Byte Array To String Gives Strange Characters
Jun 30, 2014
In this simple example, I print a byte array to String:
Java Code:
import java.io.UnsupportedEncodingException;
import java.nio.charset.Charset;
public class PrintByteArray {
public void print(){
System.out.println(Charset.defaultCharset());
byte[] arr = {1, 2, 3, 4};
[Code] ....
However, Eclipse prints out strange boxes, which I was unable to copy into this message.
It's supposed to print out the values of the bytes. What am I doing wrong?
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Oct 17, 2014
As of right now my code can take characters from a string to an array from a string like "ABCD" but the project says I have to take it from a string like "A B C D" how can I correct my code to grab the characters from a single spaced line?
Scanner sc = new Scanner(System.in);
System.out.println("Enter Order of Cars:");
String carsInput = sc.next();
int x = carsInput.length();
int[] cars = new int[x];
for (int i=0; i < cars.length; i++) {
cars[i] = carsInput.charAt(i)-64;
}
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Dec 11, 2014
I am trying to change an input String to an array of characters, but it only stores the word before the space into the array. Here is the code:
Scanner scanner = new Scanner(System.in);
System.out.println(" Enter text: " );
String text = scanner.next();
char[] characterArray = text.toCharArray(); // convert string to array of characters
String char = "";
for( i = 0; i < characterArray.length; i++) {
char = char + characterArray[i]
} System.out.println(char);
Just typing hello gives me hello, but when I type hello world it does not type in the word "world".I am trying to change an input String to an array of characters, but it only stores the word before the space into the array.Here is the code:
Scanner scanner = new Scanner(System.in);
System.out.println(" Enter text: " );
String text = scanner.next();
char[] characterArray = text.toCharArray(); // convert string to array of characters
String char = "";
for( i = 0; i < characterArray.length; i++) {
char = char + characterArray[i]
} System.out.println(char);
Just typing hello gives me hello, but when I type hello world it does not type in the word "world".
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Apr 1, 2014
I am getting byte stream as below. These looks like UTF 8 bytes
3C524F4F543E3C535452494E473E54455354204F4E4C5920535452494E473C2F535452494E473E3C2F524F4F543E
I want java code which will convert above bytes to string as shown below
<ROOT><STRING>TEST ONLY STRING</STRING></ROOT>
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Sep 27, 2014
I am currently trying to make a calculator in Java. I want to use the String split method to tokenize the string of characters inputted. I thought I was using the String split method wrongly, because I had surrounded the characters I wanted to delimit with square brackets. However, when I removed the square brackets, the code threw an exception when I pressed the equal button. The exception was a PatternSyntaxException exception. Am I using the String split method wrongly? And why is the exception thrown? Here is my code:
import javax.swing.*;//import the packages needed for gui
import java.awt.*;
import java.awt.event.*;
import java.util.Arrays;
import java.util.List;
import static java.lang.Math.*;
public class CalculatorCopy {
public static void main(String[] args) {
[Code] .....
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Mar 30, 2015
I am new to Android. I have byte array of size 10. I am passing the Decimal values (131 - 140) to byte array. But while printing I get Negative (-) values with decreasing order .
How can I get same value as positive values?
Or How can I store positive value e.g. 131 as byte array element.
Please not my requirement is array must be ByteArray only
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Apr 27, 2015
I have a checksum function that is suppose to read IPV4 packet and return a short integer value. The IPV4 packets are stored in a byte array. I am having trouble storing the first 8 bits and second 8 bits of the short integer into the byte arrays especially when they have leading 1s. For example, if my checksum returns 5571 (binary = 0001 0101 1100 0011) The first 8 bits is suppose to represent 195 but when I try to assign a larger integer type to a btye the information gets sign extended. The 195 turns into -61. I tried using bit addition like array[10] = array[10] & 0xff, but the result remains the same.
public static short checksum(byte [] a, int length) {
short sum = 0;
long data;
int i = 0;
while(length > 1) {
data = (((a[i] << 8) & 0xff00) | ((a[i + 1]) & 0xff));
sum += data;
[code]....
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Apr 30, 2014
i have I byte array ,That I was getting from the gps packets , I need to convert that into jpg file
public static void writejpegfile(byte[] someByteArray) throws FileNotFoundException, IOException {
FileOutputStream fos = new FileOutputStream("image" + new Date().getTime() + ".jpg")
try {
[Code]....
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Mar 2, 2014
I am trying to write a byte array to a blob field in my database.
Below code is not working for me because the object is actually 902 bytes, however, the database tells me that it is 11 bytes once committed.
How to write to the blob field in my database?
Java Code:
protected void addFingerprint(byte[] fingerprintBytes) {
Statement stat;
try
{
updateQuery = "UPDATE " + currentTable + " SET CLERK_FINGERPRINT_DATA_BLOB = '"
[Code] ....
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Feb 20, 2014
I just wrote a small but working code to parse a multipart message with two files binary encoded.
Problem is, after splitting the content of the files is reduced to normal "alphabetic" digits, and i dont know why.
I just appended my source code and a test file ( multipart ). And the result of my parsing. (part_0 = json, part_1 = file, part_2 = file)
Unfortunately, i dont know, if the Spring FW provides an easier way of doing so at all. Haven't found it yet.
Java Code:
String requestUrl = "http://localhost:8888/";
RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(new ByteArrayHttpMessageConverter());
HttpEntity<String> entity = new HttpEntity<String>("test");
ResponseEntity<byte[]> response = restTemplate.exchange(requestUrl, HttpMethod.GET, entity, byte[].class);
[Code] .....
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Feb 11, 2014
I and a friend are working with a project to create a file system, who manages a secondary memory simulated as a byte array in Java. We want the file system to be a hierarchical tree structure like in UNIX.
We have come quite far, but the paths are not handled correct. I seem to have mistaken the relative folder ./ for the root folder, but it should mean "working directory folder", ie, where I stand now. That is, if I stand in /dir1 as my "working directory" and make mkdir ./dir2 then should dir2 end up as subfolder in dir1. But with me it appears in the root.
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Feb 13, 2014
I have double checked this code over and over and I just can't find the problem.
What I'm trying to do is take a file and input it into an 2D array.
Ultimately, I should convert the array of integers to an array of characters, then print it out. The file contains a set of ASCII values.
After printing it out, I should then create methods to manipulate the image produced.
Using 2D arrays is a requirement for this exercise.
I think that somehow I'm overcomplicating this and the solution is a lot more simple than I think, but I can't think of what to change.
The error I am getting is:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 40
at main.main(main.java:17)
Java Code:
import java.util.*;
import java.io.*;
public class main {
public static void main(String[] args)
throws FileNotFoundException {
String[][] data = new String[22][40];
[Code] .....
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Apr 5, 2014
I'm trying to loop through a string and depending on the character, add a JLabel to a game. The problem is the character 'L' represents a lantern but is also used in the reply the game gives which is "LOOKREPLY". I've tried to use some code to ignore the LOOKREPLY bit but it's not working. Here's what I've tried.
else if(message.charAt(i) == 'L' && message.charAt(i+1) != 'O' | message.charAt(i+1) == 'Y'){
JLabel localLabel = new JLabel();
localLabel.setIcon(lantern);
panel.add(localLabel);
panel.revalidate();
panel.repaint();
But the first image on all of the JLabels is always a lantern, which is what L represents. As it's only 1 lantern this leads me to believe that it's ignoring the first 'L' but for some reason it's not ignoring the 'L' at the end of LOOKREPLY.
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Sep 16, 2014
how we can handle the string with special characters. For instance:
123456789BNJKNBJNBJKJKBNJKBJKNBJK"VJKNBJNHBJNJKBVJ KBJKNB"VHBVBBVNBVNBVBVBVBNBVNBNBJHFBVFJB FNVJBNVJNVJDFNVJKNVJKNVJKVNNVJ NN"
I get some user inputs with double quotes and i need to split to 80 chars line.
.length fails to get the length if it contains special characters like double quotes and ?
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Apr 8, 2014
like i have String s="11222ddeefs"
so here i want program output like 1=2
2=3
d=2
e=2
f=1
and s=1
it has to show no of duplicates in each character in string
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Sep 10, 2014
So what my program is supposed to do is take a number inputted by the use and then take a phrase. It then changes that phrases letter by the number inputted prior for example if you type in 2 as your int and Hello as your phrase you should get JGNNQ, which i can do. but the problem is that when i run it, it outputs like this:
J
G
N
N
Q
As separate characters how can I combine those characters in 1 string so it looks like JGNNQ? this is my code
import java.util.Scanner;
public class Dcod_MAin {
private static final Object[] String = null;
public static void main(String[] args){
Scanner input = new Scanner (System.in);
System.out.println("What is the day of the month");
int shift;
[Code] ....
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Jul 5, 2014
I need to make a string filled with naughts and crosses like this one : "xxx ooo xox". There are 3 groups separated with a space. how to fill the string randomly ?
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May 7, 2014
I just need to write a simple program/function that replaces certain letters from a string (i.e. censor( "college", "aeiou" ) returns "cllg"). I'm trying to get the code right first, and then write a function for it.I basically just thought that I would iterate over the first string, and once I had the first character, I would then iterate over the second string, to see if the character exists. I'm getting a "dead code" error on my second loop because I put the second "break."
public class ap {
public static void main(String [] args){
String s = "Hello";
String s2 = "aeiou";
[code]....
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Oct 2, 2014
I have to check a String input from the user in the form of firstName lastName (i.e. John Smith). I have to check for an exception called NonAlphabeticCharacterException that gets thrown if there is anything but a number in that string. This is what I have right now but should I create an array of char for the alphabet and then check the whole string for non alphabetic characters?
for(int i=0; i<name.length(); i++) {
if()){
throw new NonAlphabeticCharactersException("Non-alphabetic character found");
}
}
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Nov 4, 2014
I am trying to count the number of non_blank characters in a string. If there are no leading blank spaces it works fine but say i add three spaces in front it doubles the non blank characters.
import java.io.*;
import java.util.*;
public class countCharacters
{
public static void main(String[] args) throws Exception
{
String str1;
int count;
count = 0;
[Code] ....
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Oct 1, 2014
I am trying to do a program that takes all of the chars from a string and orders them in alphabetical order. It works fine, but when a is a last letter of a string it isn't being sorted.
Example: bcba = bbca, omnibus = bimnous (here u is in wrong place)
Here is my code:
public class sorty{
public static void sort(char[] a, int low, int high){
int i = low;
int j = high;
if (j - i < 2) return;
int m = (j+i)/2;
char p = a[m];
[Code] .....
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Sep 26, 2014
I am trying below challenge to display first three characters three times if the size of the string is greater than 3.
Say if i send hello i should get helhelhel
if i send xyz i should get xyzxyzxyz
I wrote as below
public String front3(String str) {
if(str.length()==3){
return str+str+str;
}
if(str.length()>3){
String str2=new String(new char[]{str.charAt(0),str.charAt(1),str.charAt(2)});
return str2;
}
}
I am getting error as below
Error:public String front3(String str) {
^^^^^^^^^^^^^^^^^^
This method must return a result of type String
Possible problem: the if-statement structure may theoretically allow a run to reach the end of the method without calling return. Consider adding a last line in the method return some_value; so a value is always returned.
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Jan 27, 2015
I was trying to create a java program which can remove the repeated characters in a String. For ex-
Input: kamehamehaaa
Output: kameh
Here is my code:-
import java.util.Scanner;
class replace {
public static void main (String args[]) {
Scanner br = new Scanner(System.in);
System.out.println("Enter a word");
[Code] ....
On executing the program, StringOutOfBoundsIndex error occurs.
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Feb 18, 2014
I do have a quick question about string manipulation. You see I've been given a simple exercise that involves asking the user to input a number between 1,000 and 999,999 and displaying the result. Simple enough, but the caveat is that if the user keys in the comma, say 24,000 instead of 24000 for example, the program is not to display the comma. I don't see how to do this without an 'if' statement. The book says the 'if' is not necessary but does offer this hint: "Read the input as a string. Measure the length of the string. Suppose it contains n characters. Then extract the substrings consisting of the first n-4 characters and the last three characters."
What good is n-4 going to do if the string's lengths varies?
Here's what I have written thus far:
import java.util.Scanner;
public class P13
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.print("Please enter a number between 1,000 and 999,999: ");
[Code] .....
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Jul 3, 2014
I'm attempting a small program as I'm teaching myself the ropes. In it, I need to compare one string (the base) to another which is just the base string that's had it's characters shuffled.
Java Code:
String base = "ABCDEFG"
String shuffled = "CDAFBEG" mh_sh_highlight_all('java');
What I need to do is run a loop that shuffles the base string each time, but compares and saves any characters that match in the correct location. For example, if shuffled = "CDAFBEG", then the G would be "locked" in place and the rest of the characters shuffled and looped back to the comparison.
I have all the code I need for shuffling the string, but I'm not sure how I would go about comparing each character and then also locking it in place. I get the basics, I think, of needed to use several variables.
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Mar 7, 2014
Is that the only way to code the JOptionPane? Seems rather similar to Sys.out
--- Update ---
I had more than this, but post was deleted somehow and this was the gist of it:
for(i = 0 ; i < charArray.length; i++){
if(Character.isDigit(charArray(i))){
address.replace("6", "*");
address.replace("7", "*");
Is there a better way to scan a character array for digits and replace any number in the array with another character ("*") in this case? The array is the address, " 1234 Runner Road " .
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