Processing a string. How would I only return a given char that matches the input string e.g. v and/or n and/or m.
Everything else that does not match will return a '*' - e.g. user input = t result = *
I assume I need to also iterate through this input string using charAt() ?
What I'm trying to do is compare String input to a char array. Let me make it a little more plain, I'm working on a cipher assignment, and my line of thought is this: I will get String input from the user, COMPARE the characters in the string input to an alphabet array, which will then be compared to the cipher array so that the cipher's counterpart can be chosen over the alphabet's. Any way that I might compare the random input keyed in by the user to that alphabet array?
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* and open the template in the editor.
*/
package firstgui;
import javax.swing.*;
import java.awt.event.*;
public class TicTacToe {
[Code] ......
Program is 10x10 board, I need to check if the user's input is a duplicate of any number in that same column, but I can't figure it out. When I tried it, it always check the same box. For example, if I entered 4 in [1][1] (going by 10x10 grid), it automatically checks right after I entered that [1][1] is the same as my input and erases it. My professor wants me to check it with the "CheckWinner" method.
I tried the following when someone told me to pass the reference of the JButton being clicked to ignore it.
private boolean CheckWinner(JButton source, String inplayer) {
//...
if (EventBoard[i][j] != source &&
EventBoard[i][j].getText().equals( inplayer )){
JOptionPane.showMessageDialog(null, "copy");
EventBoard[i][j].setText("");
}
I have a regular expression that I created and tested on some regex site, [URL] .... It worked on the test site but I can't get it to work in Java.
The code is:
String s = "MyString.ext_CAL3";
assertTrue("Didn't Match", s.matches("_CAL[0-9]+$"));
This test always fails. I cannot figure out what is wrong with it. In fact, I can't get any match no matter what regex I use.
public static void main(String[] args) {
Scanner kb = new Scanner(System.in);
int hours = getHours(kb);
char major = getMajor(kb);
[code]....
I'm trying to return a char c,o, or x if that is their "major code" that the scanner grabbed.
I am trying to get user input for a char value and am having some difficulty getting input for a char value.
Java Code:
//imports packages
import java.io.*;
import java.text.DecimalFormat;
class ModuleCulminatingTask {
public static void main (String args []) {
//declares variables
float var3, var4;
long var5 = (int)(Math.random()*10);
[code]....
I need making char[] to a string im not entirely sure what to change i'm just suppose to use a string value but the upperclassmen used char:
char[] number = clear.toLowerCase().toCharArray();
for(int c = 0; c < number.length; c++) {
if(digit[c] < 'a' || digit[c] > 'z')
continue;
[code]...
I can't figure out how to have all of the random characters generated to go into the String. Below I can only get the last character to covert over to a String.
System.out.println("Original random character string:");
String printingString = "a";
for (int i = 0; i < 50; i++)//loop to obtain 50 random characters
{
char randomChar = (char) ((Math.random() * 255) +32);
System.out.print(randomChar);
printingString = Character.toString(randomChar); }
return printingString; }
I found a fun program online and something so simple is giving me an issue. I c++ it is pretty simple fix, I can just call the strings location like an array. In java this is not the case. So far i have tried:
myString.charAt();
myString.indexOf();
There are a few other I found on google but I forget at the moment. I am just trying to close the gap on a string. It was a full sentence and I used replaceAll a few times to get several words I didn't want in the file out.
what will i compare in if statemet is the 1st letter of each if i have code="a" and name="Angelina" first letter of each is "a" and "A" then in convert it to string so that i can make it uppercase but when i compare it in if statement it always go into "not x" but the ouput that im getting is x=A y=A then it always direct me into else statement.
String code = "a";
String name = "Angelina";
char c = code.charAt(0);
char n = name.charAt(0);
[code]...
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string.
Example: the string Welcome and the letter e, is 2 times. so the program should print 2.
It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
[Code] .....
I am trying to count each char in a string. For example A = 1, B =2, C=3, I am not looking for their binary value. So the word "At" would
AT= (A=1 +T=20)=21.
I know how to do this in C++ because I am able to treat a string like an array.
Java Code: void printFile()
{
int sum=0;
String line;
for(char cr ='A';cr<'Z';cr++)
{
for(int i=0; i<myList.size();i++)
[Code]...
import java.io.IOException;
import java.util.*;
public class Guesser {
public static void main(String[] args) throws IOException {
char[] alphabet = "abcdefghijklmnopqrstuvwxyz1234567890 .,:;'-".toCharArray();
[Code] .....
I'm writing a program which will take a three letter word (for now) and then try to guess the word over and over again until it finds it, then print the word and the amount of tries it took to find it.
The problem: at the moment the program will find the word but not break out of the for loop when it does. I think it doesn't like the char to String conversion somewhere along the line.
I want to cut my string from space char but i am getting exception....
Java Code:
import java.util.Scanner;
import java.util.StringTokenizer;
public class NameSurname {
public static void main(String args[]) {
Scanner sc=new Scanner(System.in);
String s0,s1=null,s2 = null,s3=null;
s0=sc.next();
[Code] ....
Console:
Lionel andres messi
Exception in thread "main" java.util.NoSuchElementException
at java.util.StringTokenizer.nextToken(Unknown Source)
at java.util.StringTokenizer.nextToken(Unknown Source)
at com.parikshak.NameSurname.main(NameSurname.java:15) mh_sh_highlight_all('java');
I/p -O/p:
my s0=Lionel andres Messi
And I want to break it as soon as i find space and save it in s1,s2 and s3
s1=Lionel
s2=andres
s3=messi
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string. Example: the string Welcome and the letter e, is 2 times. so the program should print 2. It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
str=user_input.next();
[Code] ....
I have a simple doubt. I was studying and create some code to check the result and I found out a strange situation.
Whats wrong with this code? Why it does not print anything?
char = 0; //integer value
System.out.println( c +" String ");
and why this next works very well?
char = 1; //integer value
System.out.println( c +" String ");
I know that char is stored as a positive integer and assign with 0 is different of assign with '0'.
How can I write a method that takes a string with duplicates letters and returns the same string which does not contain duplicates. For example, if you pass it radar, it will return rad. Also i would like to know how can I Write a method that takes as parameters the secret word and the good guesses and returns a string that is the secretword but has dashes in the places where the player has not yet guessed that letter. For example, if the secret word is radar and the player has already guessed the good guesses letters r and d, the method will return r-d-r.
View Replies View RelatedMy program is user input 20 char and the program will print the most common. So I use another int arr which count the number appears in the original array. i know its not so Effective but I don't know why it run but it stop in the middle. I got this code :
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 20
at Ex2.common(Ex2.java:39)
at Ex2.main(Ex2.java:23)
import java.util.Scanner;
class Ex2 {
public static void main(String[] arg) {
Scanner reader = new Scanner (System.in);
char[] arr=new char[20];
System.out.println("Please enter 20 chars:");
for (int i=0;i<20;i++)
[Code] ....
I'm trying to find a word in an array of char.....but I'm stuck. How to formulate the code to step through the array and pick out the word. This is what I have so far...
public static void searchAcross(String string, char[][] puzzle) {
// Gets the number of rows in the matrix
int rowLength = puzzle.length;
//Gets the number of columns in the matrix.
int colLength = puzzle[0].length;
[Code] ....
I am trying to figure out how to convert a string of ASCII code into char.I know that you can use (char) to convert it, but the issue is you cannot really just it for Strings.
View Replies View RelatedI have written the code:
Java Code:
public static void main(String[]args)
{
Scanner input = new Scanner(System.in);
System.out.print("Type your text: ");
String text = input.nextLine();
int counter = text.length();
if(text.length()> 16)
[Code] ....
And input is: abcdefghijklm
output is:
Java Code:
a b c d
e f g h
i j k l
m x x x mh_sh_highlight_all('java');
So all i want is, if i type: abcdefghijklm
I want this output:
Java Code:
a e i m
b f j x
c g k x
d h l x mh_sh_highlight_all('java');
This code will let a user type 10 double's, and return the smallest of those 10 double's. But I don't really understand what happens in de last for-loop.
package hsleiden.webcat.exercise06_09;
import java.util.Scanner;
public class Exercise06_09
{
public static void main (String[] args){
double[] allNumbers = new double [10];
[Code] ....
I am having an issue with a parallel array that I created that returns array values based on an input. The code only works for the first four array locations just fine. The remaining values are not found. I thought it might be a memory allocation issue with the array size, I tried to dimension the array, however, using the Eclipse editor get errors.
import java.util.*;
import javax.swing.JOptionPane;
public class StudentIDArray {
static String[] studentNum = new String[]
{"1234", "2345", "3456", "4567", "5678", "6789", "7890", "8901", "9012", "0123"};
static String[] studentName = new String[]
[Code] .....
I want to use a method, which takes for example an int and also returns an integer. For example, if the the given integer is strong return a, if it is notstrong return b. How would you write that in a Code?
I want to use that in a more general way. I want to give a method mlong the value X of the type date and let it return an int. Type date consists of 3 int, one of them is the int month.
mlong should return an int depending on the X.moth. at the moment my code looks like this:
// File1:
public class date {
public int day;
public int month;
public int year;
}
// File 2:
public class monthlength {
public int mlong(date X) {
int t;
t = X.month;
if (t == 1 || t == 3 || t == 5 || t == 7 || t == 8 || t == 10 || t == 12)
{ return 31; }
if(t == 4 || t == 6 || t == 9 || t == 11)
{return 30;}
}
}
Write a recursive Java method countDigitx that takes two integer numbers as input (a number n and digit x) and returns the number of times digits x occurs in number n:
For example if n=23242 and x=2 then the method should return 3 that is the number of times the number 2 found in n.
Here, I want to avoid using the line **return"";** and instead return all of the values I output with **System.out.println();**
I have tried using a **StringBuilder** method, but this outputs nothing when I run my test program. I am guessing that StringBuilder must work differently in a while loop, but I can't find how!
[URL] ....
public String toString(){
int topLine = size;
int topCurrentLine = size;
int bottomLine = 1;
int bottomCurrentLine = size;
[Code] ....