Taking Range Of Names In Array And Outputting Them Alphabetically - OutOfBoundsException
Apr 24, 2014
At the moment I am studying it and the problem is Taking a range of names in an array and outputting them alphabetically, But for some reason I get an outOfBoundsException. And its starting to get to me. How to put the code in
import java.util.Scanner;
import java.util.Arrays;
public class lab241 {
public static void main(String[] args) {
Scanner kb= new Scanner(System.in);
String[ ] names = new String[4];
names[0]= ("Horatio");
names[1]= ("Anatoly");
names[3]= ("Evelyn");
names[4]= ("Anna");
Arrays.sort(names);
for(String N: names){
System.out.println(N);
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May 12, 2014
I'm having a bit of trouble outputting the difference between two array list
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.PrintWriter;
import java.util.ArrayList;
public static void main(String[] args) throws Exception {
[Code] ....
This prints out something like
Test1
Test1
Test2
Test2
Test2
Test3
Test3
Test3
Test4
Test4
Test5
Test5
Test6
Test6
Test6
Ideally, it's suppose to print out only Test2, Test3, Test6.. I've tried different combinations of loops and equals() but I never get the correct output.
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Apr 11, 2014
This piece of code is giving me the most trouble as I cannot convert the self defined class (Fraction) into int in order to store the elements in the variable (max). What is the best way to go about grabbing the next element and storing it in max and compare it to the previous to get the highest and lowest value?
System.out.println("Enter numerator / denominator");
frak[0] = new Fraction(keyb.nextInt(), keyb.nextInt());
frak[0] = max;
for (int i = 1; i < frak.length; i++){ // starting from array element 1
System.out.println("Enter numerator / denominator");
frak[i] = new Fraction(keyb.nextInt(), keyb.nextInt());
if (max > frak[i]){
}
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Oct 5, 2014
An array which contain a list of names. I let for a user input and I use that to search through the array. For example lets say the string name "Christian" is stored inside the names array and the user types in Chri, the program looks in the array and finds a name that contains Chri and prints them out. How do I go about doing this?
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Apr 19, 2013
I just started in java programming and into Arrays multidimensional. I started a simple 2 dimensional array with 5 names with genders. I 'm having issues because it does not want to print out the names with correct genders Male/ Female. The simple program should print out the 5 names with gender type.
example:
Jack - Male
Sally - Female
Dave - Male
Sue - Female
Brian - Male
Here is what I came up with so far:
public class Multiname
{
public static void main(String[] args)
{
//String[][] multiname;
String [][] multiname =
[Code] .....
This is the result:
multiname : Jack
multiname : sally
multiname : Dave
multiname : Brian
multiname : Sue
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 1
at MultiD.main(MultiD.java:29)
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Nov 30, 2014
I'm trying to create a method that takes a map and sorts it alphabetically. I think I have the logic correct but I'm getting errors when I run it:
private static void sortMapAlphabetically(
Map<String, String> termsAndDefinitions) {
Map<String, String> tempMap = new Map2<String, String>();
[Code].....
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Aug 6, 2014
I have a database of peoples names linked up to a from to enter a new employee.The form has a previous and next button that should cycle through the employees alphabetically.What im doing the cycle by now is ID which isnt in alphabetical order and just goes by the order they where entered in.
Is there any way to cycle through alphabetically instead? Is running a query each time the next/previous button is pressed the correct way or should it just grab all the names in the array. Theres probably 150 names.
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Oct 13, 2014
So we have to create a code that reads in a file that has a huge list of words. Our code has to convert every word to all lower cases and then re-sort alphabetically. I was able to turn everything to lower case, but for the re-sorting I keep getting a null pointer exception on the line of the if statement.
import java.io.*;
public class readDict {
public static void main(String args[]) {
try {
System.out.println("Opening the file...");
[Code] ....
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Apr 11, 2013
I have a problem sorting this file alphabetically by second name. Basically, my method sorts each column alphabetically but i would like to sort the file according to the second name.
File:
Moe Carl
Saul Sergio
Rocky Louis
Ike Ziken
This is how my method sorts the file:
Ike Carl
Moe Louis
Rocky Sergio
Saul ziken
Instead
Moe Carl
Rocky Louis
Saul Sergio
Ike Ziken
Code :
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.io.*;
import java.util.*;
class thedata implements Comparable
{
private String firstname;
private String secondname;
[Code] .....
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Jun 10, 2014
import java.io.*;
Class bubble
{
public static void main()throws IOException
{
BuffetedReader br=new BufferedReader (new InputStreamReader (System.in));
int j, k, temp;
String st[]=new string [10];
[Code] .....
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Oct 24, 2014
I have code that displays 3 game scores the series total and average. For some reason game 3 outputs 0 and game 1 and 2 output correctly. I don't see anything different that game 3 is doing that game 1 and game 2 aren't so I'm not sure what the problem is.
java file
package com.valenciaprogrammers.mybowlingscores;
import java.text.DateFormat;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Date;
public class BowlingScores implements Comparable<BowlingScores>{
private long id;
[Code] .....
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Feb 8, 2014
I have a project requiring me to build a program having a user input 3 words, sort them alphabetically and output the middle word. I have done some searching and seem to only come back with results for sorting 2 words. I so far have code to get the user input but I am completely lost as to how to sort them alphabetically.
import java.util.Scanner; //The Scanner is in the java.util package.
public class MiddleString {
public static void main(String [] args){
Scanner input = new Scanner(System.in); //Create a Scanner object.
String str1, str2, str3;
System.out.println("Please enter three word words : "); //Prompt user to enter the three words
[Code]...
we havnt done arrays yet and I THINK i have to do compareTo.....how to use it?
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Jan 27, 2014
Trying to learn switch statements. Can't figure out what I am doing wrong.
java Code:
import java.util.Scanner;
public class Ok1 {
public static void main(String args[]) {
Scanner input = new Scanner(System.in);
[code]...
When I run, it makes me enter letter = null and it wont output correctly.
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Oct 29, 2014
I have a loop and I was wondering why it is outputting my line twice. Here is the code:
while (x != -1) // closes the program if the user enters -1 for x
{
System.out.println("Which jar would you like to access? Please select a number between 1 and 3. Press -1 to exit.");
x = scan.nextInt();
ourpantry.Selection(x); // tells our pantry class what number the user selected
while ((response != "continue")) // loop continues until user gives a valid response
[Code] ....
This results in the Output:
Would you like to spread jam? Y or N.
Would you like to spread jam? Y or N.
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Oct 14, 2014
I created a calendar program so when the user enters a day number and a year it would show the calendar for the year . My issue was that I could not get the numbers to line up neatly and how they should look . Also if its not to much trouble I would like to know how to turn this in to a loop .
import java.util.Scanner;
public class Calendar {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("Enter a Year");
int Year = scanner.nextInt();
[Code] .....
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Oct 6, 2014
I'm having trouble with sorting Strings- 3 strings inputted by user, and I would like to output them in alphabetical order. I've used the str.compareToIgnoreCase method, and then I've tried to loop them through a series of if/ else statements. Everything I've been able to find online (including the forums here) has suggested to use the Comparator class, or to put the strings into an array, and sort list- I really would like to stick with just the String class, and its methods .
The program itself works and compiles, but I am getting logic errors that I have been unable to solve. I'm using IntelliJ Idea, and I've ran it through the built in debugger, about 100+ times (not exaggerating, lol) just to see what it's doing in particular scenarios. For instance, I can get c, a, b, to print out as a,b,c correctly, but a,b,c, will print out as b,a,c.
For me this is kind of like a Sudoku puzzle, or a Rubik's cube! Each time I fix one scenario, it breaks another one, so I don't know if there's a(logic) solution to fix all possible scenarios (abc, acb, bac etc... to all print abc) or if possibly I just need more if statements. I've only pasted in the area where I'm having problems (the if statements). I'm a big fan of the "Next Line" syntax.
(Note: please assume the non relevant content- import Scanner class, main method, etc... I didn't want to paste the entire program.)
System.out.println("Enter the first statement: ");
//input.nextLine();
string1 = input.nextLine();
System.out.println("Enter the second statement: ");
string2 = input.nextLine();
System.out.println("Enter the third statement: ");
string3 = input.nextLine();
[Code] ....
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Apr 22, 2014
My current assignment involves me outputting these 2 classes. Yet I'm not really sure in what manner I should go about doing this. I have tried creating a separate class and outputting my toString methods there but for some reason I am getting an error. .
The error message is thus;
Exception in thread "main" java.lang.NullPointerException
at Vehicle.toString(Vehicle.java:91)
at Run.main(Run.java:17)
Process completed.
import java.util.Calendar;
public class HireContract {
String reference;
Calendar startDate = null;
Calendar endDate = null;
Vehicle vehicle = null;;
String customerRef;
double rate;
[Code] .....
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Mar 30, 2014
I am currently working towards taking input from the user and storing it in an excel document. However how can I test to make sure that I am trying to save it to an empty cell. Is there some type of method that will check to make sure the cell is empty, otherwise how can this be done?
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Nov 9, 2014
I was struggling to use BufferedReader to extract some data and then perform some calculations and then have the results as outputs.
I haven't quite solved that issue but in order to progress, I hard coded some values into my application and proceeded with the actual calculation loops etc.
Currently, the value out put from one of my calculations is given as:
1.1704926E7
How can I make the console show it in a natural way. I've performed the calculation manually and it should be 11704926.5 I don't want to lose that .5!
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Sep 27, 2012
I am using SAXTransformerFactory to output an XML file but can't figure out how to output the stylesheet setting, for example:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE ectd:ectd SYSTEM "util/dtd/ich-ectd-3-2.dtd">
<?xml-stylesheet type="text/xsl" href="util/style/ectd-2-0.xsl"?>
I am using the following code to get the first two lines, I just can't see how to output the third line above.
SAXTransformerFactory mTransformerFactory = (SAXTransformerFactory) SAXTransformerFactory.newInstance();
TransformerHandler handler = mTransformerFactory.newTransformerHandler();
Transformer mTransformer = handler.getTransformer();
mTransformer.setOutputProperty(OutputKeys.VERSION, "1.0");
mTransformer.setOutputProperty(OutputKeys.ENCODING, IBF_UtilXML.XML_ENCODING_UTF8);
mTransformer.setOutputProperty(OutputKeys.DOCTYPE_SYSTEM, "util/dtd/ich-ectd-3-2.dtd");
I believe I found an example using a DOM approach but I would much prefer using SAX.
<?xml-stylesheet type="text/xsl" href="util/style/ectd-2-0.xsl"?>
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Feb 15, 2014
This is sort of like the last problem I had but it's all about the formatting at the end. I have a file that reads something like:
Name
a bunch of text here
and perhaps a second
or even a third line
I need to output this as:
Name; "a bunch of text here and perhaps a second or even a third line"
Right now I find 'Name' and it outputs:
Namea bunch of text here and perhaps a second or even a third line
How would I add ";" and quotes in the middle? I can imagine that I may need to find name, then skip to the next line and just add name manually as the variable output of the search string.
This is where I am now
public static void main(String[] args) {
boolean output=false;
String name="";
String junk="CHAMBERS";
TextIO.putln("Search for a name");
name = TextIO.getln();
TextIO.readFile("doc.txt");
[Code] .....
So I'm almost there, but those dange double Names are killing me. I tried to add a bit of code where:
if (line.indexOf(name) >= 0){}
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Oct 17, 2014
I am Having trouble with my program to validate. It is outputting null into the validation statement then it brings back a run-time error to that validation Statement for the String.
public String validateData ()
{
if (nm == null)nm = "Error! Must enter at least one character";
else nm = name;
return name;
}//end validation method
Why is this happening, and then once that is completed, why is the validation Sentence in tests Scores not able to validate. I traced it back to out put "Error, a number between 1<100".
public void validateTests ()
{
String testschange;
if (test1 < 0 || test1 > 100) {
testschange = " You have entered an invalid number, between 1-100. Please restart!";
testschange = Integer.toString( test1 ) ;
[Code] .....
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Jul 9, 2014
I have written a java app that's been working for a few years now and the client is very satisfied. However, a certain user has been experiencing a problem where the app runs fine BUT whenever it interacts with the OS (Win7 in this case), it takes ~10 mins to respond. Actions include, for example, exporting the currently displayed JTable to a CSV file or making an OS call to open up MS Word, etc.
I copied the users version of the app onto my platform (win 8.1) and tested it on winXP too with no problems which points towards an issue on the users particular PC. Furthermore, it used to run on the users PC fine until something (??) happened.
I've tried the following so far:-
1. looked at System restore to check anything new installed - nothing obvious
2. disabling anti virus - problem still occurs
3. monitoring JVM process time using Task Manager - little CPU time seems to be utilised (=> no loop etc)
I'll try :-
1. using JvisualVM - although I don't think this will show me what's going on with the OS
2. excluding the JVM and the app from all anti malware
Any app or something that shows interaction with the OS so I can trace what might be intercepting the call from my app to the OS?
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Oct 29, 2014
I have a small bug in my program. The user is asked what person(s) information they want to access but lets say they want captain they must enter "captain" twice. I think it will make more sense to you with the code. I have searched all over to see what is causing the bug but still have found no resolution. I even tried making two different scanners but that didn't work either.
I know the while loop (line 16) I am using is causing the bug because it works fine without that but then I cannot validate the input.
package myproject;
import java.util.Scanner;
public class Enterprise {
public static void main (String[]args){
String userInput;
[Code]......
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Oct 25, 2014
What I have so far are two classes, Movie class and MovieTestDrive class. I've to get the title, genre and ratings for movies and then put them into an array and call the playIt() method.
I would like to create a for loop to iterate three times for three instances of the Movie class but I don't know how to do it.
When I try to run the code, it won't work and I don't know if this is because I have Scanner running incorrectly whilst encapsulating my data. What I have so far:
class Movie {
// Create instance variables for the Movie class.
private String title;
private String genre;
private int rating;
// Use getters and setters to set and display the variables.
[Code] .....
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Oct 29, 2014
I am working on a web-application where i have a functionality which generates reports based on the data from DB. for small amount of data its working nice if the data is huge its taking more time. to avoid this problem i developed a standalone batch where i generated the jar file for the sources in web-application and made a call to the appropriate methods.
But my problem is if web-application takes 10 secs to generate the report but in the case of standalone its taking nearly 3-5 mins to generate the same report. i didn't do much of the changes in code just using the same code as web-application
I am using tomcat 6 application server to run the web-application for standalone using batch commands.....
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