Return Integer That Is The Number Of Strings That Starts With S

Apr 29, 2014

Write a Java code of the method startsWithCount that takes an array of strings words and a String S. The method should return an integer that is the number of strings that starts with S.

For example if:words = { "All", "Arab", "size", "Almond", "Allowed", "here"} and S= "All", then the method should return 2

PHP Code:

public class StringwithCount {
public static void main (String[]args) {
String strings[] = { "All", "Arab", "size", "Almond", "Allowed", "here"};
String output= "";
for ( int i  =  0;  i < words.length; i++) { 
            if (words[i].startsWith("s")) 
                c + +; 
        } 

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Nov 16, 2014

I have problems getting the right number of times for each number of the array. Here is my code:

public static void main(String[] args) {
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int num = 3;
int count = numbers(a, num);
for (int i = 0; i < a.length; i++) {

[Code]...

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// File1:
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// File 2:
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At the moment my code looks like this:

// File1:

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I don't think I am returning ALL the strings that start with A, just the last one of the for loop. Does this look somewhat correct?

public String[] startsWithA(String[] strings) {
String startsWithA = strings[0];
for(int i = 0; i < strings.length; i++) {
if(strings[i].charAt(0) == 'A') {
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}
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Jan 12, 2014

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public static void main(String[] args) {
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12 .... 7654321

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Examples:

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method name is "f"

parameter is "a" right ?
 
Writing my doubts beside the particular line in the code

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In main method why they didn't use parameters ?(String[] args)

{
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{
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[code]....

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public static double sumTo(int n ){
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throw new IllegalArgumentException();
}
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[Code] .....

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Here is the code:

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Java Code :

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[highlight = java]

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