like i have String s="11222ddeefs"
so here i want program output like 1=2
2=3
d=2
e=2
f=1
and s=1
it has to show no of duplicates in each character in string
I would like to ask how with such an array:
x_z01
x_z02
x_q01
x_q02
x_q03
From this table I have searched:
for the
"x_01"
algorithm chosen:
x_z01
for the
"x"
algorithm chose :
"x_z01"
for the
"Z01"
algorithm chose :
"x_z01"
for the
"x_q"
algorithm chose :
"x_q01"
For any character - chose any value from an array
import java.util.Scanner;
/** */
public class Array_value{
/** * @param args the command line arguments */
public static void main(String[] args) {
[Code] ....
Whether this algorithm: [Code] ....
I am currently trying to make a calculator in Java. I want to use the String split method to tokenize the string of characters inputted. I thought I was using the String split method wrongly, because I had surrounded the characters I wanted to delimit with square brackets. However, when I removed the square brackets, the code threw an exception when I pressed the equal button. The exception was a PatternSyntaxException exception. Am I using the String split method wrongly? And why is the exception thrown? Here is my code:
import javax.swing.*;//import the packages needed for gui
import java.awt.*;
import java.awt.event.*;
import java.util.Arrays;
import java.util.List;
import static java.lang.Math.*;
public class CalculatorCopy {
public static void main(String[] args) {
[Code] .....
I'm trying to loop through a string and depending on the character, add a JLabel to a game. The problem is the character 'L' represents a lantern but is also used in the reply the game gives which is "LOOKREPLY". I've tried to use some code to ignore the LOOKREPLY bit but it's not working. Here's what I've tried.
else if(message.charAt(i) == 'L' && message.charAt(i+1) != 'O' | message.charAt(i+1) == 'Y'){
JLabel localLabel = new JLabel();
localLabel.setIcon(lantern);
panel.add(localLabel);
panel.revalidate();
panel.repaint();
But the first image on all of the JLabels is always a lantern, which is what L represents. As it's only 1 lantern this leads me to believe that it's ignoring the first 'L' but for some reason it's not ignoring the 'L' at the end of LOOKREPLY.
how we can handle the string with special characters. For instance:
123456789BNJKNBJNBJKJKBNJKBJKNBJK"VJKNBJNHBJNJKBVJ KBJKNB"VHBVBBVNBVNBVBVBVBNBVNBNBJHFBVFJB FNVJBNVJNVJDFNVJKNVJKNVJKVNNVJ NN"
I get some user inputs with double quotes and i need to split to 80 chars line.
.length fails to get the length if it contains special characters like double quotes and ?
As of right now my code can take characters from a string to an array from a string like "ABCD" but the project says I have to take it from a string like "A B C D" how can I correct my code to grab the characters from a single spaced line?
Scanner sc = new Scanner(System.in);
System.out.println("Enter Order of Cars:");
String carsInput = sc.next();
int x = carsInput.length();
int[] cars = new int[x];
for (int i=0; i < cars.length; i++) {
cars[i] = carsInput.charAt(i)-64;
}
So what my program is supposed to do is take a number inputted by the use and then take a phrase. It then changes that phrases letter by the number inputted prior for example if you type in 2 as your int and Hello as your phrase you should get JGNNQ, which i can do. but the problem is that when i run it, it outputs like this:
J
G
N
N
Q
As separate characters how can I combine those characters in 1 string so it looks like JGNNQ? this is my code
import java.util.Scanner;
public class Dcod_MAin {
private static final Object[] String = null;
public static void main(String[] args){
Scanner input = new Scanner (System.in);
System.out.println("What is the day of the month");
int shift;
[Code] ....
I need to make a string filled with naughts and crosses like this one : "xxx ooo xox". There are 3 groups separated with a space. how to fill the string randomly ?
View Replies View RelatedI just need to write a simple program/function that replaces certain letters from a string (i.e. censor( "college", "aeiou" ) returns "cllg"). I'm trying to get the code right first, and then write a function for it.I basically just thought that I would iterate over the first string, and once I had the first character, I would then iterate over the second string, to see if the character exists. I'm getting a "dead code" error on my second loop because I put the second "break."
public class ap {
public static void main(String [] args){
String s = "Hello";
String s2 = "aeiou";
[code]....
I have to check a String input from the user in the form of firstName lastName (i.e. John Smith). I have to check for an exception called NonAlphabeticCharacterException that gets thrown if there is anything but a number in that string. This is what I have right now but should I create an array of char for the alphabet and then check the whole string for non alphabetic characters?
for(int i=0; i<name.length(); i++) {
if()){
throw new NonAlphabeticCharactersException("Non-alphabetic character found");
}
}
I am trying to count the number of non_blank characters in a string. If there are no leading blank spaces it works fine but say i add three spaces in front it doubles the non blank characters.
import java.io.*;
import java.util.*;
public class countCharacters
{
public static void main(String[] args) throws Exception
{
String str1;
int count;
count = 0;
[Code] ....
I am trying to do a program that takes all of the chars from a string and orders them in alphabetical order. It works fine, but when a is a last letter of a string it isn't being sorted.
Example: bcba = bbca, omnibus = bimnous (here u is in wrong place)
Here is my code:
public class sorty{
public static void sort(char[] a, int low, int high){
int i = low;
int j = high;
if (j - i < 2) return;
int m = (j+i)/2;
char p = a[m];
[Code] .....
I am trying below challenge to display first three characters three times if the size of the string is greater than 3.
Say if i send hello i should get helhelhel
if i send xyz i should get xyzxyzxyz
I wrote as below
public String front3(String str) {
if(str.length()==3){
return str+str+str;
}
if(str.length()>3){
String str2=new String(new char[]{str.charAt(0),str.charAt(1),str.charAt(2)});
return str2;
}
}
I am getting error as below
Error:public String front3(String str) {
^^^^^^^^^^^^^^^^^^
This method must return a result of type String
Possible problem: the if-statement structure may theoretically allow a run to reach the end of the method without calling return. Consider adding a last line in the method return some_value; so a value is always returned.
In this simple example, I print a byte array to String:
Java Code:
import java.io.UnsupportedEncodingException;
import java.nio.charset.Charset;
public class PrintByteArray {
public void print(){
System.out.println(Charset.defaultCharset());
byte[] arr = {1, 2, 3, 4};
[Code] ....
However, Eclipse prints out strange boxes, which I was unable to copy into this message.
It's supposed to print out the values of the bytes. What am I doing wrong?
I am trying to change an input String to an array of characters, but it only stores the word before the space into the array. Here is the code:
Scanner scanner = new Scanner(System.in);
System.out.println(" Enter text: " );
String text = scanner.next();
char[] characterArray = text.toCharArray(); // convert string to array of characters
String char = "";
for( i = 0; i < characterArray.length; i++) {
char = char + characterArray[i]
} System.out.println(char);
Just typing hello gives me hello, but when I type hello world it does not type in the word "world".I am trying to change an input String to an array of characters, but it only stores the word before the space into the array.Here is the code:
Scanner scanner = new Scanner(System.in);
System.out.println(" Enter text: " );
String text = scanner.next();
char[] characterArray = text.toCharArray(); // convert string to array of characters
String char = "";
for( i = 0; i < characterArray.length; i++) {
char = char + characterArray[i]
} System.out.println(char);
Just typing hello gives me hello, but when I type hello world it does not type in the word "world".
I was trying to create a java program which can remove the repeated characters in a String. For ex-
Input: kamehamehaaa
Output: kameh
Here is my code:-
import java.util.Scanner;
class replace {
public static void main (String args[]) {
Scanner br = new Scanner(System.in);
System.out.println("Enter a word");
[Code] ....
On executing the program, StringOutOfBoundsIndex error occurs.
I do have a quick question about string manipulation. You see I've been given a simple exercise that involves asking the user to input a number between 1,000 and 999,999 and displaying the result. Simple enough, but the caveat is that if the user keys in the comma, say 24,000 instead of 24000 for example, the program is not to display the comma. I don't see how to do this without an 'if' statement. The book says the 'if' is not necessary but does offer this hint: "Read the input as a string. Measure the length of the string. Suppose it contains n characters. Then extract the substrings consisting of the first n-4 characters and the last three characters."
What good is n-4 going to do if the string's lengths varies?
Here's what I have written thus far:
import java.util.Scanner;
public class P13
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.print("Please enter a number between 1,000 and 999,999: ");
[Code] .....
I'm attempting a small program as I'm teaching myself the ropes. In it, I need to compare one string (the base) to another which is just the base string that's had it's characters shuffled.
Java Code:
String base = "ABCDEFG"
String shuffled = "CDAFBEG" mh_sh_highlight_all('java');
What I need to do is run a loop that shuffles the base string each time, but compares and saves any characters that match in the correct location. For example, if shuffled = "CDAFBEG", then the G would be "locked" in place and the rest of the characters shuffled and looped back to the comparison.
I have all the code I need for shuffling the string, but I'm not sure how I would go about comparing each character and then also locking it in place. I get the basics, I think, of needed to use several variables.
The problem is i want to replace some string text with foreign characters, but JTextArea returns plainText.
For Example:
str = new String();
str.replace('e', 'é');
textArea.setText(str);
but textArea returns plainText.
I'am trying to converting string data into xml data using xml beans and StringEscapeUtils.This is work fine but in one case it if the data contains special characters.
Code snippet
--------------------
import org.apache.commons.lang3.StringEscapeUtils;
import org.apache.xmlbeans.XmlException;
import org.apache.xmlbeans.XmlObject;
public class ParseXMLData {
public static XmlObject parseXML(String stringXML) {
XmlObject xmlObject = null;
[Code] ....
success case
---------------------------
i/p------<aaa><bbb>This converts string to xml</bbb></aaa>
o/p---<aaa><bbb>This converts string to xml</bbb></aaa>
Failer case
-----------------
i/p----<aaa><bbb>This fails if it contains < symbols</bbb></aaa>
expected o/p----<aaa><bbb>This fails if it contains < symbols</bbb></aaa>
Observed that it converts < to '<' but as per xml rules, if data contains '< ' it fails. I want to convert staring and end tags to xml format and if data in b/w middle of starting and ending tags do'n need to convert it. How to do it.
I want to reverse a String that is input
This is what I have tried so far
public class ReverseStringTest {
public static void main(String[] args) {
Scanner in=new Scanner(System.in);
System.out.println("Enter String to replace:");
String temp=in.next();
System.out.println("Reverse String is:"+reverseString(temp));
[code]...
But its not working it is return same string that is Input.
Writing a Java program to find sum of numbers in a random string.
(Input=abc235^%$q!12&3 output=250)
If a number has - sign then u should consider it as a negative number.(Input=abc-12t%^&$dcf22 Output=10)
I have to recursively find a given string in a file. I HAVE to use the LineNumberReader class, and the output would be like so:
Line#Found : the string of the whole line
This is the code I've written:
public String findGivenString(String givenString, int currentLineNumber) {
LineNumberReader lnr = null;
try {
lnr = new LineNumberReader(new FileReader(getFile()), 4096);
lnr.setLineNumber(currentLineNumber);
String s = lnr.readLine().toLowerCase();
[Code] ....
I messed around with a bit, and it doesn't change to the new set line. Though the line number is incrementing! So it just keeps checking the first line of the file over and over again, which is why it can't find the given string. Which also throws the StackOverFlow exception I'm getting.
Here's the output if I remove the comment from the System.out...:
String @ that Line# 1: package banking;
String @ that Line# 2: package banking;
String @ that Line# 3: package banking;
String @ that Line# 4: package banking;
....
So you see it keeps checking the same line even though the line number IS incrementing.
i need to find common String between to Strings :
Example 1:
Customer Name 1: Dr. Joe Smith
Customer Name 2: Joseph Smith, MD.
I need to search the string for a match, in this example "Smith"
Example 2:
Customer Name1: New York Market Place
Customer Name 2: NY Marketplace
I need to search the string for a match, in this example Market place
Example 3:
Customer Name1: The Deli on the Corner
Customer Name 2: Corner Deli
I need to search the string for a match, in this example Deli Corner
SimpleDotComTestDrive.java:8: error: cannot find symbol
String result = dot.checkYourself(userGuess);
^
symbol: method checkYourself(String)
location: variable dot of type SimpleDotCom
1 error
Code:
public class SimpleDotCom {
int[] locationCells;
int numOfHits = 0;
public void setLocationCells(int[] locs) { locationCells = locs; }
public String checkYourSelf(String stringGuess)
{ int guess = Integer.parseInt(stringGuess);
String result = "miss"; for (int cell : locationCells) {
[Code] .....
How can find any string length without using any library method??
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