Program Repeat Until User Enters Number 4 To Exit?
Feb 18, 2014
My question is how can I make the program repeat until the user enters the number 4 to exit?
/**
* Write an application for a furniture company; the program determines the price of a table. Ask the user to choose 1 for pine, 2 for oak, or 3 for mahogany. The output is the name of the wood chosen as well as the price of the table. Pine table cost $100, oak tables cost $225, and mahogany table cost $310. Also ask the user to specify a
(1) large table or a
(2) small table.
Add $35 to the price of any large table and add nothing to the price for a small table. Display the output. Your program must repeat until the user chooses to exit.
*/
import java.util.Scanner;
public class Wood {
public static void main(String[] args) {
Scanner input = new Scanner (System.in);
System.out.println ("Table Prices");
[Code] .....
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Oct 19, 2014
In my cs class, we have to write a program that throws an exception if the user enters a negative number, the program should prompt the user to enter only positive numbers and then let them retype the number. But everytime I throw an exception, my program gets suspended.
What am I doing wrong, or is there no way to continue a program if an exception is thrown? Does the program automatically get suspended when an exception is thrown?
try{
do
{
N = kb.nextDouble();
if(N<0) {
throw new NegativeArraySizeException();
}
else
j++;
}
while(j==0);
fill.size(N);
}
catch(NegativeArraySizeException e) {
System.out.println("The number you entered must be positive. Please try again.");
}
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Aug 11, 2014
This is what I have so far, but how do I ask the user for the number or rows and give the user the option to repeat the program?
public class Pyramid {
public static void main(String[] args) {
int myLevel;
int i, j , k;
myLevel = 6;
for (i = 1; i <= myLevel; i++) {
[Code] ....
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Oct 28, 2014
In my computer science project the program has to end if the user enters 0 as his choice from a menu given to him, so how would I go about ending the program.
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Apr 17, 2014
How do i exit a java program is the user input is nothing "",This is my code
Java Code:
import java.util.Scanner;
public class MyQueue<T> implements Queue<T> {
private T[] ringbuffer;
static int capacity = 0;
int mysize = 0;
[code]....
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Oct 1, 2014
Description of the program: read a sequence of positive integers from terminal. When user types
-1, the program will print out the largest number and exit.
Program mid.java
import java.util.Scanner;
public class test
{
public static int num;
public static void main (String[] args)
{
Scanner in = new Scanner(System.in);
num = in.nextInt();
int large = num;
while(num > 0);
{
if(0 > num && num > large)
large = num;
}
System.out.println("The largest number is : " + large);
}
}
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Feb 24, 2014
import java.util.Scanner;
public class Project_5
{
public static void main (String[] args)
{
Scanner input= new Scanner (System.in);
[code]....
So I'm attempting to have this program take the users input of integers, pressing enter in between each one. If they enter a negative number it lets them know that its invalid. At the end of the program it takes all of the valid integers entered and must add them and average them. I've put the final println in there as a placeholder. If the user types in "6" then presses enter and types in "3" , the output is:
There were 3 valid numbers entered.
The sum of the valid numbers was --- and the average was ---.
There were 0 invalid numbers entered.
It then continues on allowing the user to enter more values. Here is the example output for correct code"
Enter a positive value (EOF to quit): 4
Enter a positive value (EOF to quit): 7
Enter a positive value (EOF to quit): 8
Enter a positive value (EOF to quit): 2
Enter a positive value (EOF to quit): -1
The number "-1" is invalid.
Enter a positive value (EOF to quit): 8
Enter a positive value (EOF to quit): 0
Enter a positive value (EOF to quit): -4
The number "-4" is invalid.
Enter a positive value (EOF to quit): CTRL-D
There were 6 valid numbers entered.
The sum of the valid numbers was 29 and the average was 4.83.
There were 2 invalid numbers.
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Jul 22, 2014
import java.util.Scanner;
//Calculates the prime #1000.
public class Prime {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int n, i=2, x=2;
[Code]....
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Jul 17, 2014
I need to receive input from the user, as many times as he wants. tha is done with the while loop. I also need to output the min and the max numbers the user enters, therefore i have the if statememnts. also if the user enters only one value i need to output that one value as the min and the max.
int min =0;
int max = 0;
int option = JOptionPane.YES_OPTION;
while ( option == JOptionPane.YES_OPTION){
String dataString = JOptionPane.showInputDialog("Enter an integer");
int data = Integer.parseInt(dataString);
[Code] ....
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Nov 17, 2014
I'm trying to do a user validation loop that runs until the user enters a valid binary, q, or Q. I think the rest of my program should work as intended, but here is the areas of concern:
public static boolean isBinary(String num) //Check if the entry is binary
{
for(int i = 0; i < num.length(); i++) {
if(num.charAt(i) != 0 || num.charAt(i) != 1){
return false;
[Code] .....
The program runs without errors otherwise.
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Mar 28, 2015
I have a beginning Java Program I have been working on that creates a number guessing program where the computer guesses a number that the user is thinking of within a certain range. I so far have the program below, but need getting rid of a few kinks/ adding features.
-First, I need to set it up so that the user will be prompted and give a range. It should run and produce something like this:
Welcome to this first-ever mind-guessing program!
Please pick a range (higher than 1 and no larger than 50): 32
You will choose a number between 1 and 32... and I will try to guess it.
With each of my guess, you will tell me whether I am too high (h or H), too low (l or L), match (m or M), or you want to quit (q or Q). My objective is to find the number using as few guesses as possible.
-Second, the game is supposed to give up and restart after failing the five, guesses, but for some reason, after it fails the fifth time, it prompts a fifth guess once again instead, then restarts after- I need to prevent this, so that it should look something like this:
My fourth guess is 17: h
My guess is too high?
My fifth guess is 16: h
*** I am unlucky this round. I give up.
Let's play!
My first guess is 10:
etc..
import java.util.*;
import java.lang.Math;
public class numguessprac1 {
// Declaring variables
public static String input;
public static int quit;
public static int guess;
public static int wins;
[Code] ....
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Nov 4, 2014
I have been struggling with this program for weeks. This program is supposed to take a user's inputted odd number and then print out all prime numbers lower than that number.
public class PrimeNumber
{
Scanner scan = new Scanner(System.in);
int userNum;
String neg;
public void getUserNum()
[code]...
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May 5, 2014
trying to write a program that takes a user inputted number and converts it to a binary number.
Here's what I have:
package com.java2novice.algos;
import java.util.Scanner;
public class Converter {
static Scanner console = new Scanner(System.in);
public void printBinaryFormat(int number){
int binary = console.nextInt();
[Code]...
Bugs on:
Line 13
Line 17
Line 23
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Apr 24, 2015
I am trying to write a Random Number Generator that will not contain any repeat value in a given range
something this I have try so far
import java.util.Random;
/**
* This class is used to generate a
* Range of Random Number in a range from int a to int b
*/
public class RandomNumberGenerator {
public static void main(String[] args) {
int[] arr=randomNummbers(1, 20);
for(int j=0;j<arr.length;j++){
[Code]...
although this code generate random numbers but some values are also getting duplicate.So how to write a program for random number that will not repeat any integer in range?
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Aug 18, 2014
/* Jessie Garza
* 08 / 18 / 14
* ModCalculator
*/
import java.util.Scanner; // program uses Class Scanner
import javax.swing.JOptionPane;
public class ModCalculator
{
// main method begins execution of Java application
[code]....
I am having troubles with allowing the user to input operations/digits until they want to exit, I have tried looping, but I was unsuccessful, came here hoping to figure this out.Currently I have it ending with Break statements after each switch so that they don't coincide all together.. I can't figure out how to keep the Break statement AND loop to previous code of System.out.println( "Please enter an operand which you would like me to calculate with :");
String st = input.next();
c = st.charAt(0);
System.out.println( "I will need for you to input two integers and I will output the result.");
System.out.print( "Enter first integer to calculate: " ); // prompt
number1 = input.nextInt(); // read first number from user
System.out.print( "Enter second integer to calculate: " ); // prompt
number2 = input.nextInt(); // read second number from user
and allowing it to run through the rest of the program with the options still in tact, while having an if statement of an exit keyword.
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Feb 7, 2015
I have done a rock, paper, scissors program, but it only executes once. How do I make the program repeat so you can play multiple times?
import java.util.Scanner;
import java.util.Random;
public class RockPaperScissors {
public static void main(String[] args) {
int A;
Scanner input = new Scanner(System.in);
Random random = new Random();
[code]....
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Oct 10, 2014
Basically, I have want to keep typing numbers and pressing enter and the same program keeps repeating itself. This is the code I need to repeat,
import java.util.Scanner;
class Averagecalc2 {
public static void main(String args []) {
Scanner input = new Scanner(System.in);
double num,
[Code] .....
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Oct 27, 2014
Ii am trying run a do while loop on java a specific amount of times for example if i were to type in "Enter number of years" and enter 4. i need the loop to execute 4 times or if i said 6 times then i would be 6. the program i have repeats it and takes it back to reentering "Enter number of years" i need it to execute by its self x amount of times. here is what i have so far
System.out.println("Enter the number of years: ");
years = keyboard.nextInt();
rainfall = generator.nextInt(10) + 1;
System.out.println("Year " + "rainfall amounts were");;
for (int months = 1; months <= 12; months++)
[Code]...
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Apr 16, 2014
If a user inputs nothing the code should end ... How Should i do it?
import java.util.Scanner;
public class MyQueue<T> implements Queue<T> {
private T[] ringbuffer;
static int capacity = 0;
int mysize = 0;
[Code] ....
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Nov 14, 2014
So im trying to make a coin flip game in java. Im relatively new to the language and the only other language i knew was javascript so im still learning. Ive already made one before using just one class and putting all the code inside, but im now trying to do it with methods since im trying to learn them. The basic idea of the game is that the user picks how many coins they'd like to flip, they pick heads or tails, then the computer flips the coins and calculates if there was more heads or tails to tell the user if they won or not. Im not quite complete with the program as you can see but ive already run itno an error. I was just doing some tests on the code i already have and i found that when i call the method settingUpCoin in my main class the program terminates. So basically, when i run it, it executes userImp right, transform right, but then it dosent let you enter a value for howManyCoins and terminates before you get to settingUpCoin.
(Notes: this was all done in eclipse luna build or the java ide. The class files are all separate in the actual thing i just put them together here to demonstrate my code.
import java.io.IOException;
public class Coin
{
double myCoin;
int numOfCoins;
int counter;
double arrayOfCoins[] = { };
[code]....
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Mar 12, 2014
I just want to know how I can get my program to end when the user inputs "0." By using: System.exit(0);
import java.util.Scanner;
public class TestCode
{
public static void main (String [ ]args ) {
Scanner console =new Scanner(System.in);
System.out.println("To exit program input 0");
for (int y = 1; y < 11; y++ ){ // Executes output 10 times
[code]....
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Oct 13, 2014
so I had to create a program that allows the user to enter a day using a number and then enter a year and after they did that it would create an entire calendar for that year ..so I have that but the only issue is I can not get the numbers to line up neatly.how to do the entire thing in loops, I tried a couple in here..what this would look like as loops instead of switches and cases and if else
import java.util.Scanner;
public class Calendar {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
[code]....
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Aug 28, 2014
I have been going over my code line by line, over and over again for nearly and hour now...When I execute method `file.createNewFile()`, the method returns true and throws no exceptions. It even says that the file exists. However, the file is not created and cannot be accessed until the program has exited.
File portLib = new File("");
private class RememberPortAction extends AbstractMenuItemAction
{
methods...
protected void actionPerformed() {
LibraryCreator creator = new LibraryCreator(self, logger);
File newPortLib;
[code]....
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Jan 24, 2015
This is my first java program,i am using eclipse IDE-----
package day1.example;
public class MyFirstJava {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
System.out.println("hi");
}
}
When i saved it,it shows no error.when i run it then a pop-up says "could not find the main class.the program will exit" and in the console it says---
java.lang.UnsupportedClassVersionError: day1/example/MyFirstJava : Unsupported major.minor version 51.0
at java.lang.ClassLoader.defineClass1(Native Method)
at java.lang.ClassLoader.defineClass(Unknown Source)
at java.security.SecureClassLoader.defineClass(Unknown Source)
at java.net.URLClassLoader.defineClass(Unknown Source)
at java.net.URLClassLoader.access$000(Unknown Source)
[Code] ......
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Feb 6, 2014
I am trying to write a program that asks the user to enter a number from 1 through 10 and then the program will display the roman numeral for that number.
I am also adding a error message in which i haven't yet because im still trying to figure out how to the program will do the roman numeral.'
I have used the if and else if. but when i input a number it just repeats the number back to me.
The program cimpiles but it doesn't do what i want. here is what i have so far. how can i get the program to display the roman numeral after the number is entered.
import javax.swing.JOptionPane;
public class Romannumeral
{
public static void main(String[] args)
{
double number;
[Code] .....
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Feb 2, 2015
Ok so I have my program working for the most part. In this program I am supposed to take input from the user until they enter a negative number and that works, the problem is that it doesn't work if I enter a negative number on the first prompt. For example if I enter a 100 it would prompt me again and if I enter a negative number it would quit and give me the average, but if I enter a negative number the first time I am prompted the program just gives me an error. How do I fix that?
import java.util.List;
import java.util.ArrayList;
import java.util.Scanner;
public class Application {
public static void main(String [] args){
Scanner input = new Scanner(System.in);
List<Integer> grades;
[Code] ....
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