Wrong Version Appearing For Java Command

Sep 8, 2011

I am a novice to coding and very new to Java. It appears that I am having a similar problem as the user above "Scott Allen". With a few exceptions. My issue is that when I run the command "javac" from the command prompt I am receiving the same error:- "javac is not recognized as an internal or external command, operable program or batch file"

After reading the comments from above I have configured my System Variables "Path" and "JAVA_HOME" to match the following:
JAVA_HOME: C:Program FilesJavajdk1.6.0_21in
Path: %JAVA_HOME%in; [First Variable]

There is no "Path" User variable on my computer, although there is a "TEMP" and "TMP" in the User Environment variables.

Currently I have the following Java related software installed:
- C:Program FilesJavajre6
- C:Program FilesJavajdk1.6.0_21
- C:Program FilesSunJavaDB
- C:Program FilesEclipse-jee-galileo-3.5.2

I have confirmed the "javac.exe" is located within the in directory of Javajdk.1.6.0_21..When I send "Java -version" to the command prompt the following is returned: java version "1.6.0_26"..Immediately I noticed that the version is wrong, but don't know why or what to do. Below is the output from the command "Java" using the command prompt.

Usage: java [-options] class [args...]
(to execute a class)
or java [-options] -jar jarfile [args...]
(to execute a jar file)

where options include:

-client to select the "client" VM
-server to select the "server" VM
-hotspot is a synonym for the "client" VM [deprecated]
The default VM is client.

[code]....

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