Split String From Space Char
Mar 30, 2014
I want to cut my string from space char but i am getting exception....
Java Code:
import java.util.Scanner;
import java.util.StringTokenizer;
public class NameSurname {
public static void main(String args[]) {
Scanner sc=new Scanner(System.in);
String s0,s1=null,s2 = null,s3=null;
s0=sc.next();
[Code] ....
Console:
Lionel andres messi
Exception in thread "main" java.util.NoSuchElementException
at java.util.StringTokenizer.nextToken(Unknown Source)
at java.util.StringTokenizer.nextToken(Unknown Source)
at com.parikshak.NameSurname.main(NameSurname.java:15) mh_sh_highlight_all('java');
I/p -O/p:
my s0=Lionel andres Messi
And I want to break it as soon as i find space and save it in s1,s2 and s3
s1=Lionel
s2=andres
s3=messi
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Nov 12, 2014
I am aware that the default value of char is 0. But in this program I am getting some unexpected output
public class TestClass12{
static int[] ia = new int[1];
static char ch;
public static void main(String args[]) throws Exception{
System.out.println("ch:"+ch+" ia[ch]:"+ia[ch]);
}
}
Output:
ch: ia[ch]:0
If you see the above output ch is printed as a blank space instead of 0, while the array default value is correctly printed by taking the char default value as index. Why is ch printed as blank space?
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Sep 27, 2014
I am currently trying to make a calculator in Java. I want to use the String split method to tokenize the string of characters inputted. I thought I was using the String split method wrongly, because I had surrounded the characters I wanted to delimit with square brackets. However, when I removed the square brackets, the code threw an exception when I pressed the equal button. The exception was a PatternSyntaxException exception. Am I using the String split method wrongly? And why is the exception thrown? Here is my code:
import javax.swing.*;//import the packages needed for gui
import java.awt.*;
import java.awt.event.*;
import java.util.Arrays;
import java.util.List;
import static java.lang.Math.*;
public class CalculatorCopy {
public static void main(String[] args) {
[Code] .....
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Jan 23, 2010
I am trying to split a string based on length(example length 5) of the string. But I am having a issues with this substring(start, end) method. I get all substring which are of length 5. But if the last substring is less than 5 then I am not getting that last substring. But I need the last substring even if it is less than 5.
String s = "fjdjfdfjgffgjhfjghfjkhjhjh";
String spLine;
for(int i=0; i<s.length(); i=i+5){
spLine = s.substring(i, (5+i));
}
>
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Sep 21, 2014
So I'm creating a class which when given three inputs uses them as sides of a triangle and tells ther user what type of triangle it is, or if the input is invalid, tells them why it is invalid. I'm readin the input as a string and then trying to split it into a string array, from there checking to see if it has 3 elements.. in which the data is good at that point, and then converting them to ints and checking to see if they're negative ansd finally checking to see if they can work as sides of a triangle ie a+b >c, a+c >b , b+c >a.
I'm trying to split it into an array of strings but am getting an error, and can't seem to figure out why as this should be working from what I've read of the string.split method online.
import java.util.*;
public class TriangleTest{
private int sideA;
private int sideB;
private int sideC;
public static void main(String[] args){
TriangleTest triangle = new TriangleTest("3 4 5");
[Code] ....
The output reads [Ljava.lang.String;@15db9742
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Jan 19, 2015
I have an assessment for college, the part of my code that im struggling with is the part where the user enter their first name followed by a space and then their second name. I m using ---------------fullname = JOptionPane.showInputDialog("enter your firstname followed by a space then your second name " ); ------------- to capture this. the issue is if the user only enter 1 name I need to output an error. the issue is I cant find a way to tell if the user entered a second name. This is what I have so far:
public void makename() {
// makes an inputbox to ask their name
fullname = JOptionPane.showInputDialog("enter your firstname followed by a space then your second name " );
//separates the first and second name into 2 strings in order to make the username
[code]....
The problem is it accepts anything I type in without causing an error. What should I type in to stop this? ive tried anything but I cant find a way to tell if a surname has been entered or not.
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Mar 25, 2015
I have the the string value similar to the one which i have to split based on the delimited ","
String SampleString=" 'ab,c', 'xyz', lm,n,o "
I know I can easily call split function which will eventually split the above string. But in my case the delimiter "," , is also a part of the string. If I call the function SampleString.split(',') I will get the output as listed below
ab
c
xyz
lm
n
o
but the expected output is
abc
xyz
lmno
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Jun 10, 2014
I know adjacent delimiters create empty token but is there any exception regarding last pair of delimiters ??
String a[]=":ab::cde :fg::".split(":"); // Creates 5 tokens
String a[]=":ab::cde :fg:: -Space-".split(":"); // Creates 7 tokens
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Sep 15, 2014
I have a string that look like this
"dfhsdfhds | dsfdsfdsfd dsfjkhdskjf ||ER|| jdkshfuiewryuiwfhdsfsd er dsfjsgrwhfjkds ||ER|| jkshruiewryhijdknfjksdfhdksg | "
I want to split it by "||ER||"
I try this but it splits the single "|" to not just the "||ER||" like I want.
String[] separated = response.split("||ER||");
Log.d("token",separated[0]);
Log.d("token",separated[1]);
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Nov 11, 2014
String path = "/AUTOSAR/Os_0?type=EcucModuleConfigurationValues";
String path1[] = path.split("?type");
I want to split string in such a way that I should get the content before "?" in an another variable. I tried various way but some how I am not getting expected behavior.
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Jul 23, 2014
I started using Java a couple of days ago, If you haven't guessed I want to see if the user is typing a full name or not, but I'm actually not too concerned with any more complexity than I mentioned in the title. It's ok if an input like "GLba b" comes out positive.
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Oct 14, 2014
I need making char[] to a string im not entirely sure what to change i'm just suppose to use a string value but the upperclassmen used char:
char[] number = clear.toLowerCase().toCharArray();
for(int c = 0; c < number.length; c++) {
if(digit[c] < 'a' || digit[c] > 'z')
continue;
[code]...
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Aug 30, 2014
I have a String as follows: "the|boy|is|good"
now, I want to split this string using the "|" delimeter.
I tried this :
String line = "the|boy|is|good";
line.split("|");
But it didn't split it. Is there some regex for "|"?
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Oct 19, 2014
In this exercise, create a program that asks a user for a phrase, then returns the phrase with the words in reverse order. Use the String class's .split() method for this.
Example input
The rain in Spain falls mainly on the plain
Example output
plain the on mainly falls Spain in rain The
While I understand the assignment, nowhere in the text is it covered how to reverse the order of the words in the string. I understand using the .split method, but not for this exercise.
Here is my code so far.
import java.util.*;
/**
* Java class SplitString
* This program asks for a phrase, and the code allows the phase to return in reverse order.
*/
public class SplitString {
public static void main (String[] args){
//set phrase input and mixed which will be the result
[Code] ....
As you can see, I have been googling this method and have come up nearly empty. My text does not cover the .reverse() method. The only thing it covers with .split() is how to split a string. I also tried StringBuilder with no success.
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Mar 16, 2014
I can't figure out how to have all of the random characters generated to go into the String. Below I can only get the last character to covert over to a String.
System.out.println("Original random character string:");
String printingString = "a";
for (int i = 0; i < 50; i++)//loop to obtain 50 random characters
{
char randomChar = (char) ((Math.random() * 255) +32);
System.out.print(randomChar);
printingString = Character.toString(randomChar); }
return printingString; }
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Oct 21, 2014
I found a fun program online and something so simple is giving me an issue. I c++ it is pretty simple fix, I can just call the strings location like an array. In java this is not the case. So far i have tried:
myString.charAt();
myString.indexOf();
There are a few other I found on google but I forget at the moment. I am just trying to close the gap on a string. It was a full sentence and I used replaceAll a few times to get several words I didn't want in the file out.
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Mar 15, 2014
I am trying to get resultset into a string and then use split method to store it in an array but it is not working. i tried to work it seperately as java program but it throws exception "could not find or load main class java."
String ar = "This.is.a.split.method";
String[] temp = ar.split(".");
for(int i=0;i<temp.length;i++){
System.out.println(temp[i]);
}
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Jun 23, 2014
I am encountering a problem while running this small piece of code.
public class TestSplit{
public static void main(String[] args){
String myWords[]="My.Home.Is.Being.Painted".split(".");
for(int i=0;i<myWords.length;i++)
System.out.println(myWords[i]+" ");
}
}
The problem is: it does not run at all. No error message is displayed. It just returns to the command prompt when i run it. Where am i wrong?
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May 10, 2014
String str = "#11* 1# 2*12# 3"
required o/p in array as
#11
* 1
# 2
*12
# 3
i.e splitting the strings for every 3rd string and storing it in an array of strings ...
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Mar 3, 2014
Regular expression which I want to use to split a string. The string could look similar to this:
"a = "Hello World" b = "Some other String" c = "test""
The String is read from a file where the file contents would be:
a = "Hello World" b = "Some other String" c = "test"
After splitting I would like to get the following array:
String[] splitString = new String[] {"a", "=", ""Hello World"", "b", "=", ""Some other String"", "c", "=", ""test""}
I know I could just write a simple text parser to go over the string character by character, but I would rather not do it to keep my code clean and simple. No need to reinvent the wheel.
However, I just cant seem to be able to find the right regular expression for this task. I know that a RE must exist because this can be solved by a finite automaton.
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Apr 30, 2014
what will i compare in if statemet is the 1st letter of each if i have code="a" and name="Angelina" first letter of each is "a" and "A" then in convert it to string so that i can make it uppercase but when i compare it in if statement it always go into "not x" but the ouput that im getting is x=A y=A then it always direct me into else statement.
String code = "a";
String name = "Angelina";
char c = code.charAt(0);
char n = name.charAt(0);
[code]...
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Apr 1, 2014
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string.
Example: the string Welcome and the letter e, is 2 times. so the program should print 2.
It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
[Code] .....
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Jun 5, 2014
I am trying to count each char in a string. For example A = 1, B =2, C=3, I am not looking for their binary value. So the word "At" would
AT= (A=1 +T=20)=21.
I know how to do this in C++ because I am able to treat a string like an array.
Java Code: void printFile()
{
int sum=0;
String line;
for(char cr ='A';cr<'Z';cr++)
{
for(int i=0; i<myList.size();i++)
[Code]...
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Aug 3, 2014
import java.io.IOException;
import java.util.*;
public class Guesser {
public static void main(String[] args) throws IOException {
char[] alphabet = "abcdefghijklmnopqrstuvwxyz1234567890 .,:;'-".toCharArray();
[Code] .....
I'm writing a program which will take a three letter word (for now) and then try to guess the word over and over again until it finds it, then print the word and the amount of tries it took to find it.
The problem: at the moment the program will find the word but not break out of the for loop when it does. I think it doesn't like the char to String conversion somewhere along the line.
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Apr 1, 2014
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string. Example: the string Welcome and the letter e, is 2 times. so the program should print 2. It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
str=user_input.next();
[Code] ....
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Apr 3, 2015
I have a simple doubt. I was studying and create some code to check the result and I found out a strange situation.
Whats wrong with this code? Why it does not print anything?
char = 0; //integer value
System.out.println( c +" String ");
and why this next works very well?
char = 1; //integer value
System.out.println( c +" String ");
I know that char is stored as a positive integer and assign with 0 is different of assign with '0'.
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