I am working with a program I wrote for class. I got it to compile and do what I want, But I was wondering how I can format my methods to to display a decimal with 1-2 decimal places. Would I create a method in my NumberAnalysis class to do it for me? Or would I declare an instance of the DecimalFormat class in my main method?
import java.util.Scanner; //Needed for Scanner Class import java.io.*; //Need for File and IOException import java.text.DecimalFormat; public class Ex8_11 { public static void main(String[] args) throws IOException{ { DecimalFormat decformatter = new DecimalFormat("#0.00");
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This is my output:
Lowest Number: 1.09 Highest Number: 82.76 Total Number: 367.89000000000004 Total Average Number: 30.657500000000002
Think I just solved the answer to my own question, I did it by declaring double variables in my main method and called the methods and instantiated the variables into the methods... Is there a better way to do this?
package lesson4.skowronek; import java.util.Scanner; //Needed for Scanner Class import java.io.*; //Need for File and IOException import java.text.DecimalFormat; public class Ex8_11 { public static void main(String[] args) throws IOException{
import javax.swing.JOptionPane; import java.text.DecimalFormat; public class Sample3 { public static void main(String args[]){ double amount,iRate,monPay,totalPay; int years; String amountStr;
I've been scanning forums for answers to this problem, but most deal with simple programming that you might find in a classroom (i.e. "System.out.printf") which will not work in the GUI I'm attempting to complete. Here's the tale of the tape:
The GUI is a price calculator I'm developing for my company that takes input from drop-down menus and several Jtextfields and calculates the answer based on the values contained within each. It's completely done (and functional), so I'd rather not change too much if at all possible. Because I'm dealing with decimal values then I'm getting 9 decimal places in the output JLabel, though. In order to display the answer, I'm using a series of "totalPrice.setText(..." declarations.
Because there is a fair amount of text and the values in the calculation are constantly changing, is there a way to 'simply' format the output JLabel to display only 2 decimals? Or is there an alternative solution that would work--say with a JTextfield instead--without having to completely re-code the calculator?
I am writing a simple learning program that does basic math. Everything is working as needed except for when it comes to division. I need to know if there is a way to format the users input to two decimal places and that when the program checks the users answer against the division, it gives it a yay or nay. Right now, it wants the answer out to 12 decimal places.
I need to print to 2 decimal places and I'm trying to use the printf method, but for some reason I keep getting an error. I've looked through my code, but unless I'm missing a small detail, it looks okay to me.
I'm attempting to format my doubles to two decimal places within my return statement. I have tried to use DecimalFormat but it gives me an error because my method needs to return a double and that results in a string being returned. I have also tried using the *100.00/100.00 method and that doesn't work when the number already ends in 0.
If I pass -150.00 it gives me -150.0 when I need two decimal places.
My program is supposed to include The three sides of the triangle formatted to two decimal places The perimeter formatted to one decimal place The area formatted to one decimal place The unformatted area. It does run, but it is not decimal formatted. I have read my book to try and figure out how to do this, but it doesn't make since to me.
How i would convert this java code to display using the printf statement, with two decimal places to the right...here is the source code so far, but it has a few errors and needs to be reformated for printf
import java.util.Scanner; // scanner class public class PROB3_CHAL15 { public static void main(String[] args) { double checks =0, totalfee =0, fee = 10, fee1 =.1, fee2 = .08, fee3 = .06, fee4 = .04, checkFee; String input; Scanner keyboard = new Scanner(System.in);
import java.util.Scanner; public class FindHexString { public static void main(String[] args) { String hexString = ""; //output a hex string int decNumber;//decimal number to be converted int storeInput; //copy f input decimal number
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I am trying to figure out how to convert from decimal to hexadecimal without using the java library function. This is just a guess. I could be wrong.
Java programming, I decided to write a code today that would convert decimal numbers to hexadecimal numbers. Unfortunately, it does not compile. The error message is "cannot find symbol - variable A", and might be the same error for the other variables B,C,D,E,F.
Here is my code:
public class dec2hex { public static void main (String [] args) {int nbr = 99; char a = A; char b = B; char c = C;
Given a Numbers instance, whose fields are arrays of all the built-in Java numeric types (int, long, float, double, big-decimal, etc), write a method to sort all the numbers into a master list, and then print out the numbers where the number of digits past the decimal point is equal to the index of the number in the master list.
Is there a function in Java that will give me just the numbers after the decimal? I tried Decimalformat but couldn't get it to work. Here is what I have so far; however, I think I might be on the wrong track.
public class Numbers { public static void main(String[] args) { Byte bNum = new Byte((byte) -50); Integer iNum = new Integer(168); Long lNum = new Long(100000L); Short sNum = new Short((short) 10000); Float fNum = new Float(12.19f); Double dNum = new Double(23.123); BigDecimal bd = new BigDecimal("3.14159265358979323846");
This problem is from Java . It asks me to convert a binary number in to decimal. How to program this in java? I am not able to find an effective algorithm to convert in to Java.
Ex. If I type 5943, the program will say mill = 5 hun = 9 ten = 4 uni = 3
get the picture I had to translate the decimal value names from a different language.
This is what I have tried...,
Java Code:
import java.util.Scanner;//Permite el uso de leer el teclado del usuario public class DeterminarValorDecimal//Nombra el documento { public static void main(String [] args)//Podemos ver la clase {
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But what this does is I have to enter the single digits one by one. I want to be able to type the whole number. Is there a method that reads the length of the whole number and lets me classify each digit so I can do what I want to do?
for (int i = 0; i < letters.length; i++) { double relativeFreq = (onesAverage()/letters[i]); char a = characters.charAt(i); double j = score[i]; System.out.printf();//ToDo
Above is my current code. Basically- There is a string called characters of length 26 (1 char for each letter in alphabet), a double relativeFrequency value which does a calculation and the end result is a number with lots of decimal numbers. The score array has set double values within the array.
What I want to do is create a print f statement where I print out each of the values I initialized above WITH specific amounts of spaces in between. So it should be in this order:
a (spaces) j (spaces) relativeFreq (newLine).
Between J and relativeFreq there should be 4 spaces, however if the value in relativeFreq is greater than 10 (it won't be greater than 100)- then there should be 3 spaces. Everytime I try to create a printf statement my code ends up crooked for some of the values.
for (int i = 0; i < letters.length; i++) { double relativeFreq = (onesAverage()/letters[i]); char a = characters.charAt(i); double j = score[i]; System.out.printf("%c %.4s %.4s%n",a, j, relativeFreq);
import java.util.ArrayList; import java.util.Arrays; import java.util.List; public class array { public static void main(String[] args)
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Is there a way to write this, where, alpha is one array.
Write a program that declares an array "alpha" of 50 elements of type "double". Initialize the array so that the first 25 elements are equal to the square of the index variable and the last 25 elements are equal to three times the index variable. Output the array so that 10 elements per line are printed.
If I have an array of 50 integers, can I break that to read in lines of 10?
I tried to create file and write the output of my program in it in java when i use WriteLong then the file does not contain long value, how I create this file my program is to print prime numbers between 500000 to 10000000
public class primenumber { public static void main(String[] args) { long start = 5000000; long end = 10000000; System.out.println("List of prime numbers between " + start + " and " + end); for (long i = start; i <= end; i++) { if (isPrime(i)) { System.out.println(i);
I'm using eclipse. I'm going to get straight to the point and give all the info I can, if the values in the first code box are used, shouldn't these values be left after all in the second box is done:
remainder=23, arr[0]=100, div=23/10=2.3, whole=2, and decimal=3?
When I use this code, div comes out to be just (2.0).
Java Code:
int leng=10; arr[0]=123; //int arr[1]=100; //int mh_sh_highlight_all('java'); Java Code: if (arr[0]!=arr[1]){ int remainder=arr[0]-arr[1]; arr[0]=arr[0]-remainder; double div=remainder/leng; //double div=Double.valueOf(remainder/leng); int whole=(int) Math.floor(div); int decimal=(int) ((div-whole)*leng); mh_sh_highlight_all('java');
I'm not sure were I'm going wrong in how div is being calculated, but I ultimately need div to be 2.3.
I've also used the second option commented out which still gives (2.0).
I've been working on a personal project again in Unit 3 of my text book and this time they want me to make a random phone number generator. Here's the actual directions:
"Write an application that creates and prints a random phone number of the form XXX-XXX-XXXX.
Include the dashes in the output.
Do not let the first three digits contain an 8 or 9 (but don't be more restrictive than that), and make sure that the second set of three digits is not greater than 742.
Think through the easiest way to construct the phone number. Each digit does not have to be determined separately."
With this assignment I came across 2 problems:
1. What I tried was that since the first 3 numbers have to be a random number with no 8's or 9's I tried doing this algorithm:
The problem is that Java won't allow me to generate random numbers this way. Are there any easier ways of generating numbers that doesn't contain specific number (such as 8 or 9 in this case?)
2. I was thinking about this throughout the whole project and what if I generate a number such as 27 (less than 3 or 4 digit number) rather than 3 or 4 digit numbers? How would it show 0027 or 027 instead of 27 for the phone numbers?
import java.util.Random; public class pp0303 { public static void main (String[] args){ Random generator = new Random(); int first0, first1, first2, second, third, random0;
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RESULTS:
Exception in thread "main" java.lang.Error: Unresolved compilation problems: Cannot invoke replace(char, int) on the primitive type int Cannot invoke replace(char) on the primitive type int Syntax error on token "random0", delete this token at pp0303.main(pp0303.java:15)
