Create A Program That Will Check If One Statement Is Equal To Another
Dec 5, 2014
I'm suppose to create a program that will check if one statement is equal to another but it doesnt display the message if its equal to the inputted String
import java.util.Scanner;
public class sup {
public static void main (String args[]) {
Scanner in = new Scanner (System.in);
String one;
[code]...
thats just an example I was able to do it in C++ but it doesnt do what I want in Java
Why isn't heig ever equal to heightShipArray[count] no matter what letter I type in
String[] heightShipArray = {"A", "a", "B", "b", "C", "c", "D", "d", "E", "e", "F", "f", "G", "g", "H", "h", "I", "i", "J", "j"}; boolean trueHeight = true; // checks if height is a letter between a-j/A-J do { Terminal.printLine("Input height with letters A to J");
when we create another variable and set it equal to the first : Car c2 = c1;
we're pointing c2 at the same car object that c1 points to (as opposed to pointing c2 at c1, which in turn points at the car). So if we have code like,
Car c1 = new Car(); Car[] cA = {c1, c1, c1, c1};
are we doing the same? Are we creating four *new* reference variables, each of which points at the same car (again as opposed to pointing them at c1 itself)? I think so, but want to make sure I'm understanding this correctly.
It should be possible to let the javac create a subdirectory according to the file's package statement. So I have tried: Java Code: javac -d C: estMyApp.java mh_sh_highlight_all('java');
That always gives me the message that javac could not create the directory.
I am doing an assignment for my class and I wish to know if there is anything I did wrong or what would make it easier to read, the assignment is to make a program to check if a year (the user provides the year) is a leap year.
import java.util.*; public class Assignment1 { public static void main(String[] args) { int year; System.out.println("Please enter a year.");
I am doing an assignment for a college class. We are asked to get user input and decide if it is a valid IP address and then check what class the address is and if it is a public or private address.
So far, I can get the input, and check to see if the numbers are in a valid range. I can also display the IP address to the user. I am having an issue figuring out how to get the program to check the classes and whether they are public or private.
import javax.swing.JOptionPane; /** This program will take user input and calculate whether it is a valid IP address and the class that it belongs to. */
public class shortONE_1 { public static void main(String[] args) { //Variables final int MIN_OC = 1; //Minimum number accepted final int MAX_OC = 255; //Maximum number accepted final int MIN_A = 1; //Min number for class A final int MAX_A = 127; //Max number for class A
I have this program where I'm supposed to fill an array with 1000 indices with 1000 randomly generated numbers between 1 and 1000. The program is supposed to check if any of the numbers match an index that is the same value (so for example, the number 4 is in index 4). How to check for that condition, especially using a binary search (I'm also told to use a binary search).
Right now the variable index isn't initialized because I don't know what to initialize it to exactly. How do I check to see if any numbers match the value of the same index?
import java.util.*; public class Identity { public static void main(String[] args) { int [] integers = new int [1000]; // Fill array with randomly generated numbers int [] display = GenerateRandom(integers);
Alright so I'm trying to write a code that implements a for loop and if statements that displays any number from 100-200 if the number is divisible by either 5 or 6 in rows of ten numbers each row. If it is not divisible by that number then it should go back to the beginning of the loop until it reaches 200. My main problem is that it doesn't display anything. I don't get any errors or anything but every time I run the program it just displays nothing. Sample output is at the bottom of the code.
public class Exercise5_11 { public static void main(String[] args) { int count = 0; int i = 100; //for (the numbers from 100 to 200) for (i = 100; i>100 && i<200; i++){
We're told to make a cash register program for 5 products using Java. It loops until "-1" is entered on the "Continue?" input dialog box.There should be a:
1. Main Menu - where the user will pick what to buy (one product at a time) like the sample code below and prompt the user if he will buy another product or not. If yes, the program will go back to the main menu to buy another product and if not, continue to the program. And it looks something like this: LEvFOwQ.png
2. Receipt - at the end of every transaction.
3. Daily Sales Report where it shows all receipts then grand total like:
Transaction 1
-subtotal
Transaction 2
-subtotal
and so on then,
GRAND TOTAL
4. Inventory Report where it shows the Items Available before the Selling, Items Sold, and Items Available after Selling in table format.
Below is the code for a simple cash register for only one product that I made but I need to upgrade it for it to work for 5 products. That code will serve as the basis for this program.make the switch or if-else statement for the main menu first and if I got it right I try doing the rest.
int userQty1 = Integer.parseInt(JOptionPane.showInputDialog( "Product ID Product Name Product Quantity Product Price" +prodID1 + " " +prodName1 + " " + prodQty1 + " " +prodPrice1 " " + and so on until prod5));
I am Having trouble with my program to validate. It is outputting null into the validation statement then it brings back a run-time error to that validation Statement for the String.
public String validateData () { if (nm == null)nm = "Error! Must enter at least one character"; else nm = name; return name; }//end validation method
Why is this happening, and then once that is completed, why is the validation Sentence in tests Scores not able to validate. I traced it back to out put "Error, a number between 1<100".
public void validateTests () { String testschange; if (test1 < 0 || test1 > 100) { testschange = " You have entered an invalid number, between 1-100. Please restart!"; testschange = Integer.toString( test1 ) ;
I have been assigned to write a program that has a user input random numbers then the program is to sort them in different ways. I have the coding for the different sorts but, I have an error saying that I am missing a return statement in the "Bubble" method. I am trying to return "arr[i]" in the "for loop" which gives me this error, and when I try to take the "return arr[i]" outside of the "for()" loop the error reads the it cannot locate variable "i".
import java.awt.* ; import java.awt.event.*; import javax.swing.*; public class SwingSorts extends JFrame implements ActionListener { JRadioButton bubble; JRadioButton selection;
I have an object that may contain several other objects (sub-object) and will compress those sub-objects.
My question is generally what is a good way to compare two objects, as described above, if they are equal (e.g. through equals() function)?
Intuitively there are two ways I can think of: 1. Compare each compressed bit
The disadvantage I think is it's not efficient if the object is very big. For instance, when it holds several gigabytes data, it may took too long for just comparing each bit.
2. Hash the sub-object before compressing it, and then compare all hashed values. This problem is I am not very sure if hashing is a good way to compare objects. And if collision may be the problem?
So from what iv learnt in Java and programming in general is that using a case statement is far more efficient that using multiple IF statements. I have an multiple IF statements contained within a method of my program, and would like to instead use a case statement.
I have a JScrollPane with two coulmns. In the first column I have an image pane JTable, and in the second a list with names of sections. This second column I try to divide in two columns, one (the second column) to display the names of the sections (each row contains one name), and in the other column (the third) I want to show some values for every section in the row respectively. But, instead of displaying the desired values in the third column, I get the same names of the sections as in the second column. Here is a part of the code I have:
private Vector<Section>daten = new Vector<Section>(0); //These are the values for the first column in the Jscroll private String[] header = {"Section","calcGYR"}; // These are the values for the second and third column (in this case the header for the both columns public TrafficObserveModel(Vector<Section> daten) { setData(daten);
[code]....
But I don't know how to modify the methods in order to render the desired integer values in the third column.
I have an assignment that wants me to write a Java function based on induction to determine how many numbers in an array have a value greater than, or equal to, 100.
I have started with:
Java Code:
int recurseHundred (int [] A, int n) { //n is the number of elements in the array. //Base case: if (n == 1 && n >= 100) return A[0]; //Recurse int num = recurseHundred(A, n-1); if (n-1 >= 100) return A[n-1]; else return num; } mh_sh_highlight_all('java');
I read this tutorial about overriding equal and hashcode method. [URL] ....
I understand how to override equal method, by overriding it, We can custom our compare. I also understand How to override hashcode, To make custom hash.
But still I can not understand why we do it? why if equal method override, we must override hashcode method too?If we don't what is the problem?
To honor the above contract we should always override hashCode() method whenever we override equals() method. If not, what will happen? If we use hashtables in our application, it will not behave as expected. As the hashCode is used in determining the equality of values stored, it will not return the right corresponding value for a key.
Is it the right reason in order to override:
Because when we customize equal method so it focus on special variables,We must change the hash code too in order to match with it, so hashcode also focus on those special variable.