I have a method that returns an int[]. I need to check if this int array ( unsorted ) contains a few numbers. I guess the Collection API( Java 1.6) does not have anything like Arrays.asList(<the array>) that can convert an int[] to a Set<Integer> or to a List<Integer> or to even an Integer[]. Or would it?
If not, then the only way I have is to scan the array element by element and then check if it has those numbers. Right?
a. Create an application named ArithmeticMethods whose main() method holds two integer variables. Assign values to the variables. In turn, pass each value to methods named displayNumberPlus10(), displayNumberPlus100(), and displayNumberPlus1000(). Create each method to perform the task its name implies.
b. Modify the ArithmeticMethods class to accept the values of the two integers from a user at the keyboard.
public class MyInteger {
private int value;
public MyInteger(int number){
value = number;
System.out.println("Constructor created with value of " + value);
[code]....
I can't seem to get the value for integer1 and integer2 to pass with the setValue method. I get a runtime error stating the I need to have an int value for these two integers.
I created a GUI with a jTextField as an input box and am wondering how to validate that this data is an integer from 0 - 9. Here is what I have. However the if statement shows an error that says int cannot be dereferenced.
private void doneButtonActionPerformed(java.awt.event.ActionEvent evt) {
//Create and Initialize Variable
int category = Integer.parseInt(categoryInput.getText());
if (category.matches(0-9)); //int cannot be dereferenced error here
{
[Code]...
What is wrong in this
class Gen<k,v>
{
K a;
V b;
Gen(K s, V f) {
a=s;
b=f;
[Code] .....
a is object of type k,then how can I retrieve content of a?
I am trying to split an integer for example my input is 0590
I want the output as
0
5
9
0
How to do this.
Code:
public static void main(String[] args) {
// TODO code application logic here
Calendar time = Calendar.getInstance();
int min = 1;//time.get(Calendar.MINUTE);
String blank = "0";
int checker = ((min > 10 ) ? min : blank+min);
System.out.println("The time is " + "12" + ":" + checker );
}
This is my code, as you can see, I have if the min is less than 10, display the string "0" next to it so it will be something like
blank is zero and min is one
So it will display as 01 but after min reaches 10 and above, the 0 goes away. Problem I have is, you just cant add "blank" to int checker because checker is an int and blank is a string. So what must I do in order for it to display the 0 under checker?
I would like to know which one is more appropriate to use in "for" loops or "while" loops.I don't know exactly when to use Integer or int.
for(int i=0; i<10; i++){ ... }
for(Integer i=0; i<10; i++){...}
// 1 ***** student writes this method
/** Searches for key in integer array named arr
// arr is an instance variable of the class and has been instantiated and filled with random values.
// @param key value to search for
// @return if key is found, the index of the first element
// in array whose value is key; if key is not found,
// the method returns -1
*/
public int sequentialSearch( int key ) {
// Note: To animate the algorithm, put this method call as the first statement in your for loop
// animate( i, 0 );
// where i is the index of the current array element
return 0; // replace this statement with your return statement
} // end of sequentialSearch
[Code] ....
I'm trying to insert numbers in a array of Integer neatly. When i try to insert the following numbers i have this exception.
Exception in thread "AWT-EventQueue-0" java.lang.NullPointerException
at time.Historico.insere_ordenado(Historico.java:35)
Line 35 in my code is:
"while (num >= arry[i] && arry[i] != null && i < arry.length - 1)"
Numbers:
71516357248031
I have this exception when i try to instert 80.
public Integer[] insert_neatly(Integer[] arry, Integer num)
{
Integer i, acum, aux, temp;
i = acum = 0;
if (arry[i] == null)
[Code] ....
What is wrong with this code?
I amtrying to iterate a value of L,R both are range of BigInteger but its not working
BigInteger L=in.nextBigInteger();
BigInteger R=in.nextBigInteger();
for (BigInteger bi =L;
bi<=bi.compareTo(R);
bi = bi.add(BigInteger.ONE)) {
//Task to do with Numbers
}
I am trying to iterate a for loop in range of L and R but its not working
Digit sum of an integer is the sum of all its digits. For example, the digit sum of 123 is 1+2+3 = 6
and the digit sum of 99 is 9 + 9 = 18.
But how to write the programm that will count those numbers?
class Test {
public static void main(String[] args) {
int arr[]={1,2,3,4,5};
int search = 5;
int i=0;
boolean flag=false;
[Code] .....
Above program runs fine.Above in each iteration we have 2 conditions, first to check if iteration number is less then array length and second is to match it with the search integer.I am required to reduce these two conditions and make it one only.Have tried it but no success.
I've started writing a new program that Scans for some strings. I want to specify a random Integer to those Strings in order to do my desired idea. what should I do?!! my codes are here :
import java.util.Random;
import java.util.Scanner;
public class Draw {
public static void main(String[] args) {
System.out.println("This Program is written to solve little problems in families cause of doing unwanted works!!");
[code].....
now I want to Specify an Integer to each person that has been scanned! for example if the first person is " David " , which is a String, in the next step :
Random randomNumber = new Random();
randomNumber.NextInt(101);
int David = randomNumber.NextInt(101);
I want to what should I do?
I have to make a programm where the user gives you the bank sorting code and the account number and you give him the IBAN. That was so far no problem and I was done within minutes except of one thing that I simply can't figure out even though im trying since weeks. At some point I have to convert a string to integer. My research told me its with parseInt() and I dont get a syntax error when I compile my programm (using BlueJ). But when executing the programm stops and gives me some weird bug message. Here is code and bug message:
Java Code:
public class IBAN {
public IBAN(String Bankleitzahl, String Kontonummer) {
Bankleitzahl=Bankleitzahl.replace(" ",""); // Die Leerzeichen werden entfernt
int Anzahl=Bankleitzahl.length(); // Auf der Variabel Anzahl wird die Anzahl der Zeichen von der Bankleitzahl gespeichert
[Code] .....
int a = 5;
//how do I convert a to 5 asterisks '*'?
When I do System.out.println(a); I want there to be 5 asterisks '*****'
I want to conver String value into Integer, and I have this :
String timeInterval = tfInputTinter.getText();
Integer tint=(Integer.parseInt(timeInterval))*1000;
but when I put this second line, the conversion, the program stops to work. I tried also with Integer.valueOf(timeInterval) but again I had the same problem.
how the data is stored in float. It seems like the range would be greater because it stores scientific notation rather than plain value, whilst integer arithmetic performance is better. float should be used to store bigger values and integer should be used for speed when values are smaller. As an example, I want to have cubic volumes ranging from about a handful to cargo ship. So float would be necessary for that.
View Replies View RelatedThis won't compile:
Java Code: import java.math.BigInteger;
class Problem48 {
public static void main (String[] args) {
BigInteger sum = new BigInteger(0);
for(int x = 1; x <= 1000; x++) {
[code]....
All I want to do is find the sum of all selfpowers of integer from 1 to 1000: What is wrong with my code?
OK very similar to switches & cases & ifs, but I'm wondering if I can do something like that:
public Method[] method;
method[0] = walk();
method[1] = run();
method[2] = stop();
for (int i = 0; i < x; i++){
if (i == myNumber) {
run m[i];
return;
}
}
So I wrote a method that simply calculates the sum of all integers between 1 and a given integer n. The method works fine however, as n gets big the solution will have time and space problems. Some I'm just curious if there is a better method than my iterative one that would produce a better Big O value.
public static int sum(int n)
{
int total = 0;
for (int i = 1; i <=n; i++)
total += i;
return total;
}
How do I write a program that shows the max and the min value of a float integer? I found out that in order to get the long I just type in
System.out.println(Integer.MAX_VALUE); and System.out.println(Integer.MIN_VALUE);
I don't know how to do it to a float integer.
How do I write a program that shows the max and the min value of a float integer? like for example in order to get the max value of a long integer we type System.out.println(Integer.MAX_VALUE); How would I do that for a float integer?
View Replies View RelatedMy program gives me an error when I try to "digUp" the purse. The error appears in the purse class.
import java.io.*;
public class Purse
{
//Fields
public double gp;
public double gold;
public double silver;
public double copper;
public double platinum;
public static final double GOLD_VALUE = 1;
[Code] ....
In the digUpPurse() method, it tells me
java.lang.NullPointerException
null
What this means.
I'm trying to figure out how to read in an integer and break it down into a sequence of individual digits in reverse order. Example: an integer input of 12345 gives an output of54321.
View Replies View RelatedI have to ask how many children's tickets you want to order. When I apply the code below, it just accepts whatever I input, including letters. I imagine it is to do with setting childrensTickets = 0? If I input a letter using the below it accepts - shouldn't it print the error given the input is not >=0?
System.out.print("How many children's tickets do you require? ");
int childrensTickets = 0;
boolean validChildrenValue = false;
while (validChildrenValue == false) {
if(aScanner.hasNextInt()) {
[Code] ....