Re-prompting For A String?

Mar 28, 2014

how to have a user input information again if their initial one was incorrect? For example, in this it will have the user go back to select an invoice number within range, but how do you do so if they enter words? I've tried next() and nextLine() but it hasn't worked.

Scanner input = new Scanner(System.in);
System.out.println("What is the invoice number for your purchase?");
invoice = input.nextInt();
  System.out.println("What is the sale amount of your purchase?");
amount = input.nextDouble(); 
while (invoice < 1000 || invoice > 8000) {
System.out.println("You have entered an invalid invoice number.");
System.out.println("Please select a number between 1000 and 8000.");
invoice = input.nextInt();//having trouble knowing how to input this if it were a string.
}

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Program Keeps Prompting To Enter Correct Binary Number

Sep 10, 2014

I wrote a java program for my gui number converter app, the main purpose of this program is to make sure that user enters only a binary number for conversion from binary to other number formats. the problem is my program keeps prompting me to enter correct binary number, no matter if i enter correct binary number, it will still keep prompting me to enter correct number. Here is the code

import java.util.*;
public class test {
Scanner key = new Scanner(System.in);
String in;
int b;
public test()

[Code] .....

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Nov 7, 2014

How can I write a method that takes a string with duplicates letters and returns the same string which does not contain duplicates. For example, if you pass it radar, it will return rad. Also i would like to know how can I Write a method that takes as parameters the secret word and the good guesses and returns a string that is the secretword but has dashes in the places where the player has not yet guessed that letter. For example, if the secret word is radar and the player has already guessed the good guesses letters r and d, the method will return r-d-r.

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Sep 27, 2014

I am currently trying to make a calculator in Java. I want to use the String split method to tokenize the string of characters inputted. I thought I was using the String split method wrongly, because I had surrounded the characters I wanted to delimit with square brackets. However, when I removed the square brackets, the code threw an exception when I pressed the equal button. The exception was a PatternSyntaxException exception. Am I using the String split method wrongly? And why is the exception thrown? Here is my code:

import javax.swing.*;//import the packages needed for gui
import java.awt.*;
import java.awt.event.*;
import java.util.Arrays;
import java.util.List;
import static java.lang.Math.*;
public class CalculatorCopy {
public static void main(String[] args) {

[Code] .....

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Dec 16, 2014

i am trying to write a class method which will take in a string and returns a string which is the reversed version of that string. it compiles fine but when i try to run it it states Main method not found in class StringReverse,please define the main method as public static void main(String[]args). I am new to java and cannot figure out

import javax.swing.JOptionPane;
public class StringReverse {
public String reverseString(String str){
JOptionPane.showInputDialog(null,"Please enter word");
char c = str.charAt(str.length()-1);
if(str.length() == 1) return Character.toString(c);
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May 22, 2014

I'm having trouble with the last few lines of the code. It's supposed to take a replacement string entered by the user and print out the new string. For some reason it's now allowing me to enter a replacement string

import java.util.Scanner;
public class Project02 {
public static void main(String[] args) {
Scanner keyboard = new Scanner(System.in);
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String lString = keyboard.nextLine();

[Code] ....

Output:

Enter a long string: the quick brown fox jumped over the lazy dog
Enter a substring: jumped
Length of your string: 44
Length of your substring: 6
Starting position of your substring in string: 20
String before your substring: the quick brown fox
String after your substring: over the lazy dog
Enter a position between 0 and 43: 18
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Aug 28, 2014

I have a method for a button so when a user inputs something it then will get the string value and check it against the string value within the properties file to see if it exists.

The properties file is called GitCommands.properties that contains -- > key = value <-- in it

I realised I have not used it correctly hence why I keep getting errors - I am lost on how to use it, I think perhaps that may be the issue here? I need to reference the file but I am doing it wrong? When I do use that piece of code I get null pointer exception too...

textFieldSearch.getText().equals(GitCommands.keys());

This is my button:

JButton btnSearch = new JButton("Search");
btnSearch.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
FindSelectedKey();

[code] .....

I understand I am missing my piece of code where it states "//determine whether the string is equal to the property file key string" I understand the logic fine but not actually coding it.

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String s = "fjdjfdfjgffgjhfjghfjkhjhjh";
String spLine;
for(int i=0; i<s.length(); i=i+5){
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>

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Mar 18, 2014

Code a Java method that accepts a String array and a String. The method should return true if the string can be found as an element of the array and false otherwise. Test your method by calling it from the main method which supplies its two parameters (no user input required). Use an array initialiser list to initialise the array you pass. Test thoroughly.

public class test {
public static void main(String[] args) {
Printhelloworld();
String[] verbs = {"go", "do", "some", "homework"};
printArrays(verbs);

[Code] .....

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Mar 2, 2014

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public int compareTo(LinkedListNode n){
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Mar 28, 2014

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For example:

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System.out.println("b" + headscount);
}

This doesn't give me the right value because the IDE says that equals() is an incompatible type. I also tried changing the "heads" to an variable, but the results remains the same.

I would prefer using an Array!

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Sep 21, 2014

So I'm creating a class which when given three inputs uses them as sides of a triangle and tells ther user what type of triangle it is, or if the input is invalid, tells them why it is invalid. I'm readin the input as a string and then trying to split it into a string array, from there checking to see if it has 3 elements.. in which the data is good at that point, and then converting them to ints and checking to see if they're negative ansd finally checking to see if they can work as sides of a triangle ie a+b >c, a+c >b , b+c >a.

I'm trying to split it into an array of strings but am getting an error, and can't seem to figure out why as this should be working from what I've read of the string.split method online.

import java.util.*;
public class TriangleTest{
private int sideA;
private int sideB;
private int sideC;
public static void main(String[] args){
TriangleTest triangle = new TriangleTest("3 4 5");

[Code] ....

The output reads [Ljava.lang.String;@15db9742

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Sep 11, 2014

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...
 
I've also tried using
 
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Apr 6, 2014

I have errors in the "if" and both "else if" ... The compiler says "cannot convert from String to boolean and int to String ...

instructions:

1. Add two private instance variables, String courseName and char grade to this class.

2. Add accessor and mutator methods for these instance variables.

3. Add a method register which receives an integer data type and returns String data type according to the argument passed to it ("Math" for 1, "English" for 2, "No course" for any other input)

What I have so far:

package assignment9;
 public class BannerUser
{
private int userId;
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}
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[Code] ......

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Mar 25, 2015

I have the the string value similar to the one   which i have to split based on the delimited ","
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c
xyz
lm
n
o
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Example:

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Actual Code I have right now. Again, please ignore variable names, it's what I got use to while learning.

/** The list of the types of step blocks. */
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}
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[Code] ....

For what I have now, in the Int...

for ( int var2 = 0 ; var2 < slabType.length ; var2++ )

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