String Method That Creates A Word Out Of Given Letters?
Jan 25, 2015
I want to make a method that takes a word and then checks if the word can be created from available letters. For example, if a word "johnson" can be created by using letters "jashoqwnon".
Now my goal is to make sure that if available letters contain a letter from the word, that letter is put into a String called result and then erased from the list of given letters. So, "johnson" and "jashoqwn" would produce the result "johns" and leave "aqw" unused.
Now the problem that I am facing is that I can't get Java not to use the same letter twice. So "johnson" and "jashoqwn" still gives "johnson".
I've tried everything in my power but I am missing something. Here is my code.
public static String makeAWord(String word, String letters){
String result = "";
for(int i = 0; i < word.length(); i++){
for(int j = 0; j < letters.length() ; j++){
How can I write a method that takes a string with duplicates letters and returns the same string which does not contain duplicates. For example, if you pass it radar, it will return rad. Also i would like to know how can I Write a method that takes as parameters the secret word and the good guesses and returns a string that is the secretword but has dashes in the places where the player has not yet guessed that letter. For example, if the secret word is radar and the player has already guessed the good guesses letters r and d, the method will return r-d-r.
I have built a binary tree, from a file. In each node, I am storing each word as a string, and an int frequency for each time the word occurs. For the assignment, I need to find how many words occur only once in the file. I wrote the program, but for some reason I am getting a number different from what my professor is expecting.
As far as I know, this file has loaded into the tree correctly, because all of my other answers in the assignment are correct. What am I doing wrong?
public void findUnique() { System.out.println("There are " + findUniqueWords(root, 0) + " unique words."); } private int findUniqueWords(Node subTree, int uniqueCount) { // Base Case: At the end of the branch if(subTree == null){ return uniqueCount;
I have to write a method called censor that gets an array of strings from the user as an argument and then returns an array of strings that contains all of the original strings in the same order except those with length of 4. For example if cat, dog, moose, lazy, with was entered, then it would return the exact same thing except for the words with and lazy.
Currently, my code so far just prints [Ljava.lang.String;@38cfdf and im stuck.
import java.util.Scanner; public class censorProgram { public static void main (String args[]){ Scanner input = new Scanner (System.in); System.out.println ("How many words would you like to enter?"); int lineOfText = input.nextInt();
[Code] ....
I have to make new string array in the method and return words without four letters in the main method
How to do this editing the last 3 letters of a string that i retrieve from database.. I have a string "111-222-333-000" here's the sample what i want to happen was to edit the last 3 letters of the string ,,
i insert into database "111-222-333-000" then i retrieve it for editing but what i want to happen is when i retrieve it what i can only edit was the last 3 strings only
I started using Java a couple of days ago, If you haven't guessed I want to see if the user is typing a full name or not, but I'm actually not too concerned with any more complexity than I mentioned in the title. It's ok if an input like "GLba b" comes out positive.
Start with the tree.java program (Listing 8.1) and modify it to create a binary tree from a string of letters (like A, B, and so on) entered by the user. Each letter will be displayed in its own node. Construct the tree so that all the nodes that contain letters are leaves. Parent nodes can contain some non-letter symbol like +. Make sure that every parent node has exactly two children. Don’t worry if the tree is unbalanced. Note that this will not be a search tree; there’s no quick way to find a given node. You may end up with something like this:
It also says all Letters must be Leaves
Now I had it almost similar to that picture, but it wasn't right. So ive been working on it but im getting some very strange (and frustrating) output from the following methods.
Ive included the display method just for reference. The book told me to use it so I haven't edited it. I believe my main issue is with my (incomplete) insert() method. The output goes into an infinite loop despite having a return statement break the while loop when a character is inserted.
The way I see to solve the problem is just add a (+) whenever a new subtree needs to be created. Say I add A and B, then it first creates a subtree at the root with a (+) and afterwards lists A and B as its leaves. If I insert a C, it should be able to simply move to the right child of the root and deposit the C there.
Write a method named secondHalfLetters that accepts a string as its parameter and returns an integer representing how many of letters in the string come from the second half of the alphabet (that is, have values of 'n' through 'z' inclusive). Compare case-insensitively, such that uppercase values of 'N' through 'Z' also count. For example, the call secondHalfLetters("ruminates") should return 5 because the 'r', 'u', 'n', 't', and 's' come from the second half of the alphabet. You may assume that every character in the string is a letter.
Write a GUI program to convert all lowercase letters in a string to uppercase letters, and vice versa. For example, Alb34eRt will be converted to aLB34ErT.
I am trying to write a program and the name variable can only store letters,dotes and spaces. But whenever I enter a space, the program doesn't work. Following is my code.
import java.util.Scanner; import java.util.*; public class Space { public static void main(String []args) { Scanner reader = new Scanner(System.in);
So the exercise I'm working on says to have the user enter their name and the program will output their name with the last name in all caps. i made it work BUT the only way i could figure it out was to ask for the first and last names separately creating two strings rather than one.
Of course I want to make it work how it's supposed to (with one string) so that I'm learning. I'm just having trouble conceptualizing how exactly (with varying lengths of names) to tell the program to only capitalize the second word... at first I thought create a substring beginning with the first letter of the last name and ending with the last...but again, therein lies the issue of varying name lengths.
is there a way to create a substring that beginIndex's at the first "space"? then i could just leave the endIndex parameter empty and it would take the whole word into a new string. and from there utilize toUpperCase to the new string?
Here's my code asking for the first and last names separately.
import java.util.Scanner; class nameEcho { public static void main ( String [] args ) { Scanner scan = new Scanner( System.in ); String first; String last;
I'm very new to Java, and I'm writing a code to search a string to see how many times the word "dog" is found in it. I'm not sure if this is error-free or the most efficient, but I'd like to keep it simple.
public void run() {
String input = new String("The Dogman was no ordinary dog, nor man, but rather a peculiar dog-like man who barked like a dog, and panted like a dog, he even ate like a dog. He owned a dog named Doglips, and interestingly enough, his favorite food was hotdogs.");
println(input); int index = -1; int count = 0; print("Counting dogs:"); inputarray = input.split(" ");
What I need to do is ask the user to input some text and then turn it into pig latin. I am confused on how to select each word from the string to determine if it ends in a way or ay. I am to assume that the letters are all lowercase and the text ends with a period.
import java.util.Scanner; public class Trial { public static void main(String [ ] args) { Scanner input = new Scanner(System.in);
I am looking for a way to create a method with the initial state in while loop, which will count the length of each word in a string using I want the output to be something along the lines of:
hello world how are you There are 0 words of length 0 There are 0 words of length 1 There are 0 words of length 2 There are 3 words of length 3 There are 0 words of length 4 There are 2 words of length 5
This is my code so far it sort of does the job but not the way i want it too
import java.util.Scanner; import java.util.StringTokenizer; public class Brown_Matthew_13117002{ public static int count(String s, int len){ int result=0; StringTokenizer st=new StringTokenizer(s,"[ ,;]");
[Code] ....
The output would end up being :
hello There are 0 words of length 0 world There are 0 words of length 1 how There are 0 words of length 2 are There are 3 words of length 3 you There are 0 words of length 4
I am looking for a way to create a method with the initial state in while loop, which will count the length of each word in a string using I want the output to be something along the lines of:
hello world how are you There are 0 words of length 0 There are 0 words of length 1 There are 0 words of length 2 There are 3 words of length 3 There are 0 words of length 4 There are 2 words of length 5
ithis is my code so far it sort of does the job but not the way i want it too
import java.util.Scanner; import java.util.StringTokenizer; public class Brown_Matthew_13117002{
i want a simple,beginner program to accept a string from the user and display the longest word in the string.i thought of taking the length of the string and choosing the longest string.but if the user enters a big paragraph,how can i store each word in a variable??
I am looking for a way to create a method with the initial state in while loop, which will count the length of each word in a string using I want the output to be something along the lines of:
hello world how are you There are 0 words of length 0 There are 0 words of length 1 There are 0 words of length 2 There are 3 words of length 3 There are 0 words of length 4 There are 2 words of length 5
This is my code so far it sort of does the job but not the way i want it too
import java.util.Scanner; import java.util.StringTokenizer; public class Brown_Matthew_13117002{ public static int count(String s, int len){ int result=0; StringTokenizer st=new StringTokenizer(s,"[ ,;]");
[Code] ....
The output would end up being
hello There are 0 words of lenghth 0 world There are 0 words of lenghth 1 how There are 0 words of lenghth 2 are There are 3 words of lenghth 3 you There are 0 words of lenghth 4
I think I need to use string.split instead of stringtokenizer and the while loop is incorrect it needs to loop equal to the number of letters in the longest word. But how to do either of these ?
I'm trying to find a word in an array of char.....but I'm stuck. How to formulate the code to step through the array and pick out the word. This is what I have so far...
public static void searchAcross(String string, char[][] puzzle) { // Gets the number of rows in the matrix int rowLength = puzzle.length; //Gets the number of columns in the matrix. int colLength = puzzle[0].length;
I'm trying to convert the first letter of every word in a String to uppercase. I've managed to isolate the first letter of every word and then make it uppercase but I don't know how to replace it.
public static StringBuffer makeUpperCase(){ String str = String.valueOf(input2); for(int i = 0; i < str.length(); i++){ if(str.charAt(i) == ' '){ char var = str.charAt(i + 1); var = Character.toUpperCase(var); System.out.println(var); } }
import java.awt.*; import java.applet.*; import java.awt.event.*; public class Assignment extends Applet implements ActionListener { TextArea textInput = new TextArea(); // user input Button analyzebutton = new Button("Analyze"); Button resetbutton = new Button("Reset"); Label lbloutput = new Label ("Please enter text into the textbox!");
I am trying to do is extract numbers that are in word format in a long String, i.e. a song, and return each of their numerical values, in order to add them all up. So I'd like to calculate the sum of all of the numbers in the text. This has to work for any piece of text and for all numbers up to a trillion.
So I broke the string down into tokens and stored them in a String []. And I divided up the possible numbers in word format into:
I believe that these are the only words that it will need to recognize. I began reading the tokenized string from right to left and then when I came across a unit, special or tens as the first number I hit, I would then set it's numerical value and check if the word before was also a number and whether to add or multiply etc. i.e. First number hit is a two, if the number before is sixty, then I would just add it to sixty and check the word before that and so on.
However, when implementing it, it seems like an extremely long way around it. How I could implement this in a swifter manner? An example of it working would be:
"Nine Million rockets turned Three times and met Twenty Two Aliens", it would extract, Twenty Two as 2, then 20 = 22, then extract Three as 3, and then Nine Million as 1,000,000 x 9 = 9,000,000
