I need to be able to select a file (compressed), change its file extension (to zip) and load all its content, preferably as objects. If it makes things easier one can assume all these files to be of the same type.
The content of the zip file are placed in folders, known Beforehand which might make things easier.
I am trying to write a webservice class which actually handles multipart requests. T client will try to upload zip or tar.gz files which may be upto 1GB in size.
I dont want to validate the extension i client side.
I want to validate the file extension in server side and discard the request before the file is uploaded.
I want to programmatically change the default program which an extension is opened in. So .resantic extensions for example to run in my jar file when I double-click on it. I know i need a bat file or exe file because i can't directly run the jar file. But i was wondering if its possible to run it if its an executable jar file. Else i can just make a bat file that runs my program. Also how can i on double click send the path to the file that was clicked in the args[] array so i can open the actual file aswell instead of just opening the program?
I had to change context path name of my web application due to some organizational shuffle. I have successfully changed it and it has been working fine.
But what is happening is we have used old context path name in reminder and notification emails. so When users hit links from old emails, they are getting 404 Error.
Is there any way to redirect the old request which has old context path to new one?
This is a part of my program. When the user enters "Exam Schedule" in the JtextField and clicks the add button I want the link to change to a link that opens a local pdf file. And if the user enters "Academic Calendar" the Jlabel will be set to another link. So far this works fine but the problem is that if you erase the textfield and enter another value the link of the previous value will still be there.
public void actionPerformed (ActionEvent e){ if (e.getSource ==add) { if (text.getText().equalsIgnoreCase("Exam Schedule")){ link1.setText(text.getText()); link1.setCursor(Cursor.getPredefinedCursor(Cursor.HAND_CURSOR));
This is a part of my program. When the user enters "Exam Schedule" in the JtextField and clicks the add button I want the link to change to a link that opens a local pdf file. And if the user enters "Academic Calendar" the Jlabel will be set to another link. So far this works fine but the problem is that if you erase the textfield and enter another value the link of the previous value will still be there.
public void actionPerformed (ActionEvent e){ if (e.getSource ==add) { if (text.getText().equalsIgnoreCase("Exam Schedule")){ link1.setText(text.getText()); link1.setCursor(Cursor.getPredefinedCursor(Cursor.HAND_CURSOR));
I have a program that allows the user to select what type (i.e. tif, jpg, sid) of file they have to load. I use a JCombo box for the selection type. I send this JCombo box string to my ElevationConvert class. What I want to do is check to see if that extension the user selected exists prior to converting it. If the file extension does not exist, I want to pop up a window (JOptionPane) stating is does not exit. I have tried suggestions found on this site, but does not seem to work for my application. The program works with (Process cN = Runtime), if I try not to check for the extension. But when I add the check for (If, else), it bombs. This executable runs in the main folder. The file extensions are in a subfolder called Ned.
/* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the editor. */ package terraindbbuilder1;
i want to find an embedded file extension i.e suppose if word file is there in that excel is also included then is should detect both file types word n excel and is is it possible to find an embedded file type.
I am currently working on an application with java and I want to do is upload and download details in .xlsx file. Uploading process is successfully worked but the problem is that when I download the file .xlsx with details at opening the file it gives me the following message :
Excel cannot open the file '(filename)'.xlsx' because the file format or file extension is not valid. Verify that the file has not been corrupted and that the file extension matches the format of the file.
I'm trying to make a search engine that will search my computer given a path with any options i decide. So if i decides to look for the file name "resume" with extension "pdf", it will give me the files in the directory, including subfiles.
import java.io.*; import java.util.*; import java.text.*; public class mySearch { private final static int path = 0; private final static int name = 1;
In my web application i want to upload file to drop-box. I am getting file name from browser.Is it possible to upload file to drop-box with only file name.
I am facing a problem while executing a task. My task is to make such a code which will search for my source code file (abc.java) in all directories and then displays the code in textarea inside frame and along with that i also have to display the path of the file in text field. I have coded something but i am really not getting anywhere near my task.
filePath = file.getAbsolutePath(); file = new File(filePath); streamResult = new StreamResult(file);
But it also didn't work. There I got message seems like: "Can't find resource /User/user1/Desktop/program1/resources/file.xml" - but that's really absolute path to a file.
I also made unit test which completed with "green light", but in jar its wrong with message "Can't find resource /User/user1/Desktop/program1/resources/file.xm" ....
First of all, i am using ubuntu and jdk8. My problem: displaying the current path of a file in my system Approach: I have a file called dummy.txt in a given directory which have enough permissions and i did the following:
I expected to see displayed the current path of the file without the name of the file but it is showing a different path. I just want to display the current path of the file without the name.
I already done my program with images on it but when i convert it to exe , the images is not appearing.
Usually my images are located at documents netbeansprojectprojectimage.jpg
When i run the code on netbeans the images are appearing but when i convert it to exe or jar file run on a computer without netbeans.. images is not appearing ...
As you can see I have specified a file path, as it is needed to draw the image.
The image "sun" is in a certain folder inside the directory of my jar file.
But If I were to send the whole package to my teacher to review. The file path would still remain the same, local to my computer making the image, unloadable.?
I am making a ui in which i have a JTextfield and a JButton(run). I am reading values to JTextField from text file and on pressing Jbutton a Batch file runs. Now when i press the Jbutton the batch file runs showing number running, in place of number running, i want to display the JTextfield value. So i want in place of number running it should display JTextfield value running. How can i achieve it.
I'm using jsf 2 to upload file, first I upload the file in a system directory, then trying to store the path to database with other information, my stuck is that when submitting I upload the file successfully, find it in the right place, find the other information such as description, file name ... in database but don't find the path. this is my managed bean :
I am copying the xml files from one folder to other folder, in the source folder, i have some files which have some content like "backing File="$IDP_ ROOT/metadata/iPAU-SP-metadata.xml" but while writing to the destination folder.i am replacing the "$IDP_ROOT" with my current working directory. The entire copying of files is for deploying into tomcat server. The copying is done only when server starts for the first time.Problem: If i change the folder name from my root path in my machine after i run the server,the entire process will be stopped because the destination folder files already contains the content which is with existed files names or folder names.
So i want to change it to relative path instead absolute path. What is the best way to do it? Please look at code below:
[ // Getting the current working directory String currentdir = new File(".").getAbsoluteFile().getParent() + File.separator;
I need to write the exact directory path like C:LisaestUpdate to a properties file.
I am trying it by
FileInputStream in = new FileInputStream(test.properties); Properties props = new Properties(); props.load(in); in.close(); FileOutputStream out = new FileOutputStream(newprop.properties); props.setProperty("myDirectory","C:Lisa estUpdate" ); props.store(out, null); out.close();
but the properties file is updated as C:Lisa estUpdate
Extra comes before :.
How can I remove that.
Even I tried it with an command but got same output.
I'm a Java beginner and I've been trying to scan a file using the Java Scanner. I've tried searching online for this error and I only find people's questions who have entered an incorrect relative path. I'm entering in an absolute path and I'm using Eclipse Standard Edition on a 2013 MacBook Pro with Mavericks 10.9.2.
Anyway, the error message I'm receiving on Eclipse is: Exception in thread "main" java.lang.Error: Unresolved compilation problem: Unhandled exception type FileNotFoundException
at App.main(App.java:12) public class App { public static void main(String[] args){ String fileName = "/Users/Student/Documents/index.html";
[code]...
Why it cannot find this file. I've checked the absolute file path of index.html on my Mac and I've copied and pasted it into my code.
currently I am doing my java web application project ,and it has following steps 1) Upload the txt files 2) java servlet gets the txt file's url , read the data and do the calculation 3) pass the results
I almost finished the second step , and working on the first step .Since there are so many input files at a given time , i have to use drag and drop method to get the file's location.how to pass file's path to servlet.( servlet code can read the data from the given txt file path )software used - tomcat and netbeans 8.0
I'm using a PrimeFaces UploadedFile xhtml page to select a csv file to read and write using a managed bean (SuperCSVParser.java). The file is read and written to an entity class which then persists the data to a database. The application works fine if I specify a file path on the physical server and select a csv file on that file path. But for the production version I want the user to select ANY file name from ANY directory on their local system.
I know about the FacesContext methods and I've looked at some methods from the java.io File class. Most of these methods are about getting the path from the server, where I want to 'pass' the path String from the client machine to allow the uploaded file to go through. When I try with the below code I get:
java.io.FileNotFoundException: data.csv (The system cannot find the file specified)
I'd like to know what I'm doing as I prefer not to explicitly declare a path in the final app. I'm almost sure that's possible.
