How To Access Files In Shared Folder
Apr 25, 2014I need to access and view files/foldersand if possible i can download from shared folder from other system using java
View RepliesI need to access and view files/foldersand if possible i can download from shared folder from other system using java
View Repliesi have some jsps under WEB-INF folder and as i know that they cant be access directly. so how can i access those jsps.
View Replies View Relatedwant to open a directory from java program in Ubuntu When i use exec(path) it says access denied.
View Replies View RelatedWhenever I try accessing the appdata folder from my applet it gives me the following error:
java.io.FileNotFoundException: C:users<user name>AppDataRoaming est est.class (Access is denied)
What is wrong with my code? System.out.println prints the correct name, but it fails when i try to rename the files in a directory.
import java.io.BufferedReader;
import java.io.IOException;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import java.io.*;
import java.io.File;
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i have to save some particular info of a pdf file info into a database.there are lots of folders with tons of pdf files to be analized and then getting that info saved. make the process incremental? i need the program to stop at some point. and then continue to analize the resting files in the folders (i dont want the program to start all over again from 0 )my ideas are..sorting all the files using apache commons sort (by date) method (iv seen it somewhere) and saving the last file analized in the dabatase to then continue. OR just adding some extra character to the pdf file name that has been analized like for example xx-xxx.pdf to xx-xxxa.pdf.
View Replies View RelatedHow to allow the user to select several files from one folder in the JFileChooser and copy them in a subfolder in the same folder, or another folder?
View Replies View Related-I created the project with the checkbox "Create separate folder for sources and class files."
-I've tried running the program with the "mfq.txt" file in the root directory, the src directory, and the bin directory.
-I've even tried it in all three directories at once!
-I've also refreshed my project after each change in eclipse
-My error is the "FileNotFoundException" error
Here is the line giving me trouble
Scanner file = new Scanner(new File("mfq.txt") );
Where my code is wrong/where I should put my file? :tax:
I am currently using the following Rally API Java code(below...in Java 1.7) to create an object and attach a file to it. This code works fine. But I need the code to be a little less specific and attach all files located under a folder (not just one file). How could one potentially rewrite this code (or use a different constructor/method) to accommodate such a thing? Also additional code how to narrow down results to all files with a creation date >= today.
Java Code:
import com.google.gson.JsonArray;
import com.google.gson.JsonElement;
import com.google.gson.JsonObject;
import com.rallydev.rest.RallyRestApi;
import com.rallydev.rest.request.CreateRequest;
import com.rallydev.rest.request.DeleteRequest;
import com.rallydev.rest.request.GetRequest;
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I have a requirement to read all the xml files from a parent folder and write in a spreadsheet(separate spreadsheet for each xml file)
I have written the below code in which xml and excel file name are hardcoded. The format of xml file is same.
package xmlexcel;
import org.apache.poi.hssf.usermodel.*;
import java.util.ArrayList;
import java.awt.List;
import java.io.*;
import java.util.ArrayList;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.xml.sax.SAXException;
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In the current program I am trying to read multiple text files from a folder. I keep getting the following syntax error
"Syntax error on token ";", { expected after this token".
I highlighted the line where im getting this error in red.
import java.io.*;
import java.util.*;
public class CacheData {
// Directory path here
String path = "C:myfiles*.txt";
[Code] ....
I have a matrix int[][] and I want it to be accessible to all jsp files.
The code is:
int[][] matrix = methodThatGeneratesTheMatrix;
How can I access/use this matrix in all jsp files?
I need to copy a file from Windows folder to unix folder using Java
I need a FTP utility.
The file is processed by a Java program and the file has to be written to Unix folder
I have the unix server name and folder name.
how to do it?
I am currently building a Plugin system for an application and I wanted to add a little security feature.
I have read many tutorials on this and they basically all came down to the same answer:
"Its complicated: You need a custom class loader and security manager and ... and even then its still tricky"
So I thought, before I load the classes dynamically I will simply read the class files. Why bother with a SecurityManager or ClassLoader if I can simply whitelist all allowed classes and search for all illegal Class access before I even load anything.
Where can I learn or how can I, being the most efficient way known to do so, create a folder outside my JAR file with the java source code, this then will copy YAML documents from my JAR file to that folder, then I need to read the YAML documents some way. I'm making an addon for a game, I am using an API that allows you to make a config.yml easily, and add and read entries from it, but I've read that I need to make my own methods to be able to create additional YAML documents.
I don't exactly know what to type in google to perhaps find such a page, but I did try to find a tutorial page about this or something and couldn't.
I've partially figured out how to create a folder, but I have a problem, how can I RETURN one directory to make the folder, I don't want to make the folder in the JAR file I want to make it just outside the Jar file in the same folder that the Jar file is at.
Which application i need to download and set up ?
Means like in php we can install xampp and there for a new app we need to create a folder in htdocs folder...and after that , that folder works like a app.
I am trying to use a BoxLayout to make the equivalent of the vertical flow layout within a JPanel. I followed this tutorial: URL..., but was a little confused as to what the first argument in the constructor for the BoxLayout is (the tutorials that it was "the container that it manages," but I don't know what that means). All the examples I can find online just have the first argument as what ever kind of component they are trying to initialize using the BoxLayout, so I tried that but it produces the error "BoxLayout cannot be shared. "Here is my code:
//Main class
public class TestProject
{
public static void main(String[] args)
{
GUI mainWindow = new GUI();
mainWindow.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
mainWindow.setSize(1000,1000);
mainWindow.setVisible(true);
[code]....
Can method variables be shared between users?
I was asked this on an interview and I didn't know what to make of it.
My adventures with XMLEncoder continue...
I've got a simple main routine that instantiates two structurally identical classes, and attempts to write them both out to System.out with an XMLEncoder:
package xmlencoding;
import java.beans.XMLEncoder;
public class Twice {
public String name;
public static void main(String[] args)
[code]....
I expected Line 16 and Line 24 to both write some XML-formatted output, looking very similar to each other. But here's my output:
<?xml version="1.0" encoding="UTF-8"?>
<java version="1.8.0_05" class="java.beans.XMLDecoder">
<object class="xmlencoding.Twice$C1" id="Twice$C10">
<void class="xmlencoding.Twice$C1" method="getField">
<string>him</string>
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Now, if I change Line 24 so that the second call to writeObject is to a different stream("23. XMLEncoder e2 = new XMLEncoder(System.err);"), I do get both outputs:
<?xml version="1.0" encoding="UTF-8"?>
<java version="1.8.0_05" class="java.beans.XMLDecoder">
<object class="xmlencoding.Twice$C1" id="Twice$C10">
<void class="xmlencoding.Twice$C1" method="getField">
<string>him</string>
[code]....
So, I am inferring that this means two XMLEncoder objects can't both hold references to the same OutputStream, even if the first object is closed before the second is created. In actual practice, I guess I can live with that, since I wouldn't write the XML-encoded version of two objects to the same stream (I'd get the header twice in the same file, and I believe that's a no-no). But I am surprised that this doesn't generate some kind of exception, either when the second XMLEncoder is constructed, or when its writeObject method is called. But, it just silently dies.
I have several private jars which are linked to my project and I need them to write and read values tofrom the same b-dimensional array. Actually I need a single array which in which my app and its linked jars will write to and read from it. How can I achieve that?
View Replies View RelatedWhat step to know to develop software..
View Replies View RelatedIn a program I created, I'm using a text file that contains some texts needed for the program. The method relevant to this is something like the following.
private String wordgen(){
try {
BufferedReader reader = new BufferedReader(new FileReader("src/Resources/adjectives.txt"));
Random rand = new Random();
int low = rand.nextInt(400);
String fil="";
int i=0;
while(i!=low){
[Code]...
The program runs fine in netbeans project but once the jar is created it does not corporate with the text file. ("null" is returned) How can I attach text files to jar and exe?
I am creating a very simple webpage where I am using just a little bit of JSP to include partials (header, footer and asides) that are centrally located. One of the constraint that the site owner has put is that, for SEO reason, he wants to keep the url's the way they are. Most of the pages are located in the same folder, except for one which is in a subfolder.
Here is my problem, I have the partials in a folder and at the same level the images. Now, for that page located in the subfolder, when I include the partials, it is not able to locate the images because they are located in a folder one level up. What I could do is create a copy of the image folder in the subfolder or an adapted copy of the partials (referring to the images one level up), but either solution would make for a maintenance nightmare and repeat information on the server.
Here is a visual representation of my file system:
- Top level folder
- Partial_Folder
- header.html
- footer.html
- images
- picture_1.jpg
- Page_1.html
- Page_2.html
- Another_Folder
- Page_3.html
I am creating a bukkit plugin, but my question has nothing to do with bukkit, just Java. I am trying to load a file that is located in the same folder as the jar file that is being run and I am having no luck. I can't set a manual path because if I move this plugin to a remote server it won't work. So how to get a file from the same folder as the jar.
View Replies View RelatedI have developed small program which read file from particular folder, i used method "getfilename" to read file name but system raise an error.
how can we read file name instead of completion path of file.
Within my program I allow users to write their own code to be executed. I then save that code in a .java file and then compile. This gives me a .java file and a .class file within the same package in the src folder. However, the compilation process also creates a .class file in the build folder. When the user edits their code and then re-runs it, the .class file in the build folder does not get updated with the new data, but the .class in the src folder does.
What I want to do is to execute the .class file in the src folder and not the build folder. So far I have the following method, but that somehow refers to the .class file in the build folder:
public void runMethod(String packageFilePath, String className){
try{
URI fileURI = new URI("file:/src/uk/learningAid/UserInputs/");
URL url = fileURI.toURL();
URL[] urls = new URL[]{url};
[code]....