Using Count Element Method To Count Occurrence Of Characters In Array

Jun 30, 2014

I have an array with the following characters {'E', 'L','E','P','H','A','N','T','P','O'}

now, I need an array that will store the first array such that only the occurence occurs e.g {'E','L','P','H','A','N','T','O'} Notice that the characters 'E' and 'P' occur twice and as a result were not repeated the second time in the new array.

How would one go about this using the counting elements technique?

I tried this but not sure how to use the counting elements technique.

char [] arr = new char{'E', 'L','E','P','H','A','N','T','P','O'};
char[] bucket = new char[(arr[0] * arr.length)];
for (int i = 0; i < len; i++)
bucket[arr[i]]++;

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Count Occurrence Of Int In Array

Feb 28, 2014

(Count occurrence of numbers) Write a program that reads the integers between 1 and 100 and counts the occurrences of each. Assume the input ends with 0. Here is a sample run of the program:

Enter the integers between 1 and 100: 2 5 6 5 4 3 23 43 2 0
2 occurs 2 times
3 occurs 1 time
4 occurs 1 time
5 occurs 2 times
6 occurs 1 time
23 occurs 1 time
43 occurs 1 time

Note that if a number occurs more than one time, the plural word "times" is used in the output.

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import java.util.Scanner;
import java.io.File;
import java.io.IOException;
import java.io.BufferedReader;
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{
public static void main (String[] args) throws FileNotFoundException {
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[Code] ....

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import java.io.*;
import java.util.*;
public class countCharacters
{
public static void main(String[] args) throws Exception
{
String str1;
int count;
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I've come up with this so far.

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Apr 12, 2015

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I try:

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outerloop:
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[code]....

Output:

33
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This is what I've done so far :

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[Code] ....

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package domein;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.HashSet;
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