import java.util.Scanner;
public class main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int number;
System.out.println("Input a number");
[code]....
What i want to do is that if the number is greater than 50 to count until 100. else if the number is less than fifty to count for example from 36 to zero.
I want to write a java program which displays to get the GPA of a student as a keyboard input. Then display the class of the degree according to the following criteria using a switch-case statement (if-else statements cannot be used). If the user insert an invalid gpa you should display a message Invalid GPA.
gpa ≥ 3.50 First Class Hons
3.49 ≥ gpa ≥ 3.00 Upper Second Class Hons
2.99 ≥ gpa ≥ 2.50 Lower Second Class Hons
2.49 ≥ gpa ≥ 2.00 Pass
2.00 ≥ gpa Fail
Here is my code:
import java.io.*;
public class q7
{
public static void main(String[] args)
{
InputStreamReader ISR=new InputStreamReader(System.in);
BufferedReader BR=new BufferedReader(ISR);
[code]...
.But when I use Command console to run this it says: 1111.jpg. I also wanna know is there another way to do this with switch- case statements.
I need to design, implement, and test a program to input and analyze a name. The program begins by retrieving a user input string from the keyboard. This string is intended to be the user's name. These are the errors we have to search analyze the user input for: No blanks between names firstName and lastName, Non-alphabetic characters in names, Less than two characters in first name, and Less than two characters in last name. Each of these errors must be thrown. All exceptions must be derived from a programmer-defined class called NameException. Each exception should use a detailed message to differentiate among the file types of errors.
This is the format of my NameException class, is the format itself correct? I will fill in the details of each exception I am just wondering if that is how I should set it up.
public class NameException extends Exception {
private String firstName, lastName;
public NoBlanksException(String firstName,String lastName) {
}
public NonAlphabeticalCharactersException(String firstName, String lastName) {
[Code] .....
I was told not to try and catch thrown errors in the main method, would I just create another method in the Driver class to take care of that then?
how can i make a program that declare the largest and smallest out of three numbers??
/*
* To change this license header, choose License Headers in Project Properties.
int a;
int b;
int c;
[Code]....
how to make a program that determines the highest value out of the inputted numbers.
View Replies View Relatedi want to make a piece of software that enables me to Press a key on my keyboard and then it will play a Sound. But i Want to be able to do it when i'm playing.Can code The Sound an Keys
View Replies View RelatedI created a scanner object but it's not asking for any input. when I create a new scanner and then tell it to print it it just prints a bunch of weirdness when AFIK it should be asking me to type something and then it should repeat what i entered.
View Replies View RelatedI am testing to get a double value from keyboard input as below?
import java.util.Scanner;
public class EchoLine{
public static void main(String[] args){
double amount;
Scanner myScanner=new Scanner(System.in);
amount=myScanner.nextDouble();
System.out.println(amount);
}
}
I type 5.95 in Console View of Eclipse but as a result I get an error on line 9.
so i'm working in a chat program and i'm trying to make it so that you are able to open another tab yet still be able to chat.
right now the client that the user download uses the keyadapter to get the keyboard input, but whenever the user un-focus the chat window, the keyadapter no longer gets the keyboard input.so is there another way i can get the keyboard input? so it doesn't matter what window you are focused on, you get the keyboard input either way?
I have been assigned to write a program that has a user input random numbers then the program is to sort them in different ways. I have the coding for the different sorts but, I have an error saying that I am missing a return statement in the "Bubble" method. I am trying to return "arr[i]" in the "for loop" which gives me this error, and when I try to take the "return arr[i]" outside of the "for()" loop the error reads the it cannot locate variable "i".
import java.awt.* ;
import java.awt.event.*;
import javax.swing.*;
public class SwingSorts extends JFrame implements ActionListener
{
JRadioButton bubble;
JRadioButton selection;
[Code] .....
The purpose of this program is to import via keyboard Numbers.txt and calculate the mean and standard deviation to Results.txt.I am able to get the mean calculate but when I open the Results.txt the standard deviation is 0. I don't know what is wrong with my code, but I believe it has something to do with the scanner being close. Here is the error message i receive after inputting Numbers.txt.
java.lang.IllegalStateException: Scanner closed
at java.util.Scanner.ensureOpen(Unknown Source)
at java.util.Scanner.hasNext(Unknown Source)
at StatsDemo.main(StatsDemo.java:48)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at edu.rice.cs.drjava.model.compiler.JavacCompiler.runCommand(JavacCompiler.java:272)
Java Code:
import java.text.DecimalFormat; //for number formatting
import java.util.Scanner; //for keyboard input
import java.io.*; //for using files
public class StatsDemo
{
public static void main(String [] args) throws IOException
[Code] .....
import java.util.Scanner;
public class CountStringNumbers { // show the number of Strings that were numbers . . ..
public static void main(String []args){
int count = 0;
int countNumbers=0;
Scanner input=new Scanner(System.in);
[code]...
can count the numbers from 0-9 if the user puted but if it is 10 it doesnt count it , and i need to write all the numbers to have that option. . . . Is there an easy way that includes all the numbers? like if(word.equals(number)){<<<???? (numbers) i know htat doesnt work but is there anything similar ?? ??
countNumbers++;
}
System.out.println("Type Something , , , and to end the the termination type STOP");
word=input.nextLine();
count++;
}
System.out.println("You wrote "+count+" lines wich from those lines "+countNumbers+" were numbers and the programe terminated ");
}
}
i am trying to turn an int number etc. 6 into 6 symbols the result would be "------". how can i transform int=6 into "------"? what function do i have to use to do this count?
public class Diagram {
public static void skrivDiagram() {
Random rand = new Random();
int[] frequency = new int[13]; {
for (int roll = 1; roll <= 100; roll++)
[code]....
Here i want to transform the frequency[face] into "-".
I can not enter Latin letters with macron (Latvian specific characters) in JavaFX programs. Instead something like Latin letters with acute are entered.
what I need to enter is characters like this: Latin letter "a" with macron
Browser Test Page for Unicode Character 'LATIN SMALL LETTER A WITH MACRON' (U+0101)
what is actually entered: Latin letter "a" with acute
Browser Test Page for Unicode Character 'LATIN SMALL LETTER A WITH ACUTE' (U+00E1)
There are several keyboard layouts available for Latvian language input. Problem persists only on Windows OS for layouts using tilde key or apostrophe key as deadkeys. There are no problems with Microsoft Latvian (QWERTY) layout that uses ALTGR key as deadkey. There are also no problems on Linux OS using keyboard layouts that causes problems in Windows OS. I also noticed that character input works as expected int SceneBuilder 2.0 (I believe it has been build with javaFX). There are no problems also in java Swing GUI framework. So could this be a bug in JavaFX or am I missing some configuration settings?
How can I enter latin letters with macron using keyboard layout that uses tilde deadkey?
I'm trying to make a program that will count each letter like if I put the word
e-1
h-1
l-2
o-1
The problem I'm running into is that if I put something like How now, brown cow? It should give me something like this
b - 1
c - 1
h - 1
n - 2
o - 4
r - 1
w - 4
but it doesn't instead the whole program crashes because of the punctuation marks and the spacing. Is there a way for me to fix that? All I know is that it has something to do with the alphabet[pos(letter)]++;
import java.util.Scanner;
public class CharCount {
static Scanner keyboard = new Scanner(System.in);
//this method should allow the user to enter a line of text (that should all be lower case) and then go to the printResults method
public static void main(String[] args) {
String text, character;
int count;
char letter;
int[] alphabet;
System.out.println("Enter a line of text:");
text = keyboard.nextLine().toLowerCase();// any text entered will be lower case
alphabet=countLetters(text);
[code]....
I'm trying to generate random 100 numbers, from 0 to 9, in an array using Math.random, but it only outputs 0s which is very confusing to me. Also, I need to be able to count how many different integers there are like 0s, 1s, 2s... 8s, 9s.
Here's my code, I only got as far as the array then got stumped on the counting part.
import java.util.Arrays;
public class countDigits {
public static void main(String[] args) {
//Create random generator and values
int numbers = (int)(Math.random() * 10);
int arrayCount = 1;
[Code] ....
and my results
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0
I have been struggling with this program for weeks. This program is supposed to take a user's inputted odd number and then print out all prime numbers lower than that number.
public class PrimeNumber
{
Scanner scan = new Scanner(System.in);
int userNum;
String neg;
public void getUserNum()
[code]...
Here is a code and error .....
View Replies View RelatedI'm attempting to create a program that employs a method to count the number of 7s a user puts as an input into the program. I'm just getting started, but I'm getting an error when I try to implement a main method that says "Illegal start of expression"
What adjustments could I make to eliminate this error message?
// Add a main method here.
public static void main(String[] args) {
//Error occurs here
public static int countSevens(int n) {
// 0. Clean-up. Get rid of any minus signs as that is not a digit.
n = Math.abs(n);
[Code] .....
Following is the code for my assignment where a user inputs his full name in a string from keyboard. It should be done using BufferedReader. The program will give his initials as output.
############################
For example: User inputs-> Ram Kumar Das
Program Returns-> R.K.D.
I am written the following piece of code. It does not return the correct output. If "Ram Kumar Das" is given as input, it gives R.K.K. as output. Arrays and objects are strictly not allowed.
Java Code:
import java.io.*;
public class Assignment
{
static int i=0;
static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
public static void main (String args[]) throws IOException
[Code] ....
for example if the given string is: The world is running java technology?
Ans:
T is =2
h is=2
e is=2
w is=1
n= 4
like wise i need out put of the program?
public static void main(String[] args) throws FileNotFoundException, IOException{
// TODO code application logic here
FileReader fr = new FileReader("gautam.txt");
BufferedReader br = new BufferedReader(fr);
int line = 0;
int word = 0;
int character = 0;
String s;
while((s=br.readLine())!=null)
[code]...
how to count the character from file
public class PairOfDice
{
private Die die1, die2;
public PairOfDice() {
die1 = new Die();
die2 = new Die();
[Code] .....
I am struggling with the final part of my code to get the dice to roll 1000 times and tell me how many times a 7 was rolled. I am getting these errors in jgrasp
----jGRASP exec: javac -g PairOfDice.java
PairOfDice.java:34: error: <identifier> expected
count = 0;
^
PairOfDice.java:35: error: illegal start of type
for (rep = 1; rep <= 1000; rep++) {
[Code] .....
22 errors
I wrote a program to read a .txt file and return how many times a, e, s, and t occur in the .txt file. I am getting an error that I do not know how to fix. It says Error: FileNotFoundException cannot be resolved to a type...
import java.util.Scanner;
import java.io.File;
import java.io.IOException;
import java.io.BufferedReader;
public class Count
{
public static void main (String[] args) throws FileNotFoundException {
String phrase; // a string of characters
[Code] ....
I have an array with the following characters {'E', 'L','E','P','H','A','N','T','P','O'}
now, I need an array that will store the first array such that only the occurence occurs e.g {'E','L','P','H','A','N','T','O'} Notice that the characters 'E' and 'P' occur twice and as a result were not repeated the second time in the new array.
How would one go about this using the counting elements technique?
I tried this but not sure how to use the counting elements technique.
char [] arr = new char{'E', 'L','E','P','H','A','N','T','P','O'};
char[] bucket = new char[(arr[0] * arr.length)];
for (int i = 0; i < len; i++)
bucket[arr[i]]++;
I've written most of the code (along with another classmate) to get this to work, but I can't seem to return the encrypted value. I'm also trying to figure out how to separate the digits (or if I'm supposed to) to make the numbers encrypted. The main kicker is that we have to be using methods to return the final values. Everything compiles, (It compiles, but no results really.)
A company wants to transmit data over the telephone, but they are concerned that their phones may be tapped. All of their data is transmitted as four-digit integers. They have asked you to write a program that will encrypt their data so that it may be transmitted more securely. Your program should read a four-digit integer number and encrypt it as follows: Replace each digit by the remainder after (the sum of that digit plus 7) is divided by 10. Then, swap the first digit with the third, and swap the second digit with the fourth. Then print the encrypted integer. Do the encryption in a method and send the encrypted number back to main.
Here are the method headers: public static int encrypt(int num) // Takes num as a parameter and returns the encrypted value public static int getnum() // gets one number from the user Example: If the user enters 1234 they should see: 0189
import java.util.Scanner; //Needed for Scanner class
public class LNFI_LNFI_program2
{
public static void main(String[] args)
{
getnum(); //Calls for getnum() method
[Code] ....