Negative Character Literal?
Jun 3, 2014char c=(char)-65;
This is legal but how ?? what is the value actually being stored in c ? The output is shown as .
char c=(char)-65;
This is legal but how ?? what is the value actually being stored in c ? The output is shown as .
i want to have a JLabel that could "robotically" type words character by character.
View Replies View RelatedI use Eclipse (kepler version, with JDK 7) on MacBook Pro (Lion).I want to overwrite a line printed on my console. I used "" for that. I was expecting the cursor to go to the beginning of the line. Instead, it is going to the next line.
Code:
System.out.print("Superman
Sober");
Expected Output:
Soberman
Actual Output:
----------------
Superman
Sober
What I am trying is find the XOR value between charcters of a String here is my code
public static void main(String[] args) {
System.out.println(grayCode("100"));
}
public static String grayCode(String input){
StringBuilder temp=new StringBuilder();
temp.append(input.charAt(0));
for(int j=1;j<input.length();j++){
char previous=input.charAt(j-1);
char current=input.charAt(j);
char xorVal=(char)(previous^current);
temp.append(xorVal);
}
return temp.toString();
}
but I am not getting actual XOR value of two charcters that I am trying to get.
I am trying to build up the alphabet character by character. Like:
a
ab
abc
abcd
Well as of now I can only print out the alphabet with my loop like abcdefg...z.. So here is the code I am trying to use:
public void loop4() {
char alph = 'a';
while(alph <= 'z') {
System.out.println(alph);
alph++;
}
}
I have entered more than one character but output is only one character .....
class InputUser
{
public static void main(String arg[])
throws java.io.IOException
{
char ch;
ch=(char) System.in.read();
System.out.println(ch);
}
}
what is default literal for Boolean data type?
View Replies View RelatedI have a program like below:
final String s1 = "AAA";
final String s2 = "AAA";
String s6 = s1+s2;
String s7 = "AAAAAA";
if ( s6 == s7 ){
System.out.println("s6 and s7 are same" );
}
On running, it prints "s6 and s7 are same". But if i remove the final modifier of s1 and s2 then it's not. What could be the reason?
I need to use print not println to declare stuff and I need to have string literals I think that's /n. Now when I compile it just shows row1, row2 ect. Why does it work like that?
public class art {
public static void main(String[] args) {
//local variables
String row1= "***********************";
String row2= "** *** *** **";
String row3= "** ***** ***** **";
[Code] ...
While doing trial and error got caught in the below scenario.
public class Crypt {
public static void main (String args[])
{
/*all I want is calculate a binary number (ex -: 22 , 34) using decimal base (10n).
*So, I have to convert 2 p into 10n form so I have to find n in terms of p . We have x as the input.
* The formula works as below.
*2p =10n
*p ln (2) =n ln (10)
*n = p [ln(2) / ln(10)]
*2 p = 10 p [ln(2) / ln(10)]
[Code] ....
in Operator/Literals, it says "There is no literal representation for binary numbers in C, C++, or Java." seems "0b11001" could reprensent binary numbers?
int i = 0b100;
System.out.println(i);
the output should be 4.
I'm trying to insert some data of type date into database table using hibernate.i take the input date from an xhtml form as shown below
addEvent.xhtml
Event Date (dd-mon-yy) :
<br/>
<h:inputText id="eventdate" value="#{eventBean.eventDate}" p:required="required"
p:type="date"/>
<p/>
<h:commandButton value="Add Event" actionListener="#{eventBean.addEvent}" />
<p/>
This is my addEvent method in EventBean.java
public void addEvent(ActionEvent evt) {
uname = Util.getUname();
boolean a = EventDAO.add(this);
if ( a) {
message = "Event has been added!";
[Code] ....
While executing this..i get the following error: ORA-01861: literal does not match format string. Could it be due to any mismatch in date format (chrome browser automatically takes date in the format mm-dd-yyyy )? If yes, how do I resolve it? (I'm using Oracle database)
I thought numeric literal were by default int or doubles, depending on if have a . and numbers after the But I wrote a quick test program as listed below. I understand the float float floatA = 5.5; failed to compile since 5.5 is a literal of type double and you are trying to assign this to a floag
What I am having problems with is byte byteA = 5; 5 is a literal of type int and this is being assigned to a byte and compiler should complain.The compiler does not allow two byte values to be added and assigned to a byte since the result of the addition is an int
class literalTesting{
public static void main(String[] arg){
byte byteA = 5; // allowed WHY I thought literal is an int and assigning int to byte
byte byteB = 10; // allowed
[code]...
I am working with java project which is kind of charting room..but the problem is when am writing the query for listing the message in the conversation the error prevail in my eclipse...string literal is not properly closed by double quote...this is my java file
<%
String uname=session.getAttribute("username").toString();
String pword=session.getAttribute("password").toString();
java.util.Date dat=new Date();
int x=1;
try{
[code]....
string literal is not properly closed by a double quote
View Replies View RelatedIf you write
byte b = 100; it works (implicit conversion of implicit int literal 100 to byte.
But if you have a methodvoid bla(byte b){}
And want to invoke it with a literal (which is an int by default):bla(8) then there is no implicit conversion.
Is the byte b = 100; just an exception in Java? And is it the rule that one has to explicitely cast (narrow) integer literals when passing to smaller-than-int types?
when i input a positive integer it works but when i input a negative number it doesn't work
my pseudo code:
READ input
WHILE( NOT CORRECT INPUT)
READ INPUT AGAIN;
ENDWHILE
DECLARE array arr[input]
FOR(i=0 to input-1)
arr[i]= Random number from 0 to 100;
ENDFOR
DISPLAY ARRAY
error message when i input -5 : Exception in thread "main" java.lang.NegativeArraySizeException atPosNeg.main<PosNeg.java:36>
import java.util.*;
class PosNeg{
public static void main(String args[]) {
Random generator = new Random();
Scanner scan = new Scanner(System.in);
[code]....
How do you replace negative zero value with a zero value when Printing results:
I want to remove the minus sign in -0.0000 and instead have 0.0000.
I am Printing coordinates and I do not want to have negative zero.
the coordinates are defined as double.
System.out.format(java.util.Locale.US," %.4f %.4f %.4f %.4f%n"xCur ,yCur,xNext,yNext);
0.0000 1.0000 -0.0000 0.0000
I need understanding why
1111 1101 = -3
For some reason, I'm getting the correct result, but my negative sign is having issues. For example, if I do 1/4 - (-2/4), I get (-3/4).
Here is my minus method for subtracting fractions.
/**
Subtracts a fraction from another fraction.
@param toUse, the fraction to subtract.
@return minusFraction, the result after subtraction.
*/
public Fraction minus(Fraction toUse)
[Code] .....
Here is my reduce() method, just in case...
/**
Reduces the fraction, if possible, to it's simplest form.
Converts negative fractions to the form -x/y, or if -x/-y --> x/y
*/
private void reduce() {
int lowest = Math.abs(numerator);
int highest = Math.abs(denominator);
[code]...
I only switched an operator from my previous addition method, given here as well. I think only switching the + to a - may have caused my issue.
/**
Adds two fractions together.
@param toUse, the fraction to be added.
@return plusFraction, the sum of the two fractions.
*/
public Fraction plus(Fraction toUse) {
[Code] .....
How do u find the binary of negative numbers? I already did it for positive numbers,?
View Replies View Relatedhow to avoid getting negative numbers of coins, use casting and mod to show how many quarters, dimes, nickels, and pennies there are?
import java.util.Scanner;
public class VM
{
public static void main(String[] args)
{
//money deposit
Scanner input = new Scanner(System.in);
[code]....
I am new to Android. I have byte array of size 10. I am passing the Decimal values (131 - 140) to byte array. But while printing I get Negative (-) values with decreasing order .
How can I get same value as positive values?
Or How can I store positive value e.g. 131 as byte array element.
Please not my requirement is array must be ByteArray only
I am not sure what is happening with my code, but it is giving me a negative number. I am trying to write a program that calculates the product of the odd integers between 1 and 25. I messed with the program and as soon as you enter a number over 22, the end result is a negative number.
int total = 1;
for (int i = 1; i <= 25; i += 2){
total *= i;
}
System.out.println("Product:" + total);
I am trying to raise a real number to a negative value e.g x-y(x raised to power -y) which can also be written like 1/xk . I am trying to run th program each time bt it doesnt give me the desired result.
Here is the code
public class RaiseRealPower {
public void run(){
double value =readInt("Enter value ");
double power =readInt("Enter power ");
System.out.println("Answer is " +raiseIntToPower(value,power));
[Code] ....
I am very new to Java. I have been working for a couple months on a program for school. It has not gone well. I finally was able to scrap together a working program, but i left something out that needs to be. I have to include input validation to check for negative values, prompting users to re-enter values if negative. I have included my current code, the program works perfectly, but what to do about the negative numbers.
Java Code:
package gradplanner;
import java.util.Scanner;
public class GradPlanner {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int numofclasses = 0;
int totalCUs = 0;
[Code] ....