Print Only Top 15 Highest Numbers Of Occurrence From RNG Output
Oct 15, 2014
I created a random number generator for my course and it works perfectly. I now need to print only the top 15 highest numbers of occurrence from the RNG output. How i can do this?
Here is my block of code.
package section4;
import java.util.Random;
public class Lottery {
public static void main(String[] args) {
Random rand = new Random();
int freq[] = new int[51];
I tried to create file and write the output of my program in it in java when i use WriteLong then the file does not contain long value, how I create this file my program is to print prime numbers between 500000 to 10000000
public class primenumber { public static void main(String[] args) { long start = 5000000; long end = 10000000; System.out.println("List of prime numbers between " + start + " and " + end); for (long i = start; i <= end; i++) { if (isPrime(i)) { System.out.println(i);
In a text file, I have individual titles (starting with ">" character), and under those titles, I have calculated values for a Counter. I want to search the entire text file for the highest counter under every title. After I get the highest counter, I would like to print it's title, name of the counter, and counter value. Example of the code I already have:
int letterCounter; String line; if (line.startsWith (">")) { bw.write (""); bw.write (line); } else { //code that counts how many total letters (letterCounter) under title }
I am working on an assignment but I am not getting any out put and I couldn't fix it?The class HighLow below asks for three integers and prints the highest and lowest of them on screen. Your task is to write the missing methods high and low, which receives the integers user inputs as parameters and return the highest and lowest integers respectively.
import java.util.Scanner; public class HighLow { public static void main(String[] args) { int number1, number 2, number 3, high, low; Scanner reader = new Scanner(System.in);
The class HighLow below asks for three integers and prints the highest and lowest of them on screen. Your task is to write the missing methods high and low, which receives the integers user inputs as parameters and return the highest and lowest integers respectively.
import java.util.Scanner; public class HighLow { public static void main(String[] args) { int number1, number 2, number 3, high, low; Scanner reader = new Scanner(System.in);
1.Write a JAVA program that will input 10 scores and output the Highest and Lowest score.
2.Write a JAVA program that will input the base and power and display the result: Example: Base is 4 Power is 2 the answer is 16 (Note: Math.pow( ) method is not allowed)
3.Write a JAVA program that will input an integer number, and then will output the sum of all inputted numbers. The program will stop in accepting inputs if the user entered 0.
I'm trying to make a program that generates 20 random integers between 1 and 20 and then prints the list of random numbers to the screen. After that, I want to print a different list to screen with the same numbers from the first list only skipping any number that has been already printed to the screen. So two lists are printed to the screen. The first one has 20 random numbers. The second one has those same 20 numbers but only prints the numbers in the first list that aren't duplicated. So if m
y list of 20 random integers contains three 2s and two 14s, only one 14 and one 2 is printed to the second list. Currently, my code generates 20 numbers from 1 to 20 and stores those numbers in an array but I don't know how to print solve the second part of my problem. I don't know how to print the s different list only without duplicate numbers. As a result, my output is nothing because it doesn't print any number from the first list as oppose to skipping only duplicate one.
public void randomNum(){ System.out.println("Twenty random integers: "); int max = 20; // max value for range int min = 1; // min value for range Random rand = new Random(); int[] all = new int[20];
I've to read in an array of 1000 random numbers, and then my program sorts them depending on whether the user chooses bubblesort, selectionsort, etc...My code all works fine, my problem is with the actually output display. I have method that displays the content of the array that I call for the unsorted array, and for the sorted array. So at the moment the output to the user looks like:This program sorts an array of numbers by your choosing.
Array before sorting: 148 626 817 4 312 652 643 134 etc... for 1000 numbers
Write a program to create an integer array of size 20. Then, the program should generate and insert random integers between 1 and 5, inclusive into the array. Next, the program should print the array as output.
A tremor is defined as a point of movement to and fro. To simulate it, the program will generate a random number between 0 and 19, which represents the location in the array (i.e. index number). Then, the 3 numbers to the left and right of this location should be reset to the value 0. If there isn't 3 numbers to the left and right you may assume a lesser number depending on the boundaries of the array.
Then, the final array should be printed as output. There is no user input for this program.Your program must include, at least, the following methods:
-insertNumbers, which will take as input one integer array and store the random numbers in it. -createTremor, which will generate the random number as the location and return it.
I have printed the result of my program into an output file.
For some reason I can't figure out how to get the file output.txt to actually print.
I've tried printing it like I would normally print a file but it's not working.
Java Code:
final PrintStream console = System.out; File file = new File("output.txt"); PrintStream out = new PrintStream(new FileOutputStream(file)); System.setOut(out); System.out.println(collection.toString()); System.setOut(console);
What do I do after this? mh_sh_highlight_all('java');
I am trying to write to an output file that the user names. I have flushed and closed the printwriter, so now I am at a loss. The console output works fine with the formatting, and the file is created, but I cannot get the file to populate. I have the following:
public static void main(String[] args) {
try { Scanner kb = new Scanner(System.in); System.out.print("Input file: "); String inputFileName = kb.next(); System.out.print("Output file: "); String outputFileName = kb.next(); // Construct the Scanner and PrintWriter objects for reading and writing File inputFile = new File(inputFileName); Scanner in = new Scanner(inputFile); PrintWriter out = new PrintWriter(outputFileName);
I need to receive input from the user, as many times as he wants. tha is done with the while loop. I also need to output the min and the max numbers the user enters, therefore i have the if statememnts. also if the user enters only one value i need to output that one value as the min and the max.
int min =0; int max = 0; int option = JOptionPane.YES_OPTION; while ( option == JOptionPane.YES_OPTION){ String dataString = JOptionPane.showInputDialog("Enter an integer"); int data = Integer.parseInt(dataString);
Am having trouble understanding how to print my results (I have 50 of them) , only 10 per line.
Im using an array that is 1-50. The first 25 I raise to the power of 2 and print it.
The next 25, I multiple by 3 and print it
Public class KDowling { /** * @param args the command line arguments */ public static void main(String[] args) { double [] alpha = new double[50]; //declare an array 50 indexes int num=1; // declare variable num int counter=1;
I've almost got this to work. Right now it prints out one comma for the first set of 3 numbers. For exmaple, if the user input is 12345678 the code will print out 12345,678. I'm trying to figure out how to get it to print out commas for the rest of the numbers. My first thought was to use a loop but I can't get it to work....
private static void printWithCommas(NaturalNumber n, SimpleWriter out) { assert n != null : "Violation of: n1 is not null"; assert out != null : "Violation of: out is not null"; assert out.isOpen() : "Violation of: out.is_open"; if (n.compareTo(THOUSAND) < 0) { out.print(n);
Write a program to print the even numbers and the odd numbers between 0 and 30 using a single thread and then again using multiple threads.
I already finished the single-threaded program but am having trouble with the multi-threaded one. I have three classes; one class for odd numbers, one for even numbers, and one to execute the code. Here is my code so far:
Even Numbers:
Java Code:
public class EvenNumbers extends Thread { public void run() { for (int i=1; i<=30; i++) { if (i%2 == 0) { System.out.println("Even number " + i);
[Code] ....
Unfortunately, my output ends up looking a little weird:
Java Code:
C:UsersREDACTEDDropboxSchoolworkREDACTEDJava ProgrammingUnit 5 - Exception Handling, AssertionsProgram - Thread>java MultiThread Even Numbers: Odd Numbers: Even number 2
Write a program that will read unspecified numbers of scores . The program will output the average of these scores and the scores that are below and above the average.
Example.. 1 2 3 4 5 Average is 3 Below 1 2 Above 4 5
package com.arraydemo; import java.util.TimeZone; import java.util.concurrent.TimeUnit; public class ArrayStructures { public long[] theArray; public int arraySize; public ArrayStructures(int size)
I am trying to cast an integer into a double. it works but I need two decimal number after the dot and for example I can print 7.51 but how can I get it to print 7.50 and not 7.5
public int compareTo(Money o){ int d1 = (this.dollars * 100) + this.cents; int d2 = (o.dollars * 100) + o.cents; return d1 - d2; }
On my main method I have
public static void main(String[] args){ Money money1 = new Money(10, 49); Money money2 = new Money(2, 99); System.out.println("result: " + "$" + (double)money1.compareTo(money2)/100); }
It prints 7.5 but I want it to print 7.50, how do I do this .....
class shape{ public static void main(String [] args){ for(int x =0 ; x<=6;x++){ for(int y =0 ; x > y ; y++){ System.out.print(x); } System.out.print(" "); } } }
I am able to get the integer in the array printed but I am lost on how to hold and print the distinct numbers.
This program will read in 10 numbers from the user via the console. It will display on the console only the distinct numbers, i.e. if a number appears multiple times in the input it is displayed only once.
Here is a sample test run: Enter an integer: 2 Enter an integer: 6 Enter an integer: 1 Enter an integer: 8 Enter an integer: 6 Enter an integer: 1 Enter an integer: 2 Enter an integer: 4 Enter an integer: 7 Enter an integer: 5 The number of distinct values is 7 2 6 1 8 4 7 5
Where I am doing mistake to print the numbers of Armstromg numbers requested.
import java.util.Scanner; public class ArmStrongNumber { public static void main(String[] args) { // TODO Auto-generated method stub int x, y, z=0, temp, temp1=1;
I want to make project about java communication with hardware (wiz110sr) via LAN (Rj45). And for example, my hardware have ip address 198.168.0.1 ; port: 1202, connected with my PC(via lan/Rj45). I want show the output (such as numbers and letters) from my hardware in console netbeans.
When I running my code, appear :
" Exception in thread "Thread-0" java.lang.RuntimeException: Uncompilable source code at mypkg.startListenForTCP$1.run(startListenForTCP.ja va:48) at java.lang.Thread.run(Thread.java:745) BUILD SUCCESSFUL (total time: 1 second) "