Truth Table For Logical Operators

Nov 11, 2014

I've created a truth table for logical operators. Now I'm supposed to alter the code so the table prints 1's and 0's instead of true or false. Here's a bit of the original code - just the header and the first line of the table.

System.out.println("p q AND OR XOR NOT");
System.out.println();
boolean p, q;
p = true; q = true;
System.out.print( p + " " + q + " " );
System.out.print( ( p & q) + " " + ( p | q) + " ");
System.out.println(( p ^ q ) + " " + ( !p) );

All of my ideas involve using an if-then statement, but that would be all kinds of inefficient and unwieldy, I think.

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I'm supposed to take this truth table and alter it so it displays 1's and 0's instead of true false. I'm assumed to do this I would just need to change the variable type and replace true and false with 1 and 0 but every way I try this does not work.

//a truth table for the logical operators.

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[Code] ....

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I forgot to notice, with 1 3 3 4 as parameters it jumps out at if (b < c), which is expected. but it jumps out of the whole if instead just run the else part. that's the essence of my problem.

The Exercise:

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N in the other cases

Examples (from the exercise)

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S

=> java Monoton 1 3 3 4

M

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In exercise 4, I get the same problem:

The expression !((x <= y) && (y > 5)) is equivalent to which of the following?

A. (x <= y) && (y > 5)
B. (x <= y) || (y > 5)
C. (x >= y) || (y < 5)
D. (x > y) || (y <= 5)
E. (x > y) && (y <= 5)

Exercise 4
ABCDE
Incorrect
Score: 0 / 1
Submitted: 2/10/2014 8:21pm
Your answer is incorrect.
Answer Key

The following model answer has been provided to you by the grader. Carefully compare your answer with the one provided here. The given expression is pretty long, so if you try to plug in specific numbers you may lose a lot of time. Use De Morgan's Laws instead:

!((x <= y) && (y > 5))
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When ! is distributed,
&& changes into ||, and vice-versa

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