4->5->6->3
N/A
4->5->3
My Code:
LinkedList.Java
class linkedList
{
protected Node start;
protected Node end ;
public int size ;
[Code] .....
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Mar 30, 2015
I am writing a program which writes down all possible equation y=a+b+c values from min to max (in reality this equation would more difficult, but here is just short example).
The problem is that my sorting code can't get access to full array in loop.
Is there any way to pass array to sorting code, or somehow change sorting code?
package pkg06;
public class Main {
public static void main(String[] args) {
double aS =-1;
double aE = 3;
[code]...
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May 21, 2014
This is a lab for one of my CS classes, and the assignment is to create a randomly filled array (values 10-100) and use these values as the height of an array of rectangles (essentially a bar graph)that will be drawn on a page. After that's done, the code should use the selection sort method to sort the bars least to greatest, being repainted as it's sorted.
I'm receiving no errors, the original draws just fine, and the code sorts the first position and then...it just hangs. Like it's in an infinite loop but I have all of the modifiers in place (I think. I've been staring at this code for three days straight and I don't think I really see it anymore). I've tried talking to my professor and I get that her private life is really busy right now, but she just keeps blowing me off and I don't know what to do. Anyway, done with back story and whining so here's the code.
Rectangle class:
import java.awt.*;
import javax.swing.*;
import java.awt.event.*;
public class Rectangle
[code]....
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Nov 11, 2014
I have a question about selection sort. If I had an array of numbers, 1 2 3 4 100 0, and used the selection sort method (below) on the array,would the 0 slowly work it's way down to the end?
Nest loop = full rotation of nest loop
Nest loop 1: 1 2 3 4 100 0
Nest loop 2: 1 2 3 4 100 0
Nest loop 3: 1 2 3 4 100 0
Nest loop 4: 1 2 3 4 100 0
Nest loop 5: 1 2 3 4 0 100
Nest loop 6: 1 2 3 0 4 100
etc.
METHOD:
static void selectionSort(int[] arr){
int n = arr.length;
for(int i = 0;i<n;i++){
int min = i;
for(int j = i+1;j<n;j++){
if(arr[j]<arr[min]){
min = j;
}
}
int temp = arr[i];
arr[i] = arr[min];
arr[min] = temp;
}
}
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Jun 15, 2014
Merge sort implementation on the given array i listed in the code below. I know Arrays.sort() or Collections.sort() could do the trick but i want to achieve it through merge sort.
import java.util.*;
public class Merge{
public static void main(String[] args){
String[] myStringArray=new String[]{"z","a","z","b","c","e","z","f"
,"g","a","w","d","m" ,"x","a","R"
,"q","r","y","w","j","a","v","z","b"};
}
}
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Feb 19, 2014
Code below. I am not sure if my logic is correct. I want to prompt a user to enter registration numbers from 100 to 1000, store the numbers in an array then sort them.
import java.util.Scanner;
class regnumber
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.println("registration number ", 100,1000);
[Code] ....
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Apr 23, 2015
I am trying out solving the question but i am stuck.The problem is to write a method that print data of single linked list backward using stack.The question is as follow
public class Stack{
public boolean isEmpty(){};
public void push(int n){};
public int peek(){};
public int pop(){};
}
public class node{
int data;
node next;
}
public class list{
node first;
}
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Oct 6, 2014
I have an Array of objects that contains strings. I am new to Java and have read books, the Java docs, and searched the Internet for my problem to no avail. How can I get my strings to print in a list so that the user can select an object to manipulate its attributes? I have a class called Instruments and created 10 guitar objects. Here is the code:
Instrument [] guitar = new Instrument[10];
for (int i = 0; i < 10; i++) {
guitar[0] = new Instrument("Guitar 1");
guitar[1] = new Instrument("Guitar 2");
guitar[2] = new Instrument("Guitar 3");
guitar[3] = new Instrument("Guitar 4");
[Code] ....
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Apr 28, 2014
I am trying to invoke some methods in a for loop in order to print some info stored in a List. But for some reason, compiler pops a message saying "cannot find symbol - method getEmpID(). You are using a symbol here (a name for a variable, method or class) that has not been declared in any visible scope." But I am pretty sure that method getEmpID (as also getName(), getAfm(), and payment() ) have been declared as public.
Note: My List contains objects of different type (SalariedEmployee, HourlyEmployee). I hope this is not the factor causing this problem.
Java Code:
import java.util.*;
abstract class Employee{
private String name = "";
private String afm = "";
private long EmpID;
static long count=0;
[code]....
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