Using If Else Statement For String Variables?
Oct 17, 2014
Is it possible to use a if-else statement for string variables?
I am trying to make a program that execute different depending on the user typing in "male" or not when he/she gets asked about gender. The program execute the else part no matter what the user types in.
Here is my code :
import java.util.Scanner;
public class c4Testname {
public static void main(String[]args){
Scanner input = new Scanner(System.in);
System.out.println("Type in your gender");
[Code] .....
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May 19, 2014
I am stuck with two switch statements that I feel I am close to achieving. My first switch statement is to generate random mathematical operators for the math questions in the game (generated randomly) My second switch statement is to determines which action the system will take upon the correct or incorrect answer. For the first switch statement I have a variable called num. Num is a random integer. I have an operator mapped to each outcome of num. In my second switch statement I am trying to use the variable answer as a variable in the first case but do not know how.
package pkgnew;
import java.util.Scanner;
import java.util.Random;
public class New {
public static void main(String args[]) {
//Declare and construct variables
[Code] ....
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Mar 11, 2015
Is it possible to have the value of an entered String to be set as the name of the String to be created whilst running.For example: String username= Keyboard.readString() & the user entered for example the word: "Hello".Is there a way how I can make the Java Program create another String named Hello (Inputted value of String username).
If this is allowed, what do I have to use and if possible show me exactly what I have to do with the example mentioned above?
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May 24, 2015
I want to write a program that ask if you want to go to the movies. If the user type in yes then it'll print out (Alright let go) but if the user type no then it would print (whatever). The trouble that I'm having is. What's the best way to use Boolean and Strings together in a if statement?
public class Night {
static Scanner UserInput = new Scanner (System.in);
public static void main (String [] args){
boolean user1, user2;
user1 = true;
user2 = false;
[Code] ....
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Oct 14, 2014
The problem asks me to write an expression whose value is the number of characters in a specific string. Normally, it would be a simple task of using the String.length() method, but that is not allowed. In fact, no variable declaration is allowed (it's a MyProgrammingLab assignment, if any are familiar).
Simply put, if I have a String "This is a sample string." is it possible to find the length without assigning it to anything?
In other words, the code must be able to go into the parentheses of System.out.println( ); and correctly print the length of said string.
The answer, for those curious:
System.out.println("This is a sample string.".length());
I didn't know the .length() method could be called on a literal. Now if only I could find out how to close this thread...
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Aug 3, 2014
import java.io.IOException;
import java.util.*;
public class Guesser {
public static void main(String[] args) throws IOException {
char[] alphabet = "abcdefghijklmnopqrstuvwxyz1234567890 .,:;'-".toCharArray();
[Code] .....
I'm writing a program which will take a three letter word (for now) and then try to guess the word over and over again until it finds it, then print the word and the amount of tries it took to find it.
The problem: at the moment the program will find the word but not break out of the for loop when it does. I think it doesn't like the char to String conversion somewhere along the line.
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Aug 26, 2014
I have some spatial datasets which are availabe in a opensource metadata catalog software GeoNetwork and in a PostGIS database.The problem is that the student who created the database used different IDs for the same datasets. So the IDs in the GeoNetwork differs from the IDs in the postGIS database. They only have the same name So, if someone uploads a new dataset into GeoNetwork, the same dataset is uploaded into a postGis database too.
Now I want to add a ID column into the database to give the field the same ID like the ID in geonetwork. I think I can only do this with using the filename cause they are same in both cases.Now I want to alter the table in eclipse with following code:
PHP Code:
Connection con = null;
Statement stmt = null;
String query = null;
String filen = filename.substring(0, filename.indexOf('.'));
con = DriverManager.getConnection("jdbc:postgresql_postGIS://localhost:5433" + "user=postgres;password=dominik1;" + "database=geonetwork"); --> (the connection data will later be in a properties file)
query = "ALTER TABLE " + filen + " ADD GN_id INTEGER(10) ";
stmt = con.createStatement();
stmt.execute(query); mh_sh_highlight_all('php');
But i get the following findbug error:
Failed to execute goal org.codehaus.mojo:findbugs-maven-plugin:2.5.2:check (default) on project services: failed with 1 bug
org.fao.geonet.services.resources.UploadAndProcess .exec(Element, ServiceContext) passes a nonconstant String to an execute method on an SQL statement ["org.fao.geonet.services.resources.UploadAndProces s"] At UploadAndProcess.java:[lines 83-299]..
I tried to suppress this error and worked with PreparedStatement and String.Format but I can't get rid of this error.
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Jul 12, 2014
public class PasswordGen {
public static void main (String[] args) {
Generator();
}
public static void Generator() {
char[] alphabet = "abcdefghijklmnopqrstuvwxyz".toCharArray();
[Code] ....
I'm trying to make a random password generator, but it isn't as random as I'd like it to be. I have set places where either a number, letter or symbol can go. I'd like to randomise the placement of these set types in the output from "symbol + letter + number + letter etc" to "? + ? + ?". Sample output from this code:
@W1L5m8%j4
^Y2L8z4@d1
£D6X5i3^i8
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Feb 5, 2015
Suppose I have private static void name() { ... } that has a two dimensional string array named array[. Now suppose I have private static void different() {...} and I want to write a condition where if (item == array) { ... }, how can I access my array from name() when I am in different()? I get a compile error saying cannot find symbol. My code is similar to:
Java Code:
public static void main(String[] args) {
...
String item = keyboard.nextLine();
... }
private static void name() {
...
String[][] array = new String[1][5];
[Code] .....
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Sep 10, 2014
In switch case statement string expression whether it will work or not ???
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Apr 8, 2014
I have a school assignment that involves me sorting an array of objects based on one of the class String variables. I am using as the title says a simple selection sort method. The problem I'm having is that when I run the program in debug mode, it never seems to enter the if statement in the inner loop. I would like to say I've tried a number of things to figure it out, but honestly I'm just stumped as to why it's not working.
Here is the code:
public static void sortTransactions(Transaction[] oTransaction){// This is the sorting method, obviously it's not done so it currently just prints to screen.
System.out.println("Successful call to sortTransaction()");
String min = "";
int curInd = 0;
Transaction[] temp = new Transaction[1];
[Code] ....
The output when I check to see if the array is sorted verifies that the array never does get sorted.
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Jan 17, 2015
I used the string split method in the following lines of code like this:
String[] numbers = out.split("[^d.]", 0);
String[] operations = out.split("[.d()]", 0);
When out is equal to the String "2x2.5", the array operations ends up looking like this when it is printed using the toString method:
[, , , x]
As you can see, before the array element x, there are three String variables which only contain whitespace. Why does this occur, and how can I prevent this from happening?
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Jun 6, 2014
Scanner sc = new Scanner(System.in);
String input = sc.nextLine();
if (input == "next") {
System.out.print("good Job!");
}
else {
System.out.println("Why ?");
}
//If I type in next it prints out "Why ?" instead of "Good Job!" - Why though ?
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Jul 17, 2014
I have an requirement of splitting a Date-Time String i.e. 2013/07/26 07:05:36 As you observe the above string has Date and Time with space in between them.
Now I want just want split the string not by delimiter but by length i.e. after 10th place and then assign it to 2 variable i.e. Date <----2013/07/26 and Time <---07:05:36 separately.
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Jun 19, 2014
So from what iv learnt in Java and programming in general is that using a case statement is far more efficient that using multiple IF statements. I have an multiple IF statements contained within a method of my program, and would like to instead use a case statement.
public String checkPasswordStrength(String passw) {
int strengthCount=0;
String strengthWord = "";
String[] partialRegexChecks = { ".*[a-z]+.*", // lower
".*[A-Z]+.*", // upper
".*[d]+.*", // digits
".*[@#$%!]+.*" // symbols
[code].....
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Nov 18, 2014
So I want to make a simple Java that ask the user to pick a powers and it has two options.If the user picks magic then execute the first if statement then ask the user again which type of magic the user wants.I can't make it work it keeps printing the else statement. Why is that?
import java.util.Scanner;
public class Variable {
static Scanner zcan = new Scanner(System.in);
public static void main(String[] args)
[code]....
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Apr 5, 2014
I'm trying to run an if statement with an input condition and here is my code.
import java.util.Scanner;
public class App10A {
public static void main(String[] args) {
Scanner fun = new Scanner(System.in);
System.out.println("What's your name?");
String name = fun.nextLine();
[code]....
When the computer asked me "What's your name?", I typed in Victor, then the result turned out to be "Oops, try again!".I typed in Victor (without parenthesis) and "Victor" and both gave me the negative results.What exactly should I put in in order to get "This is the result I wanted!" ? how should I modify my code in order to get "This is the result I wanted!" when I put in Victor (without changing the equal sign)?
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Mar 30, 2014
Let's get it out of the way -- I'm stumped. On something that should be pretty simple to solve. Code follows.
public class Sum {
public static void main(String [] args) {
Double nSum = 0.0;
Double aDouble = 100.0;
for (int i = 0; i < 1000; i++){
nSum += 0.1;
[Code] ....
The output:
100.000000
100.000000
false
false
false
false
false
Process finished with exit code 0
I wrote another simple program and hardcoded the values: aDouble = 100.0; bDouble= 100.0000
Using aDouble.equals(bDouble) returns true, just as one would expect.
So what am I overlooking?
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Feb 25, 2014
Having two values
<c:set var="var1" scope="view" value="#{ID1}"/>
<c:set var="var2" scope="view" value="${ID2}" />
I tried in <c:if test=${var1 == var2}>
and eq also
above condition is not working. Both are same object. How to check?
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Apr 8, 2014
New to java/programming and i cant understand why the pen variable does not display the the correct value ... For example for input 1 ; 2 ; 3 ; 4 both variables will display 10 and i dont understand why pen does not have the value 6 .
import acm.program.*;
public class Chap4_ex12 extends ConsoleProgram {
public void run () {
int pen = 0;
int r = 1;
int sum = 0;
while (r !=SANTINEL) {
r = readInt(" ? ");
pen=sum ;
[code].....
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Jan 21, 2015
Variables defined in interface are public static and final so I was thinking that we should not be able to override the variables in a class thats implementing the interface. But when I am compiling the below class, it compiles fine and gives the correct values. but when I did disp.abhi = 35; it gives a compile error (cannot override final variable)
interface display{
int abhi = 10;
void displayName();
[code]....
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Jun 24, 2014
This is my first time working with C++ and I have put together this program and came up with two errors and I am unsure what it is wanting me to do. The errors I got are:
1>c:usersownerdocumentsvisual studio 2010projectsweek5week5passing_by_value.cpp(30): error C2064: term does not evaluate to a function taking 1 arguments
1>c:usersownerdocumentsvisual studio 2010projectsweek5week5passing_by_value.cpp(38): error C2064: term does not evaluate to a function taking 1 arguments
#include<iostream>
using std::cin;
using std::cout;
using std::endl;
//initialize arrays
int incr10(int* numa,int* numb);
[Code] ....
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Apr 13, 2014
I am new in this programming language, java. I have a problem after I set my path ";C:Program Files (x86)Javajdk1.7.0_51in". I made a simple program but an error occurred. Here's the screenshot.....
Attached image(s)
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Sep 23, 2014
I continuously get an error for lines 34, 36, and 37 saying that the variables may not have been initialized.
import java.util.Scanner;
import java.util.Random;
public class MathTutor {
public static void main(String[] args) {
Random r = new Random ();
Scanner input = new Scanner (System.in);
/*int min=1;
int max=10;*/
int num1,num2,operation;
int n1= r.nextInt((9+1)+1);
int n2= r.nextInt((9+1)+1);
operation= r.nextInt(3);
int correctAnswer;
int userAnswer;
[code]....
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Feb 17, 2014
How do I use a variable in an if statement to return a public void method from another class? I've tried:
System.out.print("select 1 - 6: ");
Scanner myScanner = new Scanner(System.in);
myScanner.nextInt();
if (myScanner.nextInt()==1) {
carSelection colour = new carSelection();
colour.carSelection();
The method colour in class car selection is just 4 print line statements? I've // out the if statement to see if it is correctly calling the method and displaying the data and it is?
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May 5, 2014
I'm having a problem where an if statement isn't working. In the Person class boolean olderThan ignores my if statement so it always returns false and I just don't get why that's happening.
import java.util.Calendar;
public class Person {
private String name;
private MyDate birthday;
public Person(String name, int pp, int kk, int vv) {
this.name = name;
[code].....
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