Getting Char At A Location In String
Oct 21, 2014
I found a fun program online and something so simple is giving me an issue. I c++ it is pretty simple fix, I can just call the strings location like an array. In java this is not the case. So far i have tried:
myString.charAt();
myString.indexOf();
There are a few other I found on google but I forget at the moment. I am just trying to close the gap on a string. It was a full sentence and I used replaceAll a few times to get several words I didn't want in the file out.
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Oct 14, 2014
I need making char[] to a string im not entirely sure what to change i'm just suppose to use a string value but the upperclassmen used char:
char[] number = clear.toLowerCase().toCharArray();
for(int c = 0; c < number.length; c++) {
if(digit[c] < 'a' || digit[c] > 'z')
continue;
[code]...
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Mar 16, 2014
I can't figure out how to have all of the random characters generated to go into the String. Below I can only get the last character to covert over to a String.
System.out.println("Original random character string:");
String printingString = "a";
for (int i = 0; i < 50; i++)//loop to obtain 50 random characters
{
char randomChar = (char) ((Math.random() * 255) +32);
System.out.print(randomChar);
printingString = Character.toString(randomChar); }
return printingString; }
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Apr 30, 2014
what will i compare in if statemet is the 1st letter of each if i have code="a" and name="Angelina" first letter of each is "a" and "A" then in convert it to string so that i can make it uppercase but when i compare it in if statement it always go into "not x" but the ouput that im getting is x=A y=A then it always direct me into else statement.
String code = "a";
String name = "Angelina";
char c = code.charAt(0);
char n = name.charAt(0);
[code]...
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Apr 1, 2014
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string.
Example: the string Welcome and the letter e, is 2 times. so the program should print 2.
It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
[Code] .....
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Jun 5, 2014
I am trying to count each char in a string. For example A = 1, B =2, C=3, I am not looking for their binary value. So the word "At" would
AT= (A=1 +T=20)=21.
I know how to do this in C++ because I am able to treat a string like an array.
Java Code: void printFile()
{
int sum=0;
String line;
for(char cr ='A';cr<'Z';cr++)
{
for(int i=0; i<myList.size();i++)
[Code]...
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Aug 3, 2014
import java.io.IOException;
import java.util.*;
public class Guesser {
public static void main(String[] args) throws IOException {
char[] alphabet = "abcdefghijklmnopqrstuvwxyz1234567890 .,:;'-".toCharArray();
[Code] .....
I'm writing a program which will take a three letter word (for now) and then try to guess the word over and over again until it finds it, then print the word and the amount of tries it took to find it.
The problem: at the moment the program will find the word but not break out of the for loop when it does. I think it doesn't like the char to String conversion somewhere along the line.
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Mar 30, 2014
I want to cut my string from space char but i am getting exception....
Java Code:
import java.util.Scanner;
import java.util.StringTokenizer;
public class NameSurname {
public static void main(String args[]) {
Scanner sc=new Scanner(System.in);
String s0,s1=null,s2 = null,s3=null;
s0=sc.next();
[Code] ....
Console:
Lionel andres messi
Exception in thread "main" java.util.NoSuchElementException
at java.util.StringTokenizer.nextToken(Unknown Source)
at java.util.StringTokenizer.nextToken(Unknown Source)
at com.parikshak.NameSurname.main(NameSurname.java:15) mh_sh_highlight_all('java');
I/p -O/p:
my s0=Lionel andres Messi
And I want to break it as soon as i find space and save it in s1,s2 and s3
s1=Lionel
s2=andres
s3=messi
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Apr 1, 2014
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string. Example: the string Welcome and the letter e, is 2 times. so the program should print 2. It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
str=user_input.next();
[Code] ....
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Apr 3, 2015
I have a simple doubt. I was studying and create some code to check the result and I found out a strange situation.
Whats wrong with this code? Why it does not print anything?
char = 0; //integer value
System.out.println( c +" String ");
and why this next works very well?
char = 1; //integer value
System.out.println( c +" String ");
I know that char is stored as a positive integer and assign with 0 is different of assign with '0'.
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Feb 13, 2015
I'm trying to find a word in an array of char.....but I'm stuck. How to formulate the code to step through the array and pick out the word. This is what I have so far...
public static void searchAcross(String string, char[][] puzzle) {
// Gets the number of rows in the matrix
int rowLength = puzzle.length;
//Gets the number of columns in the matrix.
int colLength = puzzle[0].length;
[Code] ....
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Feb 8, 2014
What I'm trying to do is compare String input to a char array. Let me make it a little more plain, I'm working on a cipher assignment, and my line of thought is this: I will get String input from the user, COMPARE the characters in the string input to an alphabet array, which will then be compared to the cipher array so that the cipher's counterpart can be chosen over the alphabet's. Any way that I might compare the random input keyed in by the user to that alphabet array?
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Aug 25, 2014
I am trying to figure out how to convert a string of ASCII code into char.I know that you can use (char) to convert it, but the issue is you cannot really just it for Strings.
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Apr 17, 2015
Processing a string. How would I only return a given char that matches the input string e.g. v and/or n and/or m.
Everything else that does not match will return a '*' - e.g. user input = t result = *
I assume I need to also iterate through this input string using charAt() ?
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Jan 6, 2014
I have written the code:
Java Code:
public static void main(String[]args)
{
Scanner input = new Scanner(System.in);
System.out.print("Type your text: ");
String text = input.nextLine();
int counter = text.length();
if(text.length()> 16)
[Code] ....
And input is: abcdefghijklm
output is:
Java Code:
a b c d
e f g h
i j k l
m x x x mh_sh_highlight_all('java');
So all i want is, if i type: abcdefghijklm
I want this output:
Java Code:
a e i m
b f j x
c g k x
d h l x mh_sh_highlight_all('java');
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Apr 12, 2015
I have an array of Strings, one on each line and I need to convert them into an array of char's.
For Example:
This
is
an
Example
of
what
my
input
is.
In order to accomplish that I did the following-
String[] lotsOfText = a.gettingAnArrayAsAReturn();
char [][] myCharArray = new char [lotsOfText.length] [lotsOfText.length];
for(int i=0; i<lotsOfText.length; i++){
for(int j=0;j<lotsOfText[i].length();j++){
myCharArray[i][j] = lotsOfText[j].charAt(j); }}
But whenever I try this and then try to print the output :
for (int i = 0; i < lotsOfText.length; i++) {
for (int j = 0; j < lotsOfText[i].length(); j++) {
System.out.print(myCharArray[i][j]);
}
}
I get nothing. I'm not sure what's the flaw in my logic, is it the char array initialization that's wrong or is it something else ?
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Nov 16, 2010
I have a string array but each cell in the 1d string array stores each character the text file is :
"START START START
The quick brown fox jumps over the lazy dog 1234567890-= !"$%^&*()_+ QWERTYUIOP{}ASDFGHJKL:@~|ZXCVBNM<><? /.,mnbvcxzasdfghjkkl;'#][poiuytrewq789654123.0
+-*/``""$% hello this is a test file using all the characters availible on the keyboard for input END END END END"
so in the string it is:[0] = S, [1]=A, [2]=R ...ect along the text basically i need to convert each character in each cell of the 1d string array to its hesidecimal value..i have created my own method which will take in a char and return a string containing the charcters hex value.
public static String toHex(char c) {
char char2ascii = c;
int i = 0;
int num = (int) char2ascii;
String hex ="";
[code]...
what i want to do is run each cell through the toHex method so i eventually have a string array containing the hex value of each character in my text.
example..i want:
String[] hexarray = S, T, A, R, T
a run it through my method to convert to hex then it will become
String[] hexarray = 53, 54, 41, 52, 54
Im not allowed to use inbuilt libarys and classes to do the hex conversion thats why i have my own method for it .
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Mar 10, 2014
How to specify the file location. One way would be
PrintWriter outputFile=new PrintWriter("A:PriceList.txt");
My problem occurs when I try to specify a file location as show below
//Open an output file that appends data and does not delete it
FileWriter append_data=new FileWriter("C:hello.txt",true);
//Make a file that cvan print data into it
PrintWriter outputfile=new PrintWriter(append_data);
Apparently, I believe this is not the right way to set my own path for the file... How can I specify my file path.
One more question would be that suppose I want to specify the file location on Desktop. What the format for that?
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Sep 16, 2014
I'm trying to mark a list of locations on a map. probem is how to get this list object inside javascript? This is the JSP
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<%@ taglib uri="/struts-tags" prefix="s"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
[Code] ....
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May 8, 2014
I am writing a small app to automate some actions on my computer this requires me to open an application and click on a button I am using
Process child0 = Runtime.getRuntime().exec("/home/user/application");
to do this. The problem is every time it opens at a different lcation on the screen so i cannot click on it using the robot class due to x,y coordinates being different every time. with selenium you can use .setlocation(x,y) method but how can this be done for other applications.
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Jan 28, 2014
how to delete the files from ftp location
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Jan 28, 2014
Aatrox
Champions@3622e177
Champions@4805e9f1
Champions@57e40274
Champions@354124d6
Champions@262f4813
Champions@64f01d52
Frozen Heart
Randuin's Omen
As you can see instead of displaying the champion name it is displaying the memory location and I do not know how to fix it.
class Champions
{
String name;
Champions [] weak = new Champions [3];
Champions [] strong = new Champions [3];
String [] items = new String [3];
public static void main (String [] args)
{
[Code]...
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Aug 1, 2014
I'm trying to copy a exe file from one location to another. It seems simple, but I have failed to find anything about it besides coping the contents in txt files, but that does nothing for executable.
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Jul 15, 2014
For some reason my code returns the memory address of the array when its a print statement with a string, but it works fine when its in a separate print statement all by itself. Why? Do I need to create a toString method that converts a char array to a String to something? The reason why I ask that is becuase on Eclipse line 10 has a warning stating "Must explicitly convert char[] to a String".
public class Ex {
private String word;
public Ex(String word) {
this.word = word;
}
public char[] Display(){
char[] wordChars = this.word.toCharArray();
return wordChars;
[Code] .....
Result:
Hello world
The word is: [C@1db9742
I also tried this, knowing that it's a long shot, but that didnt do anything...
public String toString(){
Ex ex = new Ex(this.word);
char[] word = ex.Display();
String updated = word.toString();//counter intuitive?
return updated;
}
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Apr 26, 2014
The file (let's call it file.txt) is on the C: of my machine. I'm using :
System.out.print("Where is the file?: "); BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
And looking for the user to enter the location of the file in the console. How do I (the user) enter the path to the file in the console. I have tried everything... "C:file.txt", C:file.txt, and a million other combinations. Nothing seems to work. How does the console expect the file path to be written so it knows how to pick up the file?
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Feb 9, 2014
My project was to create an array holding 10 integers and populate the array with 10 random numbers. Then ask the user to guess the number. Prompt the user with a while loop if their input is out of range. Determine if the users number is in the array, and display which index location the number is in. I got most of the code done but am having trouble displaying the index location.
import javax.swing.*;
public class Homework4 {
public static void main(String[] args) {
int[] numarray = new int [10];
char repeatcode = 'y';
[code]....
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