If I try CLASSPATH: C:Program FilesMicrosoft JDBC Driver 4.0 for SQL Serversqljdbc_4.0enusqljdbc4.jar I receive a "Could not find or load main class" error.
I have an app that saves pdfs and images from a web page. The web sections send info to the server elements running in Java. I have hardcoded the path to where the images and pdfs need to be saved but on the server, these paths will be different. I'd prefer to just save them to something like:
whateverMyDeploymentDirectoryIs/files/pdfs
or something. How do I find out what my root directory is so that I can make the path relative instead of hard coded?
I am trying to create executable jar file and I have test.mf file located in the dir from where jar cmd(JavaTest) is executed and also in dir which contains class files (jTest).
C:Users m2tDesktopJavaTest>jar cvfm JarTest4.jar test.mf jTest java.io.FileNotFoundException: test.mf (The system cannot find the file specified) at java.io.FileInputStream.open(Native Method) at java.io.FileInputStream.<init>(FileInputStream.java:120) at java.io.FileInputStream.<init>(FileInputStream.java:79) at sun.tools.jar.Main.run(Main.java:150)
[Code] .....
So how can Icreate manifest file and where shall I put it ?
I am writing an Ant script using the javac command but the library I need is bundled in an ear file, how can I reference this jar in ear file without extracting the ear file.
I need to start a new JVM. To do this my (production-) code pick a certain jar and starts a class in it. The name of this class is not fix. The picked jar has other jars in its Manifest class path section.
For my tests I want to replace my jars red from the main jar with the compile target folders of my Eclipse projects that make up my Application.
Getting that folders is quite easy because i configured the Starter project to depend on the other Projects of my app so that they are available via System.getProperty("java.class.path"). But eclipse creates absolute path in there. The result is that I cannot use the output of System.getProperty("java.class.path") as command line parameter, it's simply to long.
I tried to put the class path in a temporary jar file but it looks like that the jars class path is not added to the resulting class path when i is simply added as another classpath entry at command line. On the other hand I cannot run this temporary jar file via -jar option because the main class cannot be found if it is not located in the temporary jar...
Meanwhile I found that the main problem is not so much the other Projects but the 3rd party libs which eclipse refers them in their maven repository location. They blow up my classpath. I tried to convert their paths to relative but this didn't change that much...
So my question is: 1. is there a way to provide the classpath in a text file to java executable on command line? 2. is there a way to run a jar with the -jar option if the main class is outside the jar (but within the classpath in the jars manifest)? 3. is there any other way to solve my problem resulting from the limited command line length?
this is the following task i am trying to do. Write an interface Directory to manipulate entries in a telephone directory for the University. The interface must support the following operations:
1) The ability to insert new entries into the directory. Entries should be stored in alphabetical order of surname. 2) Delete entries from the directory either by name or number 3) Provide a lookup method that will find the extension no of a member of staff given his/her name. You should try to make this method run as efficiently as possible. 4) Change a person's telephone number 5) Print the telephone directory in a neatly tabulated fashion.
Write a class ArrayDirectory that implements this interface using an array to store the telephone directory information. The class must store the surname and initial for each member of staff and their telephone extension (a four digit number which may start with a zero). You may find it useful to define a class Entry to store information about individual entries. The entries should be read into the array from a text file consisting of multiple lines in the following format:
Surname<tab>Initials<tab>Telephone extension
The part that i am stuck on is trying to do the entry method, delete entries method, loop up method, change persons telephone number and be able to print it.
This is a snippet code that im developing. (no source of it) . I am facing a trouble to extract file in the same directory as the source file (example: extract here option)
public class HelperAction { public static void unzip(String zipFilePath)throws IOException { File dir = new File(zipFilePath.substring(0,zipFilePath.length())); // create output directory if it doesn't exist if(!dir.exists()) dir.mkdirs(); FileInputStream fis;
Consider the url-pattern: <url-pattern> /Beer/* </url-pattern>
The web app structure is: -
webapps | -->AdviceApp | -->WEB-INF --> {{Beer}} This can be real or virtual.
My book says that /Beer/* can be a real or a virtual directory. What is the difference between the two and how do I create a virtual directory in tomcat ?
So i have this program that is supposed to execute a command when a button is clicked. I get an error: java.io.IOException: Cannot run program "/Users /brianallison/Documents/Java/RELAP5": error=2, No such file or directory
The actual PATH should be /Users/brianallison/Documents/Java/RELAP5 GUI/issrs/Dist.At least that is where the Java app is and the executable that I am trying to execute when the butotn is clicked. Executable name is relap5.x or relap5.exe depending on the OS.
I am trying to unzip a zip file to a directory but I've tried several different codes and none of them work.The zip structure is like this:
test.zip New Text Doc.txtNew Folder New Text Doc.txt
and this is the code I am using
try { // Open the zip file ZipFile zipFile = new ZipFile(outputFileName); Enumeration<?> enu = zipFile.entries(); while (enu.hasMoreElements()) { ZipEntry zipEntry = (ZipEntry) enu.nextElement();
I am working on a java logic game and I want it to be able to work on other people's Mac's, so I tried to figure out how to make it create a folder in which it can create files. The file creating is going fine however the folder never seems to create.Here is the code I attempted to use:
Here my code . Iam trying to open text file in window_pane it will open when i click on save it will ask destination to save file if i save example like Read.txt it will save...when i go and check in that folder Read.txt file won't found...what is the error ....
Java Code:
import javax.swing.*; import javax.swing.filechooser.FileFilter; import javax.swing.filechooser.FileNameExtensionFilter; import java.io.*; import java.net.MalformedURLException; import java.awt.*; import java.awt.event.*; public class Read extends JFrame
Here my code am trying to open text file in window_pane it will open when i click on save it will ask destination to save file if i save example like Read.txt it will save...when i go and check in that folder Read.txt file won't found..
JFileChooser fileChooser = new JFileChooser(); fileChooser.setCurrentDirectory(new File(currentDirectory));
File f = new File(currentDirectory); ArrayList<String> names = new ArrayList<>(Arrays.asList(f.list())); for (String s : names) if (s.startsWith(yearofIssueTXT.getText())) { fileChooser.setSelectedFile(new File(s));
int result = fileChooser.showOpenDialog(addNewCoinBody);
The file is not visible because it is at almost the end of the files in the directory. I want the filechooser to automatically scroll so that the file is seen in the list.
I don't really understand the question is the thing. Its about calling a file in the java program. I read the book and i can see how to call a file from a directory and how to save it and edit it but I don't understand what the instructor is asking for. Mostly what files need called and println.
Assuming the object that manages output will be called writer, write a statement that opens a text file called home.html for output by println statements.
To be file-writable and file-readable, an object must be an instance of a class that implements___________.
Write a statemnt that opens a file for input of objects and assigns a reference to the connection to ObjectIn. Assume the file is in the current directory, with the name automobiles. data.
I need to write the exact directory path like C:LisaestUpdate to a properties file.
I am trying it by
FileInputStream in = new FileInputStream(test.properties); Properties props = new Properties(); props.load(in); in.close(); FileOutputStream out = new FileOutputStream(newprop.properties); props.setProperty("myDirectory","C:Lisa estUpdate" ); props.store(out, null); out.close();
but the properties file is updated as C:Lisa estUpdate
Extra comes before :.
How can I remove that.
Even I tried it with an command but got same output.
i have a folder which contains two types of files (for eg: .csv and .tiff) with same names like, abc.csv and abc.tiff.How to compare the list of files with same names while ignoring their extensions.And my second task is to copy the content from csv file and i have to use that name as file name of .tiff file(Ex: if i have a1 as content in csv file, i have to change .tiff file name from abc.tiff to a1.tiff)
I am creating a .jar for a game I made. I'm not using any dev tools, just a DOS console call to java: %~dp0....javajdkinjar.exe -cfmv TheSwarm.jar manifest.txt *
My manifext.txt contains:
Main-Class: Game
But when I compile the jar, its manifest contains:
And I get an error about it not finding the main class. Shouldn't my Main-Class setting be added to the jar? I can manually rename it to .zip and edit the Manifest.MF but that is a huge pain when I'm testing the .jar file and regenerating it often.
I'm trying to do a program that send a single file from a client to a default directory of a Server. The program use the datagramSocket and datagramPacket for the transfer via UDP. The client sent the packet of the file correctly and the server start the receiving but every time the Server class crashes after it's receiving 4/5 packet (exactly 8192 byte)
Then i put the code of the 2 class and the 2 output.
OUTPUT CLIENT:
PROGRAM TRANSFER PACKAGES name of file is : Doc1.pdf his dimension: 11408 byte
PROGRAM TRANSFER PACKAGES START NEW CONNECTION Directory: C:prova Server waiting in port: 9876 Waiting Client... Name of file is : Doc1.pdf Dimension : 11408
[Code] ....
In this point the program go in loop and didn't anything. I don't understand how can i resolve it...
JFrame parentFrame = new JFrame(); File f12=new File("E: ewfile.txt"); JFileChooser fileChooser = new JFileChooser(); fileChooser.setSelectedFile(f12); fileChooser.setDialogTitle("Specify a file to save"); int userSelection = fileChooser.showSaveDialog(parentFrame);
[code]....
I want to save selected text file as html file in target directory....
If I specify the directory in file type or path string type how can I get a list of files that are file type .yml in that folder, so I can loop through and do something with each single file.yml in that specified directory.
