For Loops Inside Of Switch Statements
Mar 30, 2014
This is what I'm trying to do;
Java Code:
import java.util.Scanner;
class test{
public static void main ( String[] args ) {
Scanner scan = new Scanner ( System.in );
int choice = scan.nextInt();
[Code] ....
How is this doable?
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Dec 19, 2014
What I'm trying to do below is to say if (adultTickets > 0) I want to bypass the studentOAP tickets question and go straight to the question about dinner. But if (adultTickets ==0) I want to go to the studentOAP question and then if the (studentOAPTickets >0) to go to the question about dinner. But if the (studentOAPTickets ==0) I want to go straight to the question about the contact number.
System.out.print("How many adult tickets do you require? ");
int adultTickets = 0;
boolean validAdultValue = false;
while (validAdultValue == false) {
if(aScanner.hasNextInt())
[Code] ....
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Mar 8, 2014
Combining switch statements into if...else decisions? I'm basically trying to teach myself java and am at the point where I have to combine two user inputted values into if...else statements, only I don't really grasp how to do so. (This stuff is soooo addictive.) I'm trying to let the user input the type of residence they have, how many hours they are usually home, and then recommend a pet based on that. I just don't get how to input both selections they make in if...then statements. I get a bunch of errors as soon as I start the if...else part.
import java.util.Scanner;
public class PetAdvice
{
public static void main(String[] args)
{
int houseType;
int hourHome;
[Code] ....
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May 20, 2014
After this problem is fixed, my math game will run. The answer variable is supposed to be equal to the cases in the second switch statement by random but I get errors whenever I try to initialize it this way. I have been writing this program for almost 5 days now and it is finally wrapping up. Why I can't map the answer variable to the second switch statement the way I want to?
package pkgnew;
import java.util.Scanner;
import java.util.Random;
public class New {
public static void main(String args[]) {
//Declare and construct variables
Random randomnum = new Random();
int fnum, snum, answer;
[Code] .....
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Sep 25, 2014
Ok, so I've seen alot of things online about writing switch code, but I can't find any involving user input, let alone multiple input scanners.
The goal is I let the user put in two different integers and it will decide based on both of the integers which of the 15 possible results it will display.
I am also not allowed to use if/else statements in this program.
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Mar 8, 2015
SalesMan receives 200$ a week plus 9% of commission on the items he had sold that week
item 1 = 5.00
item 2 = 10.00
item 3 = 1.00
item 4 = 25.00
My code : (((I honestly dont know how to loop it... it must ask "What item did you purchase, and have the user input the number of item they purchased THAN looped back to ask again what item did they purchase untill they hit -1 to exit the loop))
import javax.swing.JOptionPane;
public class ControlStructure{
public static void main(String [] args){
double item1 = 5.00;//item 1 price
int quan1 = 0;
double total1 = 0;
[Code] .....
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Sep 11, 2014
I will like replace this code:
// boucle pour les fractions aleatoires
for (i=0; i<2; i++) {
// Creation des fractions aleatoires
Frac first = new Frac(r,5);
Frac second = new Frac(r,5);
[Code] .....
But when I use a switch case I do not have the same result as my four loops.
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Dec 2, 2014
So basically i have to read from a text file and get some information back from that and print to screen. Im quite confused and im not sure what loop i should use first to scan the text and receive certain information back?
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Apr 25, 2015
I am trying to make GPA calculator. I decided to use only switch statement and make it as simple as possible. The point is to enter as many classes and students as user wants. I keep getting credit points 0 at the end and also text format is not good too. Here is the code.
import java.util.Scanner;
import java.io.*;
public class SwitchExercise{
public static void main(String[] args) {
String grade = "";
String grades="";
String coursename="";
String headingleft="COURSES";
[code]....
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Oct 10, 2014
Basically the problem is I've been trying to loop my switch (if this is even possible) until the user enters a correct number between 1 and 4. But for some reason when the user enters a correct number (1,2,3,4) the loop runs again. Even when the user enters a wrong number the switch ignores the default and repeats what is in the do.
Am I just trying to loop something that cannot be looped or have I gone?
import java.util.Scanner;
class mammals {
int age;
int death;
String name;
[Code].....
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Mar 2, 2014
I have create as short example which contains two classes Cat and Dog followed by a switch statement in the main method.
Class Cat
public class Cat {
private String name;
//Setter
public void setName(String pName)
{name = pName;}
//Getter
public String getName()
{return name;}
// Constructor
public Cat(String catName)
{name = catName;}
[code]....
My Issue is that after creating the objects within the switch statement, is there a way to return the objects back to the main method once created within the switch ?
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May 5, 2015
cannot break from while loop. Whenever I am trying to exit from startCustomerManagement-> backEnd() -> mainScreen()..It gets stuck between mainScreen and backEnd screen. However I can exit from backEnd()->startCustomerManagement() screen
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package javaapplication19;
import java.io.BufferedReader;
[code]...
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Jul 10, 2014
can give me a sample program which solves with switch case statement with nested if inside?
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Mar 1, 2015
If I have an integer variable like int a=9 then in the switch case If i write
switch(a) {
case 4+a: System.out.println("hii");
}
Then why is this statement a compile-time error that variables cannot be used inside a case statement why does the compiler not subtitutes the values in place of the variables.
So basically what problem it creates for which the language developers did not include it as a proper syntax,is there any reason behimd this because of jump table?
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Nov 18, 2014
So I want to make a simple Java that ask the user to pick a powers and it has two options.If the user picks magic then execute the first if statement then ask the user again which type of magic the user wants.I can't make it work it keeps printing the else statement. Why is that?
import java.util.Scanner;
public class Variable {
static Scanner zcan = new Scanner(System.in);
public static void main(String[] args)
[code]....
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Sep 11, 2014
I am in the process of creating a calculator GUI that calculates different answers based on inputs two main comboboxes and numbers in the appropriate textfields. The first one allows the user to choose from 18 different materials, while the second has the user choose between two different shapes. In a brief word explanation, here's how it's set up:
User chooses material.
User chooses shape.
User types in appropriate values.
'Calculate' button clicked.
If shape = rectangle, execute rectangle calculation.
Else if shape = cylinder, execute cylinder calculation.
Everything works just fine with zero errors on all 18 materials and all kinds of decimal numbers when the second shape is selected. So the math and layout is solid. However, when the first shape is selected, it returns a $0.00 answer regardless of the input values (still no red-line errors). In efforts to troubleshoot, when I have /* Cylinder section */, the rectangle section works to a 'T'. This, I believe is caused by poor formatting in the syntax of the 'if' 'else if' in regards to the shape combobox.
//If 'Rectangle' is selected:
if(shapeDropDown.getSelectedIndex()==1) {
//6061
if(materialDropDown.getSelectedIndex()==0) {
String msg0 = "The price is: $"
+ currencyFormat.format((0.098*(number2*number3*number4)*3.06));
totalPrice.setText(msg0);
[code]....
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May 1, 2014
My initial question had to do with looping but now I'm having trouble adding certain variables.
The original thread is here: [URL] ....
If you look at the end of the code it won't recognize the "overtime" and "hourDiff". I have to use it for each level the
user chooses and am not sure how to do so. Even if I put it under the if{ statement it won't calculate. I assume it's due to it being cut off from other blocks but I'm not sure how to combine them.
My code is:
import javax.swing.JOptionPane;
public class Pay {
public static void main(String[] args) {
double salary2 = 20.00;
double salary3 = 22.00;
[Code] ....
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Oct 23, 2014
import java.util.Scanner;
public class TicTacToe {
public static void main(String[] args) {
//Create scanner
Scanner in = new Scanner(System.in);
//Declare variables to hold the board
[Code] ....
I need to create a while statement for random computer moves.
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Nov 2, 2014
I'm doing some revision for my OCAJ atm, & I came across this code in a mock question which takes two int arguments & simply returns the larger.
public int max(int x, int y){
if (x > y)
return x;
return y;
}
When evaluating it I thought this would be invalid code as would always return x. But it transpires I was way off & that this actually works! In playing around with it, it seems like the first return statement is treated as:
if {// this bit } & the second return is treated as: else{ //this bit}.
What baffles me though is that you can put any amount of additional statements before the second return and it continues to work, however if you put even a single statement before the first return, the whole thing falls over.
I guess my two questions are - Am I right in my discovery above ( that statements preceeding the first return will always break it)? & secondly is this a good way of coding? for readability, I would always do it as:
public int max(int x, int y){
if (x > y){
return x;
}
else{
return y;
}
}
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Oct 4, 2014
I am making a program, where the user answers 3 questions and then I add the number of correct answers in to the (int) numberofcorrect variable, then I want to print the results, and no matter how many correct, the program executes first the correct if statement, then the else statement.
Eg: I have 2 correct it will print:
"Grade B, 2 of 3 "
"You failed the test"
Why does it do that? How can I change my code so the else statement dosent print if one of the if statments is allready printed?I want to know how to not execute the else statement, if one of the if statements have allready been executed.Below is my current code for this problem:
if (numberofcorrect == 3){
System.out.println("Grade A, full score");}
if (numberofcorrect == 2){
System.out.println("Grade B, 2 of 3 ");}
if (numberofcorrect ==1) {
System.out.println("Grade C, 1 of 3");}
else {
System.out.println("You failed the test"); }
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Nov 18, 2014
I have read some on this but I'm trying to understand a code and the following part confuses me
if( thisCount == bestCount )
bestCandidates.add( candidate );
else if( thisCount > bestCount ) {
bestCount = thisCount;
bestCandidates.clear();
bestCandidates.add( candidate );
}
}
What I find confusing is this: If I am not mistaken the need for curly braces occurs when using more than one statement and if you use else statements.
So I wonder if I have missunderstood about the else statement and that you dont need curly braces around a one statement if statement that is followed by an else statement...
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May 18, 2014
I created a variable for the scanner called serena. Serena variable is equal to what the user inputs. My if statement says that if the answer the user enters is not equal to the actual answer then it is to display "wrong". It is a basic math game I am working on. NetBeans is telling me that I cannot use the scanner in an if statement?
package pkgnew;
import java.util.Scanner;
public class New{
public static void main(String args[]){
Scanner serena = new Scanner(System.in);
double fnum, snum, answer;
[Code] ....
Do I have to define Serena as whatever number the user inputs? If so, how?
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Dec 12, 2014
I am new to java and I am trying to write a program where someone has to guess the number. The correct number is 3. If they are below three. It tells them that they are too low and to guess again. If they are too high, it tells them they are too high and to guess again.
However, I am having problems once they enter a number and they get the response "The number was too low. Try again" as it lets them try again but doesn't tell them if it's right, wrong, or too high. I'm not sure what piece of code I am missing. Here is what I have so far:
import java.util.Scanner;
public class Guessthenumber {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Enter a number between 1-10.");
double value = input.nextDouble();
if(value == 3)
[Code] .....
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Jun 11, 2014
I have a small problem with my code that I can't figure out how to make it work the way it is supposed to. The code is supposed to be a game where a user has to guess numbers between 1-1000. The program counts how many times the user tried to guess the number and it displays a certain message if the guess number is less than 10, more than 10 or 10. I was able to write the code using loops. However, the messages will not always get printed on to the screen. The code seems to work fine except for the last part where the messages, "Either you know the secret or you got lucky", "You should be able to do better", "Aha! you know the secret!" are not always displayed like they are supposed to.
import java.util.Scanner;
public class Guess1 {
public static void main(String[] args) {
int secretNumber;
secretNumber = (int) (Math.random() * 999 + 1);
Scanner input = new Scanner(System.in);
int guess;
int replay;
int test;
test=1;
replay=1;
int count=0;
[code]....
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Mar 30, 2014
I'm having this where i'm trying to return a JPanel with tempPictures but only if they aren't already filled with "actual" pictures. However this causes problems because your never shore that the if statement will execute. I tried adding an else statement but i cant return null i must return a JPanel;
private JPanel buildTopShelf() {
if(myMediaHandler.mediaList.size() < 6) {
JPanel mediaPanel = new JPanel();
mediaPanel.setOpaque(false);
mediaPanel.setLayout(new GridLayout(1,6,22,0));
mediaPanel.setBounds(90, 14, 1020, 210);
[Code] ....
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Mar 18, 2014
I am familiar with Java but new to JSP. I have a Java Servlet app where user actions are recorded in a SQL Server database amd I now need to quickly put together a JSP front end application to view user actions. I want two drop down boxes to filter the results that will be displayed in a list box. What I need is the first drop down list box to show unique user names that have logged in. I can interrogate the database with the following SQL;
"SELECT DISTINCT(USER_ID) FROM AUDIT_MESSAGE"
Then when a user is selected from the first drop down list box (perhaps some sort of on change event) a second drop down list box shows the logins times of the selected user. Again I can interrogate the database with the following SQL;
SELECT SESSION_ID, EventTIME FROM dbo.AUDIT_MESSAGE
WHERE OPERATION = 'loginResponse' AND RESULTS = 'OK'
AND USER_ID = 'firstdropdownlistselection'
Then finally when a login time is selected in the second drop down list box all events for the selected user while logged in with that login time are displayed in the list box.
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