This SHOULD be a simple program, the gist of it is Given an element E and the array A that represents a set X (user input), write a program that determines whetherE is an element of X.I have the array list all set up to take the user input and make zero the last element of the array. I want user to input numbers into array, then have fixed numbers for E and check to see if E is in the Array. I guess I'm not sure how to check the array and see if E is in the array? Here is what I have so far...
import java.util.ArrayList;
import java.util.Scanner;
import java.util.List;
import java.util.InputMismatchException;
public class Set {
public static void main(String[] args) {
List<Integer> userInputArray = new ArrayList<Integer>();
I have an assignment and one of the prompts is to do a binary search on an array if and only if the array of Strings is sorted. The binary search part I think I have completed, but it is the sorted array check that is throwing everything off. If the array is already sorted, return true; else, return false.
// Check if the array is sorted public static boolean isSorted(String[] arr) { //for (int i = 0; i < arr.length-1; i++) //{ //if (arr[i].compareTo(arr[i+1]) > 0) //return false; //} String[] arrSorted = arr; Arrays.sort(arrSorted);
/** * Auto Generated Java Class. */ import java.util.*; public class Hangman { public static void main(String[] args) { Scanner input = new Scanner (System.in); int guess; boolean revealed[] = {false, false, false, false, false}; String word [] = {"c", "a", "n", "a", "d", "a"};
[Code] ....
I am not sure how to make the program check if the letter entered by the user matches the one in the array. also i am not sure how to make the program run again with a new word.
Nested for-loops always throw me in a loop.I found a snippet that uses 2 for-loops to check if there is a duplicate element in the array:
/* * brute force way of checking if array contains duplicates in Java comparing each elements to all other elements of array complexity on order of O(n^2) not advised in production */ public static boolean bruteforce(String[] input) { for (int i = 0; i < input.length; i++) { for (int j = 0; j < input.length; j++) { if (input[i].equals(input[j]) && i != j) { return true; } } } return false; }
Let us say we have: String[] input = new String[] {"one","two","three","one"}
I am having trouble figuring out how to check for win in tic tac toe, the way my teacher wants it is with various if statements but im not sure what to put in the parentheses. I think it would be something like
I am having an issue with my swing gui. I dynamically create tabs with information (textfields, checkboxes, combo boxes) and when I select the checkbox it disables or enables a textfield. Now when I select the checkbox it seems to resize everything, specifically my textfields from say 9 columns to probably one. I"m a little unsure why it is doing this but I have a feeling it may be an inheritence issue.
My code is below for my generation of the tabs and of the rest of the information on the gui. The gui is an inner rid layout with a top and bottom pane that are both gridbaglayouts and an outter pane as well. I am thinking I am missing something in the grid layout setup that is causing this.
1. In jsp 1 , i have 3 checkboxes(chkbox1,chkbox2,chkbox3) , if i select check boxes (chkbox1, chkbox2), and click on submit, corresponding two text fields (chkbox1,chkbox2) will have to appear in the next jsp i.e., jsp 2.
2. In jsp 1 , i have 3 checkboxes(chkbox1,chkbox2,chkbox3) , if i select check boxes (chkbox2, chkbox3), and click on submit, corresponding two text fields(chkbox2,chkbox3) will have to appear in the next jsp i.e., jsp 2.
Like this, which ever checkbox i select, corresponding text fields should appear in the subsequent jsp.
I'm trying to come up with a method that would validate each turn a player makes. For a turn to be valid, it has to only contain numbers from 0 to 3(inclusive) and at least one digit must not be 0. Here is what I`ve come up with so far. For example, with "303" as the number and "101" as the turn, the turn would be valid and my method should return true, but it does not.
public static boolean turnIsValid (String number, String turn ){ boolean rep=false; int pos1=0; char min='0'; char max='3'; while(number.length()==turn.length()&&pos1<turn.length()){
My goal is to make a working spell check program.I have made some progress, but the more I test, the more issues I get and I continue to edit the algorithm.
import java.util.*; import java.io.*; public class SpellCheckTestClass{ public static void main(String [] args) throws IOException{ ArrayList<String> englishwords = new ArrayList<String>(); ArrayList<String> suggestions = new ArrayList<String>(); Scanner in = new Scanner(System.in); String entry = in.next();
I am currently trying to write a method for checking to see if an "agent" in a cell (place in a 2d array) is satisfied. So, the assignment is a 2D array that can have a blank space, an O, or a X as a character that fills a particular space. An agent is satisfied if it has similar characters around it in a percentage that is higher than the threshold. For example, if the threshold was 60% and a cell that had an X in it, had 3 X's around it and 2 O's, then it would be satisfied because 3/5>=60%. For my code, I tried using if and else statements to isolate circumstances in the corner of the grid, the edges, and everything in between.
public static boolean isSatisfied(char[][] tissue, int row, int col, int threshold){ char check= tissue[row][col]; if (check==' '){ return true; } else{ int countx = 0; int count = 0;
I am using form based, declarative security approach. And, when some user, on login form enters user credentials (username and password), he is being redirected to certain/secured jsp page.
Part of that page content is:Hello <%=request.getUserPrincipal().getName().toString()%> You are able to view this page because you are authorized user.You can see that this is implemented using JSP scriptlet. And this works. I would like to use JSTL instead of scriptlet.
So, instead of scriptlet, I put this JSTL code: <c:out value="${requestScope.userPrincipal.name}"/>, but not getting user's username with it. Basically, I don't clearly understand where and how are these objects/user credentials being stored with Form based JAAS.
I would like on JSP page to check if some user is already logged in. So, if there is logged user to display user's name (also with JSTL).Something like this:
<c:if test="${not empty sessionScope.userPrincipal}"> User <c:out value="${sessionScope.userPrincipal.name}" /> </c:if>
Here I tried with sessionScope but still not getting anything.
My program here asks for an unit to choose from (fl.oz, gal, oz, lb, in, ft, or mi), asks how much of it they have, and asks for the unit they wish to convert to (mL, l, g, kg, mm, cm, m, or km).
My program works, refusing to convert from silly conversions such as gal to cm, telling you to re-input if they enter anything other than fl.oz, gal, etc.
The only thing I cannot figure out is if the user inputs something like "foo" when the program prompts the user for how much of the unit they have. My goal is to have the program say something like "That is not a number! Please enter a numerical value."
My current dilemma right now is that if the user inputs something other than a number, it will catch the exception and print a line telling the user it's not a number, except, it does it infinitely (stuck in a loop). Here is my code:
import java.util.InputMismatchException; import java.util.Scanner; public class UnitConversions { public static void main(String[] args) { Scanner s = new Scanner(System.in); double result = 0;
I was wondering if there was a way to check/view messages from my phone. I'm trying to create a program that will be able either read messages from my phone, or reply to them. I'm trying to get this to work for a Window Phone, but I don't know if there is a difference between doing it on a Windows Phone or Android. Most of the topics that somewhat relate to what I'm doing are all Android based.
I've looked at AT Commands, SMS Gateways, but I'm still not sure if it's entirely possible.
How could I check if an index is exist in an array list? I mean, I should enter an integer and it should return me a boolean result that saying whether if that entered value is an index or not.
I have a program that allows the user to select what type (i.e. tif, jpg, sid) of file they have to load. I use a JCombo box for the selection type. I send this JCombo box string to my ElevationConvert class. What I want to do is check to see if that extension the user selected exists prior to converting it. If the file extension does not exist, I want to pop up a window (JOptionPane) stating is does not exit. I have tried suggestions found on this site, but does not seem to work for my application. The program works with (Process cN = Runtime), if I try not to check for the extension. But when I add the check for (If, else), it bombs. This executable runs in the main folder. The file extensions are in a subfolder called Ned.
/* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the editor. */ package terraindbbuilder1;
I have to ask how many children's tickets you want to order. When I apply the code below, it just accepts whatever I input, including letters. I imagine it is to do with setting childrensTickets = 0? If I input a letter using the below it accepts - shouldn't it print the error given the input is not >=0?
System.out.print("How many children's tickets do you require? "); int childrensTickets = 0; boolean validChildrenValue = false; while (validChildrenValue == false) { if(aScanner.hasNextInt()) {
I am doing an assignment for my class and I wish to know if there is anything I did wrong or what would make it easier to read, the assignment is to make a program to check if a year (the user provides the year) is a leap year.
import java.util.*; public class Assignment1 { public static void main(String[] args) { int year; System.out.println("Please enter a year.");
