/*
* Put your documentation header here.
*/
import java.util.Scanner;
public class Lab5{
/**
* Returns an integer whose value is a^3 (a cubed).
* @param any integer to be cubed
* @return a^3 (a cubed)
[code]...
The last part with int a-j...... Is there a better way of doing this, like possibly putting into a loop and showing output from maybe a single piece of information?
I tried to create file and write the output of my program in it in java when i use WriteLong then the file does not contain long value, how I create this file my program is to print prime numbers between 500000 to 10000000
public class primenumber {
public static void main(String[] args) {
long start = 5000000;
long end = 10000000;
System.out.println("List of prime numbers between " + start + " and " + end);
for (long i = start; i <= end; i++) {
if (isPrime(i)) {
System.out.println(i);
[Code] ....
I've just written a program that generates 100 numbers that range from 0 ~ 25 using arrays, the program calls another method that sorts the even numbers into a separate array and returns the array. I need it to display both arrays, however, when I run my program, the numbers of both arrays are mixed together, and I'm not sure how to separate them.
[ public class Array1
{
public static void main(String[] args)
{
int array [ ] = new int[100];
for (int i = 0; i < array.length; i++)
{
array[i] = (int) (Math.random() * 26);
[Code] .....
I'm trying to make a program that generates 20 random integers between 1 and 20 and then prints the list of random numbers to the screen. After that, I want to print a different list to screen with the same numbers from the first list only skipping any number that has been already printed to the screen. So two lists are printed to the screen. The first one has 20 random numbers. The second one has those same 20 numbers but only prints the numbers in the first list that aren't duplicated. So if m
y list of 20 random integers contains three 2s and two 14s, only one 14 and one 2 is printed to the second list. Currently, my code generates 20 numbers from 1 to 20 and stores those numbers in an array but I don't know how to print solve the second part of my problem. I don't know how to print the s different list only without duplicate numbers. As a result, my output is nothing because it doesn't print any number from the first list as oppose to skipping only duplicate one.
public void randomNum(){
System.out.println("Twenty random integers: ");
int max = 20; // max value for range
int min = 1; // min value for range
Random rand = new Random();
int[] all = new int[20];
[Code] ....
I have to make a program that prompts the user to enter 10 numbers and at the end it prints out the distinct numbers and then the other numbers that weren't repeated...
I have the part where it prints out the distinct numbers but I stuck on how to make it print out the other numbers that didn't repeat...
import javax.swing.JOptionPane;
public class DistinctNumbers {
public static void main(String[] args) {
String getInput;
int input;
int[] numbers = new int[10];
[Code] ....
Create an integer array with 10 numbers, initialize the array to make sure there are both positive and negative integers. Write a program to generate two arrays out of the original array, one array with all positive numbers and another one with all negative numbers. Print out the number of elements and the detailed elements in each array.
public class problem3 {
public static void main(String[]args){
int[] numbers = {1, 2, 3, 4, 5, -1, -2, -3, -4, -5};
for (int i = 0; i<numbers.length;){
if(i>0){
System.out.println(numbers);
}
else
System.out.println(numbers);
}
}
}
I tried out doing number (generated randomly) != (another number) but that does not work. If I for example want a number between 1 and 10, but I do not want the number 5, what can I do in order to make this happen?
View Replies View RelatedProgram is to list all prime numbers between two entered numbers.
import java.util.Scanner;
public class question6 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Enter lower int:");
int x = input.nextInt();
[Code] .....
I wrote a program to find the sum of first 10 numbers using the for loop... here is the piece of code
public class Sum {
public static void main(String[] args) {
int sum = 0;
for (int N=0; N<= 10; N++) {
sum = sum + N;
}
System.out.print("The sum of first 20 numbers is " + sum);
}
}
I tried to write the same program using the while loop but with no success. How can i write this using while loop?
I don't know what I did to screw this up, but I had this code working to increment each employee ID by one every time a new employee was added. I tried to move the whole employeeID and newEmployeeID elements out of the constructor because everyone keeps telling me how bad it is to have those in the constructor. However, now, every time I add an employee, their ID number turns out to be 0. I have two other aspects of this project that are due soon, and if I can't fix this part, I won't be able to move forward to the other parts (which I am also stuck on at this point). The codes that are being used are as follows:
import java.io.*;
import java.util.*;
import java.nio.file.*;
import java.text.NumberFormat;
public class Employee
{
// instance variables
private String firstName;
private String lastName;
private int employeeID;
static int newEmployeeID = 0;
[Code] ....
how to add two numbers using RMI..This very simple example is taken from Chapter 24 of "Java 2: The Complete Reference" by P.Naughton and H.Schildt.The example is overly simplified but it still illustrates the basic steps in creating an RMI distributed program.
This example provides step-by-step directions for building a client/server application by using RMI. The server receives a request from a client, processes it, and returns a result. In this example, the request specifies two numbers, the server adds these together and returns the sum.(Of course, this program is intended only to illustrate the basic RMI mechanism.)The next subsections provide main steps in writing an RMI program
Define an interface that declares remote methods.The first file AddServerIntf.java defines the remote interface: it includes one method that accepts two double arguemnts and returns their sum. All remote interfaces must extend the interface Remote, that defines no methods: its purpose is simply to indicate that an interface uses remote methods.All remote methods should throw a RemoteException
import java.rmi.*;
public interface AddServerIntf extends Remote {
double add(double d1, double d2) throws RemoteException;
}
Implement the remote interface and the server
The second source file AddServerImpl.java implements the remote interface:
import java.rmi.*;
import java.rmi.server.*;
public class AddServerImpl extends UnicastRemoteObject
implements AddServerIntf {
public AddServerImpl() throws RemoteException {
}
public double add(double d1, double d2) throws RemoteException {
return d1 + d2;
}
}
All remote objects must extend UnicastRemoteObject which provide the functionaly that is needed to make objects available from remote machines. The third source file AddServer.java contains the main program for the server machine. Its primary function is to update the RMI registry on that machine. This is done by using the rebind() method of the Naming class (it is in java.rmi API). That method associates a name with an object reference.
import java.net.*;
import java.rmi.*;
public class AddServer {
public static void main(String args[]) {
try {
AddServerImpl addServerImpl = new AddServerImpl();
[code]....
Develop a client (an application or an applet) that uses the remote interface..The fourth source file AddClient.java implements the client side of this distributed application. This program requires 3 command line arguments: the IP address or name of the remote server, and two numbers that are to be summed.
The application forms an URL string using the rmi protocol, the first command line argument and the name "AddServer" that is used by naming registry of the server. The the program calls the method lookup() of the Naming class to find a reference to a remote object. All remote method invocations can then be directed to this object.The client program illustrates the remote call by using the method add(d1,d2) that will be invoked on the remote server machine from the local client machine where the client runs.
import java.rmi.*;
public class AddClient {
public static void main(String args[]) {
try {
String addServerURL = "rmi://" + args[0] + "/AddServer";
AddServerIntf addServerIntf =
[code]...
If you do not have an Internet connection, you can run all programs of this example on your local machine (both server and client). In this case, you can run
java AddClient 127.0.0.1 567 999
to use the "loop back" address (127.0.0.1) for the local machine. This will allow you to test the entire RMI mechanism without actually having to install the server on a remote computer.
The first problem is that the numbers don't round in IntelliJ.
Example: ('s in Dutch)
Geef de vorige kilometerstand: 125
Geef de huidige kilometerstand: 900
Geef het aantal getankte liters: 50
Verbruik voor 775km: 6.451612903225806/100km
That 6.4516..... is the problem, how can I make it 6.45/100km?
how to sum up two numbers of fractions?
View Replies View RelatedI was trying to get sum of numbers between two given integer and managed to do it.
public int sum(int a, int b) {
int sum=0;
while(a <= b) {
sum+=a;
a++;
}
return sum;
}
in here; when I enter the values i.e 2 and 5, it calculates 2+3+4+5 and gives me the result 14.
my question is, how could I exclude a and b in this calculation ( in this case exclude 2 and 5 and return 3+4 )
Bonus question ; how could I only calculate the odd (or even) numbers between those integers?
program that calculates and prints the sum of all numbers between two limits as the user types. Like if the user types 1 and 10 on the upper limit, it prints the following text: "1+2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55".
View Replies View Relatedhow to determine if an integer is even or odd by using a boolean method. I think I have the method right, but it's calling the method into the main that has got me stumped.
import java.util.Scanner;
public class Odd_Even {
public static void main(String[] args) {
//Scanner, variables
Scanner input = new Scanner(System.in);
int number;
[code]....
I want to make app in netbeans. When i write numbers in JTextField like 1,2,3,4,5,6... it should show me in JOptionPane information window result of ODD numbers.
View Replies View RelatedI need to add two integers in the same row of a file, separated by tab
my file abc.txt has the following entry
12 123
15 456
My program needs to add 12 with 123 and 15 with 456
I am being able to split the two entries in a row and convert them to integer but i dont know how to treat them as separate numbers and add them. For example if i try to add then 12 adds with 12 and 123 adds with 123. wheres it should be 12+123
Here is my program
import java.io.*;
public class test {
public static void main(String[] args) {
String s = "";
FileInputStream finp = null;
[Code] .....
I have been struggling to find out what to change to allow my code to find the GCF of two numbers. The instance variable in the class is num, so I need to find the GCF of a and num. It works for the example problem of 25 and 15, returning 5, however it will not work for other problems.
public int findGCD(int a)
{
int result = 0;
int newNum = num;
if ((a > num) && (a % num != 0))
[Code] .....
I think the problem in this is that the variable max is initialised as 0. Afterwards it remains in the while loop only, so the output is always 0. I dont know how to bring the last max value out of loop and print it.
import java.util.Scanner;
/**
*
* @author
* @version
*/
public class TEST1
[Code].....
package calculator;
public class operations {
int a = 5;
int b = 10;
public void add(int a,int b)
{
int c = a+b;
System.out.println(c);
}
}
I am not getting output to this question though it runs.
how can I add the numbers in quantity where it will automatically put in total?
im using netbeans.
just want the codes for how to add the listed quantity?
Assume that vehicles are going through a two-way traffic intersection. There are three types of vehicles: car, motor bikes and trucks. Generate a series of 10 random integers, between 1 and 3,inclusive.The numbers represent the type of vehicle as stated below:
NumberVehicle Category
1Car
2Motor bikes
3Trucks
Write a program, using a for loop, to count how many vehicles going through the traffic intersection are cars, motor bikes and trucks. Then, the program should print out the numbers for each vehicle category. There is no user input for this program. How do i do it so they will add up the sum of each vehicle?
The answer should be something like
Number of cars = X
Number of motor bikes = Y
Number of Trucks = Z
but i'm getting
Total number of vehicle:
cars
motorbikes
motorbikes
cars
Trucks
Trucks
motorbikes
motorbikes
Trucks
cars
public static void main(String[] args) {
[code]....
Convert Number to words using If Else Codes?
View Replies View RelatedI need to make a code that will ask the user for an array size and the numbers that go in the array. Then it must ask for a new size and copy the numbers from the first array and add numbers to fill the new array.
import java.util.Scanner;
import java.util.Arrays;
public class Lab07{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("How many numbers do you want to enter?");
[Code] ....
I can make the first array but I am getting stuck on the second this is what I am getting back
How many numbers do you want to enter?
3
Enter the 3.0 numbers now.
7
1.2
9
These are the numbers you have entered.
[7.0, 1.2, 9.0]
How many numbers do you want to enter?
5
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 3
at Lab07.resizeArray(Lab07.java:27)
at Lab07.main(Lab07.java:18)
how do I get the new array and not the error
In c++, I'm aware that you can use the ignore function to ignore numbers after space, but in string how do I ignore a number after space is found for instance, "109 33" how would I ignore 33?
View Replies View Related