//Main method
public static void main(String args[])throws IOException{
boolean runProgram = true;
Scanner keyboard = new Scanner(System.in);
//runs program while runProgram is true
while (runProgram){
[code].....
I have a problem with an if statement I've done. I'm not sure how to fix my problem. I'll post the code of the if statement and the output.
if (box = true &&(shippingSwitch ==1))
{
if (ounces < .5)
{
additionalPrice = ((ounces % .5)/(0.0625))*1.25;
shippingPrice = 15.75 + additionalPrice;//((weight / 8)+ (weight % 8));
[Code] ....
Here's the output I get using println to test it.
Please enter 1 if your package is a letter and 2 if your package is a box
2
Please enter weight in pounds (Example: 1.2):
1.2
Please enter your shipping service option:
Press 1 for Next Day Priority:
Press 2 for Next Day Standard:
Press 3 for Two Day Shipping:
1
7.00
If I comment out the else statement on the last line of code I get the following output:
Please enter 1 if your package is a letter and 2 if your package is a box
2
Please enter weight in pounds (Example: 1.2):
1.2
Please enter your shipping service option:
Press 1 for Next Day Priority:
Press 2 for Next Day Standard:
Press 3 for Two Day Shipping:
1
13.75
What I want to happen is the code under the first comment to to execute if true, or go to the code under the next comments and execute if that statement is true and if that is not true I want the last block of code to execute underneath the last comments.
How can I time my while loop to executeevery 3 seconds?
Here is my code:
class Info{
public String name;
public String version;
public String arch;
double CPUSpeed;
};
Info info = new Info();
Info[] queue = new Info[100];
[Code]...
I seem to have done it right, but it doesn't work... What is wrong?
just trying to learn it on my spare time and I'm doing do-while loops
public class help {
public static void main (String args[])
throws java.io.IOException {
char choice, ignore;
do{
System.out.println ("Choose one:");
System.out.println("1. if");
System.out.println("2.switch");
[code]....
It makes no difference in the program wither i delete this block or keep it..how while (choice < '1'| choice >'2'); translates? I would assume it would be while (choice >= '1'| choice =<'2');?
Question: you are only allowed to use numbers from 1-6. Write a program to find all the permutations when three numbers are multiplied together to give a result 8. one number cannot occur twice in any permutation.
public class number4
{ public static void main(String[] args)
{
for(int a=1; a<=4; a++)
{
for(int b=1; b<=4; b++)
{
[Code]...
my program also prints out 2 2 2. but i'm not allowed to do that. how can I stop it from printing 2 2 2 ?
Here's what "Why doesn't this work?" question. It concerns a small method which is part of a card game.
I'm trying to check a condition from a section of an array, without a predetermined number of times any given call to this method will require a check. How much of the array I'm checking could vary greatly.
Is it at all possible to nest a for loop yielding a variable number of boolean && conditions inside an if? Am I just missing the right bracketing or is this nesting (if that's the word) even possible in the language?
To clarify, below is broken code. Compiler isn't letting me accomplish this goal as I envision it.
public boolean isFlanking() {
boolean f;
int reach = Math.abs(selectorX - targetX);
if(rival.getDeck()[selectorX].getPile().isEmpty() == true &&
[Code] ....
int count = 0;
for (int x = 0; x < 3; x++)
for (int y = x; y < 3; y++)
for (int z = y; z < 3; z++)count++;
What is the value of count after the code segment is executed?
The answer is 9, but I don't really understand how this answer was derived.
for (int i = 0; i < 4; i++)
{
for (int k = 0; k < i; k++)
{
System.out.print(" ");
}
for (int j = 4; j > i; j--)
{
System.out.print("$");
}
System.out.println();
}
I was told that the answer when this code segment is printed look's like this:
$$$$
$$$
$$
$
Here's what I did:Looking at the outer for loop, (i) 0 < 4 so I went into the first inner nested loop. (k) 0 is not less than (i) 0 so I went to the 2nd inner nested loop and found that it worked, and I was able to repeat this loop 3 more times and then I exited the loop and printed the line out (giving me the first line of four $). I then went back to the outer for loop, increased i by 1 and (i) 1 < 4 so I went to the 1st inner nested loop. I used the 0 for the k first and (k) 0 < 1 so I printed out a space (now here's where I get lost) I then incremented k by 1, so k = 1, but 1 is not less than 1 (i) and so I moved on to the next nested for loop. So when this line is printed, I'll only have one space when there should be 4.
int count = 0;
for (int x = 0; x < 3; x++)
for (int y = x; y < 3; y++)
for (int z = y; z < 3; z++)
count++;
What is the value of count after the code segment is executed?
The answer is 9, but I don't really understand how this answer was derived.
I'm having trouble figuring out the Big-O notation for this loop. For now I only have it in pseudocode. I hope you understand it anyway
for i = 1 to n do
j = 1
while j <= n/2 do
print "*"
j = j + 1
end while
end for
I don't know how to write a program based on for loop like pattern printing.etc
View Replies View Relatedhow does this nested enhanced for loop execute? I dont know how to indent the code.
for (String exam : exams)
for (String level : levels)
for (String grade : grades)
System.out.println(exam+":"+level+":"+grade);
Note:
exams,levels,grades are arraylist
exams contain Java,Oracle
levels contain Basic,Advanced
grades contain pass,fail
I built a java code to print the following pattern using nested loop:
1 2 3 4 5 6 7 8 7 6 5 4 3 2 1
1 2 3 4 5 6 7 6 5 4 3 2 1
1 2 3 4 5 6 5 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1
And here is my code
public static void main(String[] args) {
for(int i=1; i<=8;i++)
{
for(int k=1;k<=i;k++)
{
System.out.print(" ");
[Code] .....
which gives the partially true output:
123456781
123456721
123456321
123454321
123454321
123654321
127654321
187654321
I couldn't figure out how to place the spaces.I have made some changes on the code, but it didn't work.
Implementation of the nested for loop. I thought it was going to go smoothly but apparently not.Purpose: This program is meant to print out all the prime numbers up to a certain range using the algorithm Sieve of Eratosthenes.
Update output: Works as expected.
Java Code:
import java.util.Scanner;
import java.util.ArrayList;
public class PrimeFactors
{
static ArrayList<Double> primeList = new ArrayList<>();
static double range = 0;
static double maxPrime = 0;
static double primeTester = 0;
[code]....
I just started playing around with Java for awhile, but got caught up in a problem when using ArrayList.
CinemaAppMain
public class CinemaAppMain {
public static void main(String[] args) {
new CinemaApp().start();
[Code]....
I am trying to get the movie name and theatre title from their ArrayList, and I know I need to go through the movie list & theatre list to find their name & title, and compare it with the user input and print out the result.
I use for(int i=0;i<movies.size();i++) to go through the the movie list, and I tried using for(int i=0;i<theatres.size();i++) to go through the theatre list. But when I printing multiple time with different user input value, it will show me strange result (screening have same movie name & theatre name, the else if statement is printed below the user input, user input is printed more than once after the first time).
Edit: I know its wrong for me to use nested for loop,if not, another solution is needed to get the item inside both of the list. (getting the "title" from movie list & "name" from theatre list)
Write a nested loop for a pyramid pattern. Well here's an ugly description of what it should look like:
1
1 2 1
1 2 4 2 1
1 2 4 8 4 2 1
1 2 4 8 16 8 4 2 1
1 2 4 8 16 32 16 8 4 2 1
1 2 4 8 16 32 64 32 16 8 4 2 1
1 2 4 8 16 32 128 64 32 16 8 4 2 1
I managed to make the pyramid using addition. However, how to turn it into multiplication x 2.
import java.util.*;
public class NumbersPyramid
{
public static void main(String[] args) {
int odd = 1;
int numSpaces = 7;
[code]....
I am working on my java program it prints out a table of angles and the sin, cos, and tan. For extra credit he wanted us to use nest loops to create a space after every five lines. I have come real close to getting this to work but have a problem with the very end of the table. The table needs to stop at 180...
public static void printTable(double angle,double sin,double cos,double tan) { // Method to create a table for the values
for (double j = 0; j <= 180;) {
for (double i = 1; i <= 5; i++) {//loop to print five lines of code
angle = Math.toRadians(j);
[Code] .....
Here is the end of the output of the table:
175.00.0872-0.9962-0.0875
176.00.0698-0.9976-0.0699
177.00.0523-0.9986-0.0524
178.00.0349-0.9994-0.0349
179.00.0175-0.9998-0.0175
180.00.0-1.00.0
181.0-0.0175-0.99980.0175
182.0-0.0349-0.99940.0349
183.0-0.0523-0.99860.0524
184.0-0.0698-0.99760.0699
I'm trying to make a custom checkboard with given user input, in the form of (# of rows, # of columns, size of each square, filler character).
So the input 2 3 5 * would look like
*****.........*****
*****.........*****
*****.........*****
*****.........*****
*****.........*****
.........*****
.........*****
.........*****
.........*****
.........*****
I've made my loop, but I am unable to get more then a 1 1 1 checkerboard properly. I am stuck on how to divide the filler characters to make the proper square size. As of now they are all one lined.
import java.util.*;
public class Checker{
public static void main(String[] args) {
int col, row, size; char filler;
System.out.println("Please enter 3 numbers and a character."); //output
[Code] ..........
I am having problem with some problems like this nested for-loop for instance ....
-----1-----
----333----
---55555---
--7777777--
-999999999-
Now I have to write a method called printDesign that produces the following output but i am not even entirely sure how to start it out now of course i know how to make a for-loop but and i guess if i was to do something for this i would do this .....
Java Code:
for(int*j=0;j<N-k;j++){
System.out.print("-");*
for(int*j=0;j<i;j++){
System.out.print(i);*
for(int*j=0;j<N-k;j++){
System.out.print("-");*
System.out.println();*
}
}
} mh_sh_highlight_all('java');
Four experiments are performed, each consisting of six tests. The number of test results for each experiment is entered by the user. Write a Java program using a nested loop to compute and display the average of the test results for each experiment.
You can run the program by entering the following test results:
Experiment 1 results:23.231.516.927.525.428.6
Experiment 2 results:34.845.227.936.833.439.4
Experiment 3 results:19.416.810.220.818.913.4
Experiment 4 results:36.939.549.245.142.750.6
How can I execute a jar file ?
how can I make such file ?
Will it be executed as an exe file in windows ?
I am making a program, where the user answers 3 questions and then I add the number of correct answers in to the (int) numberofcorrect variable, then I want to print the results, and no matter how many correct, the program executes first the correct if statement, then the else statement.
Eg: I have 2 correct it will print:
"Grade B, 2 of 3 "
"You failed the test"
Why does it do that? How can I change my code so the else statement dosent print if one of the if statments is allready printed?I want to know how to not execute the else statement, if one of the if statements have allready been executed.Below is my current code for this problem:
if (numberofcorrect == 3){
System.out.println("Grade A, full score");}
if (numberofcorrect == 2){
System.out.println("Grade B, 2 of 3 ");}
if (numberofcorrect ==1) {
System.out.println("Grade C, 1 of 3");}
else {
System.out.println("You failed the test"); }
I want to execute my jsp code to compare two dates after every 10 seconds if user enter date and current sys date are equal it will send the mail to the user automatically. Below is my jsp code
this if condition i want to check the date after every 10 seconds and when two dates are equal it will send the mail using below mail code
if(ExpcReDt.compareTo(dateStr)>0) {
out.println("Expected return date is greater than current date");
}
else if(ExpcReDt.compareTo(dateStr)==0)
[code]....
I am able to compile the below program but not able to execute.
public class String {
public static void main(String[] agrs){
System.out.println("Hello String");
}
}
Output Error:
Class String does not have a main method
I was typing up this program and when I compile it, there aren't any errors, but it won't advance past the second conditional.
Here's the code:
import static java.lang.System.*;
import javax.swing.JOptionPane;
import java.util.*;
public class area51
{
public static void main(String args[])
[Code] ....
The first two answers are 41 and right.
public class Main {
private static void foo(Integer a) {
System.out.println("Integer");
}
private static void foo(long a) {
System.out.println("long");
[Code] ....
This code prints long. Why is that? How did compiler decided that it likes long version of foo() method the most. If I had to guess I'd pick int... or possibly Integer as they are most similiar to what was passed. But why long?