Coordinates Are Inside Of A Right Triangle On Imaginary Coordinate Plane
May 24, 2014
I'm having a random x and y coordinate generate and I need to check if the coordinates are inside of a right triangle on this imaginary coordinate plane.
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Oct 29, 2014
A triangle is defined by the x- and y- coordinates of its three corner points. Compute the following the following properties of a given triangle: the lengths of all sides, the angles at all corners, the perimeter and the area. The program must prompt a user for the point coordinates. I have created a class Triangle and a class TriangleSimulator, I am stuck and can't figure out why my program won't run correctly.
import java.util.Scanner;
public class Triangle {
Scanner in = new Scanner(System.in);
private int x1;
private int x2;
private int x3;
[Code] ....
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Oct 3, 2014
I am working on a program that asks me to track the position of an imaginary ball as it bounces around an imaginary box. The user gives me input for the starting position of the ball (x,y), the bottom-left boundaries of the box (xl, yl), the top right boundaries (xr, yr) and the angle. The program then needs to find where the ball will hit the box, and then print that location and find the new angle for the next point. My program currently works in most cases if the angle is less than pi.
Here is my code
public class BouncyBall {
public static void main(String args[]){
if (args.length != 8) {
System.out.println("Error: usage is X, Y, Angle, Xl, Yl, Xr, Yr,N");
System.exit(1);
}
double x,y,xl,yl,xr,yr,angle;
int n;
x=Double.parseDouble(args[0]);
y=Double.parseDouble(args[1]);
[Code] .....
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Nov 13, 2014
Write a program to simulate this airport's operation. You might assume a simulated clock that advances in one-minute intervals. For each minute, generate two random numbers: If the first in less than LandingTime /60, a "landing arrival" has occurred and is added to the landing queue, and if the second is less than TakeOffTime /60, a "takeoff arrival" has occurred and is added to the takeoff queue.
Next, check whether the runway is free. If it is, first check whether the landing queue is nonempty, and if so, allow the first plane to land; otherwise, consider the takeoff queue. Have the program calculate the average queue length and the average time that an airplane spends in a queue.
I have most of the code done as you can see below:
* Queue Interface: Queue.java
* Queue Implementation: ArrayQueue.java
* Demo Program: Airport.java
Right now, I am stuck on the first calculation which is trying to figure out the average size of the landing queue. For some reason, as you can see at the bottom of my demo program, the average always comes out to be 0.0 and I'm not sure what's wrong.
Secondly, how to calculate the average time a plane stays inside a queue for.
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Dec 28, 2014
I'm doing a problem where the area of a triangle is returned (if valid). However, I want to return a message (i.e. 'triangle is not valid) if the triangle is invalid.
I'm not sure how to go about to doing this as my method (called area) will only let me return doubles. Possible to return a string in an else within my area method?
public class MyTriangle {
public static void main(String[] args) {
//triangle is valid if the sum of any two sides is bigger than the third
System.out.println(isValid(3, 4, 5));
System.out.println(area(543, 4, 5));
[Code] ...
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Nov 2, 2014
I am doing this math for my assignment where you have to find the imaginary number.
double dem = (b*b-4*a*c)*-1;
double dem2 = Math.sqrt(dem);
realPart = (-b/(2*a));
imagine = (dem2)/(2*a);
imagineneg = (dem2)/(2*a);
So basically I am trying to get it that the number inside the square root isnt negative. So lets say I enter a: 1, b: -1, c: 4.25. When you do the discriminant it would be -16 but I want that to be positive so I multiple it by -1 (thats the dem part). Then I sqaure root the whatever the answer is and then go to the imagine and imagineneg part where you find the imaginary number.
My problem is that instead of it being -16*-1 to get 16, some how I get 15.
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Jan 27, 2014
I am running into some trouble with Line-Plane intersection, my method works, provided I am perpendicular to the plane I want to intersect. This is caused be the plane equation (with my given x, y, and z coordinates, the equation is -Z - 1 = 0). So the equation is only relying on the Z value of anything inputted. Is there another way to calculate the equation of a plane that would rely on all axis? Here is my current code:
Java Code:
Vector3f A = new Vector3f(0, 0, -1);
Vector3f B = new Vector3f(0, 1, -1);
Vector3f C = new Vector3f(1, 1, -1);
Vector3f v1 = new Vector3f(B.x - A.x, B.y - A.y, B.z - A.z);
Vector3f v2 = new Vector3f(C.x - A.x, C.y - A.y, C.z - A.z);
float[] i = new float[]{v1.x, v2.x};
float[] j = new float[]{v1.y, v2.y};
float[] k = new float[]{v1.z, v2.z};
[Code] ....
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Apr 16, 2014
how I can use this class:
Java Code:
public class Coordinate{
public int x;
public int y;
publ Coordinate(int x, int y){
this.x = x;
this.y = y;
[code]....
How would I use Coordinate in the second code?
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Apr 12, 2014
I have a set of 2D arrays, structured as so: int[][] cage = new int[someLength][4]. Each array has a set column length of 4; the first two columns are all that concern us with this problem. They are used to define the row and height respectively of a point (e.g. 2,4).
What I need is to generate all possible permutations of the points using both row and column coordinates from the 2D array. I found a working method to generate all permutations for 1D array of ints here: [URL] ..... , under update 2 of the first answer.
Here is an example of a possible input and corresponding output desired:
In: (1,0)
(1,1)
Out:(1,0),(1,1)
(1,1),(1,0)
Ideally the result will be stored in a 2D array of ints.
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Apr 12, 2014
I have a set of 2D arrays, structured as so: int[][] cage = new int[someLength][4]. Each array has a set column length of 4; the first two columns are all that concern us with this problem. They are used to define the row and height respectively of a point (e.g. 2,4).
What I need is to generate all possible permutations of the points using both row and column coordinates from the 2D array. I found a working method to generate all permutations for 1D array of ints here: My link, under update 2 of the first answer.
Here is an example of a possible input and corresponding output desired:
In: (1,0)
(1,1)
Out:(1,0),(1,1)
(1,1),(1,0)
the result will be stored in a 2D array of ints.
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Oct 18, 2014
I've been pondering about this algorithm for about a week but I'm still not able to write a "fast" working method/algorithm to solve the Number-of-paths-exercise we were given in my class />
So here's the task:
Write an efficient java program "Paths" which solves the following task:
- Read input n ∈ N and give output a(n) which is the number of paths from (0,0) to (n,0)
it is not allowed to go over the diagonal (m,m) and also not below the x-axis (m,0)
Here are the allowed steps:
u = (1,1), U = (1,4), d = (1,−1), D = (1,−4) and H = (1,0)
steps are performed in a two-dimensional-coordinate-system!
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Mar 6, 2014
Ok Im trying to create a code right now that will take a table of rectangular coordinates and convert them to Polar coordinates in the constructor. I will eventually calculate the total distance between all points in the calculateDistancePolar method but for now I am using it to test.
It doesnt like line 29 and 31 of the class Polar and I cannot figure out why.
public class Test {
public static void main(String[] args) {
double[][] coords = {{86.92, 2.47},{70.93, 27.81},{97.74, 34.36},{30.90, 35.14},{51.66, 31.70},{0.830, 21.77},{55.91, 66.62},{32.92, 75.23},{65.26, 72.53},{83.90, 4.710}};
System.out.println("X,Y Coordinates are:");
outputArray(coords);
Polar myTest = new Polar(coords);
[Code] .....
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Feb 3, 2015
import java.awt.*;
import java.awt.image.*;
import java.awt.event.*;
import javax.swing.*;
import java.net.*;
/**
An applet that shows a rotating globe.
[Code] ....
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Aug 22, 2014
This program deals with a variation of the geographic coordinate system with Greenwich at 51° 28' 38" N. The program will be adding the three values of one coordinate to the three values of the second coordinate. Though the maximum value for seconds and minutes is 59, the user can enter values greater than that number when prompted. The maximum degree is 360 for this assignment though the user can enter values greater than that number.
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Jul 4, 2014
I am planning a race simulator car and I have a problem to get the x and y coordinates from the graph (or circuit). I explain the problem better. If I for example, drawing an arc using the library DRAW2D how do I get all the points in x and y coordinates of that arc?
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May 8, 2014
I'm working on a project right now in JavaFX, and got stuck. I am drawing a path consisting of CubicCurveTo's and I wonder if there's any way to get the X and Y coordinates from certain parts of that path.
Imagine following a curve (path) with a pencil slowly, and every second you take note the X and Y coordinate. I mean I'm not interested in the control points or start and end points, but the points "in between", preferably at a certain interval.
I've searched for many things online, but have trouble knowing exactly which words to search for. "Paths" often bring up file paths, traversing, coordinates etc. all fail to give me any good results.
I tried to be as specific I could, and I don't think my current code is of any interest in this matter.
(The point of it all is that the path should simulate the path a person walks, and I will store the coordinates in a database for every second).
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May 8, 2014
What are the x- and y-coordinates of the Points referred to as p1, p2, and p3 after the following code executes? Give your answer as an x-y pair such as (0, 0). Recall that Points and other objects use reference semantics.
PHP Code:
Point p1 = new Point();
p1.x = 17;
p1.y = 9;
Point p2 = new Point();
p2.x = 4;
p2.y = -1;
Point p3 = p2;
p1.translate(3, 1);
p2.x = 50;
p3.translate(-4, 5); mh_sh_highlight_all('php');
P1:
P2:
P3:
My guesses were: P1:(20,10) //Correct
P2:(50,-1) //Incorrect
P3:(0,4) //Incorrect
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Mar 25, 2015
How to find coordinates of transparent area in the image. I working on .png image which has transparent background and transparent area in the middle of the image. The transparent area in the middle look a like ellipse, so i want to find coordinate of top, bottom, left, and right of that area. I am using opencv.
I have tried to find pixels and from result that i got, i understand that pixel with rgb that equal to 255.0 255.0 255.0 is transparent. what i have in my mind is, if rgb with value that equal to 255 255 255 detected, i will put 1 into arraylist named transparent, and if it not equal to 255 255 255 i will put 0 into the list. So when i look into the list, if there is 1 0 or 0 1 it means that border between transparent area and colored area or vice versa. But, how to know if that border is between transparent area in the middle of image and the image, and not between background and the image. Am i doing this correctly?
Here snippet of code.
Mat imgMask = Highgui.imread(imgfile);
double[] pixels = new double[3];
System.out.println("channel " + imgMask);
for(int x = 0; x < imgMask.cols(); x++) {
for(int y = 0; y < imgMask.rows(); y++) {
pixels = imgMask.get(y, x);
[Code] .....
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Apr 3, 2014
-7984749.593824852,5368675.690126911 -7984392.035620423,5367570.791302501 -7983220.843257783,5366848.500158152 -7982343.534350842,5364796.5795687605 -7980293.251969412,5363408.488192292 -7980621.978425723,5361760.555707421 -7979175.604281852,5359233.088002191 -7977402.284793513,5358332.850725802 -7976513.843937492,5357665.108234091 -7976472.321767421,5357241.582554582 -7974834.812057852,5357842.933691362 -7973351.925120993,5354420.819505452 -7973743.435770122,5354147.992005592 -7973309.512395002,5352911.428583422 -7973639.9086436825,5352740.575552852 -7972698.034432082,5350359.050518452 -7972255.539456172,5350294.883494262 -7971909.001881332,5349519.720176511 -7970907.683061652,5349775.605440161 -7970575.617020612,5348986.585139751 -7970013.342272613,5349482.445545332 -7969898.683197102,5350177.703443532 -7968337.649977702,5350328.647515352 -7967111.243147633,5351652.264468962 -7966171.150047882,5351373.1018466605 -7966125.286417683,5352115.720678982 -7964626.258154663,5351707.120082232 -7955765.449326492,5345109.379313592 -7954159.443032822,5343966.704795052 -7942364.363746833,5335522.893249432 -7929990.868386692,5326092.063381992
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Jul 23, 2014
I extracted columns from database and made calculations inside while loop. I know i need to make array to get from it coordinates for points. I want to draw them in interface created in another class but i have black hole and don't know how to get datas from while loop to array which is below.
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Mar 16, 2015
how to create coordinates in a two-dimensional grid, in the end it shall look like A5, F6 and so on. The aim is to place 3 DotComs in this grid by coincidence. To do this one uses two arrays. One array represents one DotCom, the other represents the grid's size, in this case 49 (7x7).The code ends like this:
ArrayList<String> alphaCells = new ArrayList<String>();
...
int x = 0;
int row = 0;
int column = 0;
while (x<comSize) {
grid[coords[x]] = 1; // mark master grid points as used
row = (int)(coords[x] / gridLength);
column = coords[x] % gridLength;
temp = String.valueOf(alphabet.charAt(column));
alphaCells.add(temp.concat(Integer.toString(row));
x++;
}
return alphaCells;
}
why row and column are calculated like this. Furthermore I don't understand why the column is used to generate a character, because columns are marked with numbers and rows are marked with characters.
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Apr 26, 2014
//Design/write a class named MyPoint to represent a point with x and y coordinates. The class should contain:
//->Two variables, x and y, that represent the coordinates
//->A no-arg constructor that creates a point (0,0)
//->A constructor that constructs a point with specified coordinates
//->Two getter (accessor) methods for the variables x and y
//-> A method named distance that returns the distance from a point to another point of the MyPoint type
//-> A method named distance that returns the distance from a point to another point with specified x and y coordinates.
//Draw the UML Diagram for the class. Implement the class. Write a test program that creates two points (0,0) and (10, 30.5) and displays the distance between them.
I have written the program but not I have to do it with user input ....
class MyPoint {
private double x;
private double y;
public double getx()
{
return x;
}
public double gety()
[Code] ....
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Jan 27, 2015
The code is used to find coordinates of an image and i cannot understand how it works.
for (int y = 0; y < height; y += 2) {
for (int x = 0; x < width; x += 2) {
int px1 = secureRandom.nextInt(4);
int px2 = secureRandom.nextInt(4);
while (px1 == px2)
px2 = secureRandom.nextInt(4);
int px1x = (px1 < 2) ? px1 : px1 - 2;
int px1y = (px1 < 2) ? 0 : 1;
int px2x = (px2 < 2) ? px2 : px2 - 2;
int px2y = (px2 < 2) ? 0 : 1;
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Oct 31, 2014
I am writing a java program that takes a FROM image, a TO image, and a ratio (this is a slide bar in the GUI). Here's my code:
Java Code:
public static BufferedImage rollUp (BufferedImage from,
BufferedImage to,
double ratio) {
BufferedImage finalBufferedImage = new BufferedImage(from.getWidth(),
from.getHeight(),
from.getType());
int packedColor = 0;
for (int r = 0; r < from.getHeight(); ++r) {
for (int c = 0; c < from.getWidth() ; ++c) {
[code]...
So from 0 to 1 (ratio is a double between 0 and 1) the image will "roll up". The effect works completely in the GUI, but the console freaks out at about 0.33 ratio.. This program runs for testing in a class Main and uses a class Splittinimage.. this method is in class TwixPix. When the main class is run, a box pops up with a combo box and a slider. You pick an effect (in this case, roll up) and then slide the slider to set the ratio. The image below those two things performs the effect that was selected. Imagine a PowerPoint presentation slide effect.
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Feb 15, 2014
Ok, so I am relatively new to datagrams etc. I have three projects set up right now: Client, Client2, and Server, which all interact with each other to send coordinates of player1 and player2 back and forth (X, Y, this is in 2D space not 3D). I have everything set up perfectly except for one problem: I can only send the X coordinate back and forth for each player. I am getting the weirdest error, a parsing error. The way I communicate is I have everything sent back and forth in one string. Then I use the .split() function to turn that string into an array that contains the x and y coordinates. I've done several tests and to no avail. Here's my code:
Server:
Java Code:
package theGame;
import java.io.IOException;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetAddress;
import java.net.SocketException;
import javax.swing.JOptionPane;
public class Main {
static String p1X;
static String p1Y;
[Code] ....
Lines 177 on Client1 and 172 on client2 are where the debugger is saying that I parsed wrong.
Also, if your are going to test this you will need to have the LWJGL libraries in your build path.
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Mar 6, 2015
The idea I'd like to present, concerns the correction of "designer" drawings - those done by the design consultants - against "site/construction" drawings - them being used on site by the workers to build the project itself.
This is normally a laborious process, involving being sat at a desk with two large folders, checking each detail and measurement against the design drawing.What I'd like to present is an idea, where the co-ordinates of the design or "mother" drawing, are transferred into a usable Java program, and they could be then used to ensure correct dimensions have been applied by the the sub-contractors in their "construction" drawings.Like I said, this can normally be a process of days for a site engineer to check - process known as "QA, quality assurance".
Basically, I just need to make a presentation of having a genuine interest in Software Design and Development. It could be applied in a range of areas in terms of construction site application - checking drawings, writing up work orders, dig orders etc - but the principle of having the co-ordinates of the mother or "design" drawing scanned into an array in Java as a means to output those site drawings/orders etc, applies to each potential application.
So - in short - and not looking for crystal clear detail, just general pointers - what programs or methods could transfer a plethora of co-ordinates from a design program like Auto-Cad, to a Java program, where I assume I would then be using a program containing a complex series of loops to ensure the correctness of the derived "construction" drawings; derived from the "mother" or designer drawings, that is.
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