I've decided to go back to basics and start using pseudocode--but i want to see if my logic is correct.so here's the first program:each delegate to a certain conference must wear a tag showing their name and the organization they represent as shown below:
######################
#### Annual Conference #####
######################
##NAME: ##
######################
##ORGANIZATION: ##
######################
write a class called TagMaker that prints out tags. supply methods to (a) set the name (b) set the organization (c) print tag with the name and organization (d) clear the name and organization (e) print a blank tag. then write a TagTester class to test the TagMaker class. so this is the pseudo code (or logic) that i've come up with for the program:
TagMaker main class:
-Prompt user to enter in first and last name, as well as their organization.
-Read user input for the name and organization.
-Return user input.
-Write conference tag showing the person's information.
-Clear information.
-Print blank tag.
1. i assume i would have to import a few java libraries.
Java Code: java.util.Scanner mh_sh_highlight_all('java'); and Java Code: java.io.*; mh_sh_highlight_all('java');
2. afterwards i would declare the instance variables (private, i assume). static too? so for example: Java Code: private static string firstName mh_sh_highlight_all('java');
3. i'm not sure if this program requires a constructor...being that i'm supposed to clear the program at the end anyway.
4. i create a public class declaring my input variable. example: Java Code: String first = firstName.nextLine(); mh_sh_highlight_all('java');
5. so i then i have to create methods that get/set the user input.
getter/setter example:
Java Code:
public String getFirst(){
return first;
}
public void setFirst(){
this.first = new first;
} mh_sh_highlight_all('java');
6. to print out both tags, would i write most of the code as part of a loop and make an "if" statement where the user input is valid, it prints out a tag with information, and another "if" statement that would automatically clear the buffer?
7. last i would create a tester class that would primarily be responsible for the program's output.
I was tasked with creating a program that encrypts a line of text (for example, CANDY) by shifting the letters X amount of times. For example, if the user inputs the sentence CANDY and selects a shift of 5, the output would be: HFSID. I got this part working fine. The issue I am having is with the decryption part of the program.
This is simply the reverse of the above, as the user would enter the phrase HFSID, with a shift of 5, and the program would output: CANDY. It works fine, all except for one letter, being the "F" letter. With my code, when I enter the above word to be decrypted it outputs: C[NDY
Obviously, that [ bracket is not an 'A'. I realise the issue falls with the equation, Here is my code:
public class SimpleEncryption {
/** * @param args the command line arguments */ static int answer; public static void main(String[] args) { String cipher = JOptionPane.showInputDialog(null, "Please enter a sentence or word that you wish to encode or decode. This program uses" + " a basic cipher shift.");
The program i am working on is to take string from the user which should be a phone number then it will return true or false based upon the method that checks to see if it meets the criteria of a certain format if does not it will return false otherwise return true. I am working on a if/else structure that will print this number is valid if it meets the criteria of the method i previously mentioned or return the number is not valid if it is false. the logic of the expression i put in the parentheses of the if/else statement. This is what i have so far:
if(){ System.out.println("The phone number is valid"); } else { System.out.println("This isn't a valid phone number"); }
Do i need to compare it based upon the method that checks if it is true?
if (number % 2 == 0 && number % 3 == 0) System.out.println(number + " is divisible by 2 and 3");
if (number % 2 == 0 || number % 3 == 0) System.out.println(number+ " is divisible by 2 or 3");
if (number % 2 == 0 ^ number % 3 == 0) System.out.println(number + " is divisble by 2 or 3 but not both");
I understand the logic operators and the variable number, what i dont understand is what number % 2 == 0 and number % number == 0 mean. I know that % is a remaining operator and == means equals, i know that = and == are not the same.
I'm trying to fix this logic error in my slot machine game where no matter what slot combo comes up, it says you have won $10 and proceeds to add that amount to the balance and subtract the bet amount to the balance, even though it is not a winning combo! I've been trying to solve that and when doing so, I commented out Slot1.randNum1 == 0, Slot2.randNum2 ==0, and Slot3.randNum3 ==0 and anything relating to see if that was the problem, and it seemed like it was, because after that, the logic error described above was gone, but in doing so, the loss/win counter didn't increment, nor did the program pick up on the winning combos. However, I do not know why commenting out anything relating to randNum ==0 would cause that.
Here is the code for the processing (as you can see, some parts are commented in attempt to fix the logic error, but right now the code below is for the logic error that keeps on telling that the user has won):
public void askData () { title (); int betAmount; while (true) { try { c.setCursor (3, 1);
My code runs and populates an arraylist. However my break statement, while stopping the loop ends up being added to the arraylist. And I'm not sure how to fix this error.
public static void main(String args[]) throws Exception { // declaring variables String input = ""; // creating array list ArrayList<String> nameList = new ArrayList<String>();
I want to run a few things in my main when a JButton is pressed but can't work out the best way to do it. Here's the code in the main.
public static void main(String[] args) throws FileNotFoundException, ParseException, InterruptedException{ Map m = new Map("defaultMap"); GameLogic g = new GameLogic("defaultMap"); GodsEyeView gev = new GodsEyeView(g, m); gev.initialRun();
//Want to run this when a button is pressed. HumanUser h = new HumanUser(g); playerGUI gui = new playerGUI(h); gui.run(); gev.run(); }
I need to find the Winner using Object Orientation logic I have my old logic from my Tic Tac Toe game but it is not Object Orientated. So I want to convert it and add that code to my GUI Tic Tac Toe. I need to return a winner or tie.
I am going to develop a new web application of medium complexity. Right now i am somewhat comfortable with JSF and hibernate. I have never used JSF and hibernate together before.I just wanted to ask if it is good practice to use JSF (for both view layer and handling business logic) and hibernate(for persistence) without spring as a middle layer. The reason why i am asking this is i don't know anything about spring framework.
I'm having trouble with sorting Strings- 3 strings inputted by user, and I would like to output them in alphabetical order. I've used the str.compareToIgnoreCase method, and then I've tried to loop them through a series of if/ else statements. Everything I've been able to find online (including the forums here) has suggested to use the Comparator class, or to put the strings into an array, and sort list- I really would like to stick with just the String class, and its methods .
The program itself works and compiles, but I am getting logic errors that I have been unable to solve. I'm using IntelliJ Idea, and I've ran it through the built in debugger, about 100+ times (not exaggerating, lol) just to see what it's doing in particular scenarios. For instance, I can get c, a, b, to print out as a,b,c correctly, but a,b,c, will print out as b,a,c.
For me this is kind of like a Sudoku puzzle, or a Rubik's cube! Each time I fix one scenario, it breaks another one, so I don't know if there's a(logic) solution to fix all possible scenarios (abc, acb, bac etc... to all print abc) or if possibly I just need more if statements. I've only pasted in the area where I'm having problems (the if statements). I'm a big fan of the "Next Line" syntax.
(Note: please assume the non relevant content- import Scanner class, main method, etc... I didn't want to paste the entire program.)
System.out.println("Enter the first statement: "); //input.nextLine(); string1 = input.nextLine(); System.out.println("Enter the second statement: "); string2 = input.nextLine(); System.out.println("Enter the third statement: "); string3 = input.nextLine();
Have written a program to open Excel sheet from java program.Below line works fine.
Process p = Runtime.getRuntime().exec(new String[]{""C:Program Files (x86)Microsoft OfficeOffice12Excel.EXE"","C:UsersRASHPA~ 1.ORAAppDataLocalTempExport_xl420314062726 9379706.xls"});
But below code gives error i.e. Executable name has embedded quote, split the arguments
I'm creating a program that will compile and run another java program:Lets say I have a program in directory
D:HelloWorldsrc and compiled program will be in D:HelloWorldin inside src and bin is a folder hello (that's a package)
package hello; public class HelloWorld { public static void main(String[] args) { System.out.println("Hello World"); System.out.println("Hello World"); } }
This program will be run by another program (that's the program that I am creating).Here is the code of my program:
package runnercompiler; import java.io.IOException; import java.io.InputStream; import java.util.logging.Level; import java.util.logging.Logger; public final class RunnerCompiler {
I want to develop a Java program that uses OpenScript APIs to test my applications. The OpenScript framework automatically creates the Java Code so I was thinking of either using this code or create my own using the APIs.
I tried both options using NetBeans but I'm getting errors everywhere starting with the library import. I'm pretty new to Java so I'm sure I'm missing a lot of things here. I pasted the code below from the OpenScript framework that want to use in a stand-alone file for your reference.,
I have to read two pair of words as array from keyboard and then check corresponding words are anagram are not. If they are print 1 otherwise 0. Total number of words in the pair cannot exceed 100, the word length cannot exceed 100 and only lower case letters are allowed.My code is the following:
import java.util.Scanner; import java.util.Arrays; class MyClass { public static void main(String[] args) {
I have spent quite a few hours trying to follow an API on how to use Actions in a java program.
I have 3 JButtons and have just added a JMenu. What I want to do is to add an ACTION so that the JMenu performs the same function as the JButtons. (i.e. they both do the same thing).
I have tried to copy and follow the example from the API forum.
How to Use Actions (The Java > Tutorials > Creating a GUI With JFC/Swing > Using Other Swing Features)
The first error I get in compiling is on the following line:
Action loadFile = new LOADFILE();
However, I get the following error message:
softeng2final2.java:49: cannot find symbol symbol : class LOADFILE location: class softeng2final2 Action loadFile = new LOADFILE();
I'm new to this so take it easy on my code!! It compiles but its not giving me the correct outputs and I can't figure out why. Two words or phrases in English are anagrams if their letters (and only their letters), rearranged, are the same. We assume that upper and lower case are indistinguishable, and punctuation and spaces don't count. Some examples and non-examples:
* The eyes / they see (yes) * moo / mo (no) * Clint Eastwood / Old west Action! (yes) * Dormitory / Dirty Room (yes)
For more examples, see here.
Your job for this assignment is to solve a slight variant of the traditional anagram problem called superanagram. Here you are to write a two class application that reads in two words or phrases from the keyboard, and then judges if the first phrase is an anagram of some of the letters in the second phrase. Here are some examples:
* mo / moo (yes) * mo / mOO (yes - capitalization doesn't matter) * moo / mo (no - first phrase is NOT an anagram of some (or all) of letters of second) * rip / ziPPer (yes) * abc / aabc (yes) * aabc / abcde (no - too few a's in the second string) * flipper / rip (no) * Clint Eastwood / Old west Action! (yes - the two can have exactly the same letters)
You must use the Scanner class to read in the input strings. Use the nextLine() Scanner method, rather than next(), since spaces may be present in the two phrases that are submitted.Your program should either print YES, if the superanagram relationship is satisfied, or NO, if it isn't.
The classes MUST be called SuperAnTester, and SuperAnagram
* use the String methods toLowerCase() and (possibly) toCharArray(). The former takes all letters in a String and changes them to lower case; the latter converts a String into an array of characters. Also, this assignment is - of course - about characters and character matching. For some useful background on characters and how to work with them, watch the movies in the textbook at the ends of section 4.1 and 7.1.
* Very important: suppose you have two arrays of characters such that the first is purported to be an embedded anagram of the second, in the sense we've described above. How can you tell? The single most important thing to do, before you write a single line of code, is to work out a paper and pencil algorithm that distinguishes between superanagrams and non-superanagrams.
* Your classes must be commented! In particular, each method must have a one line comment just below the header line, which tells what the method is supposed to do.
* Algorithm Idea #1: make a scoreboard for the letters a to z. Every time you encounter a letter in the second String, up its count by 1; Then, every time you encounter a letter in the first String, lower its count by 1. Accept if the scoreboard ends up with all entries >= 0. (of course make sure you understand why this is - use pencil and paper to convince yourself!!).
* Algorithm Idea #2: convert strings to arrays. March down first array (representing the first string). When you encounter a letter, look for it in the second array. If you find it, blank out the occurrence in the second array; if you don't find it - it's not a super anagram. When you're all done, you've got a superanagram if your search in the second array never goes bad.
public class SuperAnagram{ private String wordOne; private String wordTwo; private char firstArray[]; private char secondArray[];
