String Initialization - Given 3 Names Say Which Oldest And Which Youngest
Jan 14, 2015
/*
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* To change this template file, choose Tools | Templates
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*/
package vecchiogiovane;
import java.io.*;
public class Vecchiogiovane {
/**
* @param args the command line arguments
*/
public static void main(String[] args) throws Exception{
[Code] .....
run:
run:
ins first name:
aldo
ins first age:
35
ins second name:
[Code] ....
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Dec 20, 2014
I come from a C++ background and I recently started learning Java from "Thinking in Java" 4th Edition by Bruce Eckel.What's the difference between:
// explicit in class initialization
// saw this on page 126
class A {
}
public class B {
A obj1 = new A();
A obj2 = new A();
}
and
// non static instance initialization
// saw this on page 132
class A {
}
public class B {
A obj1;
A obj2;
{
obj1 = new A();
obj2 = new A();
}
}
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Apr 29, 2014
I am trying to make a game, for some reason i have begun to get a java.lang.StackOverflowError.
I am not exactly sure how i can fix it. only removing line 14 from infopannel1 (and everything that used that class.) seems to work. im not sure what else i can do to fix it. or why its resulting in stack overflow for that matter.
I am putting in a link for the files i wrote this using bluej (several classes have no relevance, errorv2, demonstration, folderreadertest, ReadWithScanner, saveloadtest, menutest,rannum, and menutestTester. are all irrelivent to my problem.)
[URL] .....
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Sep 17, 2014
I came across this code which proves that variable initialisation occurs before even constructors are called.However, I am confused over some things.
Firstly, from my understanding, when a new House object is created in this line House h = new House(); , the no-arg constructor of the House class is called.
Since the no-arg constructor House() is called, why are all the creation of Window objects being run first ? Shouldn't Java jump straight into the no-arg constructor House() ?
class Window {
Window(int marker) { System.out.println("Window(" + marker + ")"); }
}
class House {
Window w1 = new Window(1); // Before constructor
House() {
// Show that we’re in the constructor:
System.out.println("House()");
w3 = new Window(33); // Reinitialize w3
[code]...
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May 12, 2014
I am using netbeans 7.2, glassfish 3.1.2, JSF 2.1 and Primefaces 3.2. When I add more than three menu tabs, I get this error ui layout initialization error the center-pane element does not exist the center-pane is a required element. This is my template.xhtml code:
<?xml version='1.0' encoding='UTF-8' ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml"
xmlns:ui="http://java.sun.com/jsf/facelets"
xmlns:h="http://java.sun.com/jsf/html"
xmlns:p="http://primefaces.org/ui">
[Code] ....
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Sep 9, 2014
public class SavingsAccount extends Account {
private static final double MIN_BALANCE = 100.00;
private static final double RATE = 0.035;
public SavingsAccount(Customer customer, double bal, String accountNum,
Transaction[] trans) {
super(customer, bal, accountNum, trans);
[code]....
When I execute this code there is an error in Transaction array initialization. Change the Saving account constructor from (String customer,double balance, String accountnumber,Transaction[] tr) to (String customer,double balance, String accountnumber,Transaction tr)
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Apr 2, 2015
What static initialization blocks do in java?
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Mar 20, 2015
I have a question related to q44 of Examlab.
public static void main(String... args) {
String i;
// String i = null; that would compile
if (i == null) {// this line does not compile as i was not initialized
System.out.print("A");
} else {
System.out.print("B");
i = "A";
main("A", "B");
}
}
Why does the above code not compile although the statement String i should lead to an initialisation of i to the value of null which is the default value for Strings.
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Feb 20, 2014
I remember reading Instance variables & local variables (in methods) are initialized to appropriate value by the compiler.
Is this true for static class variables and variables in nested classes ?
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May 12, 2014
I am trying a simple program to access ServletConfig initialization parameter in a jsp. But I am not clear how its working. This is web.xml
<web-app>
<servlet>
<servlet-name>Myservlet</servlet-name>
<jsp-file>/JjspInit.jsp</jsp-file>
<init-param>
<param-name>para</param-name>
<param-value>valu</param-value>
[Code] ....
Now If I hit /Allen it sets init parameter for both servlet MyServlet and jsp JjspInit. I don`t have any servlet all I have is a web.xml and a jsp page. But accessing JjspInit.jsp directly gives null.
How hiting the url /Allen prints valu. This code is on JjspInit.jsp .
So does that mean that in web.xml I have registered this jsp as the target for /Allen. And one more question directly accessing the jsp page shows null it means init parameter haven`t been set.
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Aug 15, 2014
if, instead of an ArrayList, can I do the following to initialize a Dyanmic array ? :
First, in my class, I have :
class Example{
private int rows;
private int columns;
private AnotherClass[][] 2DArray;
public Example(int rows, int columns){
this.rows = rows;
this.columns = columns;
[code]....
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Jan 13, 2015
I want to initialize my servlet based on the scope of my application.
For example, I have multiple admins with their respective email address.
I want to perform action within my servlet based on the given environment.
Would this be the right approach, if I set the admin email addresses in my web.xml as init-param:
<servlet>
<servlet-name>ServletName</servlet-name>
<servlet-class>com.mkyong.ServletDemo</servlet-class>
<init-param>
<param-name>admin1</param-name>
[Code] .....
Now if I am in the admin 1 environment, I would initialize my servlet with request parameter admin=1 and the servlet should load email address of admin 1 and similarly when in the environment 2, should load the servlet with admin 2.
call environment 1:
/servlet/Demo?admin=1
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws IOException{
[Code] .....
I could do the same by putting the email address of the respective admin as request param value, but i don't want to the email address to appear in the url.
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Feb 11, 2014
if I declare
class Example
{
int x=10;
......
}
It is not showing any error but when I declare
class Example
{
int x;
x=10;
............
}
it showing compile time error ....
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Feb 18, 2014
int[][] array1 = {{1, 2, 3}, {}, {1, 2,3, 4, 5}};
it initializes 3 one dimentional array:
1 - {1, 2, 3}
2 - {}
3 - {1, 2,3, 4, 5}
but it only declares two dimensional arrays.
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May 11, 2014
consider:
class A {
final Object b;
public A(C c) {
try {
b = c.someMethodThatMayThrowSomeException();
} catch (SomeException e) {
b = null; // This line results in compiler error: "variable b might already have been assigned"
}
} // take away b=null line and you get "variable b might not have been initialized" on this line
}
Why? How could 'b' be assigned if the exception was thrown?
Btw, the workaround is to wrap the method call:
private final Object initB() {
try {
return c.someMethodThatMayThrowSomeException();
} catch (SomeException e) {
return null;
}
}
and use b = initB(); in the constructor. But that seems like it should be unnecessary.
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Nov 21, 2014
public class HashMapTest {
private static HashMap mp;
public static void main(String[] args) {
// TODO Auto-generated method stub
mp=new HashMap<String, String>();
}
}
This is My Code if I create Object in two place
1)Outside main() method but within class.
2)Inside main() method like above
Will these two approach makes any difference ?
I am asking a general senerio for creating any Type of Objects Primitives or References?
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Jan 29, 2015
I know that I can declare and initialize an member variable inside a class in a single statement but I can't do them on separate sentence. Why?
For example, I am allowed to do the following,
class A{
int a = 5;
// rest of the class
}
But I am not allowed to do this,
class A{
int a;
a = 5; // it doesn't compile even when the variable 'a' is static
// rest of the class
}
Why java don't allow me to do that?
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Apr 21, 2015
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package BaiVeNha;
import java.util.ArrayList;
import java.util.List;
import javax.swing.table.DefaultTableModel;
[Code] ....
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May 21, 2014
I've been trying to finish this blackjack program I have been making for my programming class, however, there are a few bugs I can't seem to iron out. It's a pretty short program, it's just that I'm an idiot and can't figure basic stuff like this out. Specifically, when I try and run it, I get this error:
Error occurred during initialization of VM
java.lang.OutOfMemoryError: unable to create new native thread
Java Code:
import static java.lang.System.*;
import java.applet.Applet;
import java.util.Scanner;
import java.io.*;
import java.util.Random;
import java.util.Date;
[Code] .....
So, obviously I'm doing something horribly wrong.
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Oct 2, 2014
I have 2 enums like below
enum enum1{
TEST_1("name_1","name 1"),
TEST_2("name_2,"name 2");
private String name;
private String description;
[Code] .....
How can i map the same names in 2 enums and get message from enum 1 and code from enum 2.
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Jan 22, 2015
In my project I had to create 2 classes, Room and Animal.
Room had to have an array (NOT arrayList-I know theyre better and easier but I need to use an array, for now) This array must be able to be populated by 10 "Animals", and the Room class needs two methods, a method to add animal a to the room (rooms array) and a toString() that returns the name of the room and the names of the animals in the room. The teacher added a hint saying that this toString() should reference the animal classes toString()
Here is my code thus far:
public class Room {
private String name;
Animal[] inRoom = new Animal[10];
public Room(String roomName){
name = roomName;
} public void addAnimal(Animal a){
for(int i = 0; i < 10; i++){
[code].....
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Jan 17, 2015
I'm trying to implement a spreadsheet-like table using JTable and this is the basic structure.
String[] colnames={"A","B","C","D","E"};
String[][]data=new String[28][5];
sheet = new JTable(data,colnames);
//sheet.setBounds(10, 36, 527, 214);
JPanel tablepane=new JPanel();
tablepane.add(new JScrollPane(sheet));
tablepane.setSize(800, 400);
In a spreadsheet, alphabetical letters are column names and numbers represent rows. I have named the columns and I need to name the rows in the same way. Or if I am to set the first column in every row as row headers, how can I make then non-editable by the user? In addition to that, how can I make the table appear bigger? There's a lot of space but the table appears to be small.
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Nov 9, 2014
Program is running fine. I can create usernames and everything but somehow I cannot quit or exit the program when I enter my sentinal value "QUIT". Here is my program question: Create an application that will create a username for a school computer system. Input a user’s first and last name. The username will be the first letter of the first name followed by the first 5 letters of his last name followed by a random 3 digit number. Continue to create and display usernames until a sentinel value is entered.
import java.text.*;
import java.util.Random;
import java.text.DecimalFormat;
public class username
[code]...
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Oct 1, 2014
I'm new on Java/android and I wounder how could I get name of each control in a layout, ex.
for (int i=0;i<table1.getChildCount();i++ ) {
Object child=table1.getChildAt(i);
if( child instanceof EditText)
{
//get control name here
}
}
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Feb 2, 2014
I'm trying to use the DataFactory class to pull in a list of names, as I need to populate my app in development with randomized test data for testing.
DataFactory
So, I can get a random name like so:-
package domainentities;
import java.util.Random;
import java.util.Collections;
import org.fluttercode.datafactory.AddressDataValues;
[Code] .....
But - it always prints 'Lindsey'. I need a way of completely randomizing but I can't see the class has a method to let me do this? I can use the randomize method but this takes an int argument which will always bring back the same index value (same name).
I wonder if I am over complicating this. I can use a simple String array of names, but I don't want, like 10,000 names in my array and I want a good way of generating good, randomized data. Perhaps a .csv file of names could be read in? Here is a second method I wrote but I don't have the skills to know how to read the array values from my large .csv file:
public String randomSecondName(){
String[] lastNames = {"Smith", "Jones", "Collins","Jackson",
"Dearsley", "Trump", "Carr", "O'Connell", "Dyer", "Furstzwangler" };
Random ran = new Random();
String lastName = lastNames[ran.nextInt(lastNames.length)];
return lastName;
}
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Jul 12, 2014
I'm using MS Access database. What I want to do, is to get all names of my tables in database.My SQL query :
SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES
is it correct? I found it in one example and didn't change anything.
I could of course execute this and check, but the problem is, that it returns ResultSet(I'm using Java), and I do not know how to manipulate this object in this situation.Cause usually ResultSet contains columns and rows, I think now I should get only bunch of String values.
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