Make Int Variable That Refers To Index Number Of Array
Jan 16, 2014
I'm studying about arrays and I have some questions:
First, is there any difference between these two?
Java Code:
int x[] = new int[3];
int[] x = new int[3]; mh_sh_highlight_all('java');
It seems to me when I try them they do exactly the same, is that correct?
Second, more important question. If I want to make an int variable that refers to the index number of an array, how do I write? For example if we have
Java Code: String[] string = new String[10]; mh_sh_highlight_all('java');
And I want to have a variable "int n" that refers to an index number, so that if I set n = 5 then string[5] is selected. Note that the int n is NOT an array, but just a regular integer variable. How can I do that?
I'm trying to set a variable to point to the last full cell of an array and then create a new larger array and then have the variable be updated to point to the new array's last full cell index value.
a) Should the variable be declared static? b) What would be the best initial value to set this variable to? Shouldn't it correspond to a <for> loop index rather than a solid integer?
private lastfullcell = a[i]; private int [] a;
c) How would you update <lastfullcell> because if you passed the index through a method's loop index isn't the array index value garbage collected after the method completes?
What program needs to find is the most biggest number. It does the job, but another task of the program is to find the index of that number . The second loop should do just that, but for some reason, as the loop goes further, it passes through the if statement even though answer "a[i]" is not equal to "answer". The idea is that if a[i] and answer are equal, the "i" should represent the index number.
I'm making a program with several functions for an array of integers, one being to find the last occurrence of a given integer and returning it. The problem is that the method is returning -1 for every input, even though it's only supposed to do so for numbers not in the array. Here's the part of my code with the sections I'm having an issue with:
Driver
import java.util.Arrays; public class ArrayMethodsDriver { public static void main(String[] args) { int[] a = {7,8,8,3,4,9,8,7}; System.out.println("Last index of 8: " + ArrayMethods.findLast(a, 8)); System.out.println("Last index of 2: " + ArrayMethods.findLast(a, 2));
[Code] ....
As you can see, I'm testing 8(which should give a 6) and 2(which should give -1 because it's not in the array), and 4(which should give 4). The print statements all say -1.
Im creating my 2nd project ever and its a hangman game. I created an Array that has 20 different words in it and need to create a function that generates a random number to pick a random index of the array to obviously pick a random word. I cannot figure out the syntax for the life of me.
I am creating my 2nd project ever and its a hangman game. I created an Array that has 20 different words in it and need to create a function that generates a random number to pick a random index of the array to obviously pick a random word.
In my account driver I am trying to get the user inputted account number to get the account by account number. In my code
System.out.println("Which Account number: "); int account = scan.nextInt(); ac.get(account-1);
This works if my accounts are numbered incrementally starting with one, I want it to match the inputted account number
System.out.println("Account number: "); int num = scan.nextInt();
I am thinking a for loop is probably needed. Here is my code:
public class AccountDriver { public static void main(String[] args) { Scanner scan = new Scanner(System.in); ArrayList<Account> ac = new ArrayList<>(); boolean more=true; boolean again=false;
I was having trouble running some Java programs (not my own) in Windows XP, and in the process I uninstalled and installed JRE versions 6, 7, and 8, one at a time, probably in the order 7, 8, 7, 6, 7. The program that had the original problem only worked in V6, but some other programs stopped working. I went back to V7, and those other programs still didn't work. The message was "the registry refers to a nonexistent java runtime environment installation". The only advice I could find with Web searches was to reinstall the JRE. Needless to say, that didn't work.
So I looked at the registry, and I found that there were still references to V8, which had been uninstalled. The first was
So, there is a bug in the installer(s): if you uninstall V8 and install V7, the 'CurrentVersion' isn't set correctly, with the result that the registry points to a non-existent folder. The V8 uninstallation should delete these entries, or the V7 installation should change them.
public static void main(String args[]) { Scanner in=new Scanner(System.in); System.out.println("Enter the Total Number of Integers:"); int totalInteger=in.nextByte(); long largest=0; for(int i=1;i<=totalInteger;i++) { System.out.println("Enter Integer-"+i+":");
[code]...
I want to get Index of that particular number in which Value is largest.
I am receiving an ArrayIndexOutOfBoundsException for the following code, which moves a creature through a 2D array maze. I have altered the clauses of the first if statement for the four direct methods (north, south, east, and west) multiple times (i.e. x + 1 >= 0 && x > 0 && x - 1 > 0 && x < array.length...etc). However, while the code occasionally runs, more often than that it returns this exception. Catching the exception seems like a poor workaround though if worst comes to worst I'll do that.
I included only the relevant functions of the code:
public boolean goNorth(char[][] array) { boolean success = true;; x = getX(); //x = this.x; y = getY(); //y = this.y; if ((x - 1 >= 0 && x - 1 < array.length) && (y >= 0 && y < array[x].length)) {
I want to do a simple background which is only rendered once onto my screen. I want to use
G.fillRect(0, 0, getWidth(), getHeight());
and make the whole background black, but only once. I wanted to try out making the fillRect into a variable so I can do:
if (background == null) { //background is the variables name. G.fillRect(0, 0, getWidth(), getHeight()); }
The point is, I want G.fillRect(0, 0, getWidth(), getHeight()); to be a variable, even if this is the wrong way to approach what I want to accomplish, is it possible to make this line of code into one variable? The rest of my code if you need info:
I have this program where I'm supposed to fill an array with 1000 indices with 1000 randomly generated numbers between 1 and 1000. The program is supposed to check if any of the numbers match an index that is the same value (so for example, the number 4 is in index 4). How to check for that condition, especially using a binary search (I'm also told to use a binary search).
Right now the variable index isn't initialized because I don't know what to initialize it to exactly. How do I check to see if any numbers match the value of the same index?
import java.util.*; public class Identity { public static void main(String[] args) { int [] integers = new int [1000]; // Fill array with randomly generated numbers int [] display = GenerateRandom(integers);
I searched online for this error and found out it's because the array is smaller than the index but I am not sure how I can fix this error....
public Lamborghini[] getCarsWithHorsepowerRange(double lowHP, double highHP){ int i = DEFAULT_ZERO; Lamborghini[] carWithinHPRange = new Lamborghini[i]; for (Lamborghini lambos : inventory){ double horsePower = lambos.getHorsepower();
[Code] ....
I tried
Lamborghini[] carWithinHPRange = new Lamborghini[i+5];
//which works sometimes because once I boost up the range and so there'll be more result then the error came up again....
My project was to create an array holding 10 integers and populate the array with 10 random numbers. Then ask the user to guess the number. Prompt the user with a while loop if their input is out of range. Determine if the users number is in the array, and display which index location the number is in. I got most of the code done but am having trouble displaying the index location.
import javax.swing.*; public class Homework4 { public static void main(String[] args) { int[] numarray = new int [10]; char repeatcode = 'y';
I am trying to make different arrays each being filled with random numbers from 0 to 2000, however when I run this code I get the error mentioned in the header. here is part of my code
for (int i = 1; i <= 14; i++) { int n = (int) Math.pow(2, i); int[] list = new int[n]; for( int j = 0; j <= list.length; j++){ list[j] = (int) (Math.random() * 2000); } }
I want to find a certain element in array I have to scan through the array index starting from 0 until I find the number I am looking for. Even in data structures which use hashing like HashMap and Hashtable we will have to scan through the keys until we find the key we are looking for. So what is the use of hashing over index based searching? I mean how is hashing an advantage over an array?
I am getting error array index out of bound ... Error detail is :
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0 at abhiExample.arraytwodiam.main(arraytwodiam.java:27 )
And program is
Java Code:
package abhiExample; import java.util.Scanner; public class arraytwodiam { public static void main(String [] args) { char[][] Atrace={}; int i,j,k,l=0,row ,characters;
I'm trying to iterate through an array of integers and find the start position of the part of the array containing the most consecutive 1s.
For example given the array {1,3,1,1,1,1,5,3,2,1,1}, the method should return 2 and given {1,4,5,1,1,1,5,1} the method should return 3.
So far, I've managed to retrieve the element where the consecutive 1s begin. However, I'm unsure how to get the index of this element and this implementation doesn't work if there is more than one set of consecutive 1s.
public class GetIndex { public static int getPosition(int[] myArray) { int index = 0; int tracker = 0; int mostOnes = 0; for(int i = 0; i < myArray.length; i++) {
