I am trying to count the number of non_blank characters in a string. If there are no leading blank spaces it works fine but say i add three spaces in front it doubles the non blank characters.
import java.io.*;
import java.util.*;
public class countCharacters
{
public static void main(String[] args) throws Exception
{
String str1;
int count;
count = 0;
[Code] ....
I have an array with the following characters {'E', 'L','E','P','H','A','N','T','P','O'}
now, I need an array that will store the first array such that only the occurence occurs e.g {'E','L','P','H','A','N','T','O'} Notice that the characters 'E' and 'P' occur twice and as a result were not repeated the second time in the new array.
How would one go about this using the counting elements technique?
I tried this but not sure how to use the counting elements technique.
char [] arr = new char{'E', 'L','E','P','H','A','N','T','P','O'};
char[] bucket = new char[(arr[0] * arr.length)];
for (int i = 0; i < len; i++)
bucket[arr[i]]++;
Aeparated by blanks in a string. For simplicity, use strings without punctuation or other white space characters(tabs, newlines etc). Use a JTextArea to allow the user to enter the text and allow the text area to scroll if necessary. when the user clicks a button to count the words , the total number of words counted is displayed in a textbox that cannot be modified by the user.
now my problem is that i am not getting the counted number to display in the un-editable textbox. i also have the problem where the cusrsor is showing in the middle of the input screen instead of at the top.
import java.io.*;
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.text.*;
import java.util.*;
public class WordCounter extends JFrame implements ActionListener
[code]....
So I have 2 args[] one that reads the file name in the same directory and the other that tries to count how many of any letter (maybe even words) in the txt file ....
View Replies View RelatedI need to read the contents of file A, and B and store it in file C by joining the contents of A and B and also counting the number of letters/characters present in it.
I've come up with this so far.
import java.io.FileInputstream;
import java.io.FileNotFoundException;
import java.io.IOException;
public class JavaApplication43{
public static putwrite(string fname) throws FileNotFoundException, IOException
[code]...
I have been working on this for hours and cannot get it to work properly. The program is to count the number of characters contained in both strings and display the results. It is also to display the final statement, but only once. This version has a complete statement for each matching character.
import java.util.Scanner;
public class CountMatches {
public static void main(String[] args) {
String firstStr = ("");
String s1 = firstStr;
[Code] ....
I am currently trying to make a calculator in Java. I want to use the String split method to tokenize the string of characters inputted. I thought I was using the String split method wrongly, because I had surrounded the characters I wanted to delimit with square brackets. However, when I removed the square brackets, the code threw an exception when I pressed the equal button. The exception was a PatternSyntaxException exception. Am I using the String split method wrongly? And why is the exception thrown? Here is my code:
import javax.swing.*;//import the packages needed for gui
import java.awt.*;
import java.awt.event.*;
import java.util.Arrays;
import java.util.List;
import static java.lang.Math.*;
public class CalculatorCopy {
public static void main(String[] args) {
[Code] .....
I'm trying to loop through a string and depending on the character, add a JLabel to a game. The problem is the character 'L' represents a lantern but is also used in the reply the game gives which is "LOOKREPLY". I've tried to use some code to ignore the LOOKREPLY bit but it's not working. Here's what I've tried.
else if(message.charAt(i) == 'L' && message.charAt(i+1) != 'O' | message.charAt(i+1) == 'Y'){
JLabel localLabel = new JLabel();
localLabel.setIcon(lantern);
panel.add(localLabel);
panel.revalidate();
panel.repaint();
But the first image on all of the JLabels is always a lantern, which is what L represents. As it's only 1 lantern this leads me to believe that it's ignoring the first 'L' but for some reason it's not ignoring the 'L' at the end of LOOKREPLY.
how we can handle the string with special characters. For instance:
123456789BNJKNBJNBJKJKBNJKBJKNBJK"VJKNBJNHBJNJKBVJ KBJKNB"VHBVBBVNBVNBVBVBVBNBVNBNBJHFBVFJB FNVJBNVJNVJDFNVJKNVJKNVJKVNNVJ NN"
I get some user inputs with double quotes and i need to split to 80 chars line.
.length fails to get the length if it contains special characters like double quotes and ?
like i have String s="11222ddeefs"
so here i want program output like 1=2
2=3
d=2
e=2
f=1
and s=1
it has to show no of duplicates in each character in string
As of right now my code can take characters from a string to an array from a string like "ABCD" but the project says I have to take it from a string like "A B C D" how can I correct my code to grab the characters from a single spaced line?
Scanner sc = new Scanner(System.in);
System.out.println("Enter Order of Cars:");
String carsInput = sc.next();
int x = carsInput.length();
int[] cars = new int[x];
for (int i=0; i < cars.length; i++) {
cars[i] = carsInput.charAt(i)-64;
}
So what my program is supposed to do is take a number inputted by the use and then take a phrase. It then changes that phrases letter by the number inputted prior for example if you type in 2 as your int and Hello as your phrase you should get JGNNQ, which i can do. but the problem is that when i run it, it outputs like this:
J
G
N
N
Q
As separate characters how can I combine those characters in 1 string so it looks like JGNNQ? this is my code
import java.util.Scanner;
public class Dcod_MAin {
private static final Object[] String = null;
public static void main(String[] args){
Scanner input = new Scanner (System.in);
System.out.println("What is the day of the month");
int shift;
[Code] ....
I need to make a string filled with naughts and crosses like this one : "xxx ooo xox". There are 3 groups separated with a space. how to fill the string randomly ?
View Replies View RelatedI just need to write a simple program/function that replaces certain letters from a string (i.e. censor( "college", "aeiou" ) returns "cllg"). I'm trying to get the code right first, and then write a function for it.I basically just thought that I would iterate over the first string, and once I had the first character, I would then iterate over the second string, to see if the character exists. I'm getting a "dead code" error on my second loop because I put the second "break."
public class ap {
public static void main(String [] args){
String s = "Hello";
String s2 = "aeiou";
[code]....
I have to check a String input from the user in the form of firstName lastName (i.e. John Smith). I have to check for an exception called NonAlphabeticCharacterException that gets thrown if there is anything but a number in that string. This is what I have right now but should I create an array of char for the alphabet and then check the whole string for non alphabetic characters?
for(int i=0; i<name.length(); i++) {
if()){
throw new NonAlphabeticCharactersException("Non-alphabetic character found");
}
}
I am currently trying to count and display all the vowels in a set of given strings and can't seem to figure out what to do. I was able to print the line with the most vowels, but i also need to display them. The code is listed below and the given output.
public class Strings
{
public static void main(String[] args) {
String sentence = "I am currently studing Computer Science."
+ "My name is whatever and I am orginaially from the state of Virginia."
+ "I recenetly separated from the Air Force where I served on the Presidental Honor Guard.";
[Code] ....
The output that i am getting is:
I am currently studying Computer Science .
My name is whatever and I am originally from the state of Virginia.
I recently separated from the Air Force where I served on the Presidential Honor Guard.
The line with most vowels is:
I recently separated from the Air Force where I served on the Presidential Honor Guard.
I am trying to do a program that takes all of the chars from a string and orders them in alphabetical order. It works fine, but when a is a last letter of a string it isn't being sorted.
Example: bcba = bbca, omnibus = bimnous (here u is in wrong place)
Here is my code:
public class sorty{
public static void sort(char[] a, int low, int high){
int i = low;
int j = high;
if (j - i < 2) return;
int m = (j+i)/2;
char p = a[m];
[Code] .....
I am trying below challenge to display first three characters three times if the size of the string is greater than 3.
Say if i send hello i should get helhelhel
if i send xyz i should get xyzxyzxyz
I wrote as below
public String front3(String str) {
if(str.length()==3){
return str+str+str;
}
if(str.length()>3){
String str2=new String(new char[]{str.charAt(0),str.charAt(1),str.charAt(2)});
return str2;
}
}
I am getting error as below
Error:public String front3(String str) {
^^^^^^^^^^^^^^^^^^
This method must return a result of type String
Possible problem: the if-statement structure may theoretically allow a run to reach the end of the method without calling return. Consider adding a last line in the method return some_value; so a value is always returned.
In this simple example, I print a byte array to String:
Java Code:
import java.io.UnsupportedEncodingException;
import java.nio.charset.Charset;
public class PrintByteArray {
public void print(){
System.out.println(Charset.defaultCharset());
byte[] arr = {1, 2, 3, 4};
[Code] ....
However, Eclipse prints out strange boxes, which I was unable to copy into this message.
It's supposed to print out the values of the bytes. What am I doing wrong?
I am trying to change an input String to an array of characters, but it only stores the word before the space into the array. Here is the code:
Scanner scanner = new Scanner(System.in);
System.out.println(" Enter text: " );
String text = scanner.next();
char[] characterArray = text.toCharArray(); // convert string to array of characters
String char = "";
for( i = 0; i < characterArray.length; i++) {
char = char + characterArray[i]
} System.out.println(char);
Just typing hello gives me hello, but when I type hello world it does not type in the word "world".I am trying to change an input String to an array of characters, but it only stores the word before the space into the array.Here is the code:
Scanner scanner = new Scanner(System.in);
System.out.println(" Enter text: " );
String text = scanner.next();
char[] characterArray = text.toCharArray(); // convert string to array of characters
String char = "";
for( i = 0; i < characterArray.length; i++) {
char = char + characterArray[i]
} System.out.println(char);
Just typing hello gives me hello, but when I type hello world it does not type in the word "world".
I am looking for a way to create a method with the initial state in while loop, which will count the length of each word in a string using I want the output to be something along the lines of:
hello world how are you
There are 0 words of length 0
There are 0 words of length 1
There are 0 words of length 2
There are 3 words of length 3
There are 0 words of length 4
There are 2 words of length 5
This is my code so far it sort of does the job but not the way i want it too
import java.util.Scanner;
import java.util.StringTokenizer;
public class Brown_Matthew_13117002{
public static int count(String s, int len){
int result=0;
StringTokenizer st=new StringTokenizer(s,"[ ,;]");
[Code] ....
The output would end up being :
hello
There are 0 words of length 0
world
There are 0 words of length 1
how
There are 0 words of length 2
are
There are 3 words of length 3
you
There are 0 words of length 4
I am trying to count each char in a string. For example A = 1, B =2, C=3, I am not looking for their binary value. So the word "At" would
AT= (A=1 +T=20)=21.
I know how to do this in C++ because I am able to treat a string like an array.
Java Code: void printFile()
{
int sum=0;
String line;
for(char cr ='A';cr<'Z';cr++)
{
for(int i=0; i<myList.size();i++)
[Code]...
I am attempting to count the unique strings (a.k.a flowers) in the array along with a count of any duplicates. An example is embedded in my code below. I've only pasted the part of the program I am having trouble with. I can't figure out what I am doing incorrectly.
private void displayFlowers(String flowerPack[]) {
// TODO: Display only the unique flowers along with a count of any duplicates
/*
* For example it should say
[Code]....
I am looking for a way to create a method with the initial state in while loop, which will count the length of each word in a string using I want the output to be something along the lines of:
hello world how are you
There are 0 words of length 0
There are 0 words of length 1
There are 0 words of length 2
There are 3 words of length 3
There are 0 words of length 4
There are 2 words of length 5
ithis is my code so far it sort of does the job but not the way i want it too
import java.util.Scanner;
import java.util.StringTokenizer;
public class Brown_Matthew_13117002{
[Code].....
I was trying to create a java program which can remove the repeated characters in a String. For ex-
Input: kamehamehaaa
Output: kameh
Here is my code:-
import java.util.Scanner;
class replace {
public static void main (String args[]) {
Scanner br = new Scanner(System.in);
System.out.println("Enter a word");
[Code] ....
On executing the program, StringOutOfBoundsIndex error occurs.
I do have a quick question about string manipulation. You see I've been given a simple exercise that involves asking the user to input a number between 1,000 and 999,999 and displaying the result. Simple enough, but the caveat is that if the user keys in the comma, say 24,000 instead of 24000 for example, the program is not to display the comma. I don't see how to do this without an 'if' statement. The book says the 'if' is not necessary but does offer this hint: "Read the input as a string. Measure the length of the string. Suppose it contains n characters. Then extract the substrings consisting of the first n-4 characters and the last three characters."
What good is n-4 going to do if the string's lengths varies?
Here's what I have written thus far:
import java.util.Scanner;
public class P13
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.print("Please enter a number between 1,000 and 999,999: ");
[Code] .....