i have a service to save some form fields from the client and i need to add uploading image to that service using json. the service consumes json and produces json.
View RepliesI'm using json to submit form from web and mobile, I want to add uploading image feature to this form. How can I do that with code if possible?
View Replies View Relateddifference between webservice and service operation.
View Replies View RelatedPlease find below my JSON object ,how can we split
[
{"alpha2Code":"AF",
"alpha3Code":"AFG",
"altSpellings":"AF,Afganistan",
"area":652230.0,
"callingcode":"93",
"capital":"Kabul",
"currency":"AFN",
"gini":27.8,
[code]....
I need it should be split & Write Java code by JSONArray and JSONObject
I am new to web services and need to call a web service that has already been written. Below is the wsdl for the web service.I need to call the web service from my java program. provide the code to call the webservice?
<definitions targetNamespace="urnefaultNamespace">
<message name="CREATECONTACTUSResponse"></message>
<message name="CREATECONTACTUSRequest">
<part name="REQUESTTYPE" type="xsd:string"/>
<part name="SALESORG" type="xsd:string"/>
<part name="FIRSTNAME" type="xsd:string"/>
<part name="LASTNAME" type="xsd:string"/>
<part name="EMAILADDRESS" type="xsd:string"/>
<part name="TELEPHONENUMBER" type="xsd:string"/>
<part name="EXTENSION" type="xsd:string"/>
[code]....
URL....my file name can contain special characters but when I passing this file name as a parameter in URL using REST.I am getting exception.
View Replies View RelatedI am facing below problem while i am connecting with any services through(MashUp API).I am using below Jars
i)commons-logging-1.1.3.jar
ii)httpasyncclient-4.0-beta4.jar
iii)httpclient-4.3.6.jar
iv)httpcore-4.3.3.jar
v)httpcore-nio-4.1-beta2.jar
vi)httpmime-4.3.6.jar
vii)unirest-java-1.3.27.jar
Code:
public static void main(String[] args) throws UnirestException {
HttpResponse<InputStream> response = Unirest.post("https://ofc.p.mashape.com/directConvert/")
.header("X-Mashape-Key", "Y3MxEWkOX3mshcvQ85SZCoIqucVMp1qRpjbjsn0TYnnY8c1fIR")
.field("file", new File("<file goes here>"))
.field("format", "woff")
.field("output", "tar.gz")
.asBinary();
[code]....
i'm sending soap request but i'm getting html response it is leading to crash! how to parse html response?
View Replies View RelatedI am trying to hit the service which has been generated using apache cxf 3.0, I have generated the client using axis2 wsdl2java and whenever I tried to hit the service am getting as
"exception from OLB Service:org.xml.sax.SAXParseException: Content is not allowed in prolog."
Not sure about the cause of the issue. We have made interceptors on the server side to verify whether there is any special characters associated, but there are no such characters from provider.
I want to write one REST client program for POST request ,request and response is in JSON Format.
public String getAck() {
HttpURLConnection httpConnection = null;
URL url=null;
try {
url = new URL("http://test:8080/ils/main");
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
[Code]....
Line OutputStream os = httpConnection.getOutputStream();
I am getting connection time out problem
I have written a program in JAVA which fetches an image from MYSql Database. I get a BLOB object then I am trying to convert that BLOB object to string; again I am using that object to write the image to a file. the image file is getting created in E: but it does display any image
stmt = con.createStatement();
File imgfile = new File("E:
ew_red_phone1.jpg");
ResultSet RS=null;
Blob ProductPicture=null;
RS=stmt.executeQuery(Query);
while(RS.next())
[code]....
I would like to know what is the best way to upload & download files using Servlets/Jsp's . In some websites I have seen example using third party API(by oreilly). Is it better to follow any third party or can we do it just by using I/O streams. What are the steps of uploading files. And where do we need to store files once the user uploads ,Database or server??
View Replies View RelatedI want to create a simple ftp server which can upload and download a single file. i found code from google search but its showing error : connection refused . here is my server code n client code.
//server code
[highlight = java]
import java.io.*;
import java.net.*;
[Code].....
Is there a way to reload the page after uploading the files with the command
<p:fileUpload value="#{excursion_type.main_photo}" mode="advanced" allowTypes="/(.|/)(gif|jpe?g|png)$/" auto="false"
fileUploadListener="#{excursion_type.uploadMultiple}" update="msg" />
Cause the user does not see the lattest photos after uploading need to do reload to see them cause ajax request.
I am developing an inhouse project in my organization. I unable to implement the pdf uploading, downloading, report generation logic as i am totally new to this implementation.
View Replies View RelatedI have a template file which I'm tring to upload into a database using setBlob or setBinaryStream but I'm getting the following error:
java.lang.AbstractMethodError: setBlob
at weblogic.jdbc.wrapper.PreparedStatement.setBlob(PreparedStatement.java:1005)
at com.capitalone.citrix.ssp.dao.KatetDaoImpl.uploadReport(KatetDaoImpl.java:1697)
at com.capitalone.citrix.ssp.services.FileOpsImpl.generateDownload(FileOpsImpl.java:648)
at com.capitalone.citrix.ssp.controller.JSONController.display(JSONController.java:61)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
[Code] .....
I'm using :
Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
Weblogic Server Versions: 10.3.0.0 with Java 1.6.0_05
The driver class name for the weblogic datasource: weblogic.jdbcx.oracle.OracleDataSource
Initially, I tried:
sqlQuery = new StringBuffer();
ps = null;
sqlQuery.append("insert into KATET_REPORTS (FILE_DATA)");
[Code] ....
This failed, so I changed ps.setBlob(1,is)
to
ps.setBinaryStream(1,is). This failed as well with teh same error, just for setBinaryStream instead of setBlob.
Is there a known inconsistency between that driver and this Weblogic version? Is there something else going on? If I haven't given enough data to debug the issue here, what other data should I gather?
My requirement is - I need to browse the folder and select multiples and upload all the selected files at once. note that here i need to use single browse button ONLY.
View Replies View RelatedI am learning how to program in JAVA servlet+MySQL. Decided to make a simple program where it shows who is celebrating birthday today by retrieving data from database. At the moment I managed to get it working by loading a form.html and pressing the button in it which gets to the result.jsp and shows results there.
My plan was to get a list of people who are celebrating there birthdays initially when the website is loaded/being loaded, I mean when you enter URL into your web browser and you get it instantly in browser. Is there a way to do it the way I want (JAVA+servlet+MySQL) instead of pressing a button/link?
I have JSON which as response from third party server,i call the URL and i want to print in browser as json but it is not display browser also display well in console i post my code here
URL url = new URL ("http://api.rottentomatoes.com/api/public/v1.0/movies/770672122.json?apikey=qpdtfwugwbxt32awk8jvwcdq");
URLConnection uconn = url.openConnection();
BufferedReader in = new BufferedReader(new InputStreamReader(uconn.getInputStream()));
String line=null;
while ((line = in.readLine()) != null) {
System.out.println(line); }
output in browser
============
The XML page cannot be displayed / Cannot view XML input using style sheet. correct the error and then click the Refresh button, or try again later.
XML document must have a top level element. Error processing resource '[URL] ......'. and also The XML page cannot be displayed Cannot view XML input using style sheet. Please correct the error and then click the Refresh button, or try again later.
A semi colon character was expected. Error processing resource '[URL] ....'. Line 10, Posi...
"canonicalUrl": "/v1/products?format=json&apiKey=9uvqqsjvwxc4c4ferw922k7k",
like error showing
output in console:
{"total":19,"movies":[{"id":"771312513","title":"Captain America: The Winter Soldier","year":2014,"mpaa_rating":"PG-13","runtime":136,"critics_consensus":"Suspenseful and politically astute, Captain America: The Winter Soldier is a superior entry in the Avengers canon and is sure to thrill Marvel diehards.","release_dates":{"theater":"2014-04-04"},"ratings":{"critics_rating":"Certified Fresh","critics_score":94,"audience_score":99},"synopsis":"Steve Rogers continues his journey as the super-powered American soldier who's grasping to find his place in a modern world after being frozen in ice....
I am trying to learn how to parse a Json with java. So I have this code
import java.net.*;
import java.io.*;
public class test2 {
public static void main(String[] args) throws Exception {
[Code] .....
and it has this output
{
"response": {
"version":"0.1",
"termsofService":"http://www.wunderground.com/weather/api/d/terms.html",
"features": {
"conditions": 1
[code]...
How do I turn this information into java objects?
So I would like to get information out of a web-API. But my question is how I do this. I guess I need to read the URL first. And parse it after but what is the best way?
For example : [URL] .....
I would like some clarification on a project I am working on. I need to build a java application to query a xml and json file. I have started by parsing both documents and I am unsure if I am doing the next steps correct. I was thinking about dropping the txt file with both outcomes into a db and doing it that way, is this the right way or is there a better and more efficient way of doing things ?
View Replies View Related@RequestMapping(value = { "/mapping" }, method = RequestMethod.GET)
@ResponseBody
public Map<A, List<B>> getAsByB(HttpServletRequest httpRequest) {
return map;
}
when i try to get it by url i get an error. how can i send a response of a map as a json ?
I have a JSON string
Java Code: {
"AvailableDeliveries": {
"500": {
[Code]....
Number of JSON object can vary. I tried to generate POJO from jsonschema2pojo but it generate fix number of object inside AvailableDeliveries class. How I can define a POJO with collection of object and map corresponding field for above JSON string. I can't change the structure of JSON response as I am consuming the string.
Create Json from a List's data
View Replies View RelatedI want to read and write json to/from a file. I read the following document:
JsonReader (Java(TM) EE 7 Specification APIs)
I try to define a JsonReader object in Eclipse:
JsonReader jr
But there appears to be no import for it. Where I am supposed to get the Json library?