How To Throw Exceptions

Nov 22, 2014

I am just learning how to throw exceptions, and I'm stuck on the last part,

Here is where I created the exception that receives a string consisting of ID and wage.

public class EmployeeException extends Exception
{
public EmployeeException(String Employee)
{
super(Employee);
}
}

Here is where I created the Employee class with the two fields. I also believe I am throwing the exception if the hourly wage is < $6 or > $50.

public class Employee
{
int idNum;
double hourlyWage; 
public void Employee(int empID, double empWage) throws EmployeeException
{
idNum = empID;
hourlyWage = empWage;

[Code]...

Now, I need to write an application with three employees and display a message when an employee is successfully created or not. This is what I have so far... I'm trying to get it to work with one employee, and then I can easily go back and add two more.

import javax.swing.*;
public class ThrowEmployee
{
public static void main (String[] args)
{
try
{
Employee one = new Employee(542, 15.20);
}
 
[Code

The current compile error that I'm receiving is: ThrowEmployee.java:12: error: constructor Employee in class Employee cannot be applied to given types;

Employee one = new Employee(542, 15.20);
^
required: no arguments
found: int,double
reason: actual and formal argument lists differ in length
1 error

I have public void Employee(int empID, double empWage) in my Employee class, so why is it saying that no arguments are required? Not sure if I'm missing a step with throwing exceptions, because this error has always been a simple fix when I've come across it in the past?!?

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[Code] .....

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[Code] .....

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