How do i flush off the leading 0s from my results? I want to start with 1.
import java.util.Scanner;
public class Hex2Bin {
public static void main(String[] args) {
String hexStr;
int hexStrLen;
[code]....
i've got this code that i cant get to work as i want it to. when its exported and i run it the file i wants gets created but when i open the file there is a single number like 999998000001
import java.io.IOException;
import java.io.PrintWriter;
public class mainHej {
public static void main(String arg[]){
[code]...
i want to know when i have to use Flush in java , i saw alot of code that used it IO streaming , but i cannt understand how can i use it , or when i have to use it
View Replies View Relatedwhy I need to populate an array with leading zeros. It sounds like it wants me to populate the entire array for one number (string). When I use next(), it separates the numbers so why do I need to go the leading zeros route?
This assignment will give you practice with external input files and arrays. You are going to write a program that adds together large integers. The built-in type int has a maximum value of 2,147,483,647. Anything larger will cause what is known as overflow. Java also has a type called long that has a larger range, but even values of type long can be at most 9,223,372,036,854,775,807.The approach you are to implement is to store each integer in an array of digits, with one digit per array element. We will be using arrays of length 50, so we will be able to store integers up to 50 digits long. We have to be careful in how we store these digits. Consider, for example, storing the numbers 38423 and 27. If we store these at the front of the array with the leading digit of each number in index 0 of the array, then when we go to add these numbers together, we're likely to add them like this:
38423
27
To simulate this right-shifting of values, we will store each value as a sequence of exactly 50 digits, but we'll allow the number to have leading 0's. For example, the problem above is converted into:
0000000000000000000038423
0000000000000000000000027
Now the columns line up properly and we have plenty of space at the front in case we have even longer numbers to add to these.The data for your program will be stored in a file called sum.txt. Each line of the input file will have a different addition problem for you to solve. Each line will have one or more integers to be added together. Take a look at the input file at the end of this write-up and the output you are supposed to produce. Notice that you produce a line of output for each input line showing the addition problem you are solving and its answer. Your output should also indicate at the end how many lines of input were processed. You must exactly reproduce this output.
You should use the techniques described in chapter 6 to open a file, to read it line by line, and to process the contents of each line. In reading these numbers, you wont be able to read them as ints or longs because many of them are too large to be stored in an int or long. So youll have to read them as String values using calls on the method next(). Your first task, then, will be to convert a String of digits into an array of 50 digits. As described above, youll want to shift the number to the right and include leading 0s in front.
The String method charAt and the method Character.getNumericValue will be useful for solving this part of the problem.You are to add up each line of numbers, which means that youll have to write some code that allows you to add together two of these numbers or to add one of them to another. This is something you learned in Elementary School to add starting from the right, keeping track of whether there is a digit to carry from one column to the next. Your challenge here is to take a process that you are familiar with and to write code that performs the corresponding task.
Your program also must write out these numbers. In doing so, it should not print any leading 0s. Even though it is convenient to store the number internally with leading 0s, a person reading your output would rather see these numbers without any leading 0s.You can assume that the input file has numbers that have 50 or fewer digits and that the answer is always 50 digits or fewer. Notice, however, that you have to deal with the possibility that an individual number might be 0 or the answer might be 0. There will be no negative integers in the input file.You should solve this problem using arrays that are exactly 50 digits long. Certain bugs can be solved by stretching the array to something like 51 digits, but it shouldnt be necessary to do that and you would lose style points if your arrays require more than 50 digits.The choice of 50 for the number of digits is arbitrary (a magic number), so you should introduce a class constant that you use throughout that would make it easy to modify your code to operate with a different number of digits.
Consider the input file as an example of the kind of problems your program must solve. We might use a more complex input file for actual grading. The Java class libraries include classes called BigInteger and BigDecimal that use a strategy similar to what we are asking you to implement in this program. You are not allowed to solve this problem using BigInteger or BigDecimal. You must solve it using arrays of digits.Your program should be stored in a file called Sum.java.
Input file sum.txt
82384
204 435
22 31 12
999 483
28350 28345 39823 95689 234856 3482 55328 934803
7849323789 22398496 8940 32489 859320
729348690234239 542890432323 534322343298
3948692348692348693486235 5834938349234856234863423
999999999999999999999999 432432 58903 34
82934 49802390432 8554389 4789432789 0 48372934287
0
0 0 0
7482343 0 4879023 0 8943242
3333333333 4723 3333333333 6642 3333333333
Output that should be produced
82384 = 82384
204 + 435 = 639
22 + 31 + 12 = 65
999 + 483 = 1482
28350 + 28345 + 39823 + 95689 + 234856 + 3482 + 55328 + 934803 = 1420676
7849323789 + 22398496 + 8940 + 32489 + 859320 = 7872623034
729348690234239 + 542890432323 + 534322343298 = 730425903009860
[code]....
I am writing a program that adds together large integers. I have to store each integer in an array of digits, with one digit per array element. Array length is 50 so integer is 50 digits long. I have to store numbers in right-shifting format with leading zeros. For example,
0000000000000000000038423
0000000000000000000000027
Sum.txt contains numbers to be added. There could be one or more numbers per line.each line must be read as string with next() since it's assumed to be a very long number. String of digits needs to be converted into an array of 50 digits. Method CharAt and Character.getNumericValue will be useful. All numbers in each line are to be added. There are no negative numbers and individual number might be 0 or answer might be 0. Answer is always 50 digits or fewer.
BigDecimal or BigInteger are not allowed.
I'm lost where it says to put number with leading zeros in a 50 room array. How do I add numbers after formatting numbers with leading zeros?
I have an array made that represents digits and I am trying to make a method so that if there are zeros in front of the first significant digit I want to trim them, I understand you can't re size arrays so I have created a new array, but my code doesn't seem to run correctly? Here is my code I can't figure out what is wrong I've tried everything: (I put stars around the error**)
package music;
import java.util.Random;
public class Music {
private int length; // length of the array
private int numOfDigits; // number of actual digits in the array
int[] musicArray;
[Code] .......
If I have 0123.45 string and trying to get 12345 as result. I am trying regex like below.
String s="0123.45";
s = s.replaceAll("^0*([0-9]+).*", "$1");
It gave result 123 as leading zeros removed that is one of the things that I want. How do I achieve 12345?
I got situation where i have postal code as 0009 in database and the use is entering 0009 but somehow in my java code it only reading 9 from the xml file
This is how i define getter and setter
When i debug the code i get
passed postalcode 9
Java Code:
public String Postalcode="";
public void setPostalcode(String Postalcode) {
this.Postalcode = Postalcode;
}
public String getPostalcode() {
return Postalcode;
} mh_sh_highlight_all('java');
What if 0009 is passed i what it to remain 0009
Any way to place leading zeros onto numbers without having to convert them to strings? Is such a thing possible?
View Replies View RelatedI got situation where i have postal code as 0009 in database and the use is entering 0009 but somehow in my java code it only reading 9 from the xml file
This is how i define getter and setter :
When I debug the code i get this :
passed postalcode 9
if a user entered 0009 I what it to remain 0009
Java Code:
public String Postalcode="";
public void setPostalcode(String Postalcode) { this.Postalcode = Postalcode; }
public String getPostalcode() { return Postalcode; }