I want to find a certain element in array I have to scan through the array index starting from 0 until I find the number I am looking for. Even in data structures which use hashing like HashMap and Hashtable we will have to scan through the keys until we find the key we are looking for. So what is the use of hashing over index based searching? I mean how is hashing an advantage over an array?
View RepliesWhat is the starting index for linked list, 0 or 1. I know an array starts at 0 so wouldn't a linked list?
View Replies View RelatedI need to create a program that uses ArrayList to store integers the user inputs, then scan the array for the largest number. I would also like the user to be able to exit this loop if the number 0 is entered.
As you can see below, I'm not sure how to correctly exit the do-while loop. I found this on another forum, but it does not work.
Java Code:
import java.util.*;
public class array {
public static void main(String [] args){
ArrayList<Integer> list = new ArrayList<Integer>();
[Code] ....
I am receiving an ArrayIndexOutOfBoundsException for the following code, which moves a creature through a 2D array maze. I have altered the clauses of the first if statement for the four direct methods (north, south, east, and west) multiple times (i.e. x + 1 >= 0 && x > 0 && x - 1 > 0 && x < array.length...etc). However, while the code occasionally runs, more often than that it returns this exception. Catching the exception seems like a poor workaround though if worst comes to worst I'll do that.
I included only the relevant functions of the code:
public boolean goNorth(char[][] array) {
boolean success = true;;
x = getX();
//x = this.x;
y = getY();
//y = this.y;
if ((x - 1 >= 0 && x - 1 < array.length)
&& (y >= 0 && y < array[x].length)) {
[Code] .....
import javax.swing.*;
import java.awt.*;
import java.awt.event.ActionListener;
import java.awt.event.ActionEvent;
import java.awt.*;
import java.awt.event.*;
[Code] ......
Just cant see where the array is out og bounds the array ButtonList has 9 buttons....
I created and an Array of integers how can I get randomly get/pick the index of each array element.
View Replies View RelatedI searched online for this error and found out it's because the array is smaller than the index but I am not sure how I can fix this error....
public Lamborghini[] getCarsWithHorsepowerRange(double lowHP, double highHP){
int i = DEFAULT_ZERO;
Lamborghini[] carWithinHPRange = new Lamborghini[i];
for (Lamborghini lambos : inventory){
double horsePower = lambos.getHorsepower();
[Code] ....
I tried
Lamborghini[] carWithinHPRange = new Lamborghini[i+5];
//which works sometimes because once I boost up the range and so there'll be more result then the error came up again....
My project was to create an array holding 10 integers and populate the array with 10 random numbers. Then ask the user to guess the number. Prompt the user with a while loop if their input is out of range. Determine if the users number is in the array, and display which index location the number is in. I got most of the code done but am having trouble displaying the index location.
import javax.swing.*;
public class Homework4 {
public static void main(String[] args) {
int[] numarray = new int [10];
char repeatcode = 'y';
[code]....
I am getting Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 4 at lsb2.main(lsb2.java:44)Here is the code:
Java Code: import java.io.*;
import java.lang.Integer.*;
import java.lang.Math.*;
import java.util.*;
class lsb2
[code]....
java.lang.ArrayIndexOutOfBoundsException: 991
at Champion.main(Champions (1) (1).java:209)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Nativ e Method)
[Code]....
I am trying to make different arrays each being filled with random numbers from 0 to 2000, however when I run this code I get the error mentioned in the header. here is part of my code
for (int i = 1; i <= 14; i++) {
int n = (int) Math.pow(2, i);
int[] list = new int[n];
for( int j = 0; j <= list.length; j++){
list[j] = (int) (Math.random() * 2000);
}
}
I want to Display the Index of output Array.
here is the code:
import java.util.ArrayList;
import java.util.List;
public class selection {
private static int[] numbers= { 1, 2, 4, 8, 16, 32, 64, 128, 250, 250, 250, 250, 250, 250, 250 };
private static int[] sumsum= new int[numbers.length];
private static int sum= 1759;
[Code] .....
I am getting error array index out of bound ... Error detail is :
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0
at abhiExample.arraytwodiam.main(arraytwodiam.java:27 )
And program is
Java Code:
package abhiExample;
import java.util.Scanner;
public class arraytwodiam {
public static void main(String [] args)
{
char[][] Atrace={};
int i,j,k,l=0,row ,characters;
[Code] ....
public class Access
{
public static void main(String args[])
{
long a=2;
int j[]=new int[a];
}
}
Code shows error as "possible loss of precision" as am working with long type.but need to have my array size as 10^10 or some other logic?
I'm trying to iterate through an array of integers and find the start position of the part of the array containing the most consecutive 1s.
For example given the array {1,3,1,1,1,1,5,3,2,1,1}, the method should return 2 and given {1,4,5,1,1,1,5,1} the method should return 3.
So far, I've managed to retrieve the element where the consecutive 1s begin. However, I'm unsure how to get the index of this element and this implementation doesn't work if there is more than one set of consecutive 1s.
public class GetIndex {
public static int getPosition(int[] myArray) {
int index = 0;
int tracker = 0;
int mostOnes = 0;
for(int i = 0; i < myArray.length; i++) {
[Code] .....
class test{//class
public static void main(String[]args) {
String booking [][]= new String [30] [6] ;//two dimensional array
System.out.println("Enter the seat column you want");//column entry
char column=Keyboard.readChar();
System.out.println("Enter the seat row you want");//row entry
int row=Keyboard.readInt();
[code]...
cant get my in put to go in to the index
how to index the arrays so that i can choose specific data so that averages and maximum and minimum values can be worked out. My code is below
package weatherProgramPackage;
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
[code]....
I am trying to understand the following code.This return statement should actually return the char at myArray[index] first, then increments the index afterwords correct?
Public char next(){
return myArray[index++];
}
int[] a = new int[7];
a[0] = 0;
a[1] = 10;
a[2] = 256;
a[3] = 57;
a[4] = 33;
a[5] = -154;
a[6] = 168;
[code]....
What program needs to find is the most biggest number. It does the job, but another task of the program is to find the index of that number . The second loop should do just that, but for some reason, as the loop goes further, it passes through the if statement even though answer "a[i]" is not equal to "answer". The idea is that if a[i] and answer are equal, the "i" should represent the index number.
import java.util.*;
public class DungeonsAndDragonsRedux {
public static void main(String[] args) {
Scanner s = new Scanner (System.in);
Scanner t = new Scanner (System.in);
t.useDelimiter("\n"); // Prevent scanner from reading code after nextLine().
[code]...
I have this program that is attempting to randomly equip the player with items that are randomly chosen from a list. I don't know how to prevent it from picking the same item twice though. I also don't know how to display the items that haven't been equipped, which is another requirement of this program.
When I am trying to execute this code it is showing
Java Code:
class Sort2D
{
public static void main(String...s) {
Sort2D r=new Sort2D();
int z[][]=r.sort(new int[][]{{1,0,567,4,3,33},{333,677,34243,8987,3434,324},{446,876,23,546565,332}});
for(int i=0;i<z.length;i++)
for(int j=0;j<z[i].length;j++)
System.out.println(z[i][j]);
[Code] ....
I'm making a program with several functions for an array of integers, one being to find the last occurrence of a given integer and returning it. The problem is that the method is returning -1 for every input, even though it's only supposed to do so for numbers not in the array. Here's the part of my code with the sections I'm having an issue with:
Driver
import java.util.Arrays;
public class ArrayMethodsDriver
{
public static void main(String[] args) {
int[] a = {7,8,8,3,4,9,8,7};
System.out.println("Last index of 8: " + ArrayMethods.findLast(a, 8));
System.out.println("Last index of 2: " + ArrayMethods.findLast(a, 2));
[Code] ....
As you can see, I'm testing 8(which should give a 6) and 2(which should give -1 because it's not in the array), and 4(which should give 4). The print statements all say -1.
I have a 2-D character array and I was wondering if I can compare a given index to an out of bounds index and what would I have to write? For instance
if(array[0 - 1][0 - 1] == 'indexoutofbounds'){ **// I know that 'indexoutofbounds' is probably not the right wording**
stuff happens
}
If I can do this what would I actually have to write in where it says 'indexoutofbound' ?
I will be using this for many indexes so it wont always be [0 - 1][0 - 1] it could be [4 - 1][3 - 1] in which case it wouldn't be out of bounds and wouldn't move onto "stuff happens"....
The following code generates an array out of bounds exception
int[] myArray1 = new int[5];
for(int j = 0; j < myArray1.length; j++)
{
myArray1[j] = 10;
System.out.println("myArray1["+j+"] : " + myArray1[j]);
}
for (int i : myArray1) {
System.out.println("Blah myArray1["+i+"] : " + myArray1[i]);
}
The exception
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 10
at Tutorial2.main(Tutorial2.java:40)
So in my code, I have the user input a number, and the program will then display that element in the array (I've done this bit). However I need to write code to check that the user is entering a valid index number, and if they don't, I need to prompt them that the number they have entered is incorrect and let them retry, and I don't know how to.
This is my full code, I have added a comment underneath where I need to add the code:
import java.util.Arrays;
import java.util.Scanner;
public class StudentNames {
public static void main(String[] args) {
String[] names = new String[8];
Scanner s = new Scanner(System.in);
for (int i = 0; i < 8; i++) {
[Code] ....
I have two codes of needed to run but after processing, the said above error is preventing it from getting the general output of the code.I can't seem to find my errors or I don't have any clue at all, if perhaps you know, here's the codes:
Error :
PHP Code:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0
at simpleOutput.main(simpleOutput.java:13)
public class simpleOutput {
public static void main(String args[]){
int n = Integer.parseInt(args[0]);
for(int i = 1; i <= n; i++){
}
for(int i = 1; n <= i; n++){
System.out.print((i*n)+" ");
[code]....