How Can Two Same Integers Be Interpreted As Different Numbers
Sep 12, 2014
I have a code like following. x and y are both Integers and have same values (e.g. 5). But they are interpreted as different values. Then, it validates the following condition.
Java Code: if (x != y) {
"x and y are different..."
} mh_sh_highlight_all('java');
I want users to input their phone Number But I want to make sure it is a phone number so they don't just do 1 and then leave it.
public static void main(String[] args) { // Create the Scanner Scanner in = new Scanner(System.in); // Create the Variables int phone; if(phone > 100000000000 || phone < 100000000000) { System.err.println("Error"); }
By the Way there are 12 digits in the if statement so that is 11 0's. Because all phone numbers are 12 digits.But when I run it, it comes up with an error saying The literal 100000000000000000000 of type int is out of range.I don't know how to make it so that the int has a limited number.
I want users to input their phone Number But I want to make sure it is a phone number so they don't just do 1 and then leave it.
public static void main(String[] args) { // Create the Scanner Scanner in = new Scanner(System.in); // Create the Variables int phone; if(phone > 100000000000 || phone < 100000000000) { System.err.println("Error"); }
By the Way there are 12 digits in the if statement so that is 11 0's. Because all phone numbers are 12 digits.But when I run it, it comes up with an error saying The literal 100000000000000000000 of type int is out of range.I don't know how to make it so that the int has a limited number.
I'm trying to generate random 100 numbers, from 0 to 9, in an array using Math.random, but it only outputs 0s which is very confusing to me. Also, I need to be able to count how many different integers there are like 0s, 1s, 2s... 8s, 9s.
Here's my code, I only got as far as the array then got stumped on the counting part.
import java.util.Arrays; public class countDigits { public static void main(String[] args) { //Create random generator and values int numbers = (int)(Math.random() * 10); int arrayCount = 1;
This program simply adds integers to an ArrayList and then prompt the user if they would like to delete specific numbers that they don't want.
The output that I get when I want to delete numbers like 2 and 4 from 1 2 3 4 5 is 1 2 3 4 5 instead of 1 3 5.
Java Code:
import java.util.ArrayList; import java.util.Scanner; public class AL { // A regular array like int arr[] has to have its size declare before run-time and it's not dynamic which mean it can not grow or expand on its own. static Scanner input = new Scanner(System.in); // You have to use reference types(Integer, Double, Float); not primitive types(int).
I tried to create file and write the output of my program in it in java when i use WriteLong then the file does not contain long value, how I create this file my program is to print prime numbers between 500000 to 10000000
public class primenumber { public static void main(String[] args) { long start = 5000000; long end = 10000000; System.out.println("List of prime numbers between " + start + " and " + end); for (long i = start; i <= end; i++) { if (isPrime(i)) { System.out.println(i);
I've just written a program that generates 100 numbers that range from 0 ~ 25 using arrays, the program calls another method that sorts the even numbers into a separate array and returns the array. I need it to display both arrays, however, when I run my program, the numbers of both arrays are mixed together, and I'm not sure how to separate them.
[ public class Array1 { public static void main(String[] args) { int array [ ] = new int[100]; for (int i = 0; i < array.length; i++) { array[i] = (int) (Math.random() * 26);
I'm trying to make a program that generates 20 random integers between 1 and 20 and then prints the list of random numbers to the screen. After that, I want to print a different list to screen with the same numbers from the first list only skipping any number that has been already printed to the screen. So two lists are printed to the screen. The first one has 20 random numbers. The second one has those same 20 numbers but only prints the numbers in the first list that aren't duplicated. So if m
y list of 20 random integers contains three 2s and two 14s, only one 14 and one 2 is printed to the second list. Currently, my code generates 20 numbers from 1 to 20 and stores those numbers in an array but I don't know how to print solve the second part of my problem. I don't know how to print the s different list only without duplicate numbers. As a result, my output is nothing because it doesn't print any number from the first list as oppose to skipping only duplicate one.
public void randomNum(){ System.out.println("Twenty random integers: "); int max = 20; // max value for range int min = 1; // min value for range Random rand = new Random(); int[] all = new int[20];
I have to make a program that prompts the user to enter 10 numbers and at the end it prints out the distinct numbers and then the other numbers that weren't repeated...
I have the part where it prints out the distinct numbers but I stuck on how to make it print out the other numbers that didn't repeat...
import javax.swing.JOptionPane; public class DistinctNumbers { public static void main(String[] args) { String getInput; int input; int[] numbers = new int[10];
Create an integer array with 10 numbers, initialize the array to make sure there are both positive and negative integers. Write a program to generate two arrays out of the original array, one array with all positive numbers and another one with all negative numbers. Print out the number of elements and the detailed elements in each array.
public class problem3 { public static void main(String[]args){ int[] numbers = {1, 2, 3, 4, 5, -1, -2, -3, -4, -5}; for (int i = 0; i<numbers.length;){ if(i>0){ System.out.println(numbers); } else System.out.println(numbers); } } }
I tried out doing number (generated randomly) != (another number) but that does not work. If I for example want a number between 1 and 10, but I do not want the number 5, what can I do in order to make this happen?
Program is to list all prime numbers between two entered numbers.
import java.util.Scanner; public class question6 { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println("Enter lower int:"); int x = input.nextInt();
After the code is executed the array is supposed to contain 2,3,5,3,2. However, prime[4-0]= prime[i] and prime[4-1]= prime[i]... doesn't the loop terminate before it iterates a third time? Why are there five integers instead of only two?
import java.util.Arrays; import javax.swing.JOptionPane; public class Student { public static void main(String args[]) { String [] A =new String [4]; //krijon tabelen e emrave
[Code] ....
It Prints [firstname,secondname,thirdname,fourthname]
and [0,0,7,9]
The problem is that the first 2 integers of the second array are always 0 even if i put another grade like for example 6 or 7...
Our teacher asked to input the names and grades of the students using JOptionPane and then find the MINIMUM grade and how many times this grade is repeated...
Create a loop where you add the integers from 1 to 50.
public class Sum50 { public static void main(String[] args) { int sum = 0; int max = 50; for(int i = 0;i <= max; i++){ sum=sum+i; } System.out.println("Sum is " + sum); } }
I need to write a class in that uses the For loop and does the following things: asks user to input two integers, the second larger than the first. Next, use a for loop to sum the numbers between the two integers, including the original integer. For example: 5&8 would be 5+6+7+8 and lastly prints out the sum of this.
I have successfully been able to do the first part but when it comes to the For Loop I am a bit lost here is what I have so far
import java.util.Scanner; public class Question3 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("Please enter an integer"); int num1 =sc.nextInt(); System.out.println("please enter a larger integer"); int num2=sc.nextInt(); int sum=0; for(int i=num1; i<=num2;i++); } }
I have this code running correctly in Eclipse all except that it seems no matter where I declare, highest, lowest, average they always seem to stay at "0". I have a feeling the location of the Initialization is not the error since I have tried moving it to inside differ loops.
Stipulations on writing this code are:
Note: You do not need to use array to save each input score for this lab. A Single loop to read in each grade, compare with the current highest grade, lowest grade, and calculate the running sum at the same time.
import java.util.Scanner;
/*Write a program that prompts the user to enter the total number of students first. *Then ask the user to input each student’s grade and use loop statements to read in each grade. *Check input grade to make sure 0<=grade<=100, if the user input any other number, print out warning message and ask the user to input a new grade. Display the highest score, the lowest score and the average. */
public class LoopStatements { // Main Method public static void main(String[] args) { // Initialize int grade = 0; // grade value
my code is below and i want to read only integers.BUT the text file is starting with text and it stops executing without reading the numbers.Also i want to add the 3 parameters of each line.
try{ File fl = new File("C:/Users/Mario/Desktop/testing.txt"); //BufferedReader rd = new BufferedReader(new FileReader(fl)); Scanner sc = new Scanner(fl).useDelimiter("s+"); LinkedList<Integer> temps = new LinkedList<>(); sc.useDelimiter(System.getProperty("line.separator")); while(sc.hasNext()){
CommPortIdentifier portIdentifier = CommPortIdentifier.getPortIdentifier(port); if (portIdentifier.isCurrentlyOwned()) { System.out.println("Error: Port is currently in use"); } else { CommPort commPort = portIdentifier.open(this.getClass().getName(), 2000);
[Code].....
To set the serial port parameters i need to use Integers instead of strings.
I am trying to write a method that returns the busiest hour in a logAnalyzer class that read web server data and analyze hourly access patterns and stores them in an array. My problem is, in order to get the busiest hour, I need to go through the hourCounts array to find the element with the biggest count.
Develop a method that accepts as data input three integer numbers, calculates the sum and the product of the numbers, and displays the sum and product.
1. Prompt the user to input two positive integers: firstNum and secondNum (firstNum must be smaller than secondNum). 2. Output all the even numbers between firstNum and secondNum inclusive. 3. Output the sum of all the even numbers between firstNum and secondNum inclusive. 4. Output all the odd numbers between firstNum and secondNum inclusive. 5. Output the sum of all the odd numbers between firstNum and secondNum inclusive.
*Use while loop int firstNum, secondNum; Scanner keyboard = new Scanner(System.in); System.out.println("Enter an integer: "); firstNum = keyboard.nextInt();
[Code] ....
What to do with the while loop and how to find even and odd numbers.