User Inputs His Full Name In A String From Keyboard / Program Will Give His Initials As Output

Jan 5, 2014

Following is the code for my assignment where a user inputs his full name in a string from keyboard. It should be done using BufferedReader. The program will give his initials as output.

############################

For example: User inputs-> Ram Kumar Das

Program Returns-> R.K.D.

I am written the following piece of code. It does not return the correct output. If "Ram Kumar Das" is given as input, it gives R.K.K. as output. Arrays and objects are strictly not allowed.

Java Code:

import java.io.*;
public class Assignment
{
static int i=0;
static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
public static void main (String args[]) throws IOException

[Code] ....

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Retrieving User Input String From Keyboard - Program Errors (try / Catch)

Sep 23, 2014

I need to design, implement, and test a program to input and analyze a name. The program begins by retrieving a user input string from the keyboard. This string is intended to be the user's name. These are the errors we have to search analyze the user input for: No blanks between names firstName and lastName, Non-alphabetic characters in names, Less than two characters in first name, and Less than two characters in last name. Each of these errors must be thrown. All exceptions must be derived from a programmer-defined class called NameException. Each exception should use a detailed message to differentiate among the file types of errors.

This is the format of my NameException class, is the format itself correct? I will fill in the details of each exception I am just wondering if that is how I should set it up.

public class NameException extends Exception {
private String firstName, lastName;
public NoBlanksException(String firstName,String lastName) {
}
public NonAlphabeticalCharactersException(String firstName, String lastName) {

[Code] .....

I was told not to try and catch thrown errors in the main method, would I just create another method in the Driver class to take care of that then?

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Suppose my expected output is e7.6 , but i am getting e76.

Only the "." is missing.

Here is my BinToHex class..

import java.io.*;
public class BinToHex {
double tempDec,fractionpart;
long longofintpart,templongDec;
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[Code] .....

Here is how decimal fraction is converted into hex or here too...

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I'm working on an assignment for my Java Programming class that requires me to work with Multiple Classes.

Overview of the assignment: Create a "Database" that allows a user to input information about a College Class.

My program has three Classes:

The information that must be tracked in the Course Class is:
- Section Number
- Instructor
- Classroom
- Students (an ArrayList of class Student)

The information that must be tracked in the Student Class is:
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- Major
- GPA
- Hours

The Driver class will use the main method to print the user a prompt asking for inputs, then display all of the user's inputs after he/she wished to exit the program.

I'm having no trouble with asking the user for inputs and then checking the validations for the inputs, I'm currently struggling with return a String that houses all of the user's inputs for the variables above. The information must be returned in a method called toString(). Both the Student and Course Class must have a toString() method that returns the information in the class (value of the variables), I must then call upon these methods from the main method of the Driver Class to print them back to the user.

The toString methods within the Student & Course Classes are at the bottom of the code

To Summarize: What I need to do within the toString() methods to return the values the user has inputted for the various variables? Such as.. Should I pass something through the method? Do I need the this keyboard to pass through the variable again? I just fear that I'm currently misunderstanding a very critical part of programming.

My Driver Class

import java.util.Scanner;
public class Driver {
Course courseInputs = new Course();
Student studentInputs = new Student();
public static void main(String[] args) {

[Code] .....

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This is what I have so far, but how do I ask the user for the number or rows and give the user the option to repeat the program?

public class Pyramid {
public static void main(String[] args) {
int myLevel;
int i, j , k;
myLevel = 6;
for (i = 1; i <= myLevel; i++) {

[Code] ....

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Sep 21, 2014

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insert "}" to complete StatementKALENDER_3.java
insert "}" to complete BlockKALENDER_3.java

The code:

import java.util.*;
import java.util.Scanner;
public class KALENDER_3
}
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[code].....

I think I have just forgot to put in a few { } symbols, maybe an open loop?

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package bb.main;
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import bb.main.render.SimpleRenderer;
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[code]....

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here is my BinToHex class..

import java.io.*;
public class BinToHex {
double tempDec,fractionpart;
long longofintpart,templongDec;
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[Code] ....

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LoginScreen class

/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package deneme3;
import java.sql.Connection;

[code]....

You can see Button Action in MainProgramWindow " System.out.println( ??? );" How i can retrieve users inputs from this class ?

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/*-------------------------------------------------------------------------
import java.util.*;
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[Code].....

I am having trouble with the question counter. I need the counter to increase when c, d or e are entered. I think I need to set up a if or while loop but I'm not sure how to setup the variables. This is what I have for the counter so far.

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public class DriverSort {
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Scanner scan =new Scanner(System.in);
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[code]...

can count the numbers from 0-9 if the user puted but if it is 10 it doesnt count it , and i need to write all the numbers to have that option. . . . Is there an easy way that includes all the numbers? like if(word.equals(number)){<<<???? (numbers) i know htat doesnt work but is there anything similar ?? ??

countNumbers++;
}
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import java.util.Scanner;
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Screenshot attached, with values entered.

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import java.util.*;
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So, while doing some homework, I came across an oddity. The assignment was to take a first, middle and last name and print the initials. The above code was my first solution, however it prints the number 219 instead of JFK.

For the record, I worked around it by using the .substring method instead.

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Welcome!

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Last Name: De La Torre

Birthday : 08/12/1979

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This is what I have so far :

package myinfo;
import java.util.Scanner;

public class MyInfo {
private String name;
private String lastName;
private String birthday;
private String birthPlace;

[Code] ....

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Jan 26, 2014

Develop an algorithm for a Java program that takes as input a single letter and displays the corresponding digit on the telephone. The letters and digits on a telephone are grouped this way:

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Write the algorithm to solve this problem including steps for prompting the user, getting input from the keyboard, and displaying the results.

Write the Java program that you designed, using your algorithm as a guide. Use your algorithm as comments in the body of the main method.

Use proper indentation, and meaningful identifiers throughout the code.

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import java.util.Scanner;
public class main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int number;
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[code]....

What i want to do is that if the number is greater than 50 to count until 100. else if the number is less than fifty to count for example from 36 to zero.

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Sep 29, 2014

I am trying to write a program for converting positive binary inputs into hex.Why am i getting this errors while compiling my binary to hex converter..

Exception in thread "main" java.lang.NumberFormatException: For input string: "148.0"
at java.lang.NumberFormatException.forInputString(Num berFormatException.java:65)
at java.lang.Long.parseLong(Long.java:441)
at BinToHex.convertbintohex(BinToHex.java:24)
at Test.main(Test.java:4)

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import java.io.*;
public class BinToHex {
double tempDec,fractionpart;
long longofintpart,templongDec;
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String hexOutput,intpart,tempDecString,hex = null;

[code]....

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I want to write a java program which displays to get the GPA of a student as a keyboard input. Then display the class of the degree according to the following criteria using a switch-case statement (if-else statements cannot be used). If the user insert an invalid gpa you should display a message Invalid GPA.

gpa ≥ 3.50 First Class Hons
3.49 ≥ gpa ≥ 3.00 Upper Second Class Hons
2.99 ≥ gpa ≥ 2.50 Lower Second Class Hons
2.49 ≥ gpa ≥ 2.00 Pass
2.00 ≥ gpa Fail

Here is my code:

import java.io.*;
public class q7
{
public static void main(String[] args)
{
InputStreamReader ISR=new InputStreamReader(System.in);
BufferedReader BR=new BufferedReader(ISR);
 
[code]...

.But when I use Command console to run this it says: 1111.jpg. I also wanna know is there another way to do this with switch- case statements.

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