I just need to write a simple program/function that replaces certain letters from a string (i.e. censor( "college", "aeiou" ) returns "cllg"). I'm trying to get the code right first, and then write a function for it.I basically just thought that I would iterate over the first string, and once I had the first character, I would then iterate over the second string, to see if the character exists. I'm getting a "dead code" error on my second loop because I put the second "break."
public class ap { public static void main(String [] args){ String s = "Hello"; String s2 = "aeiou";
I want to remove all numeric number in String text
String text = She was born in 1964,and now her age is 55; String delim = ","; StringTokenizer stringTok = new StringTokenizer(text, delim); String f1 = "%-40s"; String h1 = String.format(f1, "Token list");
I am using a TreeSet to tokenize a string. The output is sorted with numeric first followed by words
E.g. 13 26 45 and before etc.....................
Is there a tidy way to remove the numeric?
Last bit of my code is :-
// print the words separating them with a space for(String word : words) { System.out.print(word + " "); } } catch (FileNotFoundException fnfe) { System.err.println("Cannot read the input file - pass a valid file name"); }
So basically, if a line in a text file contains a certain string, that specific line will be deleted. It should probably be similair to this method?
Java Code:
/** * Replace text. * @param replace * The text to replace. * @param replaceWith * The text to replace with. */ public static void replaceSelected(String replace, String replaceWith) { try { BufferedReader file = new BufferedReader(new FileReader("data/replacer.txt"));
Question 1: I am working on an assignment where I have to remove an item from a String array (see code below). When I try to remove an item after entering it I get the following error "java.lang.NullPointerException." I am not sure how to correct this error.
Question 2: In addition, I am having trouble figuring out how to count the number of occurrences of each string in the array and print the counts. I've been looking at other posts but they are more advanced and I have not yet learned how to use some of the tools they are referring to.
private void removeFlower(String flowerPack[]) { // TODO: Remove a flower that is specified by the user Scanner input=new Scanner(System.in); System.out.println(); System.out.println("Please enter the name of the flower you would like to remove:
I would like to enter a new item into a CSV file but all my items being entered are all staying on one line in the CSV file. I would like each new item to show up on a new line and I can't seem to find the code to make it work.
public String addItem(String newItem, int credits, String code) { String money = Integer.toString(credits); try { BufferedReader itemsCSV = new BufferedReader(new FileReader("itemList.csv"));
I want to write byteArray in file from String and if "/n " newline comes in String it should write from next line in file. I tried and no content starts from newline in file.
Suppose String s= "This is my Java Program /n Converting string to byteArray";
Output in file should be as :
This is my Java Program Converting string to byteArray
When i am converting byteArray in String, it showing me same output as i wants but not in file.it showing me on console.
psvm(String arr[]){ String s= "This is my Java Program Coverting string to byteArray"; FileOutputStream fos = new FileOutputStream("filepath"); fos.write(s.getBytes()); fos.close(); }
output in file : This is my Java Program Converting string to byteArray
Any other way to get content after newline in next line.
I'm now working more and more on the go and although I can carry my Macbook Air without too much trouble I've just been given an iPad Mini by work and it's far easier to do what I do with that on the move.
For work I need to open around 35 different websites at one time 4/5 times a day on the move.
With my Macbook that's no issue, as I can just use the open all function of my bookmarks, but on the iPad there is nothing that will allow me to do this.
I have looked online and a few people have had this issue and fixed it using the below Java method:
Creating a link that when clicked sets off a Javascript function that contains several window.open("url"); Clicking the link opens each website in its own tab.
I am creating a simple code in Java that replaces all tabs the user inputs with '*'. However, I am doing something wrong and I am not sure what. Here is what I have so far in Eclipse..
import java.util.Scanner; public class ReplacingTabs { public static void main(String[] args) { Scanner in = new Scanner(System.in); String s = ""; String s2 = "";
[Code] .....
There is an error with the s2 in the line String s2 = s.replace(' ','*');
I think I need to add String s2 to the loop but I am not sure how..
SO my current code creates a graph with vertices and weighted edges. This data is stored in a hashmap. The key of the hashmap is the vertex and the value is a second hashmap. This second hashmap contains the edges with the vertex it connected to as the key and the weight as the value. My current problem is that when i try to remove vertices they are removed from the key set but they stay in the value(the second hashmap) as the key for that hashmap. IS THERE A WAY TO REMOVE THE VERTEX FROM THE KEYSET OF THE SECOND HASHMAP.
Code is as follows
constructor{ adjacencyMap = new HashMap<V, HashMap<V, Integer>>(); dataMap = new HashSet<V>(); } removal method{ if(dataMap.contains(vertex)){
Referring Code 1, the book says line 16 of the code removes the element "Three" but line 17 does not remove the element "Four" because of Statement 1. The question is does remove(Object o) method invoke the == or the equals method because statement 1 and 2 seem to be in conflict
Statement 1:
Two objects are equal if their object references point to the same object. (which is nothing but definition of ==)
Statement 2:
The author refers to Statement 1 and says "As mentioned earlier, the method remove compares the objects for equality before removing it from ArrayList by calling method equals."
Java Code:
import java.util.ArrayList; public class DeleteElementsFromArrayList { public static void main(String args[]) { ArrayList<StringBuilder> myArrList = new ArrayList<>(); StringBuilder sb1 = new StringBuilder("One");
I am stuck on this exercise and I don't know what exactly is wrong. I think it's something with the .remove and the for each loop, but I am not sure.
public class seven { public static void main(String[] args) { ArrayList<String> list = new ArrayList<String>(); list.add("aaa"); list.add("brr"); list.add("unni");
[Code] ....
This is what i get
Exception in thread "main" java.util.ConcurrentModificationException at java.util.ArrayList$Itr.checkForComodification(Unknown Source) at java.util.ArrayList$Itr.next(Unknown Source) at seven.removeDuplicates(seven.java:24) at seven.main(seven.java:18)
public class werek4d { public static void main(String[] args) { int counter = 1; int[] anArray = new int[101] ; for (int i = 0; i <= 99; i++){ anArray[i] = i + 1; System.out.println(i + ": " + anArray[i] + " ");
[Code] ....
My aim is to generate a lists containing 1 to 100. I will then count the number of integers divisible by 3. After doing so, I want to delete the integers that are NOT divisible by 3 in the lists. I tried doing it, but I seem to keep on getting the same lists.
I am working on a java program that is called OrderedVector which is basically a storage or list that grows and shrinks depending on the amount of data is put in. Most of the methods in my code are correct and working, the only real issue I have lies with either the remove(E obj) method or remove(int index) method. This is the driver I am currently using to test my remove method,
public class Tester { public static void main(String[] args) { OrderedListADT<Integer> v; v = new OrderedVector<Integer>(); for(int i = 0 ; i <= 9; i++){ v.insert(i);
[code]....
the output I am receiving is
Removing 0 Size of data structure is 9 Removing 1 Size of data structure is 8 Removing 2 Size of data structure is 7
[code]....
As you can see, when I am calling the second for loop, none of the elements are being removed by my methods but the first for loop is working just fine.
Here is my code for the OrderedVector
package data_structures; import java.util.Iterator; import java.util.NoSuchElementException; public class OrderedVector<E> implements OrderedListADT<E>{ private int currentSize, maxSize; private E[] storage; public OrderedVector(){ currentSize = 0;
[code]....
So overall, my remove method should implement binary search and remove elements using either an index or the object value type.
I was trying remove duplicates element from my array without using collection API but i didn't got any output from my code.Although it is compiled successfully but on execution it didn't give any output. I guess there must be some problem in function Duplicate
Java Code:
class Union { public static void main(String...s) { Union M=new Union(); int x[]=new int[]{1,0,1,4,10,10,10,3,567,4,3,33}; int y[]=new int[]{5,4,5,4,5,4,2,3,3,1,0}; int []w=M.merge(x,y);
Ask the user to enter a sequence of at most 20 nonnegative integers. Your program should have a loop that reads the integers into an array and stops when a negative is entered (the negative number should not be stored). Invoke the average method to find the average of the integers in the array (send the array as the parameter).
how can I remove the negative number from the array and calculate the average of the posive elements without the negative ones? This is my code so far...
import java.util.Scanner; import javax.swing.JApplet; public class Parameters { //------------------------------------- //Calls the average and minimum methods //with different numbers of parameters