Displaying Location Of Array Index
Feb 9, 2014
My project was to create an array holding 10 integers and populate the array with 10 random numbers. Then ask the user to guess the number. Prompt the user with a while loop if their input is out of range. Determine if the users number is in the array, and display which index location the number is in. I got most of the code done but am having trouble displaying the index location.
import javax.swing.*;
public class Homework4 {
public static void main(String[] args) {
int[] numarray = new int [10];
char repeatcode = 'y';
[code]....
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Mar 21, 2014
The output of my code is displaying the location of the index in the console. How do I get it to display the highest grade in the array?
public GradedActivity getHighest()
{
GradedActivity highest = Grades[0];
for(int i = 0; i<=3; i++)
{
if(Grades[i].GetScore() >= highest.GetScore())
highest = Grades[i];
[code]....
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Jan 28, 2014
Aatrox
Champions@3622e177
Champions@4805e9f1
Champions@57e40274
Champions@354124d6
Champions@262f4813
Champions@64f01d52
Frozen Heart
Randuin's Omen
As you can see instead of displaying the champion name it is displaying the memory location and I do not know how to fix it.
class Champions
{
String name;
Champions [] weak = new Champions [3];
Champions [] strong = new Champions [3];
String [] items = new String [3];
public static void main (String [] args)
{
[Code]...
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Jan 14, 2015
I need to design a class named Location for locating a maximal value and its location in a two-dimensional array. The class should contain public data fields row, column, and maxValue that store the maximal value and its indices in a two dimensional array with row and column as int type and maxValue as double type.
I need to write the following method that returns the location of the largest element in a two-dimensional array:
public static location locateLargest(double[][] a)
The return value is an instance of Location. Write a test program that prompts the user to enter a two-dimensional array and displays the location of the largest element in the array.
Here is what i get when I run
Enter the number of rows and columns of the array:
3 4
Enter the array: 23.5 35 2 10
4.5 3 45 3.5
35 44 5.5 9.6
The location of the largest element is at 00
The location of the largest element is at 01
But I need it to display this instead.
Enter the number of rows and columns of the array:
3 4
Enter the array: 23.5 35 2 10
4.5 3 45 3.5
35 44 5.5 9.6
The location of the largest element is 45 at (1,2)
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Number of rows and columns: ");
int row = input.nextInt();
int col = input.nextInt();
[Code] ....
Enter the number of rows and columns of the array:
3 4
Enter the array: 23.5 35 2 10
4.5 3 45 3.5
35 44 5.5 9.6
The location of the largest element is at 00
The location of the largest element is at 01
I need it to display this instead.
Enter the number of rows and columns of the array:
3 4
Enter the array: 23.5 35 2 10
4.5 3 45 3.5
35 44 5.5 9.6
The location of the largest element is 45 at (1,2)
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Oct 13, 2014
I am receiving an ArrayIndexOutOfBoundsException for the following code, which moves a creature through a 2D array maze. I have altered the clauses of the first if statement for the four direct methods (north, south, east, and west) multiple times (i.e. x + 1 >= 0 && x > 0 && x - 1 > 0 && x < array.length...etc). However, while the code occasionally runs, more often than that it returns this exception. Catching the exception seems like a poor workaround though if worst comes to worst I'll do that.
I included only the relevant functions of the code:
public boolean goNorth(char[][] array) {
boolean success = true;;
x = getX();
//x = this.x;
y = getY();
//y = this.y;
if ((x - 1 >= 0 && x - 1 < array.length)
&& (y >= 0 && y < array[x].length)) {
[Code] .....
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Jan 11, 2015
Untitled.jpg I have been working over this game lately, and i have managed to render multiple images from an array. in this fashion. I created a Main() class with the following in it:
public Main() {
for (int i = 0; i < fuel.length; i++) {
Random r = new Random();
changef = r.nextBoolean();
y = (-600 * i) + r.nextInt(300);
if (changef)
fx = 325;
else
[Code]...
Also, this is the Fuel image class and Obstacle image class:
public void tick(Player2 p2) {
y += dy;
Random r = new Random();
if(x >= p2.getH()) {
y = -40 - r.nextInt(700);
[Code]...
(Fuel and obstacle class are identical but separate for better accessibility) I even have player class with an image listening to key events and also a scrolling background. The problem is when i run the game, the images of obstacles render themselves as i want, except for that they overlap each other, i need to prevent over lapping of this images. The fuel is read and obs is black. Heres a glance of how it looks.
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Aug 2, 2014
To simulate it, the program will generate a random number between 0 and 19, which represents the location in the array (i.e. index number). Then, the 3 numbers to the left and right of this location should be reset to the value 0. If there isn't 3 numbers to the left and right you may assume a lesser number depending on the boundaries of the array.
How to reset the numbers to 0 in the final array ?
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Oct 21, 2014
import javax.swing.*;
import java.awt.*;
import java.awt.event.ActionListener;
import java.awt.event.ActionEvent;
import java.awt.*;
import java.awt.event.*;
[Code] ......
Just cant see where the array is out og bounds the array ButtonList has 9 buttons....
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Jan 7, 2015
I created and an Array of integers how can I get randomly get/pick the index of each array element.
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Mar 29, 2015
I searched online for this error and found out it's because the array is smaller than the index but I am not sure how I can fix this error....
public Lamborghini[] getCarsWithHorsepowerRange(double lowHP, double highHP){
int i = DEFAULT_ZERO;
Lamborghini[] carWithinHPRange = new Lamborghini[i];
for (Lamborghini lambos : inventory){
double horsePower = lambos.getHorsepower();
[Code] ....
I tried
Lamborghini[] carWithinHPRange = new Lamborghini[i+5];
//which works sometimes because once I boost up the range and so there'll be more result then the error came up again....
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Feb 10, 2015
I have a problem with one method for my assignment. This is the requirement for this method: "This method uses a loop to list all accounts contained in the Array, adding each account details to a String, before outputting to screen in the format specified in the screenshot below. Ensure that there are no out of bounds exceptions by checking if each array slot has an account object before adding its details to the output String. (arrayname[index] != null)"This is my code for this method:
public void listAllAccounts() {
String allAccountsString = "List of all accounts:
";
for(int i = 0; i < ACCOUNT_SPACES; i++) {
//allAccountsString += accountArray[numAccounts];
if (accountArray[i] !=null) {
allAccountsString += accountArray[i].toString() + "
" ;
}
}
JOptionPane.showMessageDialog(null, allAccountsString);
The problem is that the Message Dialog does not display the accounts I have already created. It just displays "List of all accounts:
";
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Mar 27, 2015
When i am trying to display the contents of this array its showing arrayindexoutofbounds exception...how do i display this array?
<%
String names[][] = new String[10][2];
for(int i=0;i>=10;i++){
for(int j=0;j<=i;j++){
names[i][j]="anu";
if(j>0){
[Code] .....
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Feb 18, 2009
I am getting Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 4 at lsb2.main(lsb2.java:44)Here is the code:
Java Code: import java.io.*;
import java.lang.Integer.*;
import java.lang.Math.*;
import java.util.*;
class lsb2
[code]....
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Jan 28, 2014
java.lang.ArrayIndexOutOfBoundsException: 991
at Champion.main(Champions (1) (1).java:209)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Nativ e Method)
[Code]....
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Oct 13, 2014
I am trying to make different arrays each being filled with random numbers from 0 to 2000, however when I run this code I get the error mentioned in the header. here is part of my code
for (int i = 1; i <= 14; i++) {
int n = (int) Math.pow(2, i);
int[] list = new int[n];
for( int j = 0; j <= list.length; j++){
list[j] = (int) (Math.random() * 2000);
}
}
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Feb 6, 2014
I want to Display the Index of output Array.
here is the code:
import java.util.ArrayList;
import java.util.List;
public class selection {
private static int[] numbers= { 1, 2, 4, 8, 16, 32, 64, 128, 250, 250, 250, 250, 250, 250, 250 };
private static int[] sumsum= new int[numbers.length];
private static int sum= 1759;
[Code] .....
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Apr 15, 2014
I want to find a certain element in array I have to scan through the array index starting from 0 until I find the number I am looking for. Even in data structures which use hashing like HashMap and Hashtable we will have to scan through the keys until we find the key we are looking for. So what is the use of hashing over index based searching? I mean how is hashing an advantage over an array?
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Jan 18, 2014
I am getting error array index out of bound ... Error detail is :
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0
at abhiExample.arraytwodiam.main(arraytwodiam.java:27 )
And program is
Java Code:
package abhiExample;
import java.util.Scanner;
public class arraytwodiam {
public static void main(String [] args)
{
char[][] Atrace={};
int i,j,k,l=0,row ,characters;
[Code] ....
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Feb 5, 2015
public class Access
{
public static void main(String args[])
{
long a=2;
int j[]=new int[a];
}
}
Code shows error as "possible loss of precision" as am working with long type.but need to have my array size as 10^10 or some other logic?
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Mar 3, 2015
I'm trying to iterate through an array of integers and find the start position of the part of the array containing the most consecutive 1s.
For example given the array {1,3,1,1,1,1,5,3,2,1,1}, the method should return 2 and given {1,4,5,1,1,1,5,1} the method should return 3.
So far, I've managed to retrieve the element where the consecutive 1s begin. However, I'm unsure how to get the index of this element and this implementation doesn't work if there is more than one set of consecutive 1s.
public class GetIndex {
public static int getPosition(int[] myArray) {
int index = 0;
int tracker = 0;
int mostOnes = 0;
for(int i = 0; i < myArray.length; i++) {
[Code] .....
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Mar 22, 2014
class test{//class
public static void main(String[]args) {
String booking [][]= new String [30] [6] ;//two dimensional array
System.out.println("Enter the seat column you want");//column entry
char column=Keyboard.readChar();
System.out.println("Enter the seat row you want");//row entry
int row=Keyboard.readInt();
[code]...
cant get my in put to go in to the index
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Aug 5, 2014
how to index the arrays so that i can choose specific data so that averages and maximum and minimum values can be worked out. My code is below
package weatherProgramPackage;
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
[code]....
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Feb 14, 2015
I am trying to understand the following code.This return statement should actually return the char at myArray[index] first, then increments the index afterwords correct?
Public char next(){
return myArray[index++];
}
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Jan 29, 2014
int[] a = new int[7];
a[0] = 0;
a[1] = 10;
a[2] = 256;
a[3] = 57;
a[4] = 33;
a[5] = -154;
a[6] = 168;
[code]....
What program needs to find is the most biggest number. It does the job, but another task of the program is to find the index of that number . The second loop should do just that, but for some reason, as the loop goes further, it passes through the if statement even though answer "a[i]" is not equal to "answer". The idea is that if a[i] and answer are equal, the "i" should represent the index number.
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Apr 29, 2015
import java.util.*;
public class DungeonsAndDragonsRedux {
public static void main(String[] args) {
Scanner s = new Scanner (System.in);
Scanner t = new Scanner (System.in);
t.useDelimiter("\n"); // Prevent scanner from reading code after nextLine().
[code]...
I have this program that is attempting to randomly equip the player with items that are randomly chosen from a list. I don't know how to prevent it from picking the same item twice though. I also don't know how to display the items that haven't been equipped, which is another requirement of this program.
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Dec 15, 2014
When I am trying to execute this code it is showing
Java Code:
class Sort2D
{
public static void main(String...s) {
Sort2D r=new Sort2D();
int z[][]=r.sort(new int[][]{{1,0,567,4,3,33},{333,677,34243,8987,3434,324},{446,876,23,546565,332}});
for(int i=0;i<z.length;i++)
for(int j=0;j<z[i].length;j++)
System.out.println(z[i][j]);
[Code] ....
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