Java Method Overloading Ask For Two Names And Prints Three Different Greetings
Feb 24, 2014
The class Overloading below asks for two names and prints three different greetings. Your task is to write the class methods missing from the class declaration. Methods print the greetings as shown in the example print.
Hint:The names and parameter types of the needed methods can be checked from the main method because all methods are called there. This exercise also does not require you to copy the source code below to the return field.
The method declarations will suffice.
Example output
Type in the first name: John
Type in the second name: Doe
**********
Hi!
**********
Hi, John
**********
Hi, John and Doe
**********
import java.util.Scanner;
public class Overloading {
public static void main(String[] args) {
String firstName, secondName;
The class Overloading below asks for two names and prints three different greetings. Your task is to write the class methods missing from the class declaration. Methods print the greetings as shown in the example print. The names and parameter types of the needed methods can be checked from the main method because all methods are called there. This exercise also does not require you to copy the source code below to the return field. The method declarations will suffice.
Example output
Type in the first name: John
Type in the second name: Doe
Java Code:
import java.util.Scanner; public class Overloading { public static void main(String[] args) { String firstName, secondName; Scanner reader = new Scanner(System.in);
a project I am working on. Its a program that creates a singly linked list that stores names and high scores and prints them. For some reason it is printing an entry extra times. Also my remove function is not working properly
GameEntry class: package project; public class GameEntry implements Comparable<GameEntry> { private String name; private int score; public GameEntry(String n, int s) { name = n;
I'd like to know how to return a new array, I wrote in a method below the main method. I want to print the array but system.out.print doesn't work for arrays apparently. What structure i should use?
Write a method that prints characters using the following: public static void printChars(char ch1, char ch2, int numberPerLine). This method prints the characters between ch1 and ch2 with specific numbers per line. Characters are separated by exactly one space.Test your method with the following main method:
public static void main(String[] args) { printChars(‘A’,’z’,10); printChars(‘0’,’9’,5); }
I'm new to Methods and do not really know how to write a method header. What would an appropriate header look like for the following instance? getFilename: This method takes no parameters. It asks the user for a filename. If that file exists, it returns the filename. If it does not exist, it asks the user for another filename. It continues to ask for filenames until the user gives the name of a file that exists.
Also, how would I make a return tag for this and call it into the main method.
I'm new to Methods and do not really know how to write a method header. What would an appropriate header look like for the following instance? getFilename: This method takes no parameters. It asks the user for a filename. If that file exists, it returns the filename. If it does not exist, it asks the user for another filename. It continues to ask for filenames until the user gives the name of a file that exists.
Also, how would I make a return tag for this and call it into the main method.
I am trying to create a method that prints the square root of a number up to a certain number. It needs to take a single int parameter for example "n" , and then print all of the (positive) even perfect squares less than n, each on a separate line. I want the method to be called something like this:
public void Squares(int n) { }
I need the output to look something like this:
Example: if n = 40, your code should print
4 16 36
So I have been working for a few hours now and am really stuck.
This is what I have so far:
int count = 0; int n = 4; int max = n; while(count < max) { System.out.println(n); n = n * n; count++;
import java.util.Scanner; public class smallestnumber { public static void main(String args[]) { Scanner input=new Scanner(System.in); int smallest =0; int number;
[Code]...
here is the output of my code:
Enter the number 88 Enter the number 8 Enter the number 6 Enter the number 55
I am trying to write a java program that prints out the number that is the mathematical constant e. As you input a number, the larger it gets , the closer it comes to 2.71828 . Here is my code:
//taylor series that prints out e^1=1+1/1!+1/2!+1/3!+..... import java.util.Scanner; public class taylor_1 { public static void main(String args[]) { Scanner input=new Scanner(System.in); int factorial =1;
One of my assignments was to make a program that would read a sequence of names and then list them all.Just to be clear, it would read them all first, and then it would list them all at the same time.
In Java® identifiers, you are allowed letters and numbers (also _ $£¢€ etc, but you should avoid them in normal identifiers). So you cannot have spaces. You cannot write public class Hello World because the javac tool will see World as a separate identifier and not understand what it means and will fail to compile the code. You must write public class HelloWorld instead. And because the class is labelled public you must call the source file Hello World. java. Since you can't have two classes with the same [fully‑qualified] name, you cannot write two public classes in the same source file.
“What about names of source files?” somebody will ask. Well, some file systems will permit spaces in file names; ext4 will and I suspect so will NTFS. Can you write file names with spaces in? You would have to have a different name of the class inside the file, because you can't have spaces, and you therefore cannot make the class public, but maybe you can write a package‑private class with a different name.
On ext4, you have to write out the name of the file and the shell will interpret the space as meaning there are two different file, so you have to escape the space.
campbell@campbellsComputer:~/java$ gedit My First Class.java // My First Class.java class Foo { public static void main(String... args) { System.out.println("Hello, World!"); } } campbell@campbellsComputer:~/java$ javac My First Class.java campbell@campbellsComputer:~/java$ java Foo
I need to make a program that keeps track of peoples names, allows you to add a note to each name and preferably would reorganize whatever you put in by date or by spelling. (I suppose the phonebook application in cell phones is a good match, a supermarket's list of foods and prices would work as well).
I am trying to write a java program that asks the user for a list of names (one per line) until the user enters a blank line. At that point the program should print out the list of names entered, where each name is listed only once (i.e., uniquely) no matter how many times the user entered the name in the program. I am supposed to use an ArrayList for this problem.
My idea for a solution is to create an ArrayList<String>, read each name, i.e., line, entered and then to see if that name is already in the ArrayList. I created a for loop to check each element in the ArrayList but when I try to assign an element to a string variable I get the error "Type mismatch: cannot convert from Object to String". Not sure why that is happening because the ArrayList is defined as a String list.
I am going through Thinking in Java, 4th Ed and I came across the section that talks about overloading variable arguments. I tried out a piece of code from the book. (Method and class names not exactly the same).
public class Varargs { public static void m1(Character... args) { System.out.println("Character");
[code]....
In the above code, the compiler throws an 'Ambiguous for the type varargs' error. The error goes away if the first method is changed to:
public static void m1(char c, Character... args)
why there is ambiguity in the first piece of code and not the second.
I can understand result 3 is because of an upcast from short to int, since FunWithOverloading will not have a overloaded method with short now. However, what is happening with result 4? Shouldn't it call methodA of the subclass with the argument type short? If its because I have declared the reference variable, derived, of the type FunWithOverloading, then how come the first result correctly picks the overloaded method of the sub class?
class FunWithOverloading{ void methodA(int x){System.out.println("Integer method " + x);} void methodA(short x){System.out.println("Short method " + x);} //line 3 } class OverloadedSubClass extends FunWithOverloading{ void methodA(short x){System.out.println("Sub class short method " + x);}
Recently I have missed a few weeks of my class due to family emergencies. Because of this I have missed very important lectures. My professor has assigned me the following assignment:
Prices Write a Java program that specifies three one-dimensional arrays names price, amount, and total. Each array should be capable of holding 10 elements. Using a loop, input values for the price and amount arrays. The entries in the total array should be the product of the corresponding values in the price and amount arrays. After all the data have been entered, display the following output:
Total Price Amount
==== ==== ======
Under each column heading display the appropriate value.
I know how to display everything using printf, how to create the actual arrays and define the array size, but I am confused on how and what loop to use and how to construct it. This is what I have managed to write up so far:
import java.util.Scanner; // Imports the Scanner class import java.text.DecimalFormat; // Imports the DecimalFormat class
public class Prices { public static void main(String [] args) { double[] price = new double[10]; double[] amount = new double[10]; double[] total = new double[10];
// Create a new Scanner object Scanner keyboard = new Scanner(System.in); } //End of main method } // End of public class
I was told to create a class named Billing that includes three overloaded computeBill methods for a photobook store.
The first method takes the price of the book ordered, adds 8% tax and returns the total due. The second method takes the price of the book, and the quantity, adds tax and returns the total. The final method takes the price, quantity and a coupon discount, adds tax and returns the total.
All of this I have managed fairly well, although I keep getting a strange error at the end of my program that the constructor is undefined. The problem bits of code(the one throwing the errors) are under the comment //Enter values into each of the methods
Code:
package org.CIS406.lab2;
public class Billing { //Declarations double bookPrice; int quantityOrdered; double couponValue;
[Code] ....
My first thought was to create a constructor for each of the methods that I am using...
I have a case in which I want to sort two types of ArrayLists (using quicksort) and the method originally coded only accepts a String ArrayList. The problem is that now I want to sort an ArrayList of type int but couldn't . . . so I decided to overload the method. Since it looks very ugly to copy and paste the same chunk of code only to change the method signature I wondered if there is a better way to make this method more dynamic and be able to take in different types of ArrayLists.
My code:
private ArrayList<String> sort(ArrayList<String> ar, int lo, int hi){ if (lo < hi){ int splitPoint = partition(ar, lo, hi); sort(ar, lo, splitPoint); sort(ar, splitPoint +1, hi);
