Number Guessing Program - Computer Guesses A Number That User Is Thinking Of Within Certain Range
Mar 28, 2015
I have a beginning Java Program I have been working on that creates a number guessing program where the computer guesses a number that the user is thinking of within a certain range. I so far have the program below, but need getting rid of a few kinks/ adding features.
-First, I need to set it up so that the user will be prompted and give a range. It should run and produce something like this:
Welcome to this first-ever mind-guessing program!
Please pick a range (higher than 1 and no larger than 50): 32
You will choose a number between 1 and 32... and I will try to guess it.
With each of my guess, you will tell me whether I am too high (h or H), too low (l or L), match (m or M), or you want to quit (q or Q). My objective is to find the number using as few guesses as possible.
-Second, the game is supposed to give up and restart after failing the five, guesses, but for some reason, after it fails the fifth time, it prompts a fifth guess once again instead, then restarts after- I need to prevent this, so that it should look something like this:
My fourth guess is 17: h
My guess is too high?
My fifth guess is 16: h
*** I am unlucky this round. I give up.
Let's play!
My first guess is 10:
etc..
import java.util.*;
import java.lang.Math;
public class numguessprac1 {
// Declaring variables
public static String input;
public static int quit;
public static int guess;
public static int wins;
Write I program that generates a random number and asks the user to guess what the number is. If the user's guess is higher than the random number, the program should display "Too high, try again." If the user's guess is lower than the random number, the program should display "Too low, try again." The program should use a loop that repeats until the user correctly guesses the random number.
public class NumberGuess { public static void main(String[] args) { // Create a Random object. final static Random rand = new Random(); // max number is the upward bound number final int MAXNUMBER = 10; /** * Method should return a random number within the upward bound MAX_NUMBER.
[code]....
I get compiler error message
NumberGuess.java:25: error: ';' expected int getRandomNumber (); ^ NumberGuess.java:63: error: reached end of file while parsing System.out.println("You got it right in " + numberOfGuesses + " guesses."); ^
I wrote the following code for a lottery game. The problem comes when I run it. If one number of a 3 digit number matches, it's supposed to print "you win 1000" But regardless if a number matches or not, it says "sorry, no matches" ...
import java.util.Scanner; public class Lottery { public static void main(String[] args){ //generate lottery number int lottery = (int)(Math.random() * 1000); //Prompt the user to enter numbers Scanner input = new Scanner (System.in); System.out.print("Enter your numbers (3 digits): "); int guess = input.nextInt();
trying to write a program that takes a user inputted number and converts it to a binary number.
Here's what I have:
package com.java2novice.algos; import java.util.Scanner; public class Converter { static Scanner console = new Scanner(System.in); public void printBinaryFormat(int number){ int binary = console.nextInt();
I have been struggling with this program for weeks. This program is supposed to take a user's inputted odd number and then print out all prime numbers lower than that number.
public class PrimeNumber { Scanner scan = new Scanner(System.in); int userNum; String neg;
I am using eclipse for this project. Every time I run this program the choose method will always choose 0. Ignore the Sleep.sleep() method, there is another class in the program that performs it.
import java.util.Scanner; public class gamestart { public static int num; public static String name; public static String diff; public static String choice;
I tried this program, its guessing game. Where program decide 1 number and user will guess number. I am getting 1 problem. When user want to play game again.the random number remain same. So where i can put reset random in code..? And 1 more question if I want to write driver code for this. What should i transfer to driver code.
import java.util.Random; import java.util.Scanner; public class GuessGame { public static void main(String args[]) { String choice="y";
What's wrong with my code. It says 'you win' even when I guess an incorrect number. And then the 'win' message keeps repeating. I'm thinking I need a way to generate a new input? And then maybe take the 'win' message out of the loop, but that breaks it too.
I was told to write a program which generates a random number between 0 to 5 *including 5* and give the user 3 chances to guess this number:
-If the user enters a wrong number within 0 to 5, the user has lost one opportunity. -If the user enters a number out of range, the program should prompt the user to enter a number within the range -If the user has 3 unsuccessful attempts, the program will print the number.
I was also instructed to use :
Random randomNumber=new Random(); int i= randomNumber.nextInt(6)
I have attempted it and this is what i have so far.
import java.util.Random; import java.util.Scanner; public class Exercise1 { public static void main(String[] args) { Random randomNumber=new Random();
So I am currently writing my first assignment and have run into problems with my coding. The task was to have someone enter a 5 digit number and in return, I list each number on their respective lines. We also must create an error if a number other than 5 digits was entered. My problem is that when they enter a 1 or 2,3,4,6,7,8 digit number.. the error message occurs along with the rest of the messages (listing the numbers, etc). I want the program to end (or even re-ask to enter the numbers) if they incorrectly enter the data.
I am getting a strange error and it almost seems like its not comparing it to the random generated number just the guess that i entered before. Here are my error messages.
Exception in thread "AWT-EventQueue-0" java.lang.NullPointerException at guess.the.numbers.GuessTheNumbers$ButtonHandler.actionPerformed(GuessTheNumbers.java:119) at javax.swing.AbstractButton.fireActionPerformed(AbstractButton.java:2018) at javax.swing.AbstractButton$Handler.actionPerformed(AbstractButton.java:2341)
So im trying to make a coin flip game in java. Im relatively new to the language and the only other language i knew was javascript so im still learning. Ive already made one before using just one class and putting all the code inside, but im now trying to do it with methods since im trying to learn them. The basic idea of the game is that the user picks how many coins they'd like to flip, they pick heads or tails, then the computer flips the coins and calculates if there was more heads or tails to tell the user if they won or not. Im not quite complete with the program as you can see but ive already run itno an error. I was just doing some tests on the code i already have and i found that when i call the method settingUpCoin in my main class the program terminates. So basically, when i run it, it executes userImp right, transform right, but then it dosent let you enter a value for howManyCoins and terminates before you get to settingUpCoin.
(Notes: this was all done in eclipse luna build or the java ide. The class files are all separate in the actual thing i just put them together here to demonstrate my code.
import java.io.IOException; public class Coin { double myCoin; int numOfCoins; int counter; double arrayOfCoins[] = { };
so I had to create a program that allows the user to enter a day using a number and then enter a year and after they did that it would create an entire calendar for that year ..so I have that but the only issue is I can not get the numbers to line up neatly.how to do the entire thing in loops, I tried a couple in here..what this would look like as loops instead of switches and cases and if else
import java.util.Scanner; public class Calendar { public static void main(String[] args) { Scanner scanner = new Scanner(System.in);
Any way to shift in a range from 0-9 when I already have the shift value.
The reason I am asking this is because I am writing a telephone validation program and I got most of it complete and all I need to do now is the shift an encrypted phone number given to me by the user, and shift it however many times my shift value is.
Example: I am trying to get this phone number, 545-319-8712 to become 212-086-5489. The shift value is 3. So basically since the phone number given to me is 3 numbers higher than the phone number I am trying to get, so if the first number I receive from the user is higher than 2 then I would shift the number the user gave me down by the shift value I have already gotten.
5 shift down 3 = 2, 4 shift down 3 = 1, etc. But I also want to know how I can make a number like "1" to shift down 3 to become 8. This is the range; 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
If I have to shift a number down 4 spots and I get the number 1 from the user than I want to get the number 1 to first down four times to become 7.
[1] -> 0 -> 9 -> 8 ->[7]
Basically if I have to shift a number down 4 and the number is less than or equal to 3 then I want it to continue from 9 .
Then just reverse the steps if I have to shift a number up, USER gives me "090", i want "212" I shift the number up by 2.
My question is how can I make the program repeat until the user enters the number 4 to exit?
/** * Write an application for a furniture company; the program determines the price of a table. Ask the user to choose 1 for pine, 2 for oak, or 3 for mahogany. The output is the name of the wood chosen as well as the price of the table. Pine table cost $100, oak tables cost $225, and mahogany table cost $310. Also ask the user to specify a
(1) large table or a (2) small table.
Add $35 to the price of any large table and add nothing to the price for a small table. Display the output. Your program must repeat until the user chooses to exit.
*/ import java.util.Scanner; public class Wood { public static void main(String[] args) { Scanner input = new Scanner (System.in); System.out.println ("Table Prices");
public class printprimes2{ public static void main(String[] args){ for( int i = 1 ; i <=199 ; i++ ) //iterate 1 - 199; 2 is prime { for ( int j = 2 ; j < i ; j++ ) //iterate 2 - potential composite EXCLUSIVELY; every number can be divided by one and itself
[Code] ....
It doesn't print only prime numbers but all numbers that range from 0 to 199. What do you think I am doing wrong?
I am trying to write a program that asks the user to enter a number from 1 through 10 and then the program will display the roman numeral for that number.
I am also adding a error message in which i haven't yet because im still trying to figure out how to the program will do the roman numeral.'
I have used the if and else if. but when i input a number it just repeats the number back to me.
The program cimpiles but it doesn't do what i want. here is what i have so far. how can i get the program to display the roman numeral after the number is entered.
import javax.swing.JOptionPane; public class Romannumeral { public static void main(String[] args) { double number;
The assignment is to make a program that prints the number of prime numbers in a range. This is what i have so far. The output is a list of 2s. I created the for loop to cycle through the range of 17-53 and nested a while loop within to test each incident of the for loop to check for divisors starting with 2 until the modulus result is 0 resulting in a false for being a prime number. Then the loop should increment to the next i value. The last part is an if statement that i had intended to add counters to the k variable that would keep track of the number of prime numbers.
boolean isPrime = true; int j = 2; int k = 1; for (int i = 17; i <= 53; i++){ { while (i % j == 0){ isPrime = false;
I found an exercise online to create a small program . I have this code that I have done so far:
import java.util.Scanner; public class Test { public static void main(String args[]) { Scanner sc = new Scanner(System.in); long a = sc.nextLong(); long b = sc.nextLong(); long count = 0; // counter for (long c = a; c <= b; c++) { if (c % 2 == 0 || c % 3 == 0 || c % 5 == 0) { count++; } } System.out.println(count); } }
This program is suppose to give me the number of numbers which are dividable by either 2,3 or 5 in a range of a to b, where a<=b.
FOR EXAMPLE: a=5 b=8 ... output: 14 (since there are 14 numbers in between 5 and 8 which are dividable by either 2,3 or 5.)
It works great for all of the numbers except higher ones such as a=123456789012345678 b=876543210987654321. Here it doesn't give me any output. From what I know it is because the code is still running. But there must be a quicker way ...something that can modify the code so it finishes in the matter of seconds not hours. Something that will fasten the process of checking if the numbers are dividable...
Ok so I have my program working for the most part. In this program I am supposed to take input from the user until they enter a negative number and that works, the problem is that it doesn't work if I enter a negative number on the first prompt. For example if I enter a 100 it would prompt me again and if I enter a negative number it would quit and give me the average, but if I enter a negative number the first time I am prompted the program just gives me an error. How do I fix that?
import java.util.List; import java.util.ArrayList; import java.util.Scanner; public class Application { public static void main(String [] args){ Scanner input = new Scanner(System.in); List<Integer> grades;
In my cs class, we have to write a program that throws an exception if the user enters a negative number, the program should prompt the user to enter only positive numbers and then let them retype the number. But everytime I throw an exception, my program gets suspended.
What am I doing wrong, or is there no way to continue a program if an exception is thrown? Does the program automatically get suspended when an exception is thrown?
try{ do { N = kb.nextDouble(); if(N<0) { throw new NegativeArraySizeException(); } else j++; } while(j==0); fill.size(N); } catch(NegativeArraySizeException e) { System.out.println("The number you entered must be positive. Please try again."); }
