Generate Random 100 Numbers From 0 To 9 In Array - Count How Many Integers There Are
Mar 7, 2014
I'm trying to generate random 100 numbers, from 0 to 9, in an array using Math.random, but it only outputs 0s which is very confusing to me. Also, I need to be able to count how many different integers there are like 0s, 1s, 2s... 8s, 9s.
Here's my code, I only got as far as the array then got stumped on the counting part.
import java.util.Arrays;
public class countDigits {
public static void main(String[] args) {
//Create random generator and values
int numbers = (int)(Math.random() * 10);
int arrayCount = 1;
[Code] ....
and my results
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0
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Nov 8, 2014
So I need to generate 10 random integers in the range 1-20 but i have to store them in an array called numbers. Then I have to call a method called displayArray which displays the contents of the array and for the assignment i have to use a for loop to traverse the array. The method header for the displayArray method is:
public static void displayArray(int[] array)
This is what I have done
public class RandomIntegers {
static int numbers = 0;
public static void displayArray(int[] array) {
System.out.println(numbers + "Numbers Generated");
[Code] .....
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Jul 31, 2014
I tried out doing number (generated randomly) != (another number) but that does not work. If I for example want a number between 1 and 10, but I do not want the number 5, what can I do in order to make this happen?
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Mar 2, 2014
I am currently taking a class in the field. My assignment is to generate 6 unique random numbers using a "Do While" expression. I might be mistaken but doesnt the inner loop execute first and then it works its way out? With this logic I believe my code should work but then again its not.
public class DoLottery {
public static void main (String args[]) {
int max= 10;
int random;
int random2;
int random3;
[code]...
I originally had output at the end but decided to comment it out to see if code would execute if I placed it every time the test was true.
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Nov 9, 2014
I don't want to use an array. I do not know of a function built into Java to allow me to do this.
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Apr 24, 2014
I've just written a program that generates 100 numbers that range from 0 ~ 25 using arrays, the program calls another method that sorts the even numbers into a separate array and returns the array. I need it to display both arrays, however, when I run my program, the numbers of both arrays are mixed together, and I'm not sure how to separate them.
[ public class Array1
{
public static void main(String[] args)
{
int array [ ] = new int[100];
for (int i = 0; i < array.length; i++)
{
array[i] = (int) (Math.random() * 26);
[Code] .....
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Apr 1, 2014
Trying to generate random integers, based off user-input for amount of integers, and then sort them into an array. The problem is that the second method needs to be int[] but I cannot figure out what to make the return result. The instructions say it needs to be an int[] in the UML diagram, so I know it's not supposed to be void.
Java Code:
public void generateNewSecret() {
Random rand = new Random();{
for (int i=0; i<numDigitsSet; i++) {
secretNumber[i]= rand.nextInt(10);
System.out.println("" + secretNumber[i]);
[Code] .....
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Aug 2, 2014
To simulate it, the program will generate a random number between 0 and 19, which represents the location in the array (i.e. index number). Then, the 3 numbers to the left and right of this location should be reset to the value 0. If there isn't 3 numbers to the left and right you may assume a lesser number depending on the boundaries of the array.
How to reset the numbers to 0 in the final array ?
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Dec 8, 2014
What the fastest way to sort an array of random integers. My instructor told me to look into an algorithm that uses 2n, but that is all he gave me. I am unable to find anything of the sort (pun intended there) on google, in my text, in my other java books or on here. The only thing that I have come up with are things like mergesort with the exception that the indicies of the Array have to be even. The program that I'm writing takes user input for a minimum to maximum range, the amount of numbers to fill the array in that range, and verbose.
I've tried bubbleSort but it takes forever to sort under the conditions below. I have seen a sorting algorithm that uses n (log n) but didn't really understand how that one worked.
Using the 2n algorithm, I should be able to test the range from 1 - 1000 and have it populate an array of of 1,000,000 random integers. It should be able to complete in a matter of miliseconds.
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Feb 7, 2015
I have a problem where I have to create random integers from 1 to n + 1. When the array is displayed I have to find the missing integer from the values that are displayed and show that value. I have to use O(n^2) and O(n) operations. I have created this code so far but I cannot figure out how to make my values display n + 1. It is only displaying values 1, 2, 3, 4 and 5 in random order. I also cannot figure out how to find the missing value. I have created a boolean displayed statement but can't determine how to use it in this code.
=Java
import java.util.Random;
public class Task6
{
public static void main(String[] args)
{
int[] numbers = new int[7]; //create array of numbers
Random random = new Random();
boolean displayed = false; //boolean value to determine if number was displayed
[code]....
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Dec 8, 2014
The program I'm supposed to create generates a random number between one to ten. Then the program is to ask me if I wish to cross the road. If you choose to cross, the outcomes for 0-2 are "You crossed safely." For 3-5, 75% of the time it should say "RIP you got run over", and 35% of the time it should say "You crossed the street." For 6-8, 60% of the time it should say you made it.", and 40% of the time it should say "You died". For 9-10, it should say "RIP".
So far I have gotten the random number generation part working. I have up to here:
import java.util.Random;
public class test4 {
public static void main(String[] args) {
Random random = new Random();
for(int i =0; i < 1; i++){
int num = random.nextInt(10) + 1;
System.out.println("The number of cars on the street are: " + num + "Do you wish to cross the road?");
}
}
}
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Apr 22, 2014
I'm making a method to take an array of integers and rearrange the numbers from least to greatest, using for loops.
I'm getting the error "java. lang. ArrayIndexOutOfBoundsException: 8,
Portion of the ArrayMethods class with the sorting method
Java Code:
public static Integer[] sortArray (Integer[] a)
{
int swap;
for (int i = 0; i < a.length; i++)
[code]....
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Nov 10, 2014
For a project we have to "shuffle" items in an array using random numbers. We are supposed to generate random numbers and use those numbers to exchange array elements. But I am not sure what that means, "exchange array elements". Does that mean you generate 2 random numbers within the length of the array, and then switch the items at those locations in the array?
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Nov 21, 2014
I am writing a program that creates an array with random numbers. Then the user can choose what number of the array he/she wants to check the occurance of. This works fine, but the numbers generated seems very weird, only 2 of the 10 possible numbers are generated. 0 and one of the other 9 numbers, the 0 is always 10100 and the other one is always 101.
import java.util.Random;
import java.util.Scanner;
public class OppgaveC {
public static void sjekk() {
int randomArray[]=new int[101];
int countArray[]=new int[10];
Random rand = new Random();
[Code] ....
it also says i have a memory leak on my scanner, ow can i close this?
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Feb 15, 2015
I was inquiring about selecting random numbers from a Fibonacci array, the original post for which is here: Exiting a 'for' Loop Early. I have managed to achieve this with the following code:
System.out.println("Random numbers from the Fibonacci array");
for(int i = 0; i < limit; i++) //Limit is an 'int' of 15 & is set as the length of the Fib. array. I'm calling it for the Random array, too!!
{
Random dice = new Random();
int randomIndex = dice.nextInt(array.length); //The Fib. array was simply called 'array'!!
if (array[randomIndex] < 100)
{
System.out.print(array[randomIndex]+ " ");
}
}
When the code prints I get a random set of numbers which occur in the Fibonacci sequence preceding it. However, the actual length of this Random array also changes each time, and never more than the limit of 15 specified in the 'for' loop. What I want to try and do is print the Random array with a specific length each time. I've tried changing the conditional statement of the 'for' loop in different ways to set the Random array's length, but had no luck.
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Oct 1, 2014
Is my code right for this pseudocode:
<Declaration of the array for storing random integers and other necessary variables and / or constants. >
private int numbers;
private int max;
private int[] integer;
private Random generator;
public integer ( int n, int m )
[code]....
I need to create a program that draws random numbers and stores them in an array. How many numbers to be drawn is dependent on the array length, which is a parameter in the class constructor. (The entire array to be filled!) The program shall, however, just save the figures are not drawn already. (Ie, the array must contain only one instance of each numeral.) All figures drawn should be in the range of 100 to 1000, both limits included. These limits are defined as named constants. When all the numbers are generated and stored in the array, the program should find the largest, smallest and average value of the numbers in the array. In addition, it should find the value closest gjennomnstittetsverdien.
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Mar 10, 2015
Create an integer array with 10 numbers, initialize the array to make sure there are both positive and negative integers. Write a program to generate two arrays out of the original array, one array with all positive numbers and another one with all negative numbers. Print out the number of elements and the detailed elements in each array.
public class problem3 {
public static void main(String[]args){
int[] numbers = {1, 2, 3, 4, 5, -1, -2, -3, -4, -5};
for (int i = 0; i<numbers.length;){
if(i>0){
System.out.println(numbers);
}
else
System.out.println(numbers);
}
}
}
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Jan 16, 2015
How would I get java to generate a random number from 0-2? all I've been able to find on random numbers is math.random which gives you from .0 to .10. you can multiply this by 10 to get 1-10 or by 100 to get 1-100 but how to make it so java will simply let me tell it the rand of numbers I want or get a random number in a range that is not a multiple of 10. and I can't seem to find anything about it anywhere.
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Jun 30, 2014
I have an array with the following characters {'E', 'L','E','P','H','A','N','T','P','O'}
now, I need an array that will store the first array such that only the occurence occurs e.g {'E','L','P','H','A','N','T','O'} Notice that the characters 'E' and 'P' occur twice and as a result were not repeated the second time in the new array.
How would one go about this using the counting elements technique?
I tried this but not sure how to use the counting elements technique.
char [] arr = new char{'E', 'L','E','P','H','A','N','T','P','O'};
char[] bucket = new char[(arr[0] * arr.length)];
for (int i = 0; i < len; i++)
bucket[arr[i]]++;
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Aug 31, 2014
I am trying to get random shapes to generate automatically. I was able to get just three shapes to generate but nothing random. When I added the random code now only the frame shows up and no shapes. I also keep getting an error with frame.setVisible(true). It says identifier expected. Here is what I have so far:
Main program:
import javax.swing.*;
import java.awt.*;
import java.util.Random;
public class ShapeGen {
public static void main(String [] args) {
//Create window and set title
draw panel = new Draw();
[Code] ....
This is the draw program to generate random shapes:
import javax.swing.*;
import java.awt.*;
import java.util.Random;
public class draw extends JPanel {
public draw(Color backColor) {
setBackground(backColor);
[Code] .....
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Apr 16, 2015
I have my code which will generate a random string using an ArrayList. However, I aso want to have it generate them in random lengths, not just using all the chars and numbers.
public static void main(String[] args) {
String[] CHARS = {"A","B","C","D","E","F","G",
"H","I","J","K","L","M","N",
"O","P","Q","R","S","T","U",
"V","W","X","Y","Z","1","2",
"3","4","5","6","7","8","9","0"};
List<String> pass = Arrays.asList(CHARS);
Collections.shuffle(pass);
for (String chars : pass) {
System.out.print(chars);
}
}
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Apr 12, 2011
how to code the generated a random number from 100 to 150 inclusive for an applet
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Mar 14, 2015
The program is supposed to generate random dice rolls using the get and set methods. If the user doesn't specific how many sides the dice have, then it defaults at 6 with the constructor. The program runs but its generating 0's.
import java.util.Scanner;
public class RollOfTheDice
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
System.out.println("Time to roll the dice, how many sides do they have?");
int numSides = input.nextInt();
[Code] ....
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Jan 21, 2015
I have 2 classes a main one and another class. In the other class I have a method that has:
String gInfo(){
String[] Behavior = {"Sleeping", "Running home", "Studying", "playing pool", "walking to class"};
int rNum = (int) (Math.random() * Behavior.length);
return Behavior[rNum];
}
I call the gInfo() in the main class and run it through a loop 20 times. What I'm trying to do is get it to count the number of times that each behavior happens. and how to get it to work correctly.
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Apr 30, 2015
I am trying to make a method that generated a random number between two values that can be negative or positive.
So:
rand(-0.2, 0.2);
would give one of these: -0.2, -0.1, 0, 0.1, 0.2
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Mar 12, 2014
Instruction: You work for a telemarketing company and you are required to write a JAVA program that will generate a random phone number. (talk about a real-world application)
-The phone number should consist of 10 digits
-The first 3 are the area code and should not begin with 0, 8 or 9
-The second 3 digits should not be greater than 742 and not less than 100.
-The last 4 digits can be any digits
-Print the number using the following format: "(xxx)-xxx-xxxx", this way it will look like a real phone number (use decimal formatting)
by this : Generating Random Numbers
Using arithmetic operations
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